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Министерство здравоохранения Республики Беларусь УЧРЕЖДЕНИЕ ОБРАЗОВАНИЯ «ГРОДНЕНСКИЙ ГОСУДАРСТВЕННЫЙ МЕДИЦИНСКИЙ УНИВЕРСИТЕТ» Кафедра биологической химии Н.Э. ПЕТУШОК М.Н. КУРБАТ А.А. МАСЛОВСКАЯ БИОЛОГИЧЕСКАЯ ХИМИЯ Практикум для студентов факультета иностранных учащихся (английский язык обучения) 3-е издание Под общей редакцией профессора В.В. Лелевича N.E. PETUSHOK M.N. KURBAT A.A. MASLOVSKAYA BIOCHEMISTRY Workbook for the medical faculty for internatiomal students (in English) Edited by professor V.V. Lelevich Гродно ГрГМУ 2015 1 УДК 577.1(07)=11 ББК 28.072я73 П29 Рекомендовано Центральным научно-методическим советом УО «ГрГМУ» (протокол № 7 от 30 июня 2015 г.). Aвторы: доц. каф. биологической химии, канд. биол. наук Н.Э. Петушок; доц. каф. биологической химии, канд. мед. наук М.Н. Курбат; доц. каф. биологической химии, канд. биол. наук А.А. Масловская. Рецензент: зав. каф. нормальной физиологии, доц., канд. мед. наук О.А. Балбатун. П29 Петушок, Н.Э. Биологическая химия : практикум для студентов факультета иностранных учащихся [на англ. яз.]. – 3-е изд. = Biochemistry : workbook for the faculty of foreign students (in English) / Н.Э. Петушок, М.Н. Курбат, А.А. Масловская; под общ. ред. проф. В.В. Лелевича. – Гродно : ГрГМУ, 2015. – 80 с. ISBN 978-985-558-560-3. This workbook contains a list of laboratory works which must be performed in accordance with the curriculum on Biochemistry as well as a list of normal concentrations of some laboratory tested substrates and enzymes. УДК 577.1(07)=11 ББК 28.072я73 © Петушок Н.Э., Курбат М.Н., Масловская А.А., 2015 © УО «ГрГМУ», 2015 ISBN 978-985-558-560-3 2 CONTENT Class № 1………………………………………………………………..4 Class № 2………………………………………………………………..6 Class № 3………………………………………………………………12 Class № 4………………………………………………………………15 Class № 5………………………………………………………………17 Class № 6………………………………………………………………22 Class № 7………………………………………………………………25 Class № 9………………………………………………………………27 Class № 10……………………………………………………………..29 Class № 11……………………………………………………………..31 Class № 12……………………………………………………………..33 Class № 13……………………………………………………………..35 Class № 15……………………………………………………………..36 Class № 16……………………………………………………………..39 Class № 17………………………………………………………...…...41 Class № 18……………………………………………………………..43 Class № 19……………………………………………………………..45 Class № 20……………………………………………………………..48 Class № 21……………………………………………………………..50 Class № 22……………………………………………………………..52 Class № 24……………………………………………………………..53 Class № 25……………………………………………………………..55 Class № 26……………………………………………………………..57 Class № 27……………………………………………………………..59 Class № 29……………………………………………………………..60 Class № 30……………………………………………………………..63 Class № 31……………………………………………………………..65 Class № 32……………………………………………………………..66 Class № 33……………………………………………………………..69 Class № 34……………………………………………………………..73 Class № 35……………………………………………………………..77 Normal concentrations of some laboratory tested substrates and enzymes…………………………..………………………………..79 3 Date CLASS № 1 WORK № 1. COLORIMETRY. WORK WITH PHOTOELECTROCOLORIMETER Measurement of light absorption by a photoelectrocolorimeter is used to detect the concentration of substances in solutions. This method is based on Lambert-Beer law, which postulates that the absorbance of solution is directly proportional to the concentration of the absorbing solute and depends on the thickness of the absorbing layer (path length, d). In colorimetry monochromatic light (of a single wavelength, ) is used. LAMP MONOCHROMATOR CUVETTE PHOTOELEMENT SCALE FIGURE 1.The principal components of photoelectrocolorimeter. A light source emits light along a broad spectrum, then the monochromator selects and transmits light of a particular wavelength. The monochromatic light passes through the sample in a cuvette of path length d and is absorbed by the sample in proportion to the concentration of the absorbing species. The transmitted light is measured by a detector and demonstrated on the scale. Calculation of substances concentrations: 1) according to the formula (the standard solution with known concentration must be used); 4 where Сsample – concentration of the sample; Еsample – extinction (absorbance) of the sample; Сstandard -concentration of the standard solution; Еstandard - extinction (absorbance) of the standard solution. 2) according to calibration graph (graph of dependence of extinction on concentration). 5 Date CLASS № 2 WORK № 1. COLOUR REACTIONS OF AMINO ACIDS AND PROTEINS Colour reactions of amino acids and proteins help to detect the presence of protein in biological fluids or to identify their amino acid composition. These reactions are used for qualitative and quantitative determination of proteins and amino acids. 1.Biuret reaction PRINCIPLE OF THE METHOD. The biuret method depends on the presence of peptide bonds in proteins. When a solution of proteins is treated with cupper ions in a moderately alkaline medium (NaOH/CuSO4), a blue-violet colored Cu2+-peptide complex is formed. Biuret reaction requires presence of at least two peptide bonds in a molecule. The biuret reaction can be used for both qualitative and quantitative analysis of protein. STEPS OF WORK: 1) take 1 test tube and place it in a test tube rack. 2) add to the test tube the solutions: COMPONENTS Amount of each solution Protein solution NaOH, 10% CuSO4, 1% 5 drops 5 drops 2 drops RESULT: 6 CONCLUSION: 2.Ninhydrin reaction PRINCIPLE OF THE METHOD: amino acids, peptides and proteins boiled in the presence of ninhydrin solution firstly undergo deamination, than ammonia interact with ninhydrin with formation of blue-violet dye (Ruhemann’s pyrple). Reaction is specific for alphaamino acids. CO2 ALDEHYDE AMINO ACID+ NINHYDRIN RUHEMANN’S PURPLE (blue-violet dye) STEPS OF WORK: 1) take 1 test tube and place it in a test tube rack. 2) add to the test tube the solutions: COMPONENTS Amount of each solution Protein solution Ninhydrin 0,5% 5 drops 5 drops Boil till dye yield RESULT: CONCLUSION: 7 3. Xanthoproteic reaction (for aromatic amino acids) tyrosine dinitrotyrosine PRINCIPLE OF THE METHOD. Aromatic amino acids (phenylalanine, tyrosine, tryptophan) after heating with nitric acid undergo nitration. This process leads to formation of dark yellow dye. STEPS OF WORK: 1) take 1 test tube and place it in a test tube rack. 2) add to the test tube the solutions: COMPONENTS Amount of each solution Protein solution HNO3concentrated Boil till dye yields RESULT: CONCLUSION: 8 5 drops 5 drops 4. Fohl reaction on cysteine PRINCIPLE OF THE METHOD. Reaction is specific for cysteine. End product of the reaction – lead sulfide – is black coloured sediment. Cys Ser Black colour STEPS OF WORK: 1) take 1 test tube and place it in a test tube rack. 2) add to the test tube the solutions: COMPONENTS Amount of each solution Protein solution NaOH, 30% (СН3СОО)2Рb, 5% 5 drops 5 