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Transcript
Министерство здравоохранения Республики Беларусь
УЧРЕЖДЕНИЕ ОБРАЗОВАНИЯ
«ГРОДНЕНСКИЙ ГОСУДАРСТВЕННЫЙ МЕДИЦИНСКИЙ
УНИВЕРСИТЕТ»
Кафедра биологической химии
Н.Э. ПЕТУШОК
М.Н. КУРБАТ
А.А. МАСЛОВСКАЯ
БИОЛОГИЧЕСКАЯ ХИМИЯ
Практикум для студентов факультета иностранных учащихся
(английский язык обучения)
3-е издание
Под общей редакцией профессора В.В. Лелевича
N.E. PETUSHOK
M.N. KURBAT
A.A. MASLOVSKAYA
BIOCHEMISTRY
Workbook for the medical faculty for internatiomal students
(in English)
Edited by professor V.V. Lelevich
Гродно
ГрГМУ
2015
1
УДК 577.1(07)=11
ББК 28.072я73
П29
Рекомендовано Центральным научно-методическим советом УО «ГрГМУ»
(протокол № 7 от 30 июня 2015 г.).
Aвторы: доц. каф. биологической химии, канд. биол. наук Н.Э. Петушок;
доц. каф. биологической химии, канд. мед. наук М.Н. Курбат;
доц. каф. биологической химии, канд. биол. наук А.А. Масловская.
Рецензент: зав. каф. нормальной физиологии, доц.,
канд. мед. наук О.А. Балбатун.
П29
Петушок, Н.Э.
Биологическая химия : практикум для студентов факультета
иностранных учащихся [на англ. яз.]. – 3-е изд. = Biochemistry :
workbook for the faculty of foreign students (in English) /
Н.Э. Петушок, М.Н. Курбат, А.А. Масловская; под общ. ред. проф.
В.В. Лелевича. – Гродно : ГрГМУ, 2015. – 80 с.
ISBN 978-985-558-560-3.
This workbook contains a list of laboratory works which must be performed in
accordance with the curriculum on Biochemistry as well as a list of normal
concentrations of some laboratory tested substrates and enzymes.
УДК 577.1(07)=11
ББК 28.072я73
© Петушок Н.Э., Курбат М.Н.,
Масловская А.А., 2015
© УО «ГрГМУ», 2015
ISBN 978-985-558-560-3
2
CONTENT
Class № 1………………………………………………………………..4
Class № 2………………………………………………………………..6
Class № 3………………………………………………………………12
Class № 4………………………………………………………………15
Class № 5………………………………………………………………17
Class № 6………………………………………………………………22
Class № 7………………………………………………………………25
Class № 9………………………………………………………………27
Class № 10……………………………………………………………..29
Class № 11……………………………………………………………..31
Class № 12……………………………………………………………..33
Class № 13……………………………………………………………..35
Class № 15……………………………………………………………..36
Class № 16……………………………………………………………..39
Class № 17………………………………………………………...…...41
Class № 18……………………………………………………………..43
Class № 19……………………………………………………………..45
Class № 20……………………………………………………………..48
Class № 21……………………………………………………………..50
Class № 22……………………………………………………………..52
Class № 24……………………………………………………………..53
Class № 25……………………………………………………………..55
Class № 26……………………………………………………………..57
Class № 27……………………………………………………………..59
Class № 29……………………………………………………………..60
Class № 30……………………………………………………………..63
Class № 31……………………………………………………………..65
Class № 32……………………………………………………………..66
Class № 33……………………………………………………………..69
Class № 34……………………………………………………………..73
Class № 35……………………………………………………………..77
Normal concentrations of some laboratory tested substrates
and enzymes…………………………..………………………………..79
3
Date
CLASS № 1
WORK № 1. COLORIMETRY. WORK WITH
PHOTOELECTROCOLORIMETER
Measurement of light absorption by a photoelectrocolorimeter is
used to detect the concentration of substances in solutions. This method
is based on Lambert-Beer law, which postulates that the absorbance of
solution is directly proportional to the concentration of the absorbing
solute and depends on the thickness of the absorbing layer (path
length, d). In colorimetry monochromatic light (of a single
wavelength, ) is used.
LAMP
MONOCHROMATOR CUVETTE
PHOTOELEMENT
SCALE
FIGURE 1.The principal components of photoelectrocolorimeter.
A light source emits light along a broad spectrum, then the
monochromator selects and transmits light of a particular wavelength.
The monochromatic light passes through the sample in a cuvette of path
length d and is absorbed by the sample in proportion to the concentration
of the absorbing species. The transmitted light is measured by a detector
and demonstrated on the scale.
Calculation of substances concentrations:
1) according to the formula (the standard solution with known
concentration must be used);
4
where
Сsample – concentration of the sample;
Еsample – extinction (absorbance) of the sample;
Сstandard -concentration of the standard solution;
Еstandard - extinction (absorbance) of the standard solution.
2) according to calibration graph (graph of dependence of extinction on
concentration).
5
Date
CLASS № 2
WORK № 1. COLOUR REACTIONS OF AMINO ACIDS AND
PROTEINS
Colour reactions of amino acids and proteins help to detect the
presence of protein in biological fluids or to identify their amino acid
composition.
These reactions are used for qualitative and quantitative
determination of proteins and amino acids.
1.Biuret reaction
PRINCIPLE OF THE METHOD. The biuret method depends on
the presence of peptide bonds in proteins. When a solution of proteins is
treated with cupper ions in a moderately alkaline medium
(NaOH/CuSO4), a blue-violet colored Cu2+-peptide complex is formed.
Biuret reaction requires presence of at least two peptide bonds in a
molecule. The biuret reaction can be used for both qualitative and
quantitative analysis of protein.
STEPS OF WORK:
1) take 1 test tube and place it in a test tube rack.
2) add to the test tube the solutions:
COMPONENTS
Amount of each
solution
Protein solution
NaOH, 10%
CuSO4, 1%
5 drops
5 drops
2 drops
RESULT:
6
CONCLUSION:
2.Ninhydrin reaction
PRINCIPLE OF THE METHOD: amino acids, peptides and
proteins boiled in the presence of ninhydrin solution firstly undergo
deamination, than ammonia interact with ninhydrin with formation of
blue-violet dye (Ruhemann’s pyrple). Reaction is specific for alphaamino acids.
CO2
ALDEHYDE
AMINO ACID+ NINHYDRIN
RUHEMANN’S PURPLE (blue-violet dye)
STEPS OF WORK:
1) take 1 test tube and place it in a test tube rack.
2) add to the test tube the solutions:
COMPONENTS
Amount of each solution
Protein solution
Ninhydrin 0,5%
5 drops
5 drops
Boil till dye yield
RESULT:
CONCLUSION:
7
3. Xanthoproteic reaction (for aromatic amino acids)
tyrosine
dinitrotyrosine
PRINCIPLE OF THE METHOD. Aromatic amino acids
(phenylalanine, tyrosine, tryptophan) after heating with nitric acid
undergo nitration. This process leads to formation of dark yellow dye.
STEPS OF WORK:
1) take 1 test tube and place it in a test tube rack.
2) add to the test tube the solutions:
COMPONENTS
Amount of each solution
Protein solution
HNO3concentrated
Boil till dye yields
RESULT:
CONCLUSION:
8
5 drops
5 drops
4. Fohl reaction on cysteine
PRINCIPLE OF THE METHOD. Reaction is specific for cysteine.
End product of the reaction – lead sulfide – is black coloured sediment.
Cys
Ser
Black colour
STEPS OF WORK:
1) take 1 test tube and place it in a test tube rack.
2) add to the test tube the solutions:
COMPONENTS
Amount of each solution
Protein solution
NaOH, 30%
(СН3СОО)2Рb, 5%
5 drops
5 drops
1 drop
Boil till dye yields
RESULT:
CONCLUSION:
9
WORK № 2. QUANTITATIVE MEASUREMENT OF TOTAL
SERUM PROTEIN
PRINCIPLE OF THE METHOD. PROTEIN + NaOH/CuSO4 =
violet colour, the intensity of the color produced is proportional to the
concentration of protein present in the reaction system and detected
photometrically.
