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Transcript
Balancing reaction equations,
oxidation state, and
reduction-oxidation reactions
Summary of Types of Reactions
and Equations
***
Net Ionic Equations
If a solution of lead nitrate is added to a solution of
sodium chloride, lead chloride precipitates:
Pb(NO3)2(aq) + 2 NaCl(aq)  PbCl2(s) + 2 NaNO3(aq)
(This is a conventional equation.)
To better describe the reaction, the formulas of the
dissolved substances are replaced with their solution
inventories:
Pb2+(aq) + 2 NO3-(aq) + 2 Na+(aq) + 2 Cl-(aq) 
PbCl2(s) + 2 Na+(aq) + 2 NO3-(aq)
(This is an ionic equation.)
We can then eliminate the “spectators”.
Net Ionic Equations
The result is a net ionic equation, which tells exactly
what chemical change took place, and nothing else:
Pb2+(aq) + 2 Cl-(aq)  PbCl2(s)
Steps in writing a net ionic equation:
• Write the conventional equation, including designations of state
[(g), (l), (s), (aq)]. Balance the equation.
• Write the ionic equation by replacing each dissolved substance
(aq) with its solution inventory species. Never change states in
this step. Be sure the equation is balanced for both atoms and
charge.
• Write the net ionic equation by removing the spectators.
Reduce coefficients to lowest terms. Be sure the equation is
balanced for both atoms and charge.
Electron-transfer Reactions
Example: H2 combining with O2 to form water:
2 H2 + O2  2H2O
An electron is transferred from H to O: the H2 is
oxidized and the O2 is reduced.
We use the oxidation number (oxidation state) to keep
track of electron shifts in chemical reactions. It is
defined as “the charge which an atom appears to
have when the net electric charge on a chemical
species is apportioned according to certain rules”.
Important because: the binding of atoms results from
the transfer or sharing of electrons.
Common Oxidation States of Elements
Determining Oxidation Number of
Elements & Molecules
1. In uncombined or free elements (not ionized), each
atom has an oxidation number of 0. E.g., all of the
atoms in these molecules: H2, Na, S8, O2, P4.
2. In simple ions (i.e., charged species which contain
only one atom), the oxidation number is equal to the
charge on the ion. E.g., Na and K only form +1 ions;
thus, their oxidation numbers are +1 in all
compounds.
3. The oxidation number of oxygen is generally –2.
Exceptions: case #1, and oxygen atoms directly
bonded to other oxygen atoms (peroxides) and to
fluorine.
Determining Oxidation Number of
Elements & Molecules
4. The oxidation number of hydrogen is generally +1.
Exceptions: case #1, and hydrogen atoms combined
with elements such as Na or Ca (hydrides).
5. Oxidation numbers must be consistent with
conservation of charge. E.g., The sum of charge
must be 0 for neutral molecules. For H2O:
H: oxid. number is +1
O : oxid. number is –2
Net charge = 2(+1) + 1(-2) = 0
Determining Oxidation Number of
Elements & Molecules
6. Fractional oxidation numbers are possible. E.g., in
Na2S4O6 (sodium tetrathionate), S has an oxidation
number of +10/4:
O: 6(-2) = -12
Na: 2(+1) = 2
Residual = -10, which must be balance by S:
S: 4(+10/4) = +10
7. The oxidation number is designated by:
•
Arabic number below the atom, or
•
Roman numeral or arabic number after the
atom (in parentheses)
Determining Oxidation Number of
Elements & Molecules
Oxidation states for important N, S and C compounds:
Reduction-Oxidation Reactions
Oxidation is a chemical process in which an atom
shows an increase in oxidation number
Reduction is a chemical process in which an atom
shows an decrease in oxidation number
Oxidant
Reductant
Example: 2 H2 + O2  2H2O
0
0
1 -2
•
The hydrogen changes oxidation number from 0 to +1(is oxidized)
•
The oxygen changes oxidation number from 0 to –2 (is reduced)
Reduction-Oxidation Reactions
Oxidant
Reduction
(Oxidizing agent)
Reduced product
(gain of e-)
eOxidation
(loss of e-)
Reductant
Oxidized product
(Reducing agent)
Oxidation of zinc: Zn (s) + 2 H+  Zn2+ + H2 (g)
H2 (g)
2 H+
+1
0
e-
Zn (s)
0
Zn2+
+2
Reduction-Oxidation Reactions
Note: Strengths not necessarily related to
# of electrons transferred
Reduction-Oxidation Reactions
Procedure for balancing redox reactions in aqueous solutions:
Reduction-Oxidation Reactions
Reduction-Oxidation Reactions
Q: How do
we know
that this
happens?
A: Gibbs free
energy
calculation