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PHYSICS 2.6
WORKSHEET ONE
1
Name:
STATIC ELECTRICITY BASICS AND FIELDS
Objects can gain a static charge by the effect of friction. Electrons can be removed from one
material and
to another by the work done through movement and the
application of
forces. If a plastic rod is rubbed with woollen material, a
transfer of
can result in the rod having an excess of electrons and the
wool a
of electrons. When the rubbed area of wool is held near the
charged rod there is a weak
force between them showing that
opposite charges attract. If two plastic rods are rubbed in the same way and one of the rods is
on a thread, the second rod will be seen to
the
first one when it is brought near, showing that like charges repel.
(shortage, suspended, transferred, frictional, charge, repel, attractive)
2.
The unit of electric charge is the
3.
The charge on one electron is equal to
4.
This means that there are
5.
An electric charge produces an electric field in the space around it. Draw the shape of the
electric fields produced by the following charges. (Use field lines and remember to include
arrows which show the direction that a positive test particle would move in.)
6.
(a) Draw the electric field existing between two oppositely charged parallel plates as shown
below.
C
electrons in one coulomb of charge.
(b) Calculate the strength of this field if the plates are 0.05 m apart and the voltage between
them is 200V. (Use V = E x d )
7.
How much work must be done to transfer a charge of +0.33 C from the negative to the positive
plate of the capacitor described in Q6. ( Voltage between the plates = 200V) (Use W = V x q )
8.
If Electric Potential is the same as Voltage and is given by the equation
V = W
q
, what is an
alternative unit for Voltage (apart from Volts)
9.
Calculate the Voltage that exists between two points if 5 Joules of energy are required to
transfer 0.2 Coulombs of charge between them.
10.
Calculate the electric potential energy possessed by a 0.5 C charge that has an electric potential
of 20 V.
11.
The parallel plate capacitor shown in the diagram has
a voltage of 10V applied to it from the battery. The
Distance between the plates is 0.005 m.
(a) Calculate the Electric field strength between the plates.
(b) The plate separation was doubled to 0.010 m. What effect
would this have on the Electric Field strength?
(c) If 2 Joules of electrical energy was required to transfer an amount of charge from one plate
to the other in this capacitor, what was the quantity of charge transferred?
(d) If the Voltage between the plates was increased from 10V to 20V and the separation of the
plates remained unchanged, what would be the effect on the Electric field strength.