STEPS OF WORK:
1) take 2 test tubes, label them and place in a test tube rack.
2) add to the each test tube the solutions:
COMPONENTS
CONTROL
SAMPLE
Amount of each
solution
Gornal’s reagent
4,0 ml
4,0 ml
serum
0,1 ml
NaCl 0,9%
0,1 ml
Stir and allow standing for 20 min.
Read the extinction for sample versus the control at 540 nm
Cuvette 1 cm
RESULT:
Esample=
Find out the protein concentration in the sample from the
calibration graph:
Csample =
g/L
DIAGNOSTIC IMPORTANCE
Normal level of total protein (total protein = albumins + globulins)
in adults serum - 65-85 g/L.
10
An increased content of blood plasma total protein
(hyperproteinemia) can be caused by: collagenoses, myeloma disease,
hyperimmunoglobulinemia, hypohydratation (vomiting, diarrhea).
A decreased concentration of blood plasma total protein
(hypoproteinemia) is observed in alimentary distrophy, pregnancy,
chronic nephritis, cirrhosis, hepatitis, gastroenteropathies, carcinoma.
CONCLUSION:
11
Date
CLASS № 3
WORK № 1. DENATURATION OF PROTEIN BY NITRIC ACID
Work demonstrates the influence of chemical factors on stability of
protein in solutions.
PRINCIPLE OF THE METHOD: protein precipitated as a
sequence of denaturation and formation of complex with acid.
STEPS OF WORK:
1) take 1 test tube and place it in a test tube rack.
2) add to the test tube the solutions:
COMPONENTS
Amount of each
solution
HNO3
concentrated
10 drops
Protein solution
10 drops
Take the test tube with concentrated HNO3 under the angle 45о and
carefully, slowly add protein solution along side of a test tube.
RESULT:
CONCLUSION:
12
WORK № 2. SEPARATION OF ALBUMINS AND GLOBULINS OF
AN EGG WHITE BY SALTING-OUT
Salting-out is used for reversible precipitation of proteins. This
technique is one of steps in protein purification procedure.
PRINCIPLE OF THE METHOD. Due to the fact that protein
contains multiple charged groups, its solubility depends on the
concentrations of dissolved salts. The additional ions shield the protein's
multiple ionic charges, thereby weakening the attractive forces between
individual protein molecules (such forces can lead to aggregation and
precipitation). So, the solubility of protein decreases. This "salting out"
effect is primarily a result of the competition between the added salt ions
and the protein molecules for molecules of water.
STEPS OF WORK:
1) take 2 test tubes, label them and place in a test tube rack.
2) add to the each test tube the solutions:
COMPONENTS
SAMPLE 1
SAMPLE 2
Amount of each
component
Protein solution
NaCl (crystalline)
(NH4)2SO4-saturated
solution (100%)
1,0 ml
till full saturation
(100%)
-
1,0 ml
1,0 ml
(till 50% saturation)
Incubation 10 min
Without incubation
Filtration
Filtration
Boil
Add salt to saturation
RESULT:
(NH4)2 SO4
(powder)
RESULT:
13
CONCLUSION:
14
Date
CLASS № 4
WORK № 1. ACIDIC HYDROLYSIS OF PROTEINS
Hydrolysis of protein is a process of biopolymer’s degradation
with cleavage of peptide bonds through the assistance of water
molecules under the action of acids, alkalis or proteases.
In laboratory conditions hydrolysis of protein is used for
determination of primary structure and amino acid composition. Protein
hydrolyzates are used in clinical practice for parenteral nutrition.
Hydrolysis of proteins constantly occurs in gastrointestinal tract and in
cells of humans and animals under the action of proteolytic enzymes
PRINCIPLE OF THE METHOD. Biopolymer in reaction with
water degrades to monomers. Hydrolysis is catalyzed by protons,
hydroxyl ions and enzymes on mechanisms of nucleophilic substitution.
Total acidic hydrolysis of proteins proceeds in 12-96 hours at 100 °C.
Sequence of events in hydrolysis of protein is presented in the
scheme.
protein
High-wheight
polypeptides
PROTEASES
pepsin
trypsin and others
tr
low-wheight
polypeptides
and dipeptides
Amino acids
15
STEPS OF WORK:
1. To the flask add 20 ml of eggs white solution.

2. Add 5 ml of concentrated НCl.

3. Put 0,5 – 1 ml (5 drops) of the mixture to the test tube № 1.

4. Close the flask by rubber stopper with long glass tube (reverse
condenser).

5. Boil the mixture for 45 min.

6. After cooling take 0,5 – 1 ml (5 drops) of hydrolyzate to the
test tube № 2.

7. Adjust the pH of hydrolyzate to neutral by addition of 20 %
NaOH (to blue colour of lakmus paper).

8. Perform a biuret reaction in the test tubes № 1 and № 2.
.
RESULT:
CONCLUSION:
16
Date
CLASS № 5
WORK № 1. EFFECT OF TEMPERATURE ON AMYLASE
ACTIVITY
This work describes one of the properties of enzymes –
dependence of the rate of an enzyme-catalyzed reaction on temperature
(termolability).
PRINCIPLE OF THE METHOD:
amylase
amylase
Starch --------- dextrins ------------ maltose.
Reaction of starch with iodine gives dark blue dye.
Reaction of dextrins with iodine gives violet, red dye.
If in the sample only maltose presents, after addition of iodine
yellow colour of solution (colour of iodine) is observed.
STEPS OF WORK:
1) take 3 test tubes, label them and place in a test tube rack,
2) dissolve saliva in separate test tubes in proportion 1:10 (1 ml of
saliva + 9 ml Н2О),
3) add to the each test tube the solutions:
COMPONENTS
SAMPLE 1 SAMPLE 2
SAMPLE 3
Amount of each
solution
Starch, 1 %
Amylase of saliva
(1:10)
Allow test tubes to
standing for 10 min at
0,5 ml
0,5 ml
0,5 ml
0,5 ml
0,5 ml
0,5 ml
Room
Thermostat Boiling water
temperature (40оС)
bath (100оС)
(20оС)
After 10 min add 1-2 drops of KJ (1%)to all test tubes
17
RESULT:
CONCLUSION:
WORK № 2. EFFECT OF ACTIVATOR AND INHIBITOR ON
AMYLASE ACTIVITY
Activators and inhibitors regulate the enzymatic activity. These
data are used for studying the effects of xenobiotics and normal cell
metabolites on enzymatic processes.
STEPS OF WORK:
1) take 3 test tubes, label them and place in a test tube rack,
2) add to the each test tube the solutions:
COMPONENTS
CONTROL SAMPLE 1 SAMPLE 2
Amount of each
solution
Н20
NaCl, 1%
CuSO4, 1%
Amylase of saliva (1:10)
Starch, 1%
10 drops
20 drops
5 drops
18
8 drops
2 drops
20 drops
5 drops
8 drops
2 drops
20 drops
5 drops

Allow test tubes to stand for 5 min (10, 15 min) at a room
temperature.

Add 2-3 drops of KJ (1%) to all test tubes.
RESULT:
CONCLUSION:
WORK № 3. DETERMINATION OF AMYLASE IN BLOOD SERUM
(BY CARAWEY’S METHOD)
Determination of amylase activity in the urine and blood serum is
used for the diagnosis of diseases of pancreatic gland.
PRINCIPLE OF THE METHOD. Method is based on the
colorimetric determination of starch substrate concentration before and
after its enzymatic hydrolysis. 0,01 n iodine solution is used as working
reagent.
STEPS OF WORK:
1) take 2 test tubes, label them and place in a test tube rack,
2) add to the each test tube the solutions:
19
COMPONENTS
SAMPLE
CONTROL
Amount of each
solution
Starch substrate
0,5 ml
0,5 ml
Heat 5 min in water thermostat at 37°С
Blood serum
10 μl
°
Heat 5 min in water thermostat at 37 С
Iodine solution (0,01 n)
0,5 ml
0,5 ml
H2O dist.