drops 1 drop Boil till dye yields RESULT: CONCLUSION: 9 WORK № 2. QUANTITATIVE MEASUREMENT OF TOTAL SERUM PROTEIN PRINCIPLE OF THE METHOD. PROTEIN + NaOH/CuSO4 = violet colour, the intensity of the color produced is proportional to the concentration of protein present in the reaction system and detected photometrically. STEPS OF WORK: 1) take 2 test tubes, label them and place in a test tube rack. 2) add to the each test tube the solutions: COMPONENTS CONTROL SAMPLE Amount of each solution Gornal’s reagent 4,0 ml 4,0 ml serum 0,1 ml NaCl 0,9% 0,1 ml Stir and allow standing for 20 min. Read the extinction for sample versus the control at 540 nm Cuvette 1 cm RESULT: Esample= Find out the protein concentration in the sample from the calibration graph: Csample = g/L DIAGNOSTIC IMPORTANCE Normal level of total protein (total protein = albumins + globulins) in adults serum - 65-85 g/L. 10 An increased content of blood plasma total protein (hyperproteinemia) can be caused by: collagenoses, myeloma disease, hyperimmunoglobulinemia, hypohydratation (vomiting, diarrhea). A decreased concentration of blood plasma total protein (hypoproteinemia) is observed in alimentary distrophy, pregnancy, chronic nephritis, cirrhosis, hepatitis, gastroenteropathies, carcinoma. CONCLUSION: 11 Date CLASS № 3 WORK № 1. DENATURATION OF PROTEIN BY NITRIC ACID Work demonstrates the influence of chemical factors on stability of protein in solutions. PRINCIPLE OF THE METHOD: protein precipitated as a sequence of denaturation and formation of complex with acid. STEPS OF WORK: 1) take 1 test tube and place it in a test tube rack. 2) add to the test tube the solutions: COMPONENTS Amount of each solution HNO3 concentrated 10 drops Protein solution 10 drops Take the test tube with concentrated HNO3 under the angle 45о and carefully, slowly add protein solution along side of a test tube. RESULT: CONCLUSION: 12 WORK № 2. SEPARATION OF ALBUMINS AND GLOBULINS OF AN EGG WHITE BY SALTING-OUT Salting-out is used for reversible precipitation of proteins. This technique is one of steps in protein purification procedure. PRINCIPLE OF THE METHOD. Due to the fact that protein contains multiple charged groups, its solubility depends on the concentrations of dissolved salts. The additional ions shield the protein's multiple ionic charges, thereby weakening the attractive forces between individual protein molecules (such forces can lead to aggregation and precipitation). So, the solubility of protein decreases. This "salting out" effect is primarily a result of the competition between the added salt ions and the protein molecules for molecules of water. STEPS OF WORK: 1) take 2 test tubes, label them and place in a test tube rack. 2) add to the each test tube the solutions: COMPONENTS SAMPLE 1 SAMPLE 2 Amount of each component Protein solution NaCl (crystalline) (NH4)2SO4-saturated solution (100%) 1,0 ml till full saturation (100%) - 1,0 ml 1,0 ml (till 50% saturation) Incubation 10 min Without incubation Filtration Filtration Boil Add salt to saturation RESULT: (NH4)2 SO4 (powder) RESULT: 13 CONCLUSION: 14 Date CLASS № 4 WORK № 1. ACIDIC HYDROLYSIS OF PROTEINS Hydrolysis of protein is a process of biopolymer’s degradation with cleavage of peptide bonds through the assistance of water molecules under the action of acids, alkalis or proteases. In laboratory conditions hydrolysis of protein is used for determination of primary structure and amino acid composition. Protein hydrolyzates are used in clinical practice for parenteral nutrition. Hydrolysis of proteins constantly occurs in gastrointestinal tract and in cells of humans and animals under the action of proteolytic enzymes PRINCIPLE OF THE METHOD. Biopolymer in reaction with water degrades to monomers. Hydrolysis is catalyzed by protons, hydroxyl ions and enzymes on mechanisms of nucleophilic substitution. Total acidic hydrolysis of proteins proceeds in 12-96 hours at 100 °C. Sequence of events in hydrolysis of protein is presented in the scheme. protein High-wheight polypeptides PROTEASES pepsin trypsin and others tr low-wheight polypeptides and dipeptides Amino acids 15 STEPS OF WORK: 1. To the flask add 20 ml of eggs white solution. 2. Add 5 ml of concentrated НCl. 3. Put 0,5 – 1 ml (5 drops) of the mixture to the test tube № 1. 4. Close the flask by rubber stopper with long glass tube (reverse condenser). 5. Boil the mixture for 45 min. 6. After cooling take 0,5 – 1 ml (5 drops) of hydrolyzate to the test tube № 2. 7. Adjust the pH of hydrolyzate to neutral by addition of 20 % NaOH (to blue colour of lakmus paper). 8. Perform a biuret reaction in the test tubes № 1 and № 2. . RESULT: CONCLUSION: 16 Date CLASS № 5 WORK № 1. EFFECT OF TEMPERATURE ON AMYLASE ACTIVITY This work describes one of the properties of enzymes – dependence of the rate of an enzyme-catalyzed reaction on temperature (termolability). PRINCIPLE OF THE METHOD: amylase amylase Starch --------- dextrins ------------ maltose. Reaction of starch with iodine gives dark blue dye. Reaction of dextrins with iodine gives violet, red dye. If in the sample only maltose presents, after addition of iodine yellow colour of solution (colour of iodine) is observed. STEPS OF WORK: 1) take 3 test tubes, label them and place in a test tube rack, 2) dissolve saliva in separate test tubes in proportion 1:10 (1 ml of saliva + 9 ml Н2О), 3) add to the each test tube the solutions: COMPONENTS SAMPLE 1 SAMPLE 2 SAMPLE 3 Amount of each solution Starch, 1 % Amylase of saliva (1:10) Allow test tubes to standing for 10 min at 0,5 ml 0,5 ml 0,5 ml 0,5 ml 0,5 ml 0,5 ml Room Thermostat Boiling water temperature (40оС) bath (100оС) (20оС) After 10 min add 1-2 drops of KJ (1%)to all test tubes 17 RESULT: CONCLUSION: WORK № 2. EFFECT OF ACTIVATOR AND INHIBITOR ON AMYLASE ACTIVITY Activators and inhibitors regulate the enzymatic activity. These data are used for studying the effects of xenobiotics and normal cell metabolites on enzymatic processes. STEPS OF WORK: 1) take 3 test tubes, label them and place in a test tube rack, 2) add to the each test tube the solutions: COMPONENTS CONTROL SAMPLE 1 SAMPLE 2 Amount of each solution Н20 NaCl, 1% CuSO4, 1% Amylase of saliva (1:10) Starch, 1% 10 drops 20 drops 5 drops 18 8 drops 2 drops 20 drops 5 drops 8 drops 2 drops 20 drops 5 drops Allow test tubes to stand for 5 min (10, 15 min) at a room temperature. Add 2-3 drops of KJ (1%) to all test tubes. RESULT: CONCLUSION: WORK № 3. DETERMINATION OF AMYLASE IN BLOOD SERUM (BY CARAWEY’S METHOD) Determination of amylase activity in the urine and blood serum is used for the diagnosis of diseases of pancreatic gland. PRINCIPLE OF THE METHOD. Method is based on the colorimetric determination of starch substrate concentration before and after its enzymatic hydrolysis. 