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Statistical implications of distributed lag models Suppose we have: Yt Yt 1 ut Yt ut ut 1 2ut 2 3ut 3 ... i ut i i 0 This is the autoregressive model in moving average form. Is OLS consistent? Yt 1Yt Yt 1 Yt 1 ut Yt 1ut ˆ 2 2 2 Y Y Y t 1 t 1 t 1 plim ˆ if 1 plim Yt 1ut 0 T 1 plim Yt 21 Y2 0 T These conditions are not obviously satisfied. If u is itself serially correlated then the first will fail. The second will fail if β ≥1 as the plim will not converge. Example: Yt Yt 1 ut 1 1 ut ut 1 t 1 1 We have Yt ut ut 1 2ut 2 3ut 3 .... utYt 1 ut 1 t ut 1 ut 2 2ut 3 3ut 4 .... and taking expectations yields 2 u E utYt 1 u2 2 u2 3 2 u2 .... 1 Therefore it follows that if ρ>0 then the OLS estimator of β will be biased upwards. It is also possible to show that the estimate of ρ based on the OLS residuals will be biased downwards when ρ>0 . Finally, we can show that the Durbin-Watson statistic will be biased towards 2 when ρ>0. Given these results we should not rely on the Durbin-Watson test when the regression equation contains lagged endogenous variables. We should use an alternative test such as Durbin’s h test or the Breusch-Godfrey test. We have seen that the AR(1) model can be written as an infinite moving average. If the u’s have the standard Gaussian properties then: Yt i ut i i 0 2 u E Yt 2 2i u2 1 2 i 0 If the variance of Y is to be positive and finite we therefore require 1 If this condition is not satisfied then we say that the series contains a unit root or is non-stationary. If a series is non-stationary then: 1 T 2 Yt 1 as T t 1 T Therefore the probability limit of the OLS estimator may equal the true value even if cov(Yt-1, ut) ≠ 0. In these circumstances we say that the OLS estimator is superconsistent. However, non-stationarity creates many problems for statistical analysis in that the distributions we have derived for all the standard test statistics assume that the series are stationary. The Lag Operator When we have models with lags then it is often convenient to write them using the Lag Operator. LYt Yt 1 or Lk Yt Yt k Therefore if we have a model of the form: Yt 1 X t 2 X t 1 3Yt 1 ut This can be written as: Yt 1 2 L X t 3 LYt ut The lag operator makes it easier to manipulate equations of this type because the usual rules of algebra apply. For example: Yt 1 3 L 1 2 L X t ut 1 2 L 1 Yt Xt ut 1 3 L 1 3 L The lag polynomial for X determines the pattern of the distributed lag effect of a change in X on Y. A general result is that almost any shape of distributed lag response can be modelled as the ratio of two low order lag polynomials.