4 ml
4 ml
Blood serum
10 μl
Mix well and read the extinctions for sample and control versus the
water at 630-690 nm, cuvette 1 cm
CALCULATION.
Mean of α-amylase activity in grams of degraded starch per 1 liter
of serum for 1 hour of incubation at 370С is calculated according to the
formula:
Еc – Еs
Х = -------------------- х 240
Еc
Еc - extinction of the control;
Еs – extinction of the sample.
RESULT:
20
DIAGNOSTIC IMPORTANCE
Normal activity of α-amylase in blood serum is 16 – 30 g/h•L, in
urine it is 28 – 160 g/h•L.
Increasing of enzyme activity is observed in parotitis, pancreatitis,
malignancy of the pancreas, cirrhosis, diabetic ketoacidosis.
Decreasing of α-amylase activity is observed in atrophia of the
pancreas, kahexia.
CONCLUSION:
21
Date
CLASS № 6
WORK № 1. KINETICS OF LIPASE-CATALYZED HYDROLYSIS
OF TRIACYLGLYCEROLS
Lipolytic enzymes of pancreatic gland hydrolyze dietary lipids in
the small intestine. Bile acids emulsify lipids, activate lipase and
participate in absorption of products of lipid digestion. Studying the
kinetics of lipase action, you can watch the dinamics of enzyme activity
and factors which affect this process (temperature, concentrations of
substrate and products of reaction, presence of bile).
PRINCIPLE OF THE METHOD. Lipase catalyzes the reaction:
lipase
Triacylglycerols-------------glycerol + fatty acids
+НОН
lipase
The rate of lipase-catalyzed reaction can be estimated by the
quantity of fatty acids, formed within a certain time interval. Quantity of
fatty acids is determined by alkaline titration with fenolpftalein as
indicator and is expressed in ml of 0,01 n NaOH solution.
22
STEPS OF WORK:
1) take 2 test tubes, label them and place in a test tube rack,
2) add to the each test tube the solutions:
Components
SAMPLE 1
SAMPLE 2
(without bile)
(with bile)
Milk
10,0 ml
10,0 ml
Н2О
1,0 ml
Bile
1,0 ml
Lipase
1,0 ml
1,0 ml
(homogenate of pancreatic gland)
1) Stir and take 2 ml from each test tube to 2 small flasks + 1-2
drops of fenolftalein.Perform titration by 0,01 n NaOH to pink
colour.
2) Put the mixture into termostat at 38оС.
3) Take 2 ml of mixture from each test tube after 15, 30 and 45 min
of incubation and perform titration.
During the first titration the acids which presents in the milk before
the lipase action are neutralized. The results of the first titration (before
the lipase action) are subtracted from the results of the following
titrations.
RESULT:
Write down your result into the table:
Time of incubation,
min
0
Volume of 0,01 n NaOH solution,
used for titration
- bile
+ bile
Х
15
Y–X=Y
30
Z–X=Z
45
E–X=E
23
Plot the graph using these data:
Kinetics of lipase-catalyzed hydrolysis:
VmlNaOH
0,01n
Time (min)
15
30
45
CONCLUSION:
24
Date
CLASS № 7
STUDENTS’ INDIVIDUAL WORK
«PROTEINS, ENZYMES»
25
26
Date: _______________
CLASS № 9
LABORATORY WORK № 1. HYDROLYSIS OF NUCLEOPROTEINS
Acidic hydrolysis is used for study of nucleoproteins chemical
composition.
Scheme of nucleoproteins hydrolysis
Nucleoproteins (yeast)
H2SO4 (10%)
100oC
Protein
(Protamines or histones)
Nucleic acidc
(DNA, RNA)
High-molecular polypeptides
Polynucleotides
Tri-, Dipeptides
Amino acids
Mononucleotides
Nucleosides
Nitrogen base
(Purines or Pyrimidines)
H3PO4
Pentose
(Deoxyribose or ribose)
Color reactions for components of nucleoproteins:
Components
Reaction
Observation
Protein
Biuret reaction
Blue-violet color
Purine
Silver test
Light brown
precipitation
Pentose
Trommer test
Red color and
precipitation (Cu2O)
Phosphoric acid
Molybdenum test
Lemon-yellow color
27
Step of test: take 4 test tubes.
Biuret reaction
Hydrolyzate of nucleoproteins
NaOH 10%
CuSO4 1%
5 drops
10 drops
1-2 drops
Result:
Silver test
Hydrolyzate of nucleoproteins
(NH4)OH (conc).
AgNO3 1%
10 drops
1 drop
5 drops
Leave for 5 min
Result:
Trommer test
Hydrolyzate of nucleoproteins
NaOH 30 %
CuSO4 7 %
5 drops
10 drops
3 drops
Boil 10 sec
Result:
Molybdenum test
Hydrolyzate of nucleoproteins
Molybdenum reagent
Result:
Conclusion:
28
5 drops
20 drops
Boil 1-2 min
Date: _______________
CLASS № 10
LABORATORY WORK № 1. DETERMINATION OF URIC ACID
CONCENTRATION IN THE BLOOD SERUM.
Uric acid is an end-product of purine catabolism in human.
PRINCIPLE OF THE METHOD. Uric acid is enzymatically
(enzyme – uricase) oxidized by oxygen to produce hydrogen peroxide,
allantoin, and carbon dioxide. The H2O2 reacts with chromogen (redused
- colorless) in the presence of peroxidase to form a chromogen
(oxidised) dye. The intensity of color (pink) formed is proportional to
the uric acid concentration and can be measured photometrically.
Step of test: take 2 test tubes: experimental and control.
Components
Experimental
Standard sample
sample
Blood serum (urine)
Standard of uric acid
(375 µmol/L)
Working solution of
enzymes and chromogen
0,025 ml
-
0,025 ml
1,0 ml
1,0 ml
Stir and incubate 10 min at 37 ºC
On completion of incubation extinction
of experimental and standard samples
are measured at PEC ( = 500-520 nm)
in 5 mm thick cuvettes versus water
RESULT: Е st =
; Е ex =
; Сst = 375 µmol/L
Calculation is done by the formula:
Сex =
Cst · Еex
Еst
29
=
µmol/L.
CLINICAL AND DIAGNOSTIC VALUE
Normal values of uric acid excretion in urine are 1,5-4,5
mmol/day. In the blood – 140-340 µmol/L (female), 200-415 µmol/L
(male).
Uric acid excretion depends on the purines content in food and
intensity of nucleoproteins metabolism. Hypouricuria (decrease of uric
excretion with urine) is noted in gout, nephritis, renal insufficiency;
hyperuricuria (increase of uric excretion with urine) – in leukemia,
accelerated breakdown of nucleoproteins. In gout uric acid salts (urates)
precipitate in cartilages, muscles and joints. The content of uric acid in
the blood can be increased while in the urine – decreased.
CONCLUSION:
30
Date_______________
CLASS № 11
STUDENTS’ INDIVIDUAL WORK “BIOSYNTHESIS OF
PROTEINS”
Tasks for individual work:
1. Write structure and reaction of synthesis of valil-tRNA.
2. Make up the scheme of biosynthesis of dipeptide methionylglutamate
(initiation and elongation stages).
3. Explain the role of genetic engineering in the production of protein.
Give the scheme of process.
4. Give the scheme of polymerase chain reaction (PCR).
31
32
Date: _______________
CLASS № 12
LABORATORY WORK № 1. QUANTITATIVE
DETERMINATION OF HIGH-ENERGY COMPOUNDS IN THE
MUSCULAR TISSUE
ATP – the main macroergic compound – is synthesized by
oxidative and substrate-level phosphorylation. In muscle also present
creatinephosphate – macroerg, formed with the participation of ATP.
Both substances give energy for muscles construction.
PRINCIPLE OF THE METHOD. Reach in energy phosphate
group of ATP and creatinephoshate are hydrolysed in acidic medium
and give a colour product with ammonium molybdate in presence of
ascorbic acid.
