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Advanced kinetics Solution 1 February 24, 2017 1 Chemical kinetics 1.1 For homogeneous reactions, the rate equation corresponding to the stoichiometric equaP νi Bi is: tion 0 = i vc = 1 dci νi dt (1) where ci is the concentration of the species Bi . For heterogeneous reactions, the rate of conversion must be used: vξ = 1 dni νi dt (2) where ni is the amout of the species Bi . 1.2 In some cases, the rate equation can written in the following way: Y m vc = k ci i (3) i In this case, mi is the Porder of the reaction with respect to species Bi . The total order of mi and k is the rate constant. Not all reactions have an order. For the reaction is m = i elementary reactions, the order is directly associated to the molecularity which indicates the number of reactive particles involved in the reaction. For most reactions, when an order can be defined, it is an empirical quantity. 1.3 In the transition-state theory, reactant species have to pass a maximum energy point on the associated hypersurface to reach the product side. They stay in quasi-equilibrium on the reactant side until this maximum point is reached. The first Eyring equation provides an expression for unimolecular rate constants: kB T q 6= E0 kuni (T ) = exp − (4) h qA kB T qA stands for the partition function of the reactant A. q 6= is the restricted partition function for a fixed reaction coordinate refering to the top of the energy barrier and E0 is the activation energy. The second Eyring equation provides an expression for bimolecular rate constants: kB T qe6= E0 kbi (T ) = exp − (5) h qeA · qeB kB T 1.4 A bimolecular reaction can be considered as a reactive collision with a reaction cross section σ which depends on the translational energy of the reactive species A and B. Simple collision theories neglect the internal quantum state dependence of σ so that the rate constant k results as a thermal average over the Maxwell-Boltzmann velocity distribution: k(T ) = hvrel ihσi (6) 1 Advanced kinetics Solution 1 where hvrel i is the thermal average center-of-mass velocity: s 8kB T hvrel i = πµ February 24, 2017 (7) −1 with the reduced mass µ is defined as µ−1 = m−1 A + mB . There are several simplified models for the reaction cross section σ (hard sphere, constant cross section with a threshold, with a hyperbolic threshold...) that try to represent the energy dependence of the effective reaction cross section. Some are schematically represented in Figure 1. Figure 1: Simple models for effective collision cross section σ: hard sphere without threshold (dotted line), hard sphere with threshold (dashed line) and hyperbolic threshold (full curve). Et is the (translational) collision energy and E0 the threshold energy. σ0 is the hard sphere collision cross section (taken and modified from D. Luckhaus, M. Quack, in Encyclopedia of Chemical Physics and Physical Chemistry Vol. 1 (Fundamentals), Chapter A.3.4, pages 653–682 (IOP publishing, Bristol 2001, ed. by J. H. Moore and N. D. Spencer). 