0,01 n iodine solution is used as working reagent. STEPS OF WORK: 1) take 2 test tubes, label them and place in a test tube rack, 2) add to the each test tube the solutions: 19 COMPONENTS SAMPLE CONTROL Amount of each solution Starch substrate 0,5 ml 0,5 ml Heat 5 min in water thermostat at 37°С Blood serum 10 μl ° Heat 5 min in water thermostat at 37 С Iodine solution (0,01 n) 0,5 ml 0,5 ml H2O dist. 4 ml 4 ml Blood serum 10 μl Mix well and read the extinctions for sample and control versus the water at 630-690 nm, cuvette 1 cm CALCULATION. Mean of α-amylase activity in grams of degraded starch per 1 liter of serum for 1 hour of incubation at 370С is calculated according to the formula: Еc – Еs Х = -------------------- х 240 Еc Еc - extinction of the control; Еs – extinction of the sample. RESULT: 20 DIAGNOSTIC IMPORTANCE Normal activity of α-amylase in blood serum is 16 – 30 g/h•L, in urine it is 28 – 160 g/h•L. Increasing of enzyme activity is observed in parotitis, pancreatitis, malignancy of the pancreas, cirrhosis, diabetic ketoacidosis. Decreasing of α-amylase activity is observed in atrophia of the pancreas, kahexia. CONCLUSION: 21 Date CLASS № 6 WORK № 1. KINETICS OF LIPASE-CATALYZED HYDROLYSIS OF TRIACYLGLYCEROLS Lipolytic enzymes of pancreatic gland hydrolyze dietary lipids in the small intestine. Bile acids emulsify lipids, activate lipase and participate in absorption of products of lipid digestion. Studying the kinetics of lipase action, you can watch the dinamics of enzyme activity and factors which affect this process (temperature, concentrations of substrate and products of reaction, presence of bile). PRINCIPLE OF THE METHOD. Lipase catalyzes the reaction: lipase Triacylglycerols-------------glycerol + fatty acids +НОН lipase The rate of lipase-catalyzed reaction can be estimated by the quantity of fatty acids, formed within a certain time interval. Quantity of fatty acids is determined by alkaline titration with fenolpftalein as indicator and is expressed in ml of 0,01 n NaOH solution. 22 STEPS OF WORK: 1) take 2 test tubes, label them and place in a test tube rack, 2) add to the each test tube the solutions: Components SAMPLE 1 SAMPLE 2 (without bile) (with bile) Milk 10,0 ml 10,0 ml Н2О 1,0 ml Bile 1,0 ml Lipase 1,0 ml 1,0 ml (homogenate of pancreatic gland) 1) Stir and take 2 ml from each test tube to 2 small flasks + 1-2 drops of fenolftalein.Perform titration by 0,01 n NaOH to pink colour. 2) Put the mixture into termostat at 38оС. 3) Take 2 ml of mixture from each test tube after 15, 30 and 45 min of incubation and perform titration. During the first titration the acids which presents in the milk before the lipase action are neutralized. The results of the first titration (before the lipase action) are subtracted from the results of the following titrations. RESULT: Write down your result into the table: Time of incubation, min 0 Volume of 0,01 n NaOH solution, used for titration - bile + bile Х 15 Y–X=Y 30 Z–X=Z 45 E–X=E 23 Plot the graph using these data: Kinetics of lipase-catalyzed hydrolysis: VmlNaOH 0,01n Time (min) 15 30 45 CONCLUSION: 24 Date CLASS № 7 STUDENTS’ INDIVIDUAL WORK «PROTEINS, ENZYMES» 25 26 Date: _______________ CLASS № 9 LABORATORY WORK № 1. HYDROLYSIS OF NUCLEOPROTEINS Acidic hydrolysis is used for study of nucleoproteins chemical composition. Scheme of nucleoproteins hydrolysis Nucleoproteins (yeast) H2SO4 (10%) 100oC Protein (Protamines or histones) Nucleic acidc (DNA, RNA) High-molecular polypeptides Polynucleotides Tri-, Dipeptides Amino acids Mononucleotides Nucleosides Nitrogen base (Purines or Pyrimidines) H3PO4 Pentose (Deoxyribose or ribose) Color reactions for components of nucleoproteins: Components Reaction Observation Protein Biuret reaction Blue-violet color Purine Silver test Light brown precipitation Pentose Trommer test Red color and precipitation (Cu2O) Phosphoric acid Molybdenum test Lemon-yellow color 27 Step of test: take 4 test tubes. Biuret reaction Hydrolyzate of nucleoproteins NaOH 10% CuSO4 1% 5 drops 10 drops 1-2 drops Result: Silver test Hydrolyzate of nucleoproteins (NH4)OH (conc). AgNO3 1% 10 drops 1 drop 5 drops Leave for 5 min Result: Trommer test Hydrolyzate of nucleoproteins NaOH 30 % CuSO4 7 % 5 drops 10 drops 3 drops Boil 10 sec Result: Molybdenum test Hydrolyzate of nucleoproteins Molybdenum reagent Result: Conclusion: 28 5 drops 20 drops Boil 1-2 min Date: _______________ CLASS № 10 LABORATORY WORK № 1. DETERMINATION OF URIC ACID CONCENTRATION IN THE BLOOD SERUM. Uric acid is an end-product of purine catabolism in human. PRINCIPLE OF THE METHOD. Uric acid is enzymatically (enzyme – uricase) oxidized by oxygen to produce hydrogen peroxide, allantoin, and carbon dioxide. The H2O2 reacts with chromogen (redused - colorless) in the presence of peroxidase to form a chromogen (oxidised) dye. The intensity of color (pink) formed is proportional to the uric acid concentration and can be measured photometrically. Step of test: take 2 test tubes: experimental and control. Components Experimental Standard sample sample Blood serum (urine) Standard of uric acid (375 µmol/L) Working solution of enzymes and chromogen 0,025 ml - 0,025 ml 1,0 ml 1,0 ml Stir and incubate 10 min at 37 ºC On completion of incubation extinction of experimental and standard samples are measured at PEC ( = 500-520 nm) in 5 mm thick cuvettes versus water RESULT: Е st = ; Е ex = ; Сst = 375 µmol/L Calculation is done by the formula: Сex = Cst · Еex Еst 29 = µmol/L. CLINICAL AND DIAGNOSTIC VALUE Normal values of uric acid excretion in urine are 1,5-4,5 mmol/day. In the blood – 140-340 µmol/L (female), 200-415 µmol/L (male). Uric acid excretion depends on the purines content in food and intensity of nucleoproteins metabolism. Hypouricuria (decrease of uric excretion with urine) is noted in gout, nephritis, renal insufficiency; hyperuricuria (increase of uric excretion with urine) – in leukemia, accelerated breakdown of nucleoproteins. In gout uric acid salts (urates) precipitate in cartilages, muscles and joints. The content of uric acid in the blood can be increased while in the urine – decreased. CONCLUSION: 30 Date_______________ CLASS № 11 STUDENTS’ INDIVIDUAL WORK “BIOSYNTHESIS OF PROTEINS” Tasks for individual work: 1. Write structure and reaction of synthesis of valil-tRNA. 2. Make up the scheme of biosynthesis of dipeptide methionylglutamate (initiation and elongation stages). 3. Explain the role of genetic engineering in the production of protein. Give the scheme of process. 4. Give the scheme of polymerase chain reaction (PCR). 