Steps of the test:
Take 2 test tubes
Components
Protein-free muscle filtrate
HCl, 1M
NaOH, 1M
H2O
Ammonium molybdate, 1%
Ascorbic acid
Control
Experimental sample
sample
0,5 ml
0,5 ml
1,0 ml
1,0 ml
Boil 10 min
1,0 ml
1,0 ml
2,5 ml
2,5 ml
0,5 ml
0,5 ml
0,5 ml
0,5 ml
Stir and incubate 10 min at room
temperature
On completion of incubation
extinction of experimental sample is
measured at PEC ( = 640 nm) in 10
mm thick cuvette versus control
33
RESULT:
Ех =
Calculation is performed according to calibration graph. Put the
received result of phosphorus concentration in a sample (A) into the
formula:
C = А  3,3  40 =
mg ATP/g tissue
Find concentration of ATP in 1g of tissue:
C = m (ATP in g)/MrATP =
/507,2=
CONCLUSION:
Concentration of ATP 5µmol per 1 g of muscle (at rest condition)
34
Date________________
CLASS № 13
STUDENTS’ INDIVIDUAL WORK “ENERGY METABOLISM.
OXIDATIVE PROCESSES IN THE CELL”
Task for individual work:
1. Make up a common scheme of energy metabolism.
2. Illustrate:
2.1. Links TCA cycle with ETC.
2.2. Vitamine-dependent enzymes of TCA cycle.
2.3. Anabolic function of TCA cycle.
2.4. Regulatory enzymes of TCA cycle.
35
Date: ______________
CLASS № 15
LABORATORY WORK № 1. DETECTION OF THE SUCCINATE
DEHYDROGENASE ACTIVITY
Succinate dehydrogenase is one of the enzymes of the TCA cycle,
firmly bound to the inner mitochondrial membrane. The enzyme
catalyzes oxidation (removal of hydrogen) from succinate to form
fumarate. Coenzyme is FAD joined with the enzyme by covalent bond.
FAD is intermediary acceptor of hydrogen. The reaction catalyzed by
succinate dehydrogenase:
СООН
FAD
FADН2
СН2
СН2
СООН
СН
Succinate dehydrogenase
СООН
Succinate
СН
СООН
Fumarate
PRINCIPLE OF THE METHOD. Substrate is succinate. Final
acceptor of hydrogen is 2,6-dichlorophenolindophenol (dark-blue
colour) which, due to reduction, is converted to its colourless (reduced)
form. Conversion of dark-blue oxidized chromogen into its colourless
form allows detecting the catalytic activity of the enzyme.
Succinate
FAD
2,6-DCPI-H2
(colorless)
Fumarate
FADH2
2,6-DCPI
(blue)
Source of the enzyme is homogenate of muscles.
Malonate is competitive inhibitor of succinate dehydrogenase.
36
STEPS OF THE TEST:
Take 4 test tubes
Components
Homogenate of muscles
Н2О
Malonate
Succinate
2,6dichlorphenolindophenol
1
2
3
1,0 ml
1,0 ml 1,0 ml
(Boil 2 min)
0,5 ml
0,5 ml 1,5 ml
1,0 ml
1,0 ml
2 drops
2 drops 2 drops
4
1,0 ml
0,5 ml
1,0 ml
2 drops
Stir and incubate 15 min at 37 ºC
Result (color)
CONCLUSION:
LABORATORY WORK № 2. DETECTION OF THE CYTOCHROME
OXIDASE ACTIVITY
The enzyme cytochrome oxidase is the last enzyme in the
respiratory electron transport chain of mitochondria located in the
mitochondrial membrane. It receives an electron from cytochrome c and
transfers them to one oxygen molecule, converting molecular oxygen to
molecule of water.
PRINCIPLE OF THE METHOD Mixture of -naphthol and pphenylene diamine (reagent NADI) is oxidized by cytochrome oxidase
and in the presence of oxygen forms product of blue colour.
37
α-naphthol
n-phenylene diamine
Cytochrome oxidase
O
Steps of the test.
Muscle is divided into two parts. One part is placed on the filter
paper, the other part is put into the test-tube with 1 ml of water and
boiled for 1 min. After cooling, the boiled muscle tissue is taken from
the test-tube by a glass stick and is put on the filter paper.
Both portions of the muscle are applied by 2 drops of reagent
NADI. Incubation is performed for 5-10 min at room temperature.
RESULT:
CONCLUSION:
38
Date: _______________
CLASS № 16
DETECTION OF ADRENALIN IN THE URINE (QUALITATIVE
REACTION ON ADRENALIN)
In the adrenal medulla, catecholamines are synthesized from amino
acid tyrosine. In the liver and muscles, adrenaline and noradrenaline
activate phosphorylase which degrades glycogen. In the adipose tissue,
the hormones activate degradation of triacylglycerols.
PRINCIPLE OF THE METHOD.
The molecule of both
adrenaline and noradrenaline contains pyrocatechin ring which forms
product of emerald-green colour reacting with FeCl3. In subsequent
adding NaOH the solution obtains cherry-red colour.
STEPS OF WORK:
COMPONENTS
CONTROL
TEST
Н2О
10 drops
-
Solution of adrenaline
-
10 drops
FeCl3
1 drop
Light-yellow colour
1 drop
Emerald-green colour
NaOH , 10 %
3 drops
3 drops
Colour is not changed
Cherry-red colour
RESULT:
CONCLUSION:
39
CLINICAL AND DIAGNOSTIC VALUE
Normal concentration of adrenaline in the blood serum is not more
than 6.28 nmol/L, the excretion in the urine is 27.3 – 81.9 nmol/day.
Increased
excretion
of
adrenaline
is
observed
in
pheochromocytoma, hypertension stroke, acute period of myocardial
infarction, hepatitis and liver cirrhosis, physical exertion and emotional
stress reaction.
40
Date: _______________
CLASS № 17
INDIVIDUAL STUDENTS’ WORK «HORMONES»
Fill in the table:
Characteristics of the major hormones
Hormone
Chemical
structure
Site of
synthesis
41
Mechanism
of action
Targettissue
Biological
effect
Hypoproduction of the
hormone
Name
Signs
42
Hyperproduction of the
hornmone
Name
Signs
Date: ________________
CLASS № 18
QUANTITATIVE DETERMINATION OF THE VITAMIN C
CONCENTRATION IN THE URINE
Vitamin C (ascorbic acid) participates in the oxidative-reduction
processes, synthesis of steroid hormones and catecholamines in adrenals,
appears to be coenzyme of hydroxylases catalyzing conversion of
proline into hydroxyproline, furthers absorption of iron from the
intestine, activates pepsinogen. Vitamin C deficiency in the organism
leads to the impairment of these processes.
PRINCIPLE OF THE METHOD. Vitamin C is capable of
reducing 2,6-dichlorophenolindophenol (2,6-DCPIP). This chromogen
when oxidized is coloured (dark-blue colour in alkaline medium and red
colour in acidic medium). When reduced, the chromogen becomes
coloureless.
Reaction
mixture
is
titrated
by
2,6dichlorophenolindophenol in the acidic medium until the light-red
colour appeares.
STEPS OF WORK:
COMPONENTS
Urine
Н2О
HCl 10%
2,6-DCPIP 0,001N
TEST SAMPLE
10.0 ml
10.0 ml
20 drops
Titrate until the light-red colour is
appeared
RESULT:
CALCULATION:
43
0,088А1500
Х = ------------------- =
mg/day,
10
where 0,088 – amount of vitamin C (mg) corresponds to 1ml
0,001N 2,6-DCPIP;
А – result of titration, ml;
1500 – average daily diuresis, ml;
10 – the volume of the urine taken for titration, ml.
CLINICAL AND DIAGNOSTIC VALUE
Normal content of vitamin C in the blood serum is 34-114 μmol/L.
Normal excretion in the urine is 20-30 mg/day.
