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Evaluate each expression for x = 4, 5, 6. 1. 2x + 1 9, 11, 13 2. 0.5x + 1.5 3.5, 4, 4.5 3. x2 - 1 4. 2x + 3 15, 24, 35 19, 35, 67 Section 9.4 WHY? Infinite sequences, especially those with finite limits are involved in some key concepts in calculus. A sequence is an ordered set of numbers. Each number in the sequence is a term of the sequence. A sequence may be an infinite sequence that continues without end, such as the natural numbers, or a finite sequence that has a limited number of terms, such as {1, 2, 3, 4}. Instead of function notation, such as f(x) or a(n), sequence values are written by using subscripts. The first term is a1, the second term is a2, and the nth or kth term is an or ak. Because a sequence is a function, each number n or k has only one term value associated with it, an or ak. *** some books use n, some use k *** Reading Math an is read “a sub n.” Example 1: Find the first 6 terms and the 100th term of the sequence {ak}, in which ak = k2 – 1 akak a1a1 Process: Process: k2k–2 1– 1 12 – 1 Term Term =0 a2a2 a3a3 a4a4 a5a5 22 – 1 32 – 1 42 – 1 52 – 1 =3 =8 = 15 = 24 a6a6 62 – 1 = 35 a100 a100 1002 – 1 = 9999 Go back to your warm up #3, does this match up for x = 4, 5, 6??? You can use your calculator by using the function: y= x2 – 1 Go to table set and choose ASK for Independent Then simply type the x values and press enter You can also use your calculator by typing the following commands: 0k k+1k: k2 – 1 ▪ is the STO> button ▪ k is the ALPHA character for the ( button ▪ : is the ALPHA character for the . Button Every time you press enter it will show you the next term starting with a1 Example 2: Find the first 6 terms and the 100th term of the sequence defined recursively by the conditions: b1 = 3 bn = bn-1 + 2 bn b1 b2 b3 b4 b5 b6 for all n > 1 Process b2-1 + 2 b1 + 2 3+2 Term =3 =5 =7 =9 = 11 = 15 Example 2: Find the first 6 terms and the 100th term of the sequence defined recursively by the conditions: b1 = 3, bn = bn-1 + 2 for all n > 1 Can you see that pattern or sequence? {3, 5, 7, 9, 11, 13, …} To get the 7th term, it is 6 terms beyond the 1st which means that we can quickly get there by adding 6 2’s to the 1st term, 3. b7 = 3 + 6(2) = 15 Is this reasonable for the sequence? Now find the 100th term: 201 You have probably heard of the Fibonacci Sequence. One way to propagate the sequence is with the help of Pascal’s Triangle: =1 =1 =2 1 =3 =5 2 1 =8 1 1 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1 You can find each term of the sequence using addition, but the sequence is not arithmetic. The recursive formula for the Fibonacci sequence is: Fn = fn-2 +Fn-1 F1 =1 F2 = 1 Graphs of Arithmetic Sequences relate to linear functions (think adding for consecutive terms) Graphs of Geometric Sequences relate to exponential functions (think multiply for consecutive terms) Explicit: Explicit: Recursive: a1 = a given value an = an-1 + d (for all n > 2) Recursive: a1 = a given value (for all n > 2) Example 3: Identify the given sequences as arithmetic, geometric, neither or either? Start by checking common differences and common ratios -5, 10, -20, 40, … Geometric, the common ratio is -2 2, 2, 2, 2, … Either, the common difference is 0 And the common ratio is 1 25, 50, 75, 100, … Arithmetic, the common difference is 25 1, 4, 9, 16, … Neither, there are no common difference or common ratio The Arithmetic mean is simply adding 2 numbers and dividing by 2, it is what you think of when you think “average” Example 4: Find the missing term of the arithmetic sequence 84, ___, 110, … Example 5: Find the missing term of the arithmetic sequence 24, ___, 57, … Example 6: Find the missing term of the geometric sequence 3, ___, 18.75, … Example 7: Find the missing term of the geometric sequence 9180 , ___, 255, … Example 8: Write a recursive and an explicit formula for the given arithmetic sequence: -32, -20, -8, 4, 16 d, (common difference) = 12, Explicit: an = a1 + (n-1)d an = -32 + (n-1)12 a1, (1st term) = -32 Recursive: a1 = the first term an = an-1 + d (for all n > 2) a1 = -32 an = an-1 + 12, (for all n > 2) Example 9: Write a recursive and an explicit formula for the given geometric sequence: 3, 6, 12, 24, 48, … r, (common ratio) = 2, Explicit: an = a1 * r n-1 an = (3) 2 n-1 a1, (1st term) = 3 Recursive: a1 = the first term an = an-1 * r (for all n > 2) a1 = 3 an = (2)an-1 (for all n > 2) Just as we are concerned with the end behavior of functions, we will also be concerned with the end behavior of sequences. Converges If the degree of the numerator is the same as the degree of the denominator, the limit is the ratio of the leading coefficients If the degree of the numerator is less than the degree of eh denominator, the limit is zero. Diverges If the degree of the numerator is greater than the degree of the denominator, the limit is infinite. A sequence is a pattern A series is the sum of the terms in the sequence Finite Sequence 6, 9, 12, 15, 18 Finite Series 6 +9 + 12 + 15 + 18 Infinite Sequence 3, 7, 11, 15, … Infinite Series 3 + 7 + 11 + 15 + … For an infinite Geometric series, use the following, where a1 is the 1st term and r is the common ratio. Just as we are concerned with the end behavior of functions, we will also be concerned with the end behavior of series. Converges Diverges, (no limit) |r|<1 |r|>1 *converges to the sum S *diverges, no limit 9.4 p.739, 1-31 odd Project due 5/2 or 5/3 Quiz at the end of next class