Bacterial species
... -----------------------------------------------------------------------------------------------------------------This exam consists of 40 multiple choice questions worth 2.5 points each. On the separate testing form, please fill-in the single best choice for each question. Be sure to fill-out your s ...
... -----------------------------------------------------------------------------------------------------------------This exam consists of 40 multiple choice questions worth 2.5 points each. On the separate testing form, please fill-in the single best choice for each question. Be sure to fill-out your s ...
Genomic_DNA - McMaster Chemistry
... Create new comment This Technical Tip was first published in Trends in Genetics (1995) 11, 217-218 Many Gram-positive bacteria are used in industrial processes (e.g. Bacillus subtilis, lactococci or streptomyces), and the genetic manipulation of these organisms requires the preparation and analysis ...
... Create new comment This Technical Tip was first published in Trends in Genetics (1995) 11, 217-218 Many Gram-positive bacteria are used in industrial processes (e.g. Bacillus subtilis, lactococci or streptomyces), and the genetic manipulation of these organisms requires the preparation and analysis ...
Class Notes 1 - The University of Texas at Dallas
... – Hydrogen bonds • Within macromolecules such as proteins and nucleic acids, it can exist between two parts of the same molecule, and figures as an important constraint on such molecules' overall shape. ...
... – Hydrogen bonds • Within macromolecules such as proteins and nucleic acids, it can exist between two parts of the same molecule, and figures as an important constraint on such molecules' overall shape. ...
Genetic Engineering
... the required gene is cut out of the DNA strand by an endonuclease (enzyme) - this enzyme cuts the DNA at specific points - it leaves “sticky-ends” – which allow other genes to rejoin the same restriction enzyme (endonuclease) is used to cut the bacterial plasmid (leaving the same sticky ends) the re ...
... the required gene is cut out of the DNA strand by an endonuclease (enzyme) - this enzyme cuts the DNA at specific points - it leaves “sticky-ends” – which allow other genes to rejoin the same restriction enzyme (endonuclease) is used to cut the bacterial plasmid (leaving the same sticky ends) the re ...
Ch 020 DNA Technology II
... Gel electrophoresis: separates nucleic acids or proteins on the basis of size or electrical charge creating DNA bands of the same length ...
... Gel electrophoresis: separates nucleic acids or proteins on the basis of size or electrical charge creating DNA bands of the same length ...
The Human Genome
... • Cutting DNA into random fragments and then determining sequence of bases in each fragment. • Computers put together ...
... • Cutting DNA into random fragments and then determining sequence of bases in each fragment. • Computers put together ...
HONORS BIOLOGY FINAL EXAM REVIEW PACKET AND FORMAT
... DNA REPLICATIONOCCURS AT REPLICATION FORKS, USES DNA POLYMERASE WHICH CAN ONLY WORK IN ONE DIRECTION, NITROGEN BASES ARE ADDED AT REPLICATION FORKS, ERRORS CAN BE CORRECTED USING DNA LIGASE AND PROOFREADER ENZYMES, THE DNA STRAND IS NOT DISSEMBLED WHEN CORRECTING FOR ERRORS MDOUBLE CHROMOSOMES ARE ...
... DNA REPLICATIONOCCURS AT REPLICATION FORKS, USES DNA POLYMERASE WHICH CAN ONLY WORK IN ONE DIRECTION, NITROGEN BASES ARE ADDED AT REPLICATION FORKS, ERRORS CAN BE CORRECTED USING DNA LIGASE AND PROOFREADER ENZYMES, THE DNA STRAND IS NOT DISSEMBLED WHEN CORRECTING FOR ERRORS MDOUBLE CHROMOSOMES ARE ...
Macromolecules - Lisle CUSD 202
... monomers are linked together to form polymers dehydration synthesis (condensation) broken apart via hydrolysis ...
... monomers are linked together to form polymers dehydration synthesis (condensation) broken apart via hydrolysis ...
Acids and Bases
... You need not know this but for future reference: pH = -log [H+] E.g. suppose that your concentration was 0.010 , enter this in your calculator and press the log button, change the sign, your answer should be 2.0 ...