2 68 Advanced kinetics CHAPTER 3. STRUCTURE AND SPECTRA OF DIATOMIC MOLECULES Solution 1 February 24, 2017 • keeping higher terms in Equation (3.27). One then can account for the lengthening of 2 Quantumthemechanics average internuclear distance caused by the anharmonic vibrational motion 1 · , the Born-Oppenheimer (3.33) approxBvin =B αe (v + ) + · ·of e − framework 2.1 The energy of a diatomic molecule the 2 imation and the harmonic oscillator-rigid rotor approximation is a sum of an electronic • taking into (E account centrifugal distortion (which corresponds to an elongation of the (Un ), a vibrational vib ) and a rotational (Erot ) energy: bond as the rotational motion gets faster, i. e. at increasing J values) En,v,J = Un (Re ) + Evib (v) + Erot (J) = Un (Re ) + hνosc. (v + 1/2) + hcB̃J(J + 1) (v) Erot (J) = Bv J(J + 1) − Dv J 2 (J + 1)2 + · · · . (8) (3.34) Re is the equilibrium distance between the two atoms of the diatomic molecule. The and thus, the rotational depends on the quantum number v. corresponding energy diagramenergy is shown in Figure 4. Figure 3.2: Schematic of the rovibronic energy levels of a diatomic molecule. Figure 2: Energy diagram for a diatomic molecule in the framework of the Born-Oppenheimer approximation oscillator-rigid rotor The constants ωeand , ωe xthe ye , Be , αe , etc. are tabulated for manyapproximation. electronic states ofUmany 0 (Re ) stands e , ωe harmonic fordiatomic the energy of the electronic ground1979, state. molecules (see Huber and Herzberg, in the literature list) and can be used to calculate the rovibronic energies of a diatomic molecule. Nowadays efficient ways (and good programs) are available to solve Equation (3.25) numerically. 2.2 The electromagnetic field interacts with molecules in four different regions: The harmonic oscillator (with its potential V (Q) = 1 kQ2 ) represents a good approximation 2 • Radio waves (frequency: up to 900 wavelength ≈ meter), with nuclear to the vibrational motion of a molecule onlyMHz, in the vicinity of Re . The solution isinterct (see Lecture magnetic dipoles (NMR, Nuclear Magnetic Resonances). Radio waves also affect Physical Chemistry III) electrons in bulk system (as metals), ! creating electric currents that are hte physical " (harm.) E (v) 1 phenomena leading to vib well known as radio transmissions by antennas. = tecnologies ωe v + (3.35) hc 2 • Microwaves (frequency: GHz, wavelength usually interacts with ro1 ≈ centimeter), − 12 Q2 #√ Hvbe (Q)e ,to perturb electrons (3.36)in metals Ψv (Q) =but tational levels of small molecules can also used π v! 2v bulk system (as Wi-Fi connections usually do). PCV - Spectroscopy of atoms and molecules • InfraRed waves (frequency: THz, wavelength ≈ micrometer), can exchange energy with the vibrational levels of molecules, givin informations about the kind of atoms and bounds present. Due to quantum selection rules, only some modes can interact direcltly with the EMF; still the others can be investigated using the Raman effect. • Visible/UltraViolet light (frequency: PHz, wavelength ≈ 100 nanometer) promote elctronic excitations to high energy electronic state (also called PES). Due to symmetry conditions, this electronic states can be not bounded and rapidly induce 3 Advanced kinetics Solution 1 February 24, 2017 the dissociation of molecules. Due to high quantity of energy introduced into the molecule by a single photon, a large classes of effects (fluorescence, phosphorecence . . . ) can be observed depending on the topology of the PES. 2.3 The solution of the Schrödinger equation for the hydrogen atom can be expressed as: • Eigenvalues (i. e. the energies): En,l,m = − Z 2 µe4 1 hcR = − 2 = En 2(4πε0 )2 ~2 n2 n (9) where R is the Rydberg constant (R ' 109700 cm−1 ). • Eigenfunctions can be written as a product of a radial function Rn,l (r) and an angular function (spherical harmonics) Yl,m (θ, ϕ): Ψn,l,m (r, θ, ϕ) = Rn,l (r) Yl,m (θ, ϕ) (10) 2.4 Particle in the box: Ĥ = − ~ d2 + V (x) 2m dx2 (11) with (see figure 4) ( 0, V (x) = ∞, if 0 ≤ x ≤ L otherwise (12) The