Survey
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Chapter 8: Electrons in Atoms Electromagnetic Radiation • Electromagnetic (EM) radiation is a form of energy transmission modeled as waves moving through space. (see below left) Electromagnetic Radiation • Any wave can be characterized by its: o Speed: how fast the wave travels or propagates. – EM radiation in vacuo propagates at a constant speed of c, where c = λν = 3.00 × 108 m s−1, the ‘speed of light.’ o Wavelength (lambda or λ, in m): the distance between two adjacent crests on a wave. o Frequency (nu or ν, in s−1): the number of wavelengths passing a point per second. o Amplitude: maximum displacement of the wave. • EM radiation spans a wide range of frequencies & wavelengths 1 An FM radio station broadcasts on a frequency of 91.5 MHz. What is the wavelength of these radio waves in meters? (Hz = Hertz = cycles per second, or frequency) • The amplitudes of EM waves are signed (+/−) and ‘additive.’ o When waves in phase are added, the amplitude sum increases; this is constructive interference. o When waves out of phase are added, the amplitude sum decreases; this is destructive interference. 2 • The colors in white light can be separated into a continuous spectrum in two ways: o Diffraction: reflecting the light off a grooved surface causes the colored spectrum to appear due to interference. o Refraction: passing the light through a prism causes colors to travel at different speeds and separate into the spectrum. Atomic Spectra • The spectra produced by light from gas discharge tubes or salts in a flame consists of a limited number of wavelengths or colors. o This line spectrum is an element’s ‘fingerprint.’ 3 • Balmer deduced a formula for the frequencies of the lines observed in the atomic spectrum of hydrogen 𝜈line = 3.2881 × 1015 � 1 1 −1 − �s 22 𝑛 2 for 𝑛 = 3,4,5, ⋯ Quantum Theory • At the end of the 19th century, some phenomena could not be explained by classical physics. • Attempting to explain these phenomena a new theory was developed, quantum theory. o Central to quantum theory is the proposal that energy is not continuous, but rather is discrete in nature, that is quantized. • Max Planck (1901) explained why the intensity of EM radiation emitted by a ‘black body’ did not shoot off to infinity as predicted by classical theory. He proposed that the energy is emitted in definite (discrete) amounts called quanta. 4 • We use Planck's result in an equation that shows the energy of electromagnetic radiation is proportional to frequency 𝐸 = ℎ𝜈 where ℎ = 6.626 × 10−34 J s = Planck ' s constant • h symbolized the new quantum physics • Albert Einstein (1905) recognized that Planck's idea of light appearing as quanta (bundles or photons) was the key to understanding the mystery of the photoelectric effect. o The photoelectric effect occurs when light strikes the surface of a metal in vacuo causing an electron to be ejected. o Researchers found the energy of the ejected electron did not depend on the intensity of the light but rather on frequency. The Bohr Atom • Niels Bohr (1913) was the first to apply quantum theory to atomic structure. An impressive result of Bohr’s theory was the way it predicted the spectral lines of atomic hydrogen. 5 • Bohr theory predicted the radii of the stable orbits allowed by quantum theory 𝑟𝑛 = 𝑛2 𝑎0 where 𝑛 = 1,2,3, ⋯ and 𝑎0 = 53 pm and also the energy of an electron in an orbit −𝑅𝐻 −2.179 × 10−18 J 𝐸𝑛 = 2 = 𝑛2 𝑛 where 𝑅𝐻 = 2.179 × 10−18 J • By constructing an energy-level diagram and calculating the energies between orbits, Bohr explained the visible Balmer line spectrum of atomic hydrogen. 6 Is it likely that one of the electron orbits in the Bohr atom has a radius of 1.00 nm? Is there an energy level for the H atom, En = −2.69 x 10-20 J? 7 • This model of an electron constrained to move in quantized orbits around a central nucleus was called the Bohr Atom. o The Ground state of the Bohr H atom occurs when the electron occupies the orbit with the lowest energy (n = 1). o An Excited state occurs when the electron occupies a higher energy orbit with unfilled orbits closer to the nucleus. • As an electron moves between orbits, it absorbs or releases energy as EM radiation (E = hν). 8 • In the Bohr atom, The energy difference between initial and final energy levels ni and nf is given by −𝑅𝐻 −𝑅𝐻 1 1 1 1 ∆𝐸 = 𝐸f − 𝐸i = � 2 � − � 2 � = 𝑅𝐻 � 2 − 2 � = 2.179 × 10−18 � 2 − 2 � J 𝑛f 𝑛i 𝑛i 𝑛f 𝑛i 𝑛f ∆E > 0 if energy is absorbed (electron excitation) ∆E < 0 if energy is released (electron relaxation) • The energy of the photon either absorbed or emitted is given by (and given ∆E, this allows us to determine the EM frequency) |∆𝐸 | = 𝐸 = ℎ𝜈 Determine the wavelength of light absorbed in an electron transition from n=2 to n=4 in a hydrogen atom. 9 • The Ionization Energy of a hydrogen atom is the energy needed to remove an electron from the atom (ni = 1, nf = ∞). 