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Download Equipotential Lines 17.1 Electric Potential Energy PE = energy
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17.1 Electric Potential Energy Electric Potential Energy, PE Units: Joules Electric Potential, V Units: Volts Equipotential Lines The Electron Volt Uniform E field Assembling point charges • Capacitance • Dielectrics • Storage of Electric Energy Electric force is a conservative force and so we can assign an electric potential energy (PE) to the system PE = energy associated with an arrangement of objects that exert forces on each other PE = capacity or potential to do work Change in Gravitational PE for a mass, m, near the Earth’s surface ∆ PEba = qVba ∆ PEgravity = mgh Why does lightning occur? Electric Potential Electric Potential (Electric) Potential, Va is a scalar quantity that is associated with the charges that create the E field Va is defined to be the electric potential energy per unit charge In the real world only changes in PE are physically meaningful, so rewrite 17.2a in terms of the potential difference. Potential difference or ꞌVoltageꞌ = change in the PE per unit charge Potential energy of system small (positive) test charge placed at point a Units = volts 1V = 1 J/C Change in Electric PE for a charge, q, that moves from point a to b through a potential difference, Vba ∆ Units: volt (V) (17-2a) Potential at a = We define where V=0 (17-3) 1 V = 1 J/C. (V=0 at the “ground” in a circuit which is typically located at the negative terminal of the battery For a collection of point charges, V = 0 at r = ∞) Va depends only on the charges that create the E field – not the test charge, q. So, what does the electric potential (V) look like? 1 Electric Potential Electric Potential It’s a scalar (a number) so problem solving is easier than with electric fields (vectors) - but take care with the sign of the potential. Potential at a distance r from a point charge Q is given by, Think of potential as a topological map… (derived using calculus and assuming V = 0 at r = ∞). V is like height and q is like mass in the gravitational case [point charge] (17-5) V m ∆PEG = mgh h .. and a negative charge. For a positive pt. charge q V +Q V -Q +Q -Q r r V is HIGH near (+) charges and LOW near (-) charges ∆PEba = qVba Note, this formula gives the potential at r AND the potential difference between ∞ and r And we typically take V = 0 at r = ∞ 17.3 Equipotentials 17.3 Equipotentials We can represent the potential near a point charge, Q using spherical ‘equipotentials’ 0 V infinitely far away from Q For a collection of point charges, simply add the potentials from the individual charges. 10 V V 20 V +Q 30 V 40 V 50 V r + E field is strongest where the equipotentials are closer All points on an Equipotential line or surface are at the same potential Equipotentials and Field lines for a ‘dipole’ (equal and opposite point charges) E field lines are ⊥ to Equipotentials 2 Question… 17.3 Equipotentials In a capacitor, the potential changes linearly from one plate to the other. What is the potential at the center of the square ? (assume V = 0 very far from the charges) -Q +Q Equipotentials are equally spaced planes, parallel to the capacitor plates. l The surface of a conductor is an equipotential. -Q l +Q Electric field lines are perpendicular to equipotentials. Is E = 0 at the center too? Can the equipotentials be reversed (0 → 20V) in the figure? Equipotentials and Field lines between two capacitor plates Remember… Question Potential and Potential Energy are different! [Volts] [Joules] Look at the Capacitor again… +Q -Q A + 4 C point charge starts from rest and moves from a to b +Q -Q high PE low PE 4 C point charge a b q+ 15 V 5V 0V 10 V 20 V Potential is higher at the positive plate We choose where V = 0 V. Potential at a point is a scaler (number) that depends on the charge on the plates and where we define zero volts to be. q low PE high PE = Potential energy of the system when point charge, q is at point a, depends on the potential and q. 5V What is the change in PE when it reaches the negative plate? The + 4C charge has a mass of 1x10-3 kg. 1. 2. 3. 4. - 20 J + 20 J No change Infinite What if it were a negative 4 C charge ? How fast is it going when it reaches b ? 1. 4 m/s 2. 200 m/s 3. 40,000 m/s 4. Very close to the speed of light 3 17.4 The Electron Volt - a Unit of Energy In atoms, 1 Joule is a VERY large amount of energy so we often use a different unit: The electronvolt, eV One eV = energy acquired by a particle with charge of magnitude e when it moves through a potential difference of 1 volt. (13 cm ~ 390,000V) A 1 cm spark corresponds to a potential difference of 30,000 V e Eg: How much KE does an electron gain when it is accelerated from rest through a potential difference of 250 V ? 