31 32 Date: _______________ CLASS № 12 LABORATORY WORK № 1. QUANTITATIVE DETERMINATION OF HIGH-ENERGY COMPOUNDS IN THE MUSCULAR TISSUE ATP – the main macroergic compound – is synthesized by oxidative and substrate-level phosphorylation. In muscle also present creatinephosphate – macroerg, formed with the participation of ATP. Both substances give energy for muscles construction. PRINCIPLE OF THE METHOD. Reach in energy phosphate group of ATP and creatinephoshate are hydrolysed in acidic medium and give a colour product with ammonium molybdate in presence of ascorbic acid. Steps of the test: Take 2 test tubes Components Protein-free muscle filtrate HCl, 1M NaOH, 1M H2O Ammonium molybdate, 1% Ascorbic acid Control Experimental sample sample 0,5 ml 0,5 ml 1,0 ml 1,0 ml Boil 10 min 1,0 ml 1,0 ml 2,5 ml 2,5 ml 0,5 ml 0,5 ml 0,5 ml 0,5 ml Stir and incubate 10 min at room temperature On completion of incubation extinction of experimental sample is measured at PEC ( = 640 nm) in 10 mm thick cuvette versus control 33 RESULT: Ех = Calculation is performed according to calibration graph. Put the received result of phosphorus concentration in a sample (A) into the formula: C = А 3,3 40 = mg ATP/g tissue Find concentration of ATP in 1g of tissue: C = m (ATP in g)/MrATP = /507,2= CONCLUSION: Concentration of ATP 5µmol per 1 g of muscle (at rest condition) 34 Date________________ CLASS № 13 STUDENTS’ INDIVIDUAL WORK “ENERGY METABOLISM. OXIDATIVE PROCESSES IN THE CELL” Task for individual work: 1. Make up a common scheme of energy metabolism. 2. Illustrate: 2.1. Links TCA cycle with ETC. 2.2. Vitamine-dependent enzymes of TCA cycle. 2.3. Anabolic function of TCA cycle. 2.4. Regulatory enzymes of TCA cycle. 35 Date: ______________ CLASS № 15 LABORATORY WORK № 1. DETECTION OF THE SUCCINATE DEHYDROGENASE ACTIVITY Succinate dehydrogenase is one of the enzymes of the TCA cycle, firmly bound to the inner mitochondrial membrane. The enzyme catalyzes oxidation (removal of hydrogen) from succinate to form fumarate. Coenzyme is FAD joined with the enzyme by covalent bond. FAD is intermediary acceptor of hydrogen. The reaction catalyzed by succinate dehydrogenase: СООН FAD FADН2 СН2 СН2 СООН СН Succinate dehydrogenase СООН Succinate СН СООН Fumarate PRINCIPLE OF THE METHOD. Substrate is succinate. Final acceptor of hydrogen is 2,6-dichlorophenolindophenol (dark-blue colour) which, due to reduction, is converted to its colourless (reduced) form. Conversion of dark-blue oxidized chromogen into its colourless form allows detecting the catalytic activity of the enzyme. Succinate FAD 2,6-DCPI-H2 (colorless) Fumarate FADH2 2,6-DCPI (blue) Source of the enzyme is homogenate of muscles. Malonate is competitive inhibitor of succinate dehydrogenase. 36 STEPS OF THE TEST: Take 4 test tubes Components Homogenate of muscles Н2О Malonate Succinate 2,6dichlorphenolindophenol 1 2 3 1,0 ml 1,0 ml 1,0 ml (Boil 2 min) 0,5 ml 0,5 ml 1,5 ml 1,0 ml 1,0 ml 2 drops 2 drops 2 drops 4 1,0 ml 0,5 ml 1,0 ml 2 drops Stir and incubate 15 min at 37 ºC Result (color) CONCLUSION: LABORATORY WORK № 2. DETECTION OF THE CYTOCHROME OXIDASE ACTIVITY The enzyme cytochrome oxidase is the last enzyme in the respiratory electron transport chain of mitochondria located in the mitochondrial membrane. It receives an electron from cytochrome c and transfers them to one oxygen molecule, converting molecular oxygen to molecule of water. PRINCIPLE OF THE METHOD Mixture of -naphthol and pphenylene diamine (reagent NADI) is oxidized by cytochrome oxidase and in the presence of oxygen forms product of blue colour. 37 α-naphthol n-phenylene diamine Cytochrome oxidase O Steps of the test. Muscle is divided into two parts. One part is placed on the filter paper, the other part is put into the test-tube with 1 ml of water and boiled for 1 min. After cooling, the boiled muscle tissue is taken from the test-tube by a glass stick and is put on the filter paper. Both portions of the muscle are applied by 2 drops of reagent NADI. Incubation is performed for 5-10 min at room temperature. RESULT: CONCLUSION: 38 Date: _______________ CLASS № 16 DETECTION OF ADRENALIN IN THE URINE (QUALITATIVE REACTION ON ADRENALIN) In the adrenal medulla, catecholamines are synthesized from amino acid tyrosine. In the liver and muscles, adrenaline and noradrenaline activate phosphorylase which degrades glycogen. In the adipose tissue, the hormones activate degradation of triacylglycerols. PRINCIPLE OF THE METHOD. The molecule of both adrenaline and noradrenaline contains pyrocatechin ring which forms product of emerald-green colour reacting with FeCl3. In subsequent adding NaOH the solution obtains cherry-red colour. STEPS OF WORK: COMPONENTS CONTROL TEST Н2О 10 drops - Solution of adrenaline - 10 drops FeCl3 1 drop Light-yellow colour 1 drop Emerald-green colour NaOH , 10 % 3 drops 3 drops Colour is not changed Cherry-red colour RESULT: CONCLUSION: 39 CLINICAL AND DIAGNOSTIC VALUE Normal concentration of adrenaline in the blood serum is not more than 6.28 nmol/L, the excretion in the urine is 27.3 – 81.9 nmol/day. Increased excretion of adrenaline is observed in pheochromocytoma, hypertension stroke, acute period of myocardial infarction, hepatitis and liver cirrhosis, physical exertion and emotional stress reaction. 40 Date: _______________ CLASS № 17 INDIVIDUAL STUDENTS’ WORK «HORMONES» Fill in the table: Characteristics of the major hormones Hormone Chemical structure Site of synthesis 41 Mechanism of action Targettissue Biological effect Hypoproduction of the hormone Name Signs 42 Hyperproduction of the hornmone Name Signs Date: ________________ CLASS № 18 QUANTITATIVE DETERMINATION OF THE VITAMIN C CONCENTRATION IN THE URINE Vitamin C (ascorbic acid) participates in the oxidative-reduction processes, synthesis of steroid hormones and catecholamines in adrenals, appears to be coenzyme of hydroxylases catalyzing conversion of proline into hydroxyproline, furthers absorption of iron from the intestine, activates pepsinogen. Vitamin C deficiency in the organism leads to the impairment of these processes. PRINCIPLE OF THE METHOD. Vitamin C is capable of reducing 2,6-dichlorophenolindophenol (2,6-DCPIP). This chromogen when oxidized is coloured (dark-blue colour in alkaline medium and red colour in acidic medium). When reduced, the chromogen becomes coloureless. Reaction mixture is titrated by 2,6dichlorophenolindophenol in the acidic medium until the light-red colour appeares. STEPS OF WORK: COMPONENTS Urine Н2О HCl 10% 2,6-DCPIP 0,001N TEST SAMPLE 10.0 ml 10.0 ml 20 drops Titrate until the light-red colour is appeared RESULT: CALCULATION: 43 0,088А1500 Х = ------------------- = mg/day, 10 where 0,088 – amount of vitamin C (mg) corresponds to 1ml 0,001N 2,6-DCPIP; А – result of titration, ml; 1500 – average daily diuresis, ml; 10 – the volume of the urine taken for titration, ml. CLINICAL AND DIAGNOSTIC VALUE Normal content of vitamin C in the blood serum is 34-114 μmol/L. Normal excretion in the urine is 20-30 mg/day. Determination of vitamin C in the urine allows