Experiment 9
... Theory: Majority of diluted solutions are not stable systems and tend to change their concentration within time. That is why chemicals are usually stored as solids or concentrated solutions dilute when necessary. Hydrochloric acid is an aqueous solution of a gaseous hydrogen chloride HCl. With the c ...
... Theory: Majority of diluted solutions are not stable systems and tend to change their concentration within time. That is why chemicals are usually stored as solids or concentrated solutions dilute when necessary. Hydrochloric acid is an aqueous solution of a gaseous hydrogen chloride HCl. With the c ...
BONUS: Which line in the above graph represents G for the reaction
... which change will cause an increase in the pressure of CO2(g) when equilibrium is re-established? (A) ...
... which change will cause an increase in the pressure of CO2(g) when equilibrium is re-established? (A) ...
Preface from the Textbook - McGraw Hill Higher Education
... How Principles and Chemistry Are the Same Principles of General Chemistry was created from its parent text, Chemistry: The Molecular Nature of Matter and Change, when four expert chemistry teachers—three consulting professors and the author—joined to distill the concepts and skills at the heart of g ...
... How Principles and Chemistry Are the Same Principles of General Chemistry was created from its parent text, Chemistry: The Molecular Nature of Matter and Change, when four expert chemistry teachers—three consulting professors and the author—joined to distill the concepts and skills at the heart of g ...
final review cp2 1213 by chapter
... 6. Calculate the concentration of a solution (in molarity) that is prepared by dissolving 58.5 g NaCl in 100 mL water. ...
... 6. Calculate the concentration of a solution (in molarity) that is prepared by dissolving 58.5 g NaCl in 100 mL water. ...
Basic Chemical Concepts I
... The gaseous NH3 is driven out of the reaction vessel into a second flask where it is neutralized with an excess of HCl(aq). Then, the unreacted HCl can be titrated with NaOH. In this way a quantitative determination of NO3– can be achieved. A 25.00 mL sample of nitrate solution was treated with zinc ...
... The gaseous NH3 is driven out of the reaction vessel into a second flask where it is neutralized with an excess of HCl(aq). Then, the unreacted HCl can be titrated with NaOH. In this way a quantitative determination of NO3– can be achieved. A 25.00 mL sample of nitrate solution was treated with zinc ...
A Classification of AP Chemistry Reactions
... The second type of redox that involve oxygen-containing compounds such as nitrates, sulfates, permanganates, dichromates, etc. First of all, since these are redox reactions, one thing must be oxidized and another must be reduced. Jotting down oxidation numbers can be helpful. Second, almost all of t ...
... The second type of redox that involve oxygen-containing compounds such as nitrates, sulfates, permanganates, dichromates, etc. First of all, since these are redox reactions, one thing must be oxidized and another must be reduced. Jotting down oxidation numbers can be helpful. Second, almost all of t ...
Basic Chemical Concepts I
... The gaseous NH3 is driven out of the reaction vessel into a second flask where it is neutralized with an excess of HCl(aq). Then, the unreacted HCl can be titrated with NaOH. In this way a quantitative determination of NO3– can be achieved. A 25.00 mL sample of nitrate solution was treated with zinc ...
... The gaseous NH3 is driven out of the reaction vessel into a second flask where it is neutralized with an excess of HCl(aq). Then, the unreacted HCl can be titrated with NaOH. In this way a quantitative determination of NO3– can be achieved. A 25.00 mL sample of nitrate solution was treated with zinc ...
Chemistry
... in a liquid – Henry’s law, graph of partial pressure of a gas vs its mole fraction in solution, effect of pressure, temperature, applications of Henry’s law. Solution of liquid in liquid – Raoult’s law- statement, mathematical expression, numerical problems, ideal solution – characteristics, graph, ...
... in a liquid – Henry’s law, graph of partial pressure of a gas vs its mole fraction in solution, effect of pressure, temperature, applications of Henry’s law. Solution of liquid in liquid – Raoult’s law- statement, mathematical expression, numerical problems, ideal solution – characteristics, graph, ...
apch04 test review_ans
... 2 AgNO3 (aq) + CaCl2 (aq) 2 AgCl (s) + Ca(NO3)2 (aq) Need to calculate moles of CaCl2 to determine the molarity (moles CaCl2 per L solution). Use stoichiometry mass to mole calculation. 0.9256 g AgCl ...
... 2 AgNO3 (aq) + CaCl2 (aq) 2 AgCl (s) + Ca(NO3)2 (aq) Need to calculate moles of CaCl2 to determine the molarity (moles CaCl2 per L solution). Use stoichiometry mass to mole calculation. 0.9256 g AgCl ...
Chromatographic Enrichment of Lithium Isotopes by Hydrous
... the ion exchanger phase. Oi et al.7 investigated the lithium isotope effect in aqueous ion exchange systems by cation exchange chromatography. They obtained the value of the separation factor of 1.00089-1.00171 at 25 oC. Kim et al. 8 also investigated the separation of lithium isotopes with 1,7,13-t ...