... You need not know this but for future reference: pH = -log [H+] E.g. suppose that your concentration was 0.010 , enter this in your calculator and press the log button, change the sign, your answer should be 2.0 ...
RNA
... • during the RNA processing is created messenger RNA – mRNA • snRNPs = spliceosome • Regulation ...
... • during the RNA processing is created messenger RNA – mRNA • snRNPs = spliceosome • Regulation ...
Unit C Outline
... Biology 12 backbone -right-handed double helix - name the 4 bases of RNA and describe the structure of RNA using: -nucleotide (ribose sugar) -sugar-phosphate backbone -linear, singlestranded Core C6. I can compare the following pairs: saturated and unsaturated fats, DNA and RNA ...
... Biology 12 backbone -right-handed double helix - name the 4 bases of RNA and describe the structure of RNA using: -nucleotide (ribose sugar) -sugar-phosphate backbone -linear, singlestranded Core C6. I can compare the following pairs: saturated and unsaturated fats, DNA and RNA ...
genetic engineering
... First, the DNA is extracted/ removed from an opened cell. Restriction enzymes are then used to cut the DNA at a specific section of nucleotides. The fragments are then separated and analyzed using gel electrophoresis (used to compare genomes of different organisms) this way scientists can locate & ...
... First, the DNA is extracted/ removed from an opened cell. Restriction enzymes are then used to cut the DNA at a specific section of nucleotides. The fragments are then separated and analyzed using gel electrophoresis (used to compare genomes of different organisms) this way scientists can locate & ...
DNA Fingerprinting (RFLP Analysis) Introduction DNA fingerprinting
... We will use this procedure in lab to identify whether a sample of DNA found at a crime scene belongs to one of three suspects. The technique has a variety of other uses such as being used to identify whether individuals carry genes for certain genetic diseases. ...
... We will use this procedure in lab to identify whether a sample of DNA found at a crime scene belongs to one of three suspects. The technique has a variety of other uses such as being used to identify whether individuals carry genes for certain genetic diseases. ...
Decoding mRNA
... acid tyrosine. 8. Write the name of the amino acid that corresponds to each mRNA code. The first one has been done for you. mRNA Code ...
... acid tyrosine. 8. Write the name of the amino acid that corresponds to each mRNA code. The first one has been done for you. mRNA Code ...
Ch. 5 Pppt
... of organic compounds and hydrolysis in the digestion of organic compounds. How to recognize the 4 biologically important organic compounds (carbs, lipids, proteins, nucleic acids) by their structural formulas. The cellular functions of all four organic compounds. The 4 structural levels of proteins ...
... of organic compounds and hydrolysis in the digestion of organic compounds. How to recognize the 4 biologically important organic compounds (carbs, lipids, proteins, nucleic acids) by their structural formulas. The cellular functions of all four organic compounds. The 4 structural levels of proteins ...
BIOL 222 - philipdarrenjones.com
... replication fork, and the lagging strand is synthesized in the opposite direction B) the leading strand is synthesized by adding nucleotides to the 3' end of the growing strand, and the lagging strand is synthesized by adding nucleotides to the 5' end C) the lagging strand is synthesized continuousl ...
... replication fork, and the lagging strand is synthesized in the opposite direction B) the leading strand is synthesized by adding nucleotides to the 3' end of the growing strand, and the lagging strand is synthesized by adding nucleotides to the 5' end C) the lagging strand is synthesized continuousl ...
Unit 1 Topic 2: Genes and Health
... condensation reactions) and describe how complimentary base pairing and the hydrogen bonding between two complimentary strands are involved in the formation of the DNA double helix. 11.Describe DNA replication (including the role of DNA polymerase), and explain how Meselson and Stahl’s classic exper ...
... condensation reactions) and describe how complimentary base pairing and the hydrogen bonding between two complimentary strands are involved in the formation of the DNA double helix. 11.Describe DNA replication (including the role of DNA polymerase), and explain how Meselson and Stahl’s classic exper ...