Determination of vitamin C in the urine allows assessing the
content of vitamin C in the organism, for there is normally proportion
between concentration of the vitamin in the blood serum and amount of
the vitamin excreted in the urine. However in hypovitaminosis C, the
content of ascorbic acid in the urine is not always decreased. Often it is
normal despite the appreciable deficiency of the vitamin in tissues.
In healthy people administration of 100 mg of vitamin C per os
results in the increase of its concentration in the both blood serum and
urine. In hypovitaminosis C, tissues being experienced need for the
vitamin retain administered load of ascorbic acid and its concentration in
the urine is not increased.
Concentration of vitamin C in the urine is decreased in acute and
chronic infectious diseases, anemia, steatorea, malabsorption,
alcoholism.
CONCLUSION:
44
Date: ________________
CLASS № 19
LABORATORY WORK № 1. MEASURMET OF GLUCOSE
CONCENTRATION IN BLOOD SERUM BY ENZYMATIC
(GLUCOSE OXIDASE) METHOD
Determination of glucose in the blood is used for assessment of
carbohydrates metabolism condition and for pathology diagnosis
(hypoglycemia and hiperglycemia). Now enzymatic method using
enzyme glucose oxidase is widespread.
PRINCIPAL OF THE METHOD. Glucose oxidase is complex
FAD-containing enzyme, that catalyses the oxidation of glucose to
hydrogen peroxide (H2O2) and gluconolactone. The H2O2 reacts with
chromogen (redused - colorless) in the presence of peroxidase to form a
chromogen (oxidised) dye - pink. The intensity of color formed is
proportional to the glucose concentration and can be measured
photometrically.
glucose oxidase
Glucose
H2O
gluconolactone
FAD
gluconate
FADH2
H2O
O2
H2O2
Chromogen (oxidized, pink)
Chromogen
redused, colorless
45
The formed product is of a pink color. Staining intensity is
proportional to glucose concentration and measured photometrically.
Step of test: take 3 test tubes: experimental, standard and control.
COMPONENTS Experimental
Standard
Control
sample
sample
sample
Blood serum
0,02 ml
Standard of
0,02 ml
glucose (5,55
mmol/L
Water (dist)
0,02 ml
Working
2,0 ml
2,0 ml
2,0 ml
solution of
enzymes
Stir and incubate 20 min at 37ºC
On completion of incubation extinction of experimental and standard
samples are measured at PEC ( = 500 nm) in 5 mm thick cuvettes
versus the control sample
RESULT: Е st =
; Е ex =
; Сst = 5,55 mmol/L
Calculation is performed according to the formula:
Сex =
Cst · Еex
Еst
=
mmol/L.
CLINICAL AND DIAGNOSTIC VALUE
Normal values of glucose concentration in serum in adult is 3,336,4 mmol/L.
Increase of glucose content in the blood (hyperglycemia) is
observed in physiological condition (stress, carbohydrates intake) and
pathology: diabetes mellitus, acute pancreatitis, myocardial infarction,
hyperfunction of same endocrine glands (thyrotoxicosis, glucagonoma,
Icenko-Cushing's syndrome, pheochromocytoma).
46
Decrease of blood glucose level (hypoglycemia) occurs in
physiological condition (starvation, insufficiency of diet carbohydrates,
hard physical work) and same diseases: insulinoma, Addison's disease,
arsenic, phosphorus, benzole, chlorophorm poisoning, disturbances of
carbohydrates absorption in GIT, glycogenoses and over dosage of
insulin while treating diabetes mellitus.
CONCLUSION:
47
Date: ________________
CLASS № 20
LABORATORY WORK № 1. GLUCOSE TOLERANCE TEST
A glucose tolerance test (GTT) is a medical test in which glucose
is given and blood samples taken afterward to determine how quickly it
is cleared from the blood. The test is usually used to test for diabetes,
insulin resistance, and sometimes reactive hypoglycemia and rarer
disorders of carbohydrate metabolism.
Procedure of test. Usually the GTT is performed in the morning.
The patient is instructed to fast for 8-12 hours prior to the tests. Before
the test begins, a sample of blood will be taken. After this, the person
receives glucose at a dose 1 g/kg of body weight (or 1,5 g/kg of
sucrose), dissolved in glass of water. Blood samples are taken up to four
times at 30 min after consumption (30, 60, 90, 120 min) of the sugar to
measure the blood glucose. Draw a graph – glycemic curve:
Fasting plasma glucose (measured before the GTT begins) in
healthy person should be between 3,3-6,4 mmol/L (110 mg/dL). The
glucose concentration reaches its maximum for 60 min (Note! No more
than 9,9 mmol/L – renal threshold of glucose) and returns to a start point
for 120 min (often it becomes lower than initial). In case of disturbances
of carbohydrates metabolism glycemic curves are distinguished from
normal (hyper- and hipoglycemic curve).
48
STEPS OF TEST
Using glucose oxidase method (see previous class) determine
concentration of glucose in 3 samples: 1st – fasting leves (0 min), 2nd –
after 60 min and 3d - after 120 min of sugar consumption. Draw the
glycemic curve.
RESULT:
CONCLUSION:
49
Date: ________________
CLASS № 21
LABORATORY WORK № 1.
MEASUREMENT OF PYRUVATE IN THE URINE
Pyruvate is one of central intermediate products of carbohydrate
metabolism and produced in all tissues in great amount. Metabolic
pathways of pyruvate illustrate in the scheme:
PRINCIPAL OF THE METHODS. Pyruvate interacting with 2,4dinitrophenylhydrasine
in
alkaline
medium
forms
2,4dinitrophenylhydrasone derivatives of yellow-orange color, the staining
intensity of which is proportional to concentration of pyruvate.
2, 4 – DNP-hydrosone PA
2, 4 - DNPH
50
STEPS OF TEST:
take 2 test tubes: experimental and control.
COMPONENTS
Urine
Н2О
КОН (25 %)
2,4-Dinitrophenylhydrasine
(0,1%)
Experimental
Control sample
sample
1,0 ml
1,0 ml
1,0 ml
1,0 ml
Shake 1 min
0,5 ml
0,5 ml
Shake and leave for 15 min at room
temperature
Determine extinction of experimental
sample versus control sample using 5
mm cuvettes,  = 470-480 nm
RESULT:
Е=
.
Calculation is performed according to calibration graph. The
received result (in µg) should be multiplied by empiric coefficient
11,366.
С = ……. x 11,366 =
µmol/day.
CLINICAL AND DIAGNOSTIC VALUE
Normal value of pyruvate excretion in urine is 114-284 µmol/day
(10-25 µg/day). In the blood – 56,8-113,6 µmol/L.
In hypovitaminosis of B1 in the blood and other tissues, especially
in the brain, a great amount of pyruvate is accumulated and its excretion
with urine increases. The content of this acid in the blood increases in
diabetes mellitus, cardiac insufficiency, hyperfunction of the
hypophysis-adrenal system.
CONCLUSION:
51
Date _________________
CLASS № 22
STUDENTS’ INDIVIDUAL WORK
“METABOLISM OF CARBOHYDRATES”
Tasks for individual work:
1. Compose metabolic scheme of carbohydrates metabolism.
2. Accentuate:
2.1. Diagnostic significant substrates (glucose, pyruvate, lactate,
glycogen, galactose, fructose).
2.2. Clinical and diagnostic enzymes (glucose-6-phoshatase,
fructose-1,6-diphosphatealdolase, lactatedehydrogenase (LDH),
glycogen phosphorylase, glucose-6-phoshate dehydrogenase).
2.3. Regulatory enzymes of glycolysis, biosynthesis of glycogen,
pentose phosphate pathway. Vitamin-dependent enzymes.
52
Date: _________________
CLASS № 24
LABORATORY WORK № 1.
MEASUREMENT OF TRIACYLGLYCEROLS
IN THE BLOOD SERUM
PRINCIPLE OF THE METHOD. Triacylglycerols (TAG) are
hydrolyzed by lipoproteinlipase to produce glycerol and free fatty acids.