solutions of the time-independent Schrödinger equation are: n 2 h2 8mL2 r nπx 2 = sin L L En = (13) Ψn (14) 2.5 Operators are well defined only when applied to a function, i.e. a vector in a Hilbert space H; moreover, they do commute only if they have a multiplicative effect on the vector. For a generic function f in coordinate space, we have: 1 ∂ ∂ 1 2 ∂ ∂ ∂2 x̂ + x̂ − f = x̂ − x̂ + x̂ − 2 f = 2 ∂ x̂ ∂ x̂ 2 ∂ x̂ ∂ x̂ ∂ x̂ 2 1 2 ∂f ∂[x̂f ] ∂ f 1 2 ∂f ∂f ∂ x̂ ∂ 2 f x̂ f − x̂ + − 2 = x̂ f − x̂ +x +f − 2 = 2 ∂ x̂ ∂ x̂ ∂ x̂ 2 ∂ x̂ ∂ x̂ ∂ x̂ ∂ x̂ 2 2 1 2 ∂ f 1 2 ∂ x̂ f − 2 + f = x̂ − 2 + 1 f , ∀f ∈ H 2 ∂ x̂ 2 ∂ x̂ 4 Advanced kinetics Solution 1 February 24, 2017 Figure 3: Representation of the potential describing a particle in a box of length L. If we multiply the space derivative by the immaginary unit i, we found the definition of ladder operators for an harmonic oscillator. Using the definition of momentum p̂ = −i~∂/∂x we use the same approach above to obtain [x̂, p̂]f = x̂p̂f − p̂x̂f = −i~x̂ ∂f ∂ x̂f ∂f ∂ x̂ ∂f + i~ = − i~x̂ + i~f + i~x̂ = i~f ∂x ∂x ∂x ∂x ∂x Using the commutator property [ÂB̂, Ĉ] = (Â, [B̂, Ĉ]] + [Â, Ĉ]B̂), we find that: 1 2 [p̂ , x̂]f 2m i~ 1 p̂[p̂, x̂] + [p̂, x̂]p̂ f = (p̂ + p̂)f = 2m 2m i~p̂ = f m [Ĥ, x̂]f = [T̂ , x̂]f + [V̂ , x̂]f = [Ĥ, p̂]f = [T̂ , p̂]f + [V̂ , p̂]f = [V̂ , p̂]f = −i~ V̂ = i~ ∂ V̂ f ∂ x̂ ∂f ∂[V̂ f ] ∂f ∂f ∂ V̂ − = −i~ V̂ − V̂ −f ∂ x̂ ∂ x̂ ∂ x̂ ∂ x̂ ∂ x̂ 1 1 [V̂ , p̂2 ]f = [V̂ , p̂]p̂ + p̂[V̂ , p̂] f 2m 2m i~ ∂ V̂ ∂ V̂ i~ ∂ V̂ ∂[∂ V̂ /∂ x̂f ] p̂ + p̂ f = p̂ − i~ = 2m ∂ x̂ ∂ x̂ 2m ∂ x̂ ∂ x̂ 2 i~ ∂ V̂ ∂ V̂ ∂ V̂ = p̂ − i~ 2 + p̂ f = 2m ∂ x̂ ∂ x̂ ∂ x̂ i~ ∂ V̂ ∂ 2 V̂ = 2 p̂ − i~ 2 f 2m ∂ x̂ ∂ x̂ [V̂ , T̂ ]f = 5 (15) Advanced kinetics Solution 1 February 24, 2017 3 Tunneling process 3.1 Scheme of the potential energy hypersurface Figure 4: Vibrational term value diagram of the torsional band of phenol, including the electronic Born-Oppenheimer potential (dashed) and the lowest adiabatic channel potential (bold), both shifted to E = 0 at the minimum (after S. Albert, P. Lerch, R. Prentner, M. Quack, Angew. Chem. Int. Ed. 52 (2013) 346-349). 3.2 The first four eigenfunctions of the time-independent Schrödinger equation are depicted in Figure 4. 3.3 The general expression for the solution of the time-dependent Schrödinger equation considering the two lowest energy levels ϕ1 and ϕ2 of energies E1 and E2 respectively is: 1 iE1 t i∆E12 t Ψ (t) = √ exp − ϕ1 + ϕ2 exp − (16) ~ ~ 2 with ∆E12 = E1 − E2 . Assuming that ϕ1 and ϕ2 are real functions, the probability density is given by: 1 2 ∆E12 t ∗ 2 P (t) = Ψ (t)Ψ (t) = ϕ + ϕ2 + 2ϕ1 ϕ2 cos 2 1 ~ (17) which is a periodic function with the period T = 2π~/∆E12 . 3.4 For the vibrational ground state: TGS = (c ∆ν̃GS )−1 = 17.5 ns For the first torsional excited state: Ttors. = (c ∆ν̃tors. )−1 = 370 ps 3.5 In classically allowed regions E − V > 0, whereas in forbidden regions E − V < 0. The conjunction points between them, called turning points, necessary exist when E − V = 0 and are crucial elements in semiclassiclal methods. If we take the 1D Schrödinger equation 6 Advanced kinetics Solution 1 ~2 ∂ 2 ψ + V ψ = Eψ 2m ∂x2 ∂2 2m ψ = 2 (V − E)ψ 2 ∂x √ ~ February 24, 2017 − ψ ≈ ei (18) 2m(E−V )/~2 x Therefore, when E −V > 0, the square root in the exponetial is real and the wavefunction have a oscillotary behaviour, due to imaginary factor (cfr Euler’s formula); in this case the probability density |ψ|2 is greater than zero. Otherwise, the wavefunction has a negative exponential behaviour, and its probability density go to zero with it. 7