* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Download Math 095 – Formulas
Big O notation wikipedia , lookup
Abuse of notation wikipedia , lookup
Positional notation wikipedia , lookup
Location arithmetic wikipedia , lookup
Large numbers wikipedia , lookup
Hyperreal number wikipedia , lookup
Factorization wikipedia , lookup
Line (geometry) wikipedia , lookup
System of polynomial equations wikipedia , lookup
Division by zero wikipedia , lookup
Elementary algebra wikipedia , lookup
Mathematics of radio engineering wikipedia , lookup
Math 095 Reference Sheet Order of Operations: (Please Excuse My Dear Aunt Sally) Parentheses Exponents Multiplication Done at the same time - left to right Division Addition Done at the same time - left to right Subtraction Slope Formulas: π = π ππππ Q π= πππ π ππ’π πππππ‘π = (π₯1 , π¦1 ) πππ (π₯2 , π¦2 ) or π = πβππππ ππ π¦ (βπ¦) πβππππ ππ π₯ (βπ₯) } } π¦ βπ¦ or π = π₯2 βπ₯1 2 1 Horizontal Line: π¦ = ππ₯ + π π¦ β π¦1 = π(π₯ β π₯1 ) Vertical Line: What Can Slope and Intercepts Tell You About lines? One Line Two Lines Y - Intercept formula: Point β Slope formula: π¦=π π₯=π Slope: Positive Negative Zero Undefined Same Same Opposite Reciprocal Different y-Int: Any Any Any None Different Same Same or Different Same or Different Increasing Decreaseing Horizontal Vertical Parrallel Coinciding Perpendicular Intersecting Solving Linear Equations: 1. Deal with any parentheses in the problem. 2. Combine like terms on each side of the equal sign. 3. Move terms with the needed variable on one side of the equal sign everything else to the other side. 4. Isolate the needed variable. Interest: π΄=π+πΌ Simple πΌ = πππ‘ First, Outside, Inside, Last (π1 π₯ + π1 )(π2 π₯ + π2 ) = π1 π2 π₯ 2 + (π1 π2 + π2 π1 )π₯ + π1 π2 Factoring Special Forms π΄2 + 2π΄π΅ + π΅2 = (π΄ + π΅)2 π΄2 β 2π΄π΅ + π΅2 = (π΄ β π΅)2 π΄2 β π΅2 = (π΄ + π΅)(π΄ β π΅) 3 π΄ + π΅3 = (π΄ + π΅)(π΄2 β π΄π΅ + π΅2 ) π΄3 β π΅3 = (π΄ β π΅)(π΄2 + π΄π΅ + π΅2 ) P=Principle r = rate (decimal) A=Future Amount t = time n = # of times compounded per year Continuously Compound Compounded π ππ‘ π΄ = π (1 + ) π π΄ = ππ ππ‘ Step 3: Step 4: Step 5: PT P2 Use with ππ₯ 2 + ππ₯ + π The βACβ Method: Step 1: Step 2: Mixture Problems: A βVisualβ Way P1 Binomial Expansion: You may know it as a four letter word starting with βFβ Multiply βaβ and βcβ Find factors of your new number that will add to equal βbβ. Rewrite βbxβ using your two new numbers. Factor by grouping. Move your βcommonβ binomial out, and make your other two terms a new binomial Quadratic Equation: A1 A2 AT π₯= Discriminant: π¨π π·π + π¨π π·π = π¨π» π·π» Variation: βkβ the constant of variation Varies with the