The glycerol participates in a series of coupled enzymatic reactions, in
which glycerol kinase and glycerol phosphate oxidase are involved and
H2O2 is generated. The H2O2 reacts with chromogen (redused –
colorless) in the presence of peroxidase to form a chromogen dye
(oxidised). The intensity of color (pink) formed is proportional to the
TAG concentration and can be measured photometrically.
Step of test: take 3 test tubes: experimental, standard and control
COMPONENTS Experimental
Standard
Control sample
sample
sample
Blood serum
0,02 ml
Standard of
0,02 ml
TAG (2,5
mmol/l)
Water (dist)
0,02 ml
Working
2,0 ml
2,0 ml
2,0 ml
solution of
enzymes and
chromogen
Stir and incubate 10 min at 37ºC
On completion of incubation extinction of experimental and standard
samples are measured at PEC ( = 500 nm) in 5 mm thick cuvettes
versus the control sample
RESULT:
Е st =
; Е ex =
; Сst = 2,5 mmol/L
53
Calculation is performed according to the formula:
Сex =
Cst · Еex
Еst
=
mmol/L.
From the received result 0,11 mmol/L should be subtracted
(concentration of free glycerol in the blood).
CLINICAL AND DIAGNOSTIC VALUE.
Normal values of TAG in the blood are 0,40-1,54 mmol/L
(female), 0,45-1,82 mmol/L (male).
Reasons of hypertriacylglycerolemia:
- high-fat food intake,
- obesity, starvation, diabetes mellitus, cirrhosis, glicogenosis type
I, III and IV.
Hypotriacylglycerolemia is observed in lack of synthesis of
apoprotein B (apoB) in the liver.
CONCLUSION:
54
Date: __________
CLASS № 25
LABORATORY WORK № 1.
MEASUREMENT OF CHOLESTEROL CONCENTRATION IN
BLOOD SERUM BY ENZYMATIC METHOD
Principle of the method. Cholesterol esters are hydrolyzed to free
cholesterol by cholesterol ester hydrolase. The free cholesterol produced
is oxidized by cholesterol oxidase to cholest-4-en-3-one with the
simultaneous production of hydrogen peroxide. The H2O2 reacts with
chromogen (redused – colorless) in the presence of peroxidase to form
an oxidised chromogen dye. The intensity of color (pink) formed is
proportional to the cholesterol concentration and can be measured
photometrically.
Step of test: take 3 test tubes: experimental, standard and control.
COMPONENTS Experimental
Standard
Control sample
sample
sample
Blood serum
0,02 ml
Standard of
0,02 ml
cholesterol (5,17
mmol/L)
Water (dist)
0,02 ml
Working
2,0 ml
2,0 ml
2,0 ml
solution of
enzymes and
chromogen
Stir and incubate 10 min at 37ºC
On completion of incubation extinction of experimental and standard
samples are measured at PEC ( = 500 nm) in 5 mm thick cuvettes
versus the control sample
RESULT: Е st =
; Е ex =
55
; Сst = 5,17 mmol/L
Calculation is performed according to the formula:
Сex =
Cst · Еex
Еst
=
mmol/L.
CLINICAL AND DIAGNOSTIC VALUE.
Normal value of cholesterol in blood is 3,6-5,2 mmol/L. The
increased plasma cholesterol level (hypercholesterolemia) is observed
in atherosclerosis, diabetes mellitus, mechanic and parenchymatous
jaundice, nephritis, hypothyroidism. Decrease of plasma cholesterol
level (hypocholesterolemia) is observed in anemias, fasting,
tuberculosis, hyperthyroidism, cancerous cachexia, feverish states
CONCLUSION:
56
Date: ________________
CLASS № 26
LABORATORY WORK № 1.
MEASUREMENT OF LOW DENSITY LIPOPROTEINS (LDL) IN
THE BLOOD SERUM.
PRINCIPLE OF THE METHOD. The method is based on the
ability of LDL to sediment in the presence of calcium chloride and
heparin; the solution becomes turbid. Concentration of LDL in plasma is
determined by the degree of solution turbidity.
STEP OF TEST: take test tube
Experimental sample
0,2 ml
Blood serum
СаСl2 (0,27%)
2 ml
Stir and measure extinction (E1) at PEC
( = 630 nm) in 5 mm thick cuvettes
versus water
Put back mixture in to test tube
Heparin
0,04 ml
Stir, incubate 4 min (exactly!) and
measure extinction (E2) under the same
condition
RESULT:
Е1 =
Е2 =
;
.
Concentration of LDL = (Е2 – Е1) х 10 =
57
g/L
CLINICAL AND DIAGNOSTIC VALUE
Normal value of LDL in blood serum is 2-4 g/L.
The increased level of plasma LDL is observed in atherosclerosis,
diabetes
mellitus,
obesity,
hepatitis,
hypothyroidism
hyperlipoproteinemias (type II).
CONCLUSION:
58
Date______________
CLASS № 27
STUDENTS’ INDIVIDUAL WORK “METABOLISM OF LIPIDS”
Tasks for individual work:
1. Compose metabolic scheme of lipids metabolism.
2. Accentuate:
2.1. Diagnostic significant substrates (total lipids, triacylglycerols,
cholesterol, lipoproteins, ketone bodies).
2.2. Clinical and diagnostic enzymes (lipase, lipoproteinlipase).
2.3. Regulatory enzymes of β-oxidation, biosynthesis of fatty acids
and cholesterol, lipolisis.
2.4. Vitamin-dependent enzymes.
59
Date: _______________
CLASS № 29
DETERMINATION OF ALANINE AMINOTRANSFERASE
ACTIVITY IN THE BLOOD SERUM
Aminotransferases are enzymes catalyzing the transfer of amino
group from amino acids to keto acids with the formation of a new amino
acid and a new keto acid without intermediary release of ammonia.
Aminotrasferase contains derivative of vitamin В6 as a coenzyme. The
activity of aminotransefases is used to assess the amino acid metabolism
in different tissues.
PRINCIPLE OF THE METHOD: the enzyme alanine
aminotranferase (AlAT or ALT) catalyzes the reaction in which alanine
is transaminated with alpha-ketoglutate to form pyruvate and glutamate:
AlAT
Alanine
+
α-Ketoglutarate
В6
Glutamate
+
Pyruvate
Pyruvate reacts with 2,4-dinitrophenylhydrazine, and in the
presence of KOH, forms 2,4-dinitrophenylhydrazone pyruvate of brownand-red colour:
The intensity of the colour is measured colorimetrically. The
amount of pyruvate produced in the transamination reaction is
proportional to the activity of AlAT in the blood serum.
STEP OF TEST: two test-tubes are taken.
60
COMPONENTS
Substrate mixture
Physiological solution NaCl (0.85%)
Blood serum
TEST
CONTROL
SAMPLE
SAMPLE
0,25 ml
0,25 ml
-
0,05 ml
0,05 ml
-
Mixing. Water bath at 37оС for 30 min.
2,4-Dinitrophenylhydrazine
0,25 ml
0,25 ml
Mixing. Leave at a test-tube support to wait for 20 min at room
temperature.
NaOH
2,5 ml
2,5 ml
Mixing. Leave at a test-tube support to wait for 10 min at room
temperature.
PEC, λ= 500-530 nm, cuvette 1 cm; measurement against the
control sample.
RESULT:
Е=
;
According to the standard graph the activity of alanine
aminotransferase is ………….. mmol/ L / h.
CLINICAL AND DIAGNOSTIC VALUE.
The enzyme alanine aminotransferase is present in cells of many
tissues. But in maximal amounts it is in hepatocytes. Normally, AlAT
activity is low in the blood serum. In certain diseases accompanied by
cell destruction (necrosis) or the increased cell membrane permeability
(inflammation) AlAT releases from hepatocytes into the blood plasma.
61
Normal serum level of alanine aminotransferase activity is 0,1-0,68
mmol/L/h.
Increased activity of AlAT is observed in hepatitis, necrosis of
hepatocytes, obstructive jaundice.
CONCLUSION:
62
Date: _______________
CLASS № 30
DETERMINATION OF UREA IN THE BLOOD SERUM
Urea is the major product of ammonia detoxification in the body.
