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§ 5.2 More Work with Exponents and Scientific Notation Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 1 The Power Rule The Power Rule and Power of a Product or Quotient Rule for Exponents If a and b are real numbers and m and n are integers, then (am)n = amn Power Rule (ab)n = an · bn Power of a Product a b n an n b Power of a Quotient Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 2 The Power Rule Example: Simplify each of the following expressions. (23)3 = 23·3 = 29 = 512 (x4)2 = x4·2 = x8 (5x2y)3 = 53 · (x2)3 · y3 = 125x6 y3 4 p p 3 3 3 r 3r 2 2 4 4 p 3 r 2 4 4 3 4 p8 12 81r Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 3 Summary of Exponent Rules If m and n are integers and a and b are real numbers, then: Product Rule for exponents am · an = am+n Power Rule for exponents (am)n = amn Power of a Product (ab)n = an · bn n an a Power of a Quotient n , b 0 b b Quotient Rule for exponents am mn a , a0 n a Zero exponent a0 = 1, a 0 Negative exponent a n 1 , a0 n a Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 4 Simplifying Expressions Simplify by writing the following expression with positive exponents or calculating. 3 ab 4 7 3 3 a b 2 3 2 3 3 2 4 3 ab 7 ab 3 a b 3 a b 2 3 2 Power of a quotient rule 4 6 2 2 2 4 2 3 2 7 2 2 3 2 Power of a product rule 8 3a b a 6( 14) 26 48 4 8 8 8 14 6 3 a b 3 a b 4 8 3a b 3b Product rule a8 81b 4 Power rule Quotient rule Negative exponents Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 5 Operations with Scientific Notation Multiplying and dividing with numbers written in scientific notation involves using properties of exponents. Example Perform the following operations. 1) (7.3 102)(8.1 105) = (7.3 · 8.1) (102 · 105) = 59.13 103 = 59,130 1.2 10 4 1.2 10 4 5 0 . 3 10 0.000003 2) 9 9 4 10 4 10 Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 6 Operations with Scientific Notation Multiplying and dividing with numbers written in scientific notation involves using properties of exponents. Example Perform the following operations. 1) (7.3 102)(8.1 105) = (7.3 · 8.1) (10-2 ·105) = 59.13 103 = 59,130 1.2 10 4 1.2 10 4 5 0 . 3 10 0.000003 2) 9 9 4 10 4 10 Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 7 § 5.3 Polynomials and Polynomial Functions Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 8 Polynomial Vocabulary Term – a number or a product of a number and variables raised to powers Coefficient – numerical factor of a term Constant – term which is only a number Polynomial is a sum of terms involving variables raised to a whole number exponent, with no variables appearing in any denominator. Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 9 Polynomial Vocabulary In the polynomial 7x5 + x2y2 – 4xy + 7 There are 4 terms: 7x5, x2y2, -4xy and 7. The coefficient of term 7x5 is 7, of term x2y2 is 1, of term –4xy is –4 and of term 7 is 7. 7 is a constant term. Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 10 Types of Polynomials Monomial is a polynomial with one term. Binomial is a polynomial with two terms. Trinomial is a polynomial with three terms. Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 11 Degrees Degree of a term To find the degree, take the sum of the exponents on the variables contained in the term. Degree of a constant is 0. Degree of the term 5a4b3c is 8 (remember that c can be written as c1). Degree of a polynomial To find the degree, take the largest degree of any term of the polynomial. Degree of 9x3 – 4x2 + 7 is 3. Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 12 Combining Like Terms Like terms are terms that contain exactly the same variables raised to exactly the same powers. Warning! Only like terms can be combined through addition and subtraction. Example: Combine like terms to simplify. x2y + xy – y + 10x2y – 2y + xy = x2y + 10x2y + xy + xy – y – 2y (Like terms are grouped together) = (1 + 10)x2y + (1 + 1)xy + (– 1 – 2)y = 11x2y + 2xy – 3y Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 13 Adding Polynomials Adding Polynomials To add polynomials, combine all the like terms. Example: Add. (3x – 8) + (4x2 – 3x +3) = 3x – 8 + 4x2 – 3x + 3 = 4x2 + 3x – 3x – 8 + 3 = 4x2 – 5 Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 14 Subtracting Polynomials Subtracting Polynomials To subtract polynomials, add its opposite. Example: Subtract. 