Square Directly π¦ =πβπ₯ π¦ = π β π₯2 Inversely Page 1 of 2 π¦= π π₯ π¦= π π₯2 + 0 2 real solutions 2 complex solutions 1 real solution βπ ± βπ 2 β 4ππ 2π The Vertex of a Quadratic: π(π₯) = ππ₯ 2 + ππ₯ + π The vertex form: π 2 β 4ππ A is the amount and P is the percent. One of these will be missing Use with ππ₯ 2 + ππ₯ + π = 0 π(π₯) = π(π₯ β β)2 + π The vertex is the point (β, π) (β, π) = (β π π , π (β )) 2π 2π Distance, Rate, and Time π = ππ‘ Rev 2.0 4/17/2015 Math 095 Reference Sheet Square Rectangle Triangle Parallogram Trapazoid Circle Perimeter π = 4π π = 2π + 2π€ π = 2π + 2π π΄ = π 2 π΄ = ππ€ π =π+π+π+π΅ 1 π΄ = β(π + π΅) 2 πΆ = 2ππ Area Cube Rectangler Solid π = π+π+π 1 π΄ = πβ 2 Right Circular Cylinder Cone Right Pyramid Sphere Volume π = π 3 π = ππ€β π = ππ 2 β 1 π = ππ 2 β 3 1 π = ππ€β 3 4 π = ππ 2 3 Surface Area π = 6π 2 π = 2ππ€ + 2πβ + 2βπ€ π = 2ππβ + 2ππ 2 π = ππβπ 2 + β2 + ππ 2 π€ 2 π 2 π = ππ€ + πβ( ) + β2 + π€ β( ) + β2 2 2 π = 4ππ 2 π΄ = πβ Pythagorean Theorem: Between Two Points (π₯1 , π¦1 ) and (π₯2 , π¦2 ) The hypotenuse βcβ is the longest side and it is opposite the right angle! Distance π = β(π₯2 β π₯1 )2 + (π¦2 β π¦1 )2 π = ββ1 Complex Numbers: Midpoint Formula π₯2 + π₯1 π¦2 + π¦1 ( , ) 2 2 π2 + π 2 = π 2 π΄ = ππ 2 Complex Numbers Have a Real Part and an Imaginary Part Real π + Imaginary ππ Complex numbers have complex conjugates Circles: Center = (π, π) Radius = π Absolute Value: The distance from zero !!! Just think it makes things positive !!! |π₯ β π| = π (π₯ β π) = π β(π₯ β π) = π OR π₯βπ =π βπ₯ + π = π π₯ =π+π π₯ =πβπ 2 (π₯ β β) + (π¦ β π) = π Interval Set Builder π₯<π (ββ, π) {π₯| π₯ < π } π₯β₯π [π, β) {π₯| π₯ β₯ π } π<π₯<π (π, π) {π₯| π < π₯ < π } π<π₯β€π (π, π] {π₯| π < π₯ β€ π } πβ€π₯<π [π, π) {π₯| π β€ π₯ < π } πβ€π₯β€π [π, π] {π₯| π β€ π₯ β€ π } Page 2 of 2 2 π + ππ π β ππ When you multiply remember to treat π like π Inequalities: Remember to change the direction of the inequality when multiplying or dividing by a negative. Solution Center: βHow to answer the questionβ A number that makes the equation true Solve for βxβ An ordered pair that makes the equation true Find a point The point(s) where a graph crosses the X Axis X -Intercept The point(s) where a graph crosses the Y Axis Y-Intercept Notation 2 πβ₯π β1 β π β€ β1 β π βπ β€ βπ until you get ππ which is β π. π= π π5 = π 2 π = β1 π 6 = β1 3 π = βπ π 7 = βπ 4 π = 1 π8 = 1 π₯= (π₯, π¦) ( ,0) (0, ) Graph Meter Conversions Gram kilo hecto deca UNIT deci 1000 100 10 1 0.1 1 ππ = 5280 ππ‘ 1 ππ = 16 ππ§ 1 πππ = 4 ππ‘ = 16 π 9 πΉ = πΆ + 32 5 Rev 2.0 Liter centi 0.01 milli 0.001 1 ππ = 1.61 ππ 1 ππ = 0.45 ππ 1 πππ = 3.79 πΏ 1 π πππ‘ = 0.09 π2 4/17/2015