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Electric Potential A difference in electrical potential between the upper atmosphere and the ground can cause electrical discharge (motion of charge). Ch 25 – Electric Potential So far, we’ve discussed electric force and fields. Now, we associate a potential energy function with electric force. This is identical to what we did with gravity last semester. gravity m1m2 Fg G 2 rˆ r m g G 2 rˆ r m1m2 U g G r electricity Fe ke q1 q2 r2 q E k e 2 rˆ r ? Ch 25.1 – Electric Potential and Potential Difference • Place a test charge, q0, into an E-field. The charge will experience a force: F q0 E • This force is a conservative force. • Pretend an external agent does work to move the charge through the E-field. • The work done by the external agent equals at least the negative of the work done by the E-field. Do Now (9/19/13): • What does the word “voltage” mean to you? • Where have you seen the word before? • What is the formula for work? (think back to last year!) Ch 25.1 – Electric Potential and Potential Difference Potential difference due to work being done on a particle W V qo • This physical quantity only depends on the electric field. • Potential Difference – the change in potential energy per unit charge between two points in an electric field. • Units: Volts, [V] = [J/C] • A change in electric potential energy can only occur if a test charge actually moves through the E-field. Ch 25.1 – Electric Potential and Potential Difference • Units of the potential difference are Volts: 1 V 1 J/C • 1 J of work must be done to move 1 C of charge through a potential difference of 1 V. Ch 25.1 – Electric Potential and Potential Difference • We now redefine the units of the electric field in terms of volts. 1 N/C 1 V/m E-field units in terms of volts per meter Voltage • What is the formula for work? W Fd W Fd V q q • Simplify: Fd F V d q q V Ed Example: • What is the voltage on a proton at rest in an E-field of 20 N/C? Practice: • Complete AT LEAST one problem from the Potential Difference paper • When you finish, raise your hand to get it stamped • Once you have your stamp you may work on that paper, your quiz review, or your notecard Ch 25.1 – Electric Potential and Potential Difference • Another useful unit (in atomic physics) is the electron-volt. 1 eV 1.60 10-19 C V 1.60 10-19 J The electron-volt • One electron-volt is the energy required to move one electron worth of charge through a potential difference of 1 volt. • If a 1 volt potential difference accelerates an electron, the electron acquires 1 electron-volt worth of kinetic energy. Quick Quiz 25.1 Points A and B are located in a region where there is an electric field. How would you describe the potential difference between A and B? Is it negative, positive or zero? Pretend you move a negative charge from A to B. How does the potential energy of the system change? Is it negative, positive or zero? Ch 25.2 – Potential Difference in a Uniform E-Field Let’s calculate the potential difference between A and B separated by a distance d. Assume the E-field is uniform, and the path, s, between A and B is parallel to the field. V E d s B A Ch 25.2 – Potential Difference in a Uniform E-Field Let’s calculate the potential difference between A and B separated by a distance d. Assume the E-field is uniform, and the displacement, s, between A and B is parallel to the field. V E d s B A B V Eds cos 1 A B V E ds A V Ed Ch 25.2 – Potential Difference in a Uniform E-Field V Ed The negative sign tells you the potential at B is lower than the potential at A. VB < VA Electric field lines always point in the direction of decreasing electric potential. Ch 25.2 – Potential Difference in a Uniform E-Field Now, pretend a charge q0 moves from A to B. The change in the charge-field PE is: U q0 V q0 Ed If q0 is a positive charge, then ΔU is negative. When a positive charge moves down field, the charge-field system loses potential energy. Ch 25.2 – Potential Difference in a Uniform E-Field Electric fields accelerate charges… that’s what they do. What we’re saying here is that as the E-field accelerates a positive charge, the charge-field system picks up kinetic energy. At the same time, the charge-field system loses an equal amount of potential energy. Why? Because in an isolated system without friction, mechanical energy must always be conserved. Ch 25.2 – Potential Difference in a Uniform E-Field If q0 is negative then ΔU is positive as it moves from A to B. U q0 V q0 Ed When a negative charge moves down field, the charge-field system gains potential energy. If a negative charge is released from rest in an electric field, it will accelerate against the field. Ch 25.2 – Potential Difference in a Uniform E-Field Consider a more general case. Assume the E-field is uniform, but the path, s, between A and B is not parallel to the field. V E d s B A Ch 25.2 – Potential Difference in a Uniform E-Field Consider a more general case. Assume the E-field is uniform, but the path, s, between A and B is not parallel to the field. B V E ds E ds E s B A A U q0 V q0 E s Ch 25.2 – Potential Difference in a Uniform E-Field V E s If s is perpendicular to E (path C-B), the electric potential does not change. Any surface oriented perpendicular to the electric field is thus called a surface of equipotential, or an equipotential surface. Quick Quiz 25.2 The labeled points are on a series of equipotential surfaces associated with an electric field. Rank (from greatest to least) the work done by the electric field on a positive charge that moves from A to B, from B to C, from C to D, and from D to E. EG 25.1 – E-field between to plates of charge A battery has a specified potential difference ΔV between its terminals and establishes that potential difference between conductors attached to the terminals. This is what batteries do. A 12-V battery is connected between two plates as shown. The separation distance is d = 0.30 cm, and we assume the E-field between the plates is uniform. Find the magnitude of the E-field between the plates. EG 25.1 – Proton in a Uniform E-field A proton is released from rest at A in a uniform E-field of magnitude 8.0 x 104 V/m. The proton displaces through 0.50 m to point B, in the same direction as the E-field. Find the speed of the proton after completing the 0.50 m displacement.