4 – (– y – 4) = 4 + y + 4 = y + 4 + 4 = y + 8 (– a2 + 1) – (a2 – 3) + (5a2 – 6a + 7) = – a2 + 1 – a2 + 3 + 5a2 – 6a + 7 = – a2 – a2 + 5a2 – 6a + 1 + 3 + 7 = 3a2 – 6a + 11 Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 15 Adding and Subtracting Polynomials In the previous examples, after discarding the parentheses, we would rearrange the terms so that like terms were next to each other in the expression. You can also use a vertical format in arranging your problem, so that like terms are aligned with each other vertically. Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 16 § 5.4 Multiplying Polynomials Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 17 Multiplying Polynomials Multiplying Two Polynomials To multiply any two polynomials, use the distributive property and multiply each term of one polynomial by each term of the other polynomial. Then combine like terms. Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 18 Multiplying Polynomials Example: Multiply each of the following. 1) (3x2)(– 2x) = (3)(– 2)(x2 · x) = – 6x3 2) (4x2)(3x2 – 2x + 5) = (4x2)(3x2) – (4x2)(2x) + (4x2)(5) = 12x4 – 8x3 + 20x2 (Distributive property) (Multiply the monomials) 3) (2x – 4)(7x + 5) = 2x(7x + 5) – 4(7x + 5) = 14x2 + 10x – 28x – 20 = 14x2 – 18x – 20 Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 19 Multiplying Polynomials Example: Multiply (3x + 4)2 Remember that a2 = a · a, so (3x + 4)2 = (3x + 4)(3x + 4). (3x + 4)2 = (3x + 4)(3x + 4) = (3x)(3x + 4) + 4(3x + 4) = 9x2 + 12x + 12x + 16 = 9x2 + 24x + 16 Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 20 Multiplying Polynomials Example: Multiply (a + 2)(a3 – 3a2 + 7). (a + 2)(a3 – 3a2 + 7) = a(a3 – 3a2 + 7) + 2(a3 – 3a2 + 7) a4 – 3a3 + 7a + 2a3 – 6a2 + 14 = a4 – a3 – 6a2 + 7a + 14 = Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 21 Multiplying Polynomials Example: Multiply (3x – 7y)(7x + 2y) (3x – 7y)(7x + 2y) = (3x)(7x + 2y) – 7y(7x + 2y) = 21x2 + 6xy – 49xy + 14y2 = 21x2 – 43xy + 14y2 Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 22 Multiplying Polynomials Example: Multiply (5x – 2z)2 (5x – 2z)2 = (5x – 2z)(5x – 2z) = (5x)(5x – 2z) – 2z(5x – 2z) = 25x2 – 10xz – 10xz + 4z2 = 25x2 – 20xz + 4z2 Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 23 Multiplying Polynomials Example: Multiply (2x2 + x – 1)(x2 + 3x + 4) (2x2 + x – 1)(x2 + 3x + 4) = (2x2)(x2 + 3x + 4) + x(x2 + 3x + 4) – 1(x2 + 3x + 4) = 2x4 + 6x3 + 8x2 + x3 + 3x2 + 4x – x2 – 3x – 4 = 2x4 + 7x3 + 10x2 + x – 4 Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 24 Multiplying Polynomials You can also use a vertical format in arranging the polynomials to be multiplied. In this case, as each term of one polynomial is multiplied by a term of the other polynomial, the partial products are aligned so that like terms are together. This can make it easier to find and combine like terms. Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 25 Example: Multiply (2x – 4)(7x + 5) (2x – 4)(7x + 5) = 2x(7x) + 2x(5) – 4(7x) – 4(5) = 14x2 + 10x – 28x – 20 = 14x2 – 18x – 20 We multiplied these same two binomials together in the previous section, using a different technique, but arrived at the same product. Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 26 Special Products Square of a Binomial (a + b)2 = a2 + 2ab + b2 (a – b)2 = a2 – 2ab + b2 Product of the Sum and Difference of Two Terms (a + b)(a – b) = a2 – b2 Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 27 Special Products Although you will arrive at the same results for the special products by using the techniques of this section or last section, memorizing these products can save you some time in multiplying polynomials. Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 28 Evaluating Polynomials We can use function notation to represent polynomials. For example, P(x) = 2x3 – 3x + 4. Evaluating a polynomial for a particular value involves replacing the value for the variable(s) involved. Example: Find the value P(2) = 2x3 – 3x + 4. P(2) = 2(2)3 – 3(2) + 4 = 2(8) + 6 + 4 = 6 Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 29 Evaluating Polynomials Techniques of multiplying polynomials are often useful when evaluating polynomial functions at polynomial values. Example: If f(x) = 2x2 + 3x – 4, find f(a + 3). We replace the variable x with a + 3 in the polynomial function. f(a + 3) = 2(a + 3)2 + 3(a + 3) – 4 = 2(a2 + 6a + 9) + 3a + 9 – 4 = 2a2 + 12a + 18 + 3a + 9 – 4 = 2a2 + 15a + 23 Martin-Gay, Intermediate Algebra: A Graphing Approach, 4ed 30