File - Intervention
... gene. Each organism is genetically different because of the sequence of their bases. Deoxyribonucleic acid (DNA) is the master copy of an organism’s genetic information. The information in DNA contains instructions used to form nearly all of an organism’s proteins. DNA is the blueprint for how an ...
... gene. Each organism is genetically different because of the sequence of their bases. Deoxyribonucleic acid (DNA) is the master copy of an organism’s genetic information. The information in DNA contains instructions used to form nearly all of an organism’s proteins. DNA is the blueprint for how an ...
DNA Template for Protein Transcription Directions: 1) Use the DNA
... DNA Template for Protein Transcription Directions: 1) Use the DNA template (above) to find the corresponding piece of mRNA. (Remember you have to identify the starting point in the strand first. The start CODON is?) 2) Once you have identified the starting point, transcribe the mRNA for that gene se ...
... DNA Template for Protein Transcription Directions: 1) Use the DNA template (above) to find the corresponding piece of mRNA. (Remember you have to identify the starting point in the strand first. The start CODON is?) 2) Once you have identified the starting point, transcribe the mRNA for that gene se ...
Important Experiments
... a. The DNA must stay in the 41. _______________in order to stay protected. This is why transcription must take place. b. RNA copies of the DNA are sent out of the nucleus to assemble proteins. c. The numbers of the following steps match the numbers in the diagram: 1. The DNA double Helix unwinds. 2. ...
... a. The DNA must stay in the 41. _______________in order to stay protected. This is why transcription must take place. b. RNA copies of the DNA are sent out of the nucleus to assemble proteins. c. The numbers of the following steps match the numbers in the diagram: 1. The DNA double Helix unwinds. 2. ...
lecture5
... One of the most frequent is the loss of an amino group ("deamination") — resulting, for example, in a C being converted to a U. ...
... One of the most frequent is the loss of an amino group ("deamination") — resulting, for example, in a C being converted to a U. ...
The Nobel Prize in Chemistry 1948 Arne Tiselius
... TESS The Nobel Prize in Chemistry 1948 Arne Tiselius ...
... TESS The Nobel Prize in Chemistry 1948 Arne Tiselius ...
Chapters 10a and 11 PowerPoint
... The sequence of nitrogenous bases on one strand of a DNA molecule is GGCAGTTCATGC. What would be the sequence of bases on the complementary strand? In general, describe the steps that occur during DNA replication. ...
... The sequence of nitrogenous bases on one strand of a DNA molecule is GGCAGTTCATGC. What would be the sequence of bases on the complementary strand? In general, describe the steps that occur during DNA replication. ...
Nucleic acid analogue
Nucleic acid analogues are compounds which are analogous (structurally similar) to naturally occurring RNA and DNA, used in medicine and in molecular biology research.Nucleic acids are chains of nucleotides, which are composed of three parts: a phosphate backbone, a pucker-shaped pentose sugar, either ribose or deoxyribose, and one of four nucleobases.An analogue may have any of these altered. Typically the analogue nucleobases confer, among other things, different base pairing and base stacking properties. Examples include universal bases, which can pair with all four canonical bases, and phosphate-sugar backbone analogues such as PNA, which affect the properties of the chain (PNA can even form a triple helix).Nucleic acid analogues are also called Xeno Nucleic Acid and represent one of the main pillars of xenobiology, the design of new-to-nature forms of life based on alternative biochemistries.Artificial nucleic acids include peptide nucleic acid (PNA), Morpholino and locked nucleic acid (LNA), as well as glycol nucleic acid (GNA) and threose nucleic acid (TNA). Each of these is distinguished from naturally occurring DNA or RNA by changes to the backbone of the molecule.In May 2014, researchers announced that they had successfully introduced two new artificial nucleotides into bacterial DNA, and by including individual artificial nucleotides in the culture media, were able to passage the bacteria 24 times; they did not create mRNA or proteins able to use the artificial nucleotides. The artificial nucleotides featured 2 fused aromatic rings.