1 1 ∆𝐸 = 𝐸f − 𝐸i = 𝑅𝐻 � 2 − 2 � = 𝑅𝐻 = 2.179 × 10−18 J 1 ∞ • The Bohr atom works for any ‘atom’ with one electron, such as He+ or Li2+, by introducing nuclear charge into the equation. The energy of an orbit in such an atom is −𝑧 2 𝑅𝐻 𝐸𝑛 = 𝑛2 where z = atomic number = nuclear charge = # of protons For example, n = 2 in Hg79+ 𝐸2 = −�802 �𝑅𝐻 4 • The Bohr atom was a revolutionary application of the new quantum theory, but it only worked for ‘atoms’ with one electron! It did not work for multielectron atoms. These more complex systems needed further refinements to quantum theory Two Ideas Leading to a New Quantum Mechanics • Louis de Broglie (1924) posited: If light waves can exhibit particle-like properties (photons), then perhaps particles (electrons) can exhibit wave-like behavior. • The wavelength of these “matter waves” is 10 𝜆= ℎ 𝑝 = ℎ 𝑚𝑚 Assuming Superman has a mass of 91 kg, what is his wavelength if he is traveling at one-fifth the speed of light? • Werner Heisenberg (1926) established that there is a limit to how precisely we can measure the position of a particle (x) and the momentum of that particle (p) simultaneously. The Heisenberg Uncertainty Principle is deep! It tells us that there is an inherent limit to the precision of a measurement. ℎ ∆𝑥 ∆𝑝 = (∆position)(∆momentum) ≥ 4𝜋 Wave Mechanics • All of these new concepts culminated in the formulation of the ‘Wave Mechanics,’ the laws for the motion of electrons in atoms. • A standing wave is a wave motion that reflects back on itself in such a way that the wave contains a certain number of points (nodes) that undergo no motion. • Erwin Schrödinger (1926) proposed that an electron’s matter wave could be described by a wave function corresponding to a standing wave (ψ or psi). 11 𝑛𝑛𝑛 2 𝜓𝑛 (𝑥 ) = � sin � � 𝐿 𝐿 where n = 1,2,3,… • The simplest model that shows how ψ relates to the energy levels of an electron is the one-dimensional ‘particle in a box.’ This model gives quantized energies for ψ. o Note how the wave function changes signs at the nodes • By applying de Broglie’s relationship (λ=h/p) to the kinetic energy of the particle in the box, we obtain this expression for the kinetic energy of an electron in ψn: 𝑛2 ℎ 2 𝐾𝐾𝑛 = 8𝑚 𝐿2 where 𝑛 = 1,2,3, ⋯ • Note that the kinetic energy is never zero since n≥1. o Lowest possible energy when n=1 is the zero-point energy. o This is consistent with the Heisenberg Uncertainty Principle because zero KE would violate ∆x ∆p ≥ h/4π. • The most compact form of the Schrödinger equation is Eψ = Hψ. • Schrödinger did not provide physical interpretation for ψ, but Max Born (1926) did: ψ2 is the probability of finding an electron at some point in space. 12 • Wave function solutions to the Schrödinger equation are called orbitals (‘like an orbit’) to distinguish them from Bohr’s ‘orbits.’ • We will not go into further mathematics of the Schrödinger Equation except to point out that the solutions yield three quantum numbers that specify a particular orbital; we will look at these quantum numbers, allowed values, and their meaning. 13 Quantum Numbers and Electron Orbitals • Here are the 3 quantum numbers from Schrödinger Equation. o n – – – = the principal quantum number (shell or energy level) Allowed values: n = 1, 2, 3, 4, … Meaning: The distance of the orbital from the nucleus Relationship to Periodic Table: Period number = n o l = orbital angular momentum quantum number (subshell) – Allowed values: l = 0, 1, 2, 3, … , n−1 (if n=3, l =0,1,2) – Meaning: The shape of the orbital – Relationship to Periodic Table: Sets of group numbers = l – Letters often used: l =0 = s, l = 1 = p, l = 2 =d, l = 3 = f o ml = magnetic quantum number – Allowed values: ml = −l, −l+1,…, 0,…, l−1, +l (example: for l = 2 or 5d, ml = −2, −1, 0, +1, +2) – Meaning: The orientation of the orbital in 3 dimensions – Relationship to Periodic Table: No permanent association. but we can say that an orbital spans two groups 14 15 The Fourth and Last Quantum Number! • Wolfgang Pauli (1924) proposed a fourth quantum number (ms=magnetic spin) to explain how two electrons could occupy the same space (i.e. orbital) at the same time. • The Pauli Exclusion Principle: two electrons can occupy the same orbital only if they have opposite spins (↑ or ↓). Corollary: No two electrons in an atom can have the same four quantum numbers (Quantum