250 V It gains 250 eV of KE and loses 250 eV of PE (energy conservation). Work Question The work done by the electric force (Wba) on a charge q as it moves in an electric field is defined to be minus the change in the electric potential energy Wba = - ∆PEba = - qVba Units = Joules (17.2b ) E q b a (only if ∆KE=0) C (assume ∆KE = 0) How much work is done by an external force to move a 1 C charge from .. The work done by an external force in moving a charge q in an electric field is Wext = qVba B A ∆PEba = PEb – PEa Note the different sign for external work 15 V 10 V 5V E a b A → B? B → C? C → A? (Phys111: = ∆ + ∆) ← use this if ∆KE ≠ 0 4 The next three slides have been updated. I removed the derivation of equation 17-4a Question… 17.2 Relation between electric potential and field How does E relate to V? The component of E in a given direction is equal to the rate at which the electric potential decreases over distance in that direction = − ∆ ∆ [general E] What is the electric field inside a capacitor if one plate is at +12 V and the other plate is at -3 V? The plates are separated by 2 mm. 2 mm New units for electric field: V/m E points in direction of decreasing V +12 V -3 V So for the uniform electric field inside a capacitor… E inside a capacitor is equal to minus the potential difference between the plates divided by the plate separation =− The potential is 20 V everywhere in this region… What is E in this region? [uniform E] (17-4a) Example: Work required to assemble a number of point charges - To calculate the external work required to assemble several point charges use + (let ∆KE = 0) (assume Wext = q Vba ∆ = 0) + Example: Work required to assemble a number of point charges How much work is done by an external force to bring a 2nd charge (Q2) from infinity and place it a distance r from Q1? Q1 r Q1 1 Zero ! There are no other charges present so Vba (17-5) Wext = Q2V1 = Q2 kQ1 r Use the above eqn. and bring the charges in from infinity one at a time How much work is done by an external force to bring charge Q1 from infinity and place it at the origin? 1 Work done by external force to move Q2 is Q1 V = 0 at r = ∞ Potential difference (due to Q1) between infinity and r, is Q2 Q2 r13 Q3 Work done by an external force in moving Q3 is, r23 Wext = Q3V1+Q3V2 = Q3(V1+V2) = Q3 kQ1 + Q3 kQ2 r13 r23 For more charges, just add more terms. = 0, and Wext = 0 Total work needed to assemble the charges is the sum of all steps 5 What can you say about the work done by an EXTERNAL FORCE to bring a +1 µC charge from far away and place it on the third corner of the equilateral triangle? 1. 2. 3. 4. 17.7 Capacitance + 1 µC Its positive Its negative Its zero Huh? d - 1 µC A capacitor consists of two conductors that are close but not touching. d d + 1 µC How much WORK is done by the ELECTRIC FORCE when the – 2.0 µC charge moves closer to the positive charge, as shown? 10.0 cm + 3.0 µC − 2.0 µC 4.0 cm Capacitor symbol (the + 3 µC charge is fixed in space) (1) 0 J (2) - 0.12 J (3) - 0.65 J (4) + 0.81 J What does a capacitor do? 17.7 Capacitance For a charged capacitor.. charge on each plate Units: farad (F) 1 F = 1 C/V 17.8 Dielectrics A dielectric is an insulator, characterized by a dielectric constant K. voltage across capacitor (17-7) Capacitance depends on geometry and capacitor materials. Capacitance of a parallel-plate capacitor INCREASES when it is filled with a dielectric: C = K ε0 A/d For a parallel-plate capacitor (with air gap) ε = K ε0 (17-9) (17-8) circuit diagram Permittivity of free space 8.85 x 10-12 C2/Nm2 d ε = permittivity of the material Max field a dielectric can experience without breaking down. 6 17.8 Dielectrics Eg: What happens when a dielectric is inserted into a capacitor connected to a battery? C 17.9 Storage of Electric Energy Question What happens when a dielectric is inserted into an isolated capacitor that has charge Q on it? A charged capacitor also stores electric energy Energy stored (PE) = work done to charge the capacitor. C (17-10) V +Q -Q V stays constant (battery keeps V constant) C increases (due to dielectric) Q increases (Q = CV, more charge is pulled from battery) 1. 2. 3. 4. 5. Q stays constant, C decreases, V decreases Q stays constant, C decreases, V increases Q stays constant, C increases, V decreases Q stays constant, C increases, V increases Q increases, C stays constant, V increases Question... A charged parallel-plate capacitor is disconnected from a battery. Suppose the capacitor plates are pulled apart. Energy density, uE = stored energy per unit volume, is the same no matter the origin of the electric field: Units J/m3 uE = (17-11) Pointed conductors, ion winds, lightning and St. Elmo’s fire +Q -Q In Ch. 16 we saw that E = 0 inside a conductor and is ⊥ to the outer surface. In non-spherical conductors, surface charge densities and electric fields are biggest where the curvature is greatest. Equipotentials are closer together there too. What happens to the potential energy stored in the capacitor ? 1. It increases 2. It decreases 3. It stays the same Where does that energy come from? If the E field is strong enough an “ion wind” or “corona discharge” may occur (St. Elmo Fire) conductor Equipotentials (dashed) Big surface charge density and E field Field lines (solid) 7 Summary of Chapter 17 Work done by electric force on a charge that moves in electric field is minus change in PE: Change in potential energy when a charge q moves through potential difference of V is, E = - V/d Wba = - ∆PE ∆PE = qV (17-3) Uniform field (17-4a) Potential difference between r and ∞ due to pt. charge Q Point charge (17-5) Equipotential = line or surface at constant potential. Charge on a capacitor: Capacitance of a parallel-plate capacitor: A dielectric is an insulator. It can be used to increase the capacitance of a capacitor by a factor K. 8