assessing the content of vitamin C in the organism, for there is normally proportion between concentration of the vitamin in the blood serum and amount of the vitamin excreted in the urine. However in hypovitaminosis C, the content of ascorbic acid in the urine is not always decreased. Often it is normal despite the appreciable deficiency of the vitamin in tissues. In healthy people administration of 100 mg of vitamin C per os results in the increase of its concentration in the both blood serum and urine. In hypovitaminosis C, tissues being experienced need for the vitamin retain administered load of ascorbic acid and its concentration in the urine is not increased. Concentration of vitamin C in the urine is decreased in acute and chronic infectious diseases, anemia, steatorea, malabsorption, alcoholism. CONCLUSION: 44 Date: ________________ CLASS № 19 LABORATORY WORK № 1. MEASURMET OF GLUCOSE CONCENTRATION IN BLOOD SERUM BY ENZYMATIC (GLUCOSE OXIDASE) METHOD Determination of glucose in the blood is used for assessment of carbohydrates metabolism condition and for pathology diagnosis (hypoglycemia and hiperglycemia). Now enzymatic method using enzyme glucose oxidase is widespread. PRINCIPAL OF THE METHOD. Glucose oxidase is complex FAD-containing enzyme, that catalyses the oxidation of glucose to hydrogen peroxide (H2O2) and gluconolactone. The H2O2 reacts with chromogen (redused - colorless) in the presence of peroxidase to form a chromogen (oxidised) dye - pink. The intensity of color formed is proportional to the glucose concentration and can be measured photometrically. glucose oxidase Glucose H2O gluconolactone FAD gluconate FADH2 H2O O2 H2O2 Chromogen (oxidized, pink) Chromogen redused, colorless 45 The formed product is of a pink color. Staining intensity is proportional to glucose concentration and measured photometrically. Step of test: take 3 test tubes: experimental, standard and control. COMPONENTS Experimental Standard Control sample sample sample Blood serum 0,02 ml Standard of 0,02 ml glucose (5,55 mmol/L Water (dist) 0,02 ml Working 2,0 ml 2,0 ml 2,0 ml solution of enzymes Stir and incubate 20 min at 37ºC On completion of incubation extinction of experimental and standard samples are measured at PEC ( = 500 nm) in 5 mm thick cuvettes versus the control sample RESULT: Е st = ; Е ex = ; Сst = 5,55 mmol/L Calculation is performed according to the formula: Сex = Cst · Еex Еst = mmol/L. CLINICAL AND DIAGNOSTIC VALUE Normal values of glucose concentration in serum in adult is 3,336,4 mmol/L. Increase of glucose content in the blood (hyperglycemia) is observed in physiological condition (stress, carbohydrates intake) and pathology: diabetes mellitus, acute pancreatitis, myocardial infarction, hyperfunction of same endocrine glands (thyrotoxicosis, glucagonoma, Icenko-Cushing's syndrome, pheochromocytoma). 46 Decrease of blood glucose level (hypoglycemia) occurs in physiological condition (starvation, insufficiency of diet carbohydrates, hard physical work) and same diseases: insulinoma, Addison's disease, arsenic, phosphorus, benzole, chlorophorm poisoning, disturbances of carbohydrates absorption in GIT, glycogenoses and over dosage of insulin while treating diabetes mellitus. CONCLUSION: 47 Date: ________________ CLASS № 20 LABORATORY WORK № 1. GLUCOSE TOLERANCE TEST A glucose tolerance test (GTT) is a medical test in which glucose is given and blood samples taken afterward to determine how quickly it is cleared from the blood. The test is usually used to test for diabetes, insulin resistance, and sometimes reactive hypoglycemia and rarer disorders of carbohydrate metabolism. Procedure of test. Usually the GTT is performed in the morning. The patient is instructed to fast for 8-12 hours prior to the tests. Before the test begins, a sample of blood will be taken. After this, the person receives glucose at a dose 1 g/kg of body weight (or 1,5 g/kg of sucrose), dissolved in glass of water. Blood samples are taken up to four times at 30 min after consumption (30, 60, 90, 120 min) of the sugar to measure the blood glucose. Draw a graph – glycemic curve: Fasting plasma glucose (measured before the GTT begins) in healthy person should be between 3,3-6,4 mmol/L (110 mg/dL). The glucose concentration reaches its maximum for 60 min (Note! No more than 9,9 mmol/L – renal threshold of glucose) and returns to a start point for 120 min (often it becomes lower than initial). In case of disturbances of carbohydrates metabolism glycemic curves are distinguished from normal (hyper- and hipoglycemic curve). 48 STEPS OF TEST Using glucose oxidase method (see previous class) determine concentration of glucose in 3 samples: 1st – fasting leves (0 min), 2nd – after 60 min and 3d - after 120 min of sugar consumption. Draw the glycemic curve. RESULT: CONCLUSION: 49 Date: ________________ CLASS № 21 LABORATORY WORK № 1. MEASUREMENT OF PYRUVATE IN THE URINE Pyruvate is one of central intermediate products of carbohydrate metabolism and produced in all tissues in great amount. Metabolic pathways of pyruvate illustrate in the scheme: PRINCIPAL OF THE METHODS. Pyruvate interacting with 2,4dinitrophenylhydrasine in alkaline medium forms 2,4dinitrophenylhydrasone derivatives of yellow-orange color, the staining intensity of which is proportional to concentration of pyruvate. 2, 4 – DNP-hydrosone PA 2, 4 - DNPH 50 STEPS OF TEST: take 2 test tubes: experimental and control. COMPONENTS Urine Н2О КОН (25 %) 2,4-Dinitrophenylhydrasine (0,1%) Experimental Control sample sample 1,0 ml 1,0 ml 1,0 ml 1,0 ml Shake 1 min 0,5 ml 0,5 ml Shake and leave for 15 min at room temperature Determine extinction of experimental sample versus control sample using 5 mm cuvettes, = 470-480 nm RESULT: Е= . Calculation is performed according to calibration graph. The received result (in µg) should be multiplied by empiric coefficient 11,366. С = ……. x 11,366 = µmol/day. CLINICAL AND DIAGNOSTIC VALUE Normal value of pyruvate excretion in urine is 114-284 µmol/day (10-25 µg/day). In the blood – 56,8-113,6 µmol/L. In hypovitaminosis of B1 in the blood and other tissues, especially in the brain, a great amount of pyruvate is accumulated and its excretion with urine increases. The content of this acid in the blood increases in diabetes mellitus, cardiac insufficiency, hyperfunction of the hypophysis-adrenal system. CONCLUSION: 51 Date _________________ CLASS № 22 STUDENTS’ INDIVIDUAL WORK “METABOLISM OF CARBOHYDRATES” Tasks for individual work: 1. Compose metabolic scheme of carbohydrates metabolism. 2. Accentuate: 2.1. Diagnostic significant substrates (glucose, pyruvate, lactate, glycogen, galactose, fructose). 2.2. Clinical and diagnostic enzymes (glucose-6-phoshatase, fructose-1,6-diphosphatealdolase, lactatedehydrogenase (LDH), glycogen phosphorylase, glucose-6-phoshate dehydrogenase). 