Numbers = n, l, ml, ms). Summary of the Four Quantum Numbers • n = the principal quantum number (shell) o n = 1, 2, 3, 4, … o Distance of the orbital from the nucleus • l = orbital angular momentum quantum number (subshell) o l = 0, 1, 2, 3, … , n−1 o Shape of the orbital; l=0=s, l=1=p, l=2=d, l=3=f • ml = magnetic quantum number o ml = −l, −l+1, …, 0, …, l−1, +l o Orientation of the orbital in 3D • ms = electron spin quantum number o ms = +½, −½ (also denoted by ↑ and ↓) 16 Degenerate and Non-Degenerate Orbitals • Degenerate orbitals all have the same energy. o In a hydrogen atom (only one electron) all orbitals in a shell (principal energy level) are degenerate. • In a multielectron atom orbitals, within a subshell are degenerate, but subshells within a shell are not degenerate. Interactions between electrons remove degeneracy. o As degeneracy is removed in multielectron atoms, subshells separate in energy and the lowest energy subshells fill first. The filling order is observed in the Periodic Table!! subshells in a shell degenerate subshells not degenerate greater separation 17 penetration Electron Configurations • We use the energy ordering of shells and subshells, and the number of orbitals per subshell, to write electron configurations. o The electron configuration of an atom or ion lists subshells that are occupied (i.e. have electrons in them). See the PT! • Subshells are occupied in the following order 1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f 6d 7p • How do we remember this? The Periodic Table! 18 • Subshells have these maximum occupancies: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p6 7s2 5f14 6d10 7p6 The The The The s subshell holds p subshell holds d subshell holds f subshell holds • Let’s look at the guiding principles for filling orbitals: o Aufbau principle: ‘building up’ principle; electrons fill lowest energy orbitals first; yields the ground state configuration. o Hund’s Rule: when degenerate orbitals (within a subshell) are being filled, the electrons occupy the orbitals singly first, all with the same spin, before pairing up. o Pauli exclusion principle: an orbital can hold at most two electrons; electrons in same orbital must have opposite spins. • The Ground State electron configuration can be written a few different ways. Here are examples for oxygen (O has 8 e−): spdf notation (condensed) spdf notation (expanded) orbital diagram Noble gas shorthand 19 You can mix and match these! Identify the element having the electron configuration 1s2 2s2 2p6 3s2 3p6 4s2 3d2 Use spdf condensed notation to show the electron configuration of iodine. How many electrons does the iodine atom have in its 3d subshell? _______ How many unpaired electrons are in an iodine atom? _______ (Condensed is default!) 1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f Represent electron configuration of iron with an orbital diagram __ 1s __ 2s __ __ __ 2p __ 3s __ __ __ 3p __ 4s __ __ __ __ __ 3d Represent the electron configuration of bismuth with an orbital diagram; use the Noble gas shorthand __ 6s __ __ __ __ __ __ __ 4f __ __ __ __ __ 5d __ __ __ 6p For an atom of Sn, indicate the number of (a) electron shells that are either filled or partially filled ______; (b) 3p electrons ______; (c) 5d electrons ______; and (d) unpaired e− ______ 1s 2s 2p 3s 3p 4s 3d 4p 5s 20 4d 5p 6s 4f 5d 6p • Valence electrons are those electrons in the highest numbered shell and any partially filled d or f subshells. (Only valence electrons are involved in chemical bonding and reactions.) • Core electrons are those electrons that are not valence electrons! Electrons in ‘filled shells’ that may have empty d or f subshells. (Core electrons are too tightly held to get involved in chemical bonding or reactions.) • Electron configurations of Cr and Cu and the stability of halffilled subshells. 21 • Penetration occurs when the radial probability of an outer subshell brings e−‘s closer to the nucleus than an inner subshell. o The 4s subshell fills before the 3d because the 4s subshell penetrates inside the 3d subshell. • Penetration also explains the non-degeneracy of subshells within a shell. This accounts for the energy ordering of the sublevels: d>p>s. 22 • Assessing electron configurations: o Is it a ground state configuration? o Is it an excited state configuration? o Is it a ‘legal’ electron configuration? – If not, what filling rules have been violated? Assess the following configurations for nitrogen (7 electrons). 1s2 2s2 2p3 1s2 2s2 2p2 3s1 1s2 2s2 2p2 2d1 1s2 2s2 ↑↑ ↑_ __ 2p 1s2 2s2 ↑↓ ↑_ __ 2p 1s2 2s2 ↓_ ↓_ ↓_ 2p 1s2 2s2 ↑_ ↓_ ↑_ 2p 1s1 2s2 2p3 7g1 23