* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Download Chapter 7
Signal-flow graph wikipedia , lookup
Loudspeaker wikipedia , lookup
Dynamic range compression wikipedia , lookup
Stage monitor system wikipedia , lookup
Stray voltage wikipedia , lookup
Sound reinforcement system wikipedia , lookup
Voltage optimisation wikipedia , lookup
Pulse-width modulation wikipedia , lookup
Three-phase electric power wikipedia , lookup
Scattering parameters wikipedia , lookup
Variable-frequency drive wikipedia , lookup
Alternating current wikipedia , lookup
Mains electricity wikipedia , lookup
Schmitt trigger wikipedia , lookup
Buck converter wikipedia , lookup
Current source wikipedia , lookup
Switched-mode power supply wikipedia , lookup
Electromagnetic compatibility wikipedia , lookup
Instrument amplifier wikipedia , lookup
Two-port network wikipedia , lookup
Audio power wikipedia , lookup
Resistive opto-isolator wikipedia , lookup
Public address system wikipedia , lookup
Distribution management system wikipedia , lookup
Regenerative circuit wikipedia , lookup
Opto-isolator wikipedia , lookup
Electronics Principles & Applications Fifth Edition Charles A. Schuler Chapter 7 More About Small-Signal Amplifiers ©1999 Glencoe/McGraw-Hill INTRODUCTION • Amplifier Coupling • Voltage Gain • FET Amplifier • Negative Feedback • Frequency Response Capacitive coupling is convenient in cascade ac amplifiers. VCC These two points are at different dc voltages. Direct coupling is required for dc gain. VCC The darlington is a popular dc arrangement. VCC VCC Transformer coupling offers the advantage of impedance matching. 10:1 P S 10 W ZRATIO = TRATIO2 = 102 = 100 ZCOLLECTOR = 100 x 10 W = 1000 W VCC Transformer coupling can be used in bandpass amplifiers to achieve selectivity. Gain fR Amplifier coupling quiz Capacitive coupling is not useful for _________ amplifiers. dc Dc frequency response requires ________ coupling. direct Transformer coupling offers the advantage of _________ matching. impedance Tuned transformer coupling provides frequency _____________. selectivity A darlington amplifier is an example of _________ coupling. direct More about solving the practical circuit for its ac conditions: VCC = 