... the ion exchanger phase. Oi et al.7 investigated the lithium isotope effect in aqueous ion exchange systems by cation exchange chromatography. They obtained the value of the separation factor of 1.00089-1.00171 at 25 oC. Kim et al. 8 also investigated the separation of lithium isotopes with 1,7,13-t ...
CHEM 102 FINAL EXAM WINTER 07-08
... 23. In a 1.2 M solution of HClO4, a strong acid, [H3O+] = _________, and [OH-] = _________. a. 1.0 × 10-7 M; 1.0 × 10-7 M b. 8.3 × 10-15 M; 1.2 M c. 1.2 M; 8.3 × 10-15 M d. 1.2 M; 1.2 M ANSWER: c 24. The value of the ionization constant for a weak acid HA is 4.2 × 10-7. What is the pH of a 0.35 M s ...
... 23. In a 1.2 M solution of HClO4, a strong acid, [H3O+] = _________, and [OH-] = _________. a. 1.0 × 10-7 M; 1.0 × 10-7 M b. 8.3 × 10-15 M; 1.2 M c. 1.2 M; 8.3 × 10-15 M d. 1.2 M; 1.2 M ANSWER: c 24. The value of the ionization constant for a weak acid HA is 4.2 × 10-7. What is the pH of a 0.35 M s ...
Chapter 1 - TamAPChemistryHart
... What types of compounds can act as Lewis acids? • Lewis acids generally have an incomplete octet (e.g., BF3). Consider the reaction between NH3 and BF3. This reaction occurs because BF3 has a vacant orbital in its valence shell. It therefore acts as an electron-pair acceptor (a Lewis acid) toward NH ...
... What types of compounds can act as Lewis acids? • Lewis acids generally have an incomplete octet (e.g., BF3). Consider the reaction between NH3 and BF3. This reaction occurs because BF3 has a vacant orbital in its valence shell. It therefore acts as an electron-pair acceptor (a Lewis acid) toward NH ...
Condensed Phase Ethanol Conversion to Higher Alcohols Tyler L
... The Peng-Robinson-Wong-Sandler (PRWS), predictive Soave-Redlich-Kwong (PSRK), and Schwartzentruber--Renon (SR-Polar) equations of state were chosen for initial model screening. These equations of state are known for accurate prediction of vapor pressures because they incorporate the acentric (ω) fac ...
... The Peng-Robinson-Wong-Sandler (PRWS), predictive Soave-Redlich-Kwong (PSRK), and Schwartzentruber--Renon (SR-Polar) equations of state were chosen for initial model screening. These equations of state are known for accurate prediction of vapor pressures because they incorporate the acentric (ω) fac ...
examination review
... It is worth remembering at this time that acidic solutions are also created by certain substances that react with water to form H+(aq)ions. You have already learned that non-metal oxides react with water to form acidic solutions. For example: SO2(g) + H2O(l) Æ SO32-(aq) + 2H+(aq) ...
... It is worth remembering at this time that acidic solutions are also created by certain substances that react with water to form H+(aq)ions. You have already learned that non-metal oxides react with water to form acidic solutions. For example: SO2(g) + H2O(l) Æ SO32-(aq) + 2H+(aq) ...
Liquid–liquid extraction
Liquid–liquid extraction (LLE) consists in transferring one (or more) solute(s) contained in a feed solution to another immiscible liquid (solvent). The solvent that is enriched in solute(s) is called extract. The feed solution that is depleted in solute(s) is called raffinate.Liquid–liquid extraction also known as solvent extraction and partitioning, is a method to separate compounds based on their relative solubilities in two different immiscible liquids, usually water and an organic solvent. It is an extraction of a substance from one liquid into another liquid phase. Liquid–liquid extraction is a basic technique in chemical laboratories, where it is performed using a variety of apparatus, from separatory funnels to countercurrent distribution equipment. This type of process is commonly performed after a chemical reaction as part of the work-up.The term partitioning is commonly used to refer to the underlying chemical and physical processes involved in liquid–liquid extraction, but on another reading may be fully synonymous with it. The term solvent extraction can also refer to the separation of a substance from a mixture by preferentially dissolving that substance in a suitable solvent. In that case, a soluble compound is separated from an insoluble compound or a complex matrix.Solvent extraction is used in nuclear reprocessing, ore processing, the production of fine organic compounds, the processing of perfumes, the production of vegetable oils and biodiesel, and other industries.Liquid–liquid extraction is possible in non-aqueous systems: In a system consisting of a molten metal in contact with molten salts, metals can be extracted from one phase to the other. This is related to a mercury electrode where a metal can be reduced, the metal will often then dissolve in the mercury to form an amalgam that modifies its electrochemistry greatly. For example, it is possible for sodium cations to be reduced at a mercury cathode to form sodium amalgam, while at an inert electrode (such as platinum) the sodium cations are not reduced. Instead, water is reduced to hydrogen. A detergent or fine solid can be used to stabilize an emulsion, or third phase.