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Norton's Theorem (4.3, 7.8) Dr. S. M. Goodnick October 22, 2003 ECE201 Lect-23 1 Introduction • Any Thevenin equivalent circuit is in turn equivalent to a current source in parallel with a resistor [source transformation]. • A current source in parallel with a resistor is called a Norton equivalent circuit. • Finding a Norton equivalent circuit requires essentially the same process as finding a Thevenin equivalent circuit. ECE201 Lect-23 2 Independent Sources Isc Circuit with one or more independent sources RTh Norton equivalent circuit ECE201 Lect-23 3 No Independent Sources RTh Circuit without independent sources Norton equivalent circuit ECE201 Lect-23 4 Finding the Norton Equivalent • Circuits with independent sources: – Find Voc and Isc – Compute RTh • Circuits without independent sources: – Apply a test voltage (current) source – Find resulting current (voltage) – Compute RTh ECE201 Lect-23 5 Example: Strain Gauge • Strain is the amount of deformation of a body due to an applied force-it is defined as the fractional change in length. • Strain can be positive (tensile) or negative (compressive). • One type of strain gauge is made of a foil grid on a thin backing. ECE201 Lect-23 6 A Strain Gauge Backing Foil • The strain gauge’s resistance varies as a function of the strain: DR = GF e R • e is the strain, R is the nominal resistance, GF is the Gauge Factor ECE201 Lect-23 7 Typical values • Measured strain values are typically fairly small-usually less than 10-3. • GF is usually close to 2. • Typical values for R are 120W, 350W, and 1000W. • A typical change in resistance is DR = 2•10-3•120W = 0.24W ECE201 Lect-23 8 Measuring Small Changes in R • To measure such small changes in resistance, the strain gauge is placed in a Wheatstone bridge circuit. • The bridge circuit uses an excitation voltage source and produces a voltage that depends on DR. ECE201 Lect-23 9 The Bridge Circuit R+DR R Vex –V + – + out R ECE201 Lect-23 R 10 Norton Equivalent for Any e R 4 6e RTh 4 1 2e Vex 2e I sc R 4 6e ECE201 Lect-23 11 Thevenin/Norton Analysis 1. Pick a good breaking point in the circuit (cannot split a dependent source and its control variable). 2. Thevenin: Compute the open circuit voltage, VOC. Norton: Compute the short circuit current, ISC. For case 3(b) both VOC=0 and ISC=0 [so skip step 2] ECE201 Lect-23 12 Thevenin/Norton Analysis 3. Compute the Thevenin equivalent resistance, RTh (or impedance, ZTh). (a) If there are only independent sources, then short circuit all the voltage sources and open circuit the current sources (just like superposition). (b) If there are only dependent sources, then must use a test voltage or current source in order to calculate RTh (or ZTh) = VTest/Itest (c) If there are both independent and dependent sources, then compute RTh (or ZTh) from VOC/ISC. ECE201 Lect-23 13 Thevenin/Norton Analysis 4. Thevenin: Replace circuit with VOC in series with RTh, ZTh. Norton: Replace circuit with ISC in parallel with RTh, ZTh. Note: for 3(b) the equivalent network is merely RTh (or ZTh), that is, no voltage (or current) source. Only steps 2 & 4 differ from Thevenin & Norton! ECE201 Lect-23 14 Class Examples • Learning Extension E4.4 • Learning Extension E7.15(c) ECE201 Lect-23 15