2.3. Regulatory enzymes of glycolysis, biosynthesis of glycogen, pentose phosphate pathway. Vitamin-dependent enzymes. 52 Date: _________________ CLASS № 24 LABORATORY WORK № 1. MEASUREMENT OF TRIACYLGLYCEROLS IN THE BLOOD SERUM PRINCIPLE OF THE METHOD. Triacylglycerols (TAG) are hydrolyzed by lipoproteinlipase to produce glycerol and free fatty acids. The glycerol participates in a series of coupled enzymatic reactions, in which glycerol kinase and glycerol phosphate oxidase are involved and H2O2 is generated. The H2O2 reacts with chromogen (redused – colorless) in the presence of peroxidase to form a chromogen dye (oxidised). The intensity of color (pink) formed is proportional to the TAG concentration and can be measured photometrically. Step of test: take 3 test tubes: experimental, standard and control COMPONENTS Experimental Standard Control sample sample sample Blood serum 0,02 ml Standard of 0,02 ml TAG (2,5 mmol/l) Water (dist) 0,02 ml Working 2,0 ml 2,0 ml 2,0 ml solution of enzymes and chromogen Stir and incubate 10 min at 37ºC On completion of incubation extinction of experimental and standard samples are measured at PEC ( = 500 nm) in 5 mm thick cuvettes versus the control sample RESULT: Е st = ; Е ex = ; Сst = 2,5 mmol/L 53 Calculation is performed according to the formula: Сex = Cst · Еex Еst = mmol/L. From the received result 0,11 mmol/L should be subtracted (concentration of free glycerol in the blood). CLINICAL AND DIAGNOSTIC VALUE. Normal values of TAG in the blood are 0,40-1,54 mmol/L (female), 0,45-1,82 mmol/L (male). Reasons of hypertriacylglycerolemia: - high-fat food intake, - obesity, starvation, diabetes mellitus, cirrhosis, glicogenosis type I, III and IV. Hypotriacylglycerolemia is observed in lack of synthesis of apoprotein B (apoB) in the liver. CONCLUSION: 54 Date: __________ CLASS № 25 LABORATORY WORK № 1. MEASUREMENT OF CHOLESTEROL CONCENTRATION IN BLOOD SERUM BY ENZYMATIC METHOD Principle of the method. Cholesterol esters are hydrolyzed to free cholesterol by cholesterol ester hydrolase. The free cholesterol produced is oxidized by cholesterol oxidase to cholest-4-en-3-one with the simultaneous production of hydrogen peroxide. The H2O2 reacts with chromogen (redused – colorless) in the presence of peroxidase to form an oxidised chromogen dye. The intensity of color (pink) formed is proportional to the cholesterol concentration and can be measured photometrically. Step of test: take 3 test tubes: experimental, standard and control. COMPONENTS Experimental Standard Control sample sample sample Blood serum 0,02 ml Standard of 0,02 ml cholesterol (5,17 mmol/L) Water (dist) 0,02 ml Working 2,0 ml 2,0 ml 2,0 ml solution of enzymes and chromogen Stir and incubate 10 min at 37ºC On completion of incubation extinction of experimental and standard samples are measured at PEC ( = 500 nm) in 5 mm thick cuvettes versus the control sample RESULT: Е st = ; Е ex = 55 ; Сst = 5,17 mmol/L Calculation is performed according to the formula: Сex = Cst · Еex Еst = mmol/L. CLINICAL AND DIAGNOSTIC VALUE. Normal value of cholesterol in blood is 3,6-5,2 mmol/L. The increased plasma cholesterol level (hypercholesterolemia) is observed in atherosclerosis, diabetes mellitus, mechanic and parenchymatous jaundice, nephritis, hypothyroidism. Decrease of plasma cholesterol level (hypocholesterolemia) is observed in anemias, fasting, tuberculosis, hyperthyroidism, cancerous cachexia, feverish states CONCLUSION: 56 Date: ________________ CLASS № 26 LABORATORY WORK № 1. MEASUREMENT OF LOW DENSITY LIPOPROTEINS (LDL) IN THE BLOOD SERUM. PRINCIPLE OF THE METHOD. The method is based on the ability of LDL to sediment in the presence of calcium chloride and heparin; the solution becomes turbid. Concentration of LDL in plasma is determined by the degree of solution turbidity. STEP OF TEST: take test tube Experimental sample 0,2 ml Blood serum СаСl2 (0,27%) 2 ml Stir and measure extinction (E1) at PEC ( = 630 nm) in 5 mm thick cuvettes versus water Put back mixture in to test tube Heparin 0,04 ml Stir, incubate 4 min (exactly!) and measure extinction (E2) under the same condition RESULT: Е1 = Е2 = ; . Concentration of LDL = (Е2 – Е1) х 10 = 57 g/L CLINICAL AND DIAGNOSTIC VALUE Normal value of LDL in blood serum is 2-4 g/L. The increased level of plasma LDL is observed in atherosclerosis, diabetes mellitus, obesity, hepatitis, hypothyroidism hyperlipoproteinemias (type II). CONCLUSION: 58 Date______________ CLASS № 27 STUDENTS’ INDIVIDUAL WORK “METABOLISM OF LIPIDS” Tasks for individual work: 1. Compose metabolic scheme of lipids metabolism. 2. Accentuate: 2.1. Diagnostic significant substrates (total lipids, triacylglycerols, cholesterol, lipoproteins, ketone bodies). 2.2. Clinical and diagnostic enzymes (lipase, lipoproteinlipase). 2.3. Regulatory enzymes of β-oxidation, biosynthesis of fatty acids and cholesterol, lipolisis. 2.4. Vitamin-dependent enzymes. 59 Date: _______________ CLASS № 29 DETERMINATION OF ALANINE AMINOTRANSFERASE ACTIVITY IN THE BLOOD SERUM Aminotransferases are enzymes catalyzing the transfer of amino group from amino acids to keto acids with the formation of a new amino acid and a new keto acid without intermediary release of ammonia. Aminotrasferase contains derivative of vitamin В6 as a coenzyme. The activity of aminotransefases is used to assess the amino acid metabolism in different tissues. PRINCIPLE OF THE METHOD: the enzyme alanine aminotranferase (AlAT or ALT) catalyzes the reaction in which alanine is transaminated with alpha-ketoglutate to form pyruvate and glutamate: AlAT Alanine + α-Ketoglutarate В6 Glutamate + Pyruvate Pyruvate reacts with 2,4-dinitrophenylhydrazine, and in the presence of KOH, forms 2,4-dinitrophenylhydrazone pyruvate of brownand-red colour: The intensity of the colour is measured colorimetrically. The amount of pyruvate produced in the transamination reaction is proportional to the activity of AlAT in the blood serum. STEP OF TEST: two test-tubes are taken. 60 COMPONENTS Substrate mixture Physiological solution NaCl (0.85%) Blood serum TEST CONTROL SAMPLE SAMPLE 0,25 ml 0,25 ml - 0,05 ml 0,05 ml - Mixing. Water bath at 37оС for 30 min. 2,4-Dinitrophenylhydrazine 0,25 ml 0,25 ml Mixing. Leave at a test-tube support to wait for 20 min at room temperature. NaOH 2,5 ml 2,5 ml Mixing. Leave at a test-tube support to wait for 10 min at room temperature. PEC, λ= 500-530 nm, cuvette 1 cm; measurement against the control sample. RESULT: Е= ; According to the standard graph the activity of alanine aminotransferase is ………….. mmol/ L / h. CLINICAL AND DIAGNOSTIC VALUE. The enzyme alanine aminotransferase is present in cells of many tissues. But in maximal amounts it is in hepatocytes. Normally, AlAT activity is low in the blood serum. In certain diseases accompanied by cell destruction (necrosis) or the increased cell membrane permeability (inflammation) AlAT releases from hepatocytes into the blood plasma. 61 Normal serum level of alanine aminotransferase activity is 0,1-0,68 mmol/L/h. Increased activity of AlAT is observed in hepatitis, necrosis of hepatocytes, obstructive jaundice. CONCLUSION: 62 Date: _______________ CLASS № 30 DETERMINATION OF UREA IN THE BLOOD SERUM Urea is the major product of ammonia detoxification in the body. Urea is the end product of the amino acid (protein) metabolism. The liver is the only site of urea synthesis. Urea is released from hepatocytes into the blood and then is freely filtered by glomeruli into the urine. Urea concentration in the blood and urine may serve as an indicator of the liver and renal function. PRINCIPLE OF THE METHOD: Urea reacts with diacetyl monooxime in the presence of HCl to form FeCl3 and thiosemicarbazide. The products form red-coloured complex. The intensity of the colour is proportional to the concentration in the blood. STEPS OF THE TEST: three test-tubes – test, standard and control samples. COMPONENTS TEST SAMPLE STANDARD SAMPLE CONTROL SAMPLE 0,1 ml - - - - 0,1 ml (16,65 mmol/L) - 0,1 ml - Reagent mixture 2,0 ml 2,0 ml 2,0 ml Blood serum H2O Standard solution of urea Water bath 100о С for 5 min. Cooling. PEC, λ= 500-560 nm, cuvette 1 cm, measurements against the control sample within 15 min. 63 RESULT: Еtest = ; Еstand = ; Сstand = 16,65 mmol/L. CALCULATION: Еtest Сtest = · 16,65 = mmol/L. Еstand CLINICAL AND DIAGNOSTIC VALUE. The normal urea level in the blood serum is 2,5-8,3 mmol/L. Urinary excretion of urea is 333-583 mmol/day. Urea level is decreased in the blood and urine in hepatitis, cirrhosis and genetic disorders of the urea cycle (as a result of impaired urea synthesis). In nephritis and renal failure, when renal filtration is impaired, urea is retained, and hence its concentration is increased in the blood (synthesis of urea in the liver is normal), but is decreased in the urine (renal filtration is impaired; therefore urea accumulates in the blood but does not excrete in the urine). CONCLUSION: 64 Date CLASS № 31 METABOLISM OF NUCLEOTIDES STUDENTS’ INDIVIDUALWORK «AMINO ACIDS METABOLISM» 1. Compose metabolic scheme of amino acid metabolism. 2. Accentuate: 2.1. Sources of amino acids in tissues. 2.2. General pathways of amino acid metabolism. 2.3. Intracellular detoxification of ammonia. 2.4. Biosynthesis of urea. 2.5. Amino acids which breakdown leads to formation of acetylCoA. 2.6. Subsrates of citric acid cycle which are end products of amino acids breakdown. 2.7. Normal levels of end products of amino acids and nucleotides breakdown in the blood. 65 Date CLASS № 32 WORK № 1. QUANTITATIVE DETERMINATION OF THE BILIRUBIN IN THE BLOOD SERUM When hemoglobin is destroyed in the body, heme is also degraded, mainly in the reticuloendothelial cells of the liver, spleen, and bone marrow. Indirect bilirubin (the end product of heme degradation) formed in peripheral tissues is transported to the liver by plasma albumin. In the liver indirect bilirubin is detoxified by its binding with glucuronic acid. In the blood serum present two types of bilirubin: indirect and direct. Indirect (or “free”) bilirubin, which is unconjugated with glucuronic acid, is easily adsorbed on blood plasma proteins. Therefore in performing an analysis for bilirubin content in the blood, the proteins complexed to bilirubin are preliminary precipitated with ethanol. After that, bilirubin is allowed to react with diazo reagent (indirect reaction). The form of bilirubin that would react without the addition of ethanol is termed “direct”. The sum of these pigments gives “total” bilirubin. Disturbances of bilirubin metabolism lead to development of jaundice. Measurements of plasma total, conjugated and unconjugated bilirubin help in differential diagnosis for jaundice of different types. PRINCIPLE OF THE METHOD: diazo reagent interacts with direct bilirubin with formation of pink dye. Indirect bilurubin is insoluble in water and gives indirect reaction with diazo reagent, that is, the reaction produces a specific colour after preliminary treatment. STEPS OF TEST: 1. Determination of total bilirubin: COMPONENTS Control Sample 1. Total reagent 1,0 ml 1,0 ml 2. NaCl, 0,9% 0,04 ml 3. Total nitrite-reagent 0,04 ml 4. Blood serum Stir and incubate 5 min at 18°С 0,1 ml Stir and incubate 20 min at 18°С 66 0,1 ml PEC (546 nm), 5 mm thick cuvettes, sample versus the control, Е1 = 2. Determination of direct bilirubin: COMPONENTS Control Sample 1. Direct reagent 1,0 ml 1,0 ml 2. NaCl, 0,9% 0,04 ml 3. Direct nitrite-reagent 0,04 ml Stir and incubate 2 min at 18°С 4. Blood serum 0,1 ml 0,1 ml Stir and incubate 5 min at 18°С PEC (546 nm), 5 mm thick cuvettes, sample versus the control, Е2 = RESULTS: Сtotal bilirubin = Е1 · 222,3 μmol/L = Сdirect bilirubin = Е2 · 222,3 μmol/L = Сundirect bilirubin = Сtotal bilirubin – Сdirect bilirubin = μmol/L DIAGNOSTIC IMPORTANCE Normal level of total bilirubin in blood serum 5,0-20,5 μmol/L; conjugated bilirubin (direct) – 1,0-7,5 μmol/L; unconjugated bilirubin (undirect) – 1,7-17,1 μmol/L. The increased level of total bilirubin is observed in neonatal jaundice, liver dysfunction (toxin- or inflammation-induced), blockage of the bile ducts, hemolytic anemias. In parenchymatous (hepatic) jaundice: - in the blood increased content of direct and indirect bilirubin; - in the urine present direct bilirubin and urobilinogen. In obstructive (mechanic) jaundice: - in the blood increased content of direct bilirubin; - in the urine present direct bilirubin (choluria); - the fecal level of stercobilin is decreased (acholic stools); 67 In hemolytic jaundice: - in the blood increased content of indirect bilirubin; - in the urine increased the level stercobilinogen; - the fecal level of stercobilin is increased. CONCLUSION: 68 Date CLASS № 33 WORK № 1. DETERMINATION OF HEMOGLOBIN CONCENTRATION IN THE BLOOD The hemoglobin content and number of erythrocytes are sensitive to different physiologic and pathologic factors, drug treatment. That’s why the determination of hemoglobin concentration is important in diagnosis. PRINCIPLE OF THE METHOD: hemoglobin oxidized by K3[Fe(CN)6] to hemiglobin. Hemiglobin react with acetoanhydrine with formation of coloured hemiglobincyanide. Concentration of hemiglobincyanide is detected photometrycally. STEPS OF WORK: take test tube COMPONENTS Sample Blood 0,02 ml Reagent 5,0 ml Stir and incubate10 min, Read the extinction of samples versus the control (reagent) at 540 nm, cuvette 10 mm RESULT: Еs = Calculation is performed according to the formula: С = Еs х 392 = g/L 69 DIAGNOSTIC IMPORTANCE Normal concentration of hemoglobin in the blood is 115-145 g/L (female), 130-160 g/L (male). Increased concentration of hemoglobin is observed hypohydratation, tissue hypoxia, ulcer disease, in neonates within first hours of life. Decreased concentration of hemoglobin is observed in anemias, hemoglobinopathies, deficiency of vitamins В12, Е and folic acid. CONCLUSION: WORK № 2. DETERMINATION OF CALCIUM CONCENTRATION IN THE BLOOD SERUM Calcium is a major structural component of osseous tissue, is involved in the processes of blood clotting, muscular contraction, neuromuscular excitation. It is also a second messenger of hormone action. PRINCIPLE OF THE METHOD: calcium in alkaline medium in reaction with glioxalbis(2-hidroxianilin) (GBHA) gives dye. Intensity of colour is directly depends on concentration of calcium. 