Urea is the end product of the amino acid (protein) metabolism. The
liver is the only site of urea synthesis. Urea is released from hepatocytes
into the blood and then is freely filtered by glomeruli into the urine.
Urea concentration in the blood and urine may serve as an indicator of
the liver and renal function.
PRINCIPLE OF THE METHOD: Urea reacts with diacetyl
monooxime in the presence of HCl to form FeCl3 and
thiosemicarbazide. The products form red-coloured complex. The
intensity of the colour is proportional to the concentration in the blood.
STEPS OF THE TEST: three test-tubes – test, standard and control
samples.
COMPONENTS
TEST SAMPLE
STANDARD
SAMPLE
CONTROL
SAMPLE
0,1 ml
-
-
-
-
0,1 ml
(16,65 mmol/L)
-
0,1 ml
-
Reagent mixture
2,0 ml
2,0 ml
2,0 ml
Blood serum
H2O
Standard solution of urea
Water bath 100о С for 5 min.
Cooling.
PEC, λ= 500-560 nm, cuvette 1 cm, measurements against the
control sample within 15 min.
63
RESULT:
Еtest =
;
Еstand =
;
Сstand = 16,65 mmol/L.
CALCULATION:
Еtest
Сtest =
· 16,65 =
mmol/L.
Еstand
CLINICAL AND DIAGNOSTIC VALUE.
The normal urea level in the blood serum is 2,5-8,3 mmol/L.
Urinary excretion of urea is 333-583 mmol/day.
Urea level is decreased in the blood and urine in hepatitis, cirrhosis
and genetic disorders of the urea cycle (as a result of impaired urea
synthesis). In nephritis and renal failure, when renal filtration is
impaired, urea is retained, and hence its concentration is increased in the
blood (synthesis of urea in the liver is normal), but is decreased in the
urine (renal filtration is impaired; therefore urea accumulates in the
blood but does not excrete in the urine).
CONCLUSION:
64
Date
CLASS № 31
METABOLISM OF NUCLEOTIDES
STUDENTS’ INDIVIDUALWORK «AMINO ACIDS
METABOLISM»
1. Compose metabolic scheme of amino acid metabolism.
2. Accentuate:
2.1. Sources of amino acids in tissues.
2.2. General pathways of amino acid metabolism.
2.3. Intracellular detoxification of ammonia.
2.4. Biosynthesis of urea.
2.5. Amino acids which breakdown leads to formation of acetylCoA.
2.6. Subsrates of citric acid cycle which are end products of amino
acids breakdown.
2.7. Normal levels of end products of amino acids and nucleotides
breakdown in the blood.
65
Date
CLASS № 32
WORK № 1. QUANTITATIVE DETERMINATION OF THE
BILIRUBIN IN THE BLOOD SERUM
When hemoglobin is destroyed in the body, heme is also degraded,
mainly in the reticuloendothelial cells of the liver, spleen, and bone
marrow. Indirect bilirubin (the end product of heme degradation)
formed in peripheral tissues is transported to the liver by plasma
albumin. In the liver indirect bilirubin is detoxified by its binding with
glucuronic acid.
In the blood serum present two types of bilirubin: indirect and
direct. Indirect (or “free”) bilirubin, which is unconjugated with
glucuronic acid, is easily adsorbed on blood plasma proteins. Therefore
in performing an analysis for bilirubin content in the blood, the proteins
complexed to bilirubin are preliminary precipitated with ethanol. After
that, bilirubin is allowed to react with diazo reagent (indirect reaction).
The form of bilirubin that would react without the addition of ethanol is
termed “direct”. The sum of these pigments gives “total” bilirubin.
Disturbances of bilirubin metabolism lead to development of
jaundice. Measurements of plasma total, conjugated and unconjugated
bilirubin help in differential diagnosis for jaundice of different types.
PRINCIPLE OF THE METHOD: diazo reagent interacts with
direct bilirubin with formation of pink dye. Indirect bilurubin is
insoluble in water and gives indirect reaction with diazo reagent, that is,
the reaction produces a specific colour after preliminary treatment.
STEPS OF TEST: 1. Determination of total bilirubin:
COMPONENTS
Control
Sample
1. Total reagent
1,0 ml
1,0 ml
2. NaCl, 0,9%
0,04 ml
3. Total nitrite-reagent
0,04 ml
4. Blood serum
Stir and incubate 5 min at 18°С
0,1 ml
Stir and incubate 20 min at 18°С
66
0,1 ml
PEC (546 nm), 5 mm thick cuvettes, sample versus the control,
Е1 =
2. Determination of direct bilirubin:
COMPONENTS
Control
Sample
1. Direct reagent
1,0 ml
1,0 ml
2. NaCl, 0,9%
0,04 ml
3. Direct nitrite-reagent
0,04 ml
Stir and incubate 2 min at 18°С
4. Blood serum
0,1 ml
0,1 ml
Stir and incubate 5 min at 18°С
PEC (546 nm), 5 mm thick cuvettes, sample versus the control,
Е2 =
RESULTS:
Сtotal bilirubin = Е1 · 222,3 μmol/L =
Сdirect bilirubin = Е2 · 222,3 μmol/L =
Сundirect bilirubin = Сtotal bilirubin – Сdirect bilirubin =
μmol/L
DIAGNOSTIC IMPORTANCE
Normal level of total bilirubin in blood serum 5,0-20,5 μmol/L;
conjugated bilirubin (direct) – 1,0-7,5 μmol/L; unconjugated bilirubin
(undirect) – 1,7-17,1 μmol/L.
The increased level of total bilirubin is observed in neonatal
jaundice, liver dysfunction (toxin- or inflammation-induced), blockage
of the bile ducts, hemolytic anemias.
In parenchymatous (hepatic) jaundice:
- in the blood increased content of direct and indirect bilirubin;
- in the urine present direct bilirubin and urobilinogen.
In obstructive (mechanic) jaundice:
- in the blood increased content of direct bilirubin;
- in the urine present direct bilirubin (choluria);
- the fecal level of stercobilin is decreased (acholic stools);
67
In hemolytic jaundice:
- in the blood increased content of indirect bilirubin;
- in the urine increased the level stercobilinogen;
- the fecal level of stercobilin is increased.
CONCLUSION:
68
Date
CLASS № 33
WORK № 1. DETERMINATION OF HEMOGLOBIN
CONCENTRATION IN THE BLOOD
The hemoglobin content and number of erythrocytes are sensitive
to different physiologic and pathologic factors, drug treatment. That’s
why the determination of hemoglobin concentration is important in
diagnosis.
PRINCIPLE OF THE METHOD: hemoglobin oxidized by
K3[Fe(CN)6] to hemiglobin. Hemiglobin react with acetoanhydrine with
formation of coloured hemiglobincyanide. Concentration of
hemiglobincyanide is detected photometrycally.
STEPS OF WORK: take test tube
COMPONENTS
Sample
Blood
0,02 ml
Reagent
5,0 ml
Stir and incubate10 min,
Read the extinction of samples versus the control (reagent) at
540 nm, cuvette 10 mm
RESULT:
Еs =
Calculation is performed according to the formula:
С = Еs х 392 =
g/L
69
DIAGNOSTIC IMPORTANCE
Normal concentration of hemoglobin in the blood is 115-145 g/L
(female), 130-160 g/L (male).
Increased
concentration
of
hemoglobin
is
observed
hypohydratation, tissue hypoxia, ulcer disease, in neonates within first
hours of life.
Decreased concentration of hemoglobin is observed in anemias,
hemoglobinopathies, deficiency of vitamins В12, Е and folic acid.
CONCLUSION:
WORK № 2. DETERMINATION OF CALCIUM
CONCENTRATION IN THE BLOOD SERUM
Calcium is a major structural component of osseous tissue, is
involved in the processes of blood clotting, muscular contraction,
neuromuscular excitation. It is also a second messenger of hormone
action.
