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Example 4.10 Irwin, Page 127 Find the Thevenin equivalent circuit at points A-B for the circuit shown. We need to find two quantities: VTH = Voc and RTH = Voc/ISC If we use nodal analysis and/or mesh analysis or any other appropriate techniques, we find VTH = 0V and ISC = 0A (because there are no independent sources of power in the circuit) RTH = Voc / ISC = 0V/0A = ????? VTH = 0V is equivalent to a short circuit ISC = 0A is equivalent to an open circuit The Thevenin (Norton) equivalent consists of a single resistor. Fall 2001 ENGR-201 Example 4.8 1 Example 4.10 – Find RTH To make our work easier, we will find RTH to the at points C-D first. To find RTH apply a known voltage source (1V) and determine the amount of current demanded. . 1V R TH = IS Fall 2001 ENGR-201 Example 4.8 2 Example 4.10 – Find RTH at C-D 1V 1mA 1k VX =2000I X =2V IX = 1V-2V IS =I X + 1mA-0.5mA =0.5mA 2k 1V 2k R TH C D 0.5mA We can now replace the circuit to the left of points C-D with its Thevenin equivalent. Fall 2001 ENGR-201 Example 4.8 3 Example 4.10 – Find RTH R TH A-B =2k|| 3k 2k R TH A-B 1.43k The Thevenin (and Norton) equivalent circuit, then, is Fall 2001 ENGR-201 Example 4.8 4