70 STEPS OF WORK: COMPONENTS Control Reagent Н2О Са, standard solution Blood serum 1 ml 0,01 ml - Standard 1 ml 0,01 ml - Sample 1 ml 0,01 ml Stir and incubate 5 min at 18°С. Read the extinction of samples versus the control at λ = 574 nm, 5 mm thick cuvettes (colour is stable 5-12 min). RESULT: Еs = Еst = Еs CALCULATIONS: Сs = · 2,5 = mmol/L Еst 71 DIAGNOSTIC IMPORTANCE Normal concentration of calcium in the blood is 2,25-2,75 mmol/L. Physiologic hypercalcemia is observed in neonates, in some persons after mails. Pathologic hypercalcemia is observed in hyperparathyrosis (calcium is washed out of the bones into the blood plasma), acromegaly, myeloma disease, thyrotoxicosis, cancer with bones destruction, cancer of lung, kidney, pancreas, liver. Hypocalcemia is observed in deficiency of vitamin D, hypoparathyrosis, nephroses, chronic renal insufficiency, glomerulonephritis, cirrhosis, acute pancreatitis. CONCLUSION: 72 Date CLASS № 34 BIOCHEMICAL ANALYSIS OF THE URINE The compounds that occur in the normal urine at very low concentration escaping their determination by routine analytical techniques are called “pathologic components of urine”. These compounds are proteins, glucose, ketone bodies, bile and blood pigments. Determination of these compounds is used for diagnosis and treatment watch. 1. QUALITATIVE REACTION ON PROTEIN PRINCIPLE OF THE METHOD: denaturation of protein by nitric acid (or sulphsalicilic acid) STEPS OF WORK: 1) take 2 test tubes, label them and place in a test tube rack, 2) add to the each test tube the solutions: COMPONENTS Control Sample URINE 1,0 ml Н2О 1,0 ml Sulphosalicilic acid 20% (or НNО3 concentr.) 3 drops 3 drops RESULT: CLINICAL AND DIAGNOSTIC VALUE In the urine protein may occur in nephritis, cystitis, hypertension, sometimes in pregnancy, nephroses. CONCLUSION: 73 2. QUANTITATIVE DETERMINATION OF PROTEIN IN THE URINE PRINCIPLE OF THE METHOD: the method based on the Heller’s test with concentrated nitric acid. STEPS OF WORK: 1) take 1 ml of HNO3 to 4 test tubes; 2) in other 2 test tubes prepare urine solutions as described in the table COMPONENTS sample 1 sample 2 sample 3 sample 4 Dissolution - 1 : 10 1 : 20 1 :30 Urine 1,0 ml 0,1 ml 0,1 ml 0,1 ml Н2О 0,9 ml 1,9 ml 2,9 ml Add with pipette dissolved urine (1 ml) on nitric acid HNO3 concetr. 1,0 ml 1,0 ml 1,0 ml 1,0 ml RESULT: CONCLUSION: 74 3. QUANTITATIVE DETERMINATION OF GLUCOSE IN THE URINE PRINCIPLE OF THE METHOD: method is based on ability of glucose to reduce CuOH in alkaline medium to Cu2O (red-coloured sediment). STEPS OF WORK: COMPONENTS Sample Hainesse reagent 9 drops Urine 2 drops Stir and heat RESULT: CLINICAL AND DIAGNOSTIC VALUE The presence of glucose in the urine (glucosuria) is observed in diabetes mellitus, kidney damage, chlorophorm poisoning. CONCLUSION: 4. QUALITATIVE REACTION ON BLOOD PIGMENTS PRINCIPLE OF THE METHOD: test is based on the oxidation of bezidine by oxygen which formed in reaction of hydrogen peroxide degradation catalyzed by hemoglobin. STEPS OF TEST: - take 20 drops of urine to the test tube, boil it then cool; - to the urine add 20 drops of bezidine solution and 2 drops of hydrogen peroxide. The solution obtains blue or green colour in presence of blood pigments. RESULT: CONCLUSION: 75 5. URINE STRIP EXPRESS TESTS 76 Date CLASS № 35 WORK № 1.QUANTITATIVE MEASUREMENT OF PROTEIN IN THE LIQUOR PRINCIPLE OF THE METHOD. PROTEIN + NaOH/CuSO4 = violet colour, the intensity of the color produced is proportional to the concentration of protein present in the reaction system and detected photometrically. STEPS OF WORK: 1) take 2 test tubes, label them and place in a test tube rack. 2) add to the each test tube the solutions: COMPONENTS Control Sample Gornal’s reagent 4,0 ml 4,0 ml liquor 0,1 ml NaCl 0,9% 0,1 ml Stir and allow incubate 20 min. Read the extinction for sample versus the control at 540 nm, cuvette 10 mm RESULT: Esample = Find out the protein concentration in the sample from the calibration graph Csample = g/L DIAGNOSTIC IMPORTANCE Normal level of total protein in liquor is 0,22-0,33 g/L. An increased content of protein in the (hyperproteinrhachia) is observed in meningitis, brain tumors. Hypoproteinrhachia is observed in hydrocephaly, hypersecretion, intracranial hypertension. 77 liquor liquor CONCLUSION: 78 NORMAL CONCENTRATIONS OF SOME LABORATORY TESTED SUBSTRATES AND ENZYMES BLOOD SERUM (PLASMA) 1. Alanine aminotransferase (AlAT) 0,1-0,68 mmol/h·L 2. Albumins 40-50 g/L 3. Amylase 16-30 g/h·L 4. Aspartate aminotransferase (AsAT) 0,1-0,45 mmol/h·L 5. Calcium 2,25-2,75 mmol/L 6. Chloride 95-110 mmol/L 7. Creatinin 53-115 µmol/L 8. Fibrinogen 2-4 g/L 9. Globulins 20-30 g/L 10.Glucose 3,3-6,4 mmol/L 11.Hemoglobin 115-145 g/L (female); 130-160 g/L (male) 12. Iron 8,8-31,0 µmol/L 13. Potassium 3,2-5,6 mmol/L 14. Sodium 130-155 mmol/L 15.Total bilirubin 5,0-20,5 µmol/L 16.Total protein 65-85 g/L 17. Triacylglycerols 0,4-1,54 mmol/L (female); 0,45-1,82 mmol/L (male) 18. Urea 2,50-8,3 mmol/L 19. Uric acid 140-340 µmol/L (female); 200-415 µmol/L (male) 20. Cholesterol 3,6-5,2 mmol/L URINE 1. Amilase 28-160 g/h·L 2. Urea 333-583 mmol/day 3. Uric acid 1,6-6,4 mmol/day CEREBROSPINAL FLUID 1. Chloride 120-130 mmol/L 2. Glucose 2,5-3,89 mmol/L 3. Protein 0,22-0,33 g/L 79 Учебное издание Петушок Наталья Эдуардовна Курбат Михаил Николаевич Масловская Алла Анатольевна БИОЛОГИЧЕСКАЯ ХИМИЯ Практикум для студентов факультета иностранных учащихся (английский язык обучения) 3-е издание Под общей редакцией профессора В.В. Лелевича BIOCHEMISTRY Workbook for the medical faculty for internatiomal students (in English) Edited by professor V.V. Lelevich Ответственный за выпуск В.В. Воробьев Компьютерная верстка И.И. Прецкайло Корректор Е.А. Дабкене Подписано в печать 05.08.2015. Формат 60х84/16. Бумага офсетная. Гарнитура Таймс. Ризография. Усл. печ. л. 4,65. Уч.-изд. л. 1,60. Тираж 99 экз. Заказ 131. Издатель и полиграфическое исполнение учреждение образования «Гродненский государственный медицинский университет» ЛП № 02330/445 от 18.12.2013. Ул. Горького, 80, 230009, Гродно. 80