PRINCIPLE OF THE METHOD: calcium in alkaline medium in
reaction with glioxalbis(2-hidroxianilin) (GBHA) gives dye. Intensity of
colour is directly depends on concentration of calcium.
70
STEPS OF WORK:
COMPONENTS
Control
Reagent
Н2О
Са, standard solution
Blood serum
1 ml
0,01 ml
-
Standard
1 ml
0,01 ml
-
Sample
1 ml
0,01 ml
Stir and incubate 5 min at 18°С.
Read the extinction of samples versus the control at λ = 574 nm, 5
mm thick cuvettes (colour is stable 5-12 min).
RESULT:
Еs =
Еst =
Еs
CALCULATIONS: Сs =
· 2,5 = mmol/L
Еst
71
DIAGNOSTIC IMPORTANCE
Normal concentration of calcium in the blood is 2,25-2,75 mmol/L.
Physiologic hypercalcemia is observed in neonates, in some
persons after mails. Pathologic hypercalcemia is observed in
hyperparathyrosis (calcium is washed out of the bones into the blood
plasma), acromegaly, myeloma disease, thyrotoxicosis, cancer with
bones destruction, cancer of lung, kidney, pancreas, liver.
Hypocalcemia is observed in deficiency of vitamin D,
hypoparathyrosis,
nephroses,
chronic
renal
insufficiency,
glomerulonephritis, cirrhosis, acute pancreatitis.
CONCLUSION:
72
Date
CLASS № 34
BIOCHEMICAL ANALYSIS OF THE URINE
The compounds that occur in the normal urine at very low
concentration escaping their determination by routine analytical
techniques are called “pathologic components of urine”. These
compounds are proteins, glucose, ketone bodies, bile and blood
pigments. Determination of these compounds is used for diagnosis and
treatment watch.
1. QUALITATIVE REACTION ON PROTEIN
PRINCIPLE OF THE METHOD: denaturation of protein by nitric
acid (or sulphsalicilic acid)
STEPS OF WORK:
1) take 2 test tubes, label them and place in a test tube rack,
2) add to the each test tube the solutions:
COMPONENTS
Control
Sample
URINE
1,0 ml
Н2О
1,0 ml
Sulphosalicilic acid 20%
(or НNО3 concentr.)
3 drops
3 drops
RESULT:
CLINICAL AND DIAGNOSTIC VALUE
In the urine protein may occur in nephritis, cystitis, hypertension,
sometimes in pregnancy, nephroses.
CONCLUSION:
73
2. QUANTITATIVE DETERMINATION OF PROTEIN IN THE URINE
PRINCIPLE OF THE METHOD: the method based on the
Heller’s test with concentrated nitric acid.
STEPS OF WORK:
1) take 1 ml of HNO3 to 4 test tubes;
2) in other 2 test tubes prepare urine solutions as described in the table
COMPONENTS
sample 1
sample 2
sample 3
sample 4
Dissolution
-
1 : 10
1 : 20
1 :30
Urine
1,0 ml
0,1 ml
0,1 ml
0,1 ml
Н2О
0,9 ml
1,9 ml
2,9 ml
Add with pipette dissolved urine (1 ml) on nitric acid
HNO3 concetr.
1,0 ml
1,0 ml
1,0 ml
1,0 ml
RESULT:
CONCLUSION:
74
3. QUANTITATIVE DETERMINATION OF GLUCOSE IN THE URINE
PRINCIPLE OF THE METHOD: method is based on ability of
glucose to reduce CuOH in alkaline medium to Cu2O (red-coloured
sediment).
STEPS OF WORK:
COMPONENTS
Sample
Hainesse reagent
9 drops
Urine
2 drops
Stir and heat
RESULT:
CLINICAL AND DIAGNOSTIC VALUE
The presence of glucose in the urine (glucosuria) is observed in
diabetes mellitus, kidney damage, chlorophorm poisoning.
CONCLUSION:
4. QUALITATIVE REACTION ON BLOOD PIGMENTS
PRINCIPLE OF THE METHOD: test is based on the oxidation of
bezidine by oxygen which formed in reaction of hydrogen peroxide
degradation catalyzed by hemoglobin.
STEPS OF TEST:
- take 20 drops of urine to the test tube, boil it then cool;
- to the urine add 20 drops of bezidine solution and 2 drops of
hydrogen peroxide.
The solution obtains blue or green colour in presence of blood pigments.
RESULT:
CONCLUSION:
75
5. URINE STRIP EXPRESS TESTS
76
Date
CLASS № 35
WORK № 1.QUANTITATIVE MEASUREMENT OF PROTEIN IN
THE LIQUOR
PRINCIPLE OF THE METHOD. PROTEIN + NaOH/CuSO4 =
violet colour, the intensity of the color produced is proportional to the
concentration of protein present in the reaction system and detected
photometrically.
STEPS OF WORK:
1) take 2 test tubes, label them and place in a test tube rack.
2) add to the each test tube the solutions:
COMPONENTS
Control
Sample
Gornal’s reagent
4,0 ml
4,0 ml
liquor
0,1 ml
NaCl 0,9%
0,1 ml
Stir and allow incubate 20 min.
Read the extinction for sample versus the control at 540 nm, cuvette 10 mm
RESULT:
Esample =
Find out the protein concentration in the sample from the
calibration graph
Csample =
g/L
DIAGNOSTIC IMPORTANCE
Normal level of total protein in liquor is 0,22-0,33 g/L.
An
increased
content
of
protein
in
the
(hyperproteinrhachia) is observed in meningitis, brain tumors.
Hypoproteinrhachia is observed in hydrocephaly,
hypersecretion, intracranial hypertension.
77
liquor
liquor
CONCLUSION:
78
NORMAL CONCENTRATIONS
OF SOME LABORATORY TESTED SUBSTRATES
AND ENZYMES
BLOOD SERUM (PLASMA)
1. Alanine aminotransferase (AlAT) 0,1-0,68 mmol/h·L
2. Albumins 40-50 g/L
3. Amylase 16-30 g/h·L
4. Aspartate aminotransferase (AsAT) 0,1-0,45 mmol/h·L
5. Calcium 2,25-2,75 mmol/L
6. Chloride 95-110 mmol/L
7. Creatinin 53-115 µmol/L
8. Fibrinogen 2-4 g/L
9. Globulins 20-30 g/L
10.Glucose 3,3-6,4 mmol/L
11.Hemoglobin 115-145 g/L (female); 130-160 g/L (male)
12. Iron 8,8-31,0 µmol/L
13. Potassium 3,2-5,6 mmol/L
14. Sodium 130-155 mmol/L
15.Total bilirubin 5,0-20,5 µmol/L
16.Total protein 65-85 g/L
17. Triacylglycerols 0,4-1,54 mmol/L (female); 0,45-1,82 mmol/L (male)
18. Urea 2,50-8,3 mmol/L
19. Uric acid 140-340 µmol/L (female); 200-415 µmol/L (male)
20. Cholesterol 3,6-5,2 mmol/L
URINE
1. Amilase 28-160 g/h·L
2. Urea 333-583 mmol/day
3. Uric acid 1,6-6,4 mmol/day
CEREBROSPINAL FLUID
1. Chloride 120-130 mmol/L
2. Glucose 2,5-3,89 mmol/L
3. Protein 0,22-0,33 g/L
79
Учебное издание
Петушок Наталья Эдуардовна
Курбат Михаил Николаевич
Масловская Алла Анатольевна
БИОЛОГИЧЕСКАЯ ХИМИЯ
Практикум для студентов факультета иностранных учащихся
(английский язык обучения)
3-е издание
Под общей редакцией профессора В.В. Лелевича
BIOCHEMISTRY
Workbook for the medical faculty for internatiomal students
(in English)
Edited by professor V.V. Lelevich
Ответственный за выпуск В.В. Воробьев
Компьютерная верстка И.И. Прецкайло
Корректор Е.А. Дабкене
Подписано в печать 05.08.2015.
Формат 60х84/16. Бумага офсетная.
Гарнитура Таймс. Ризография.
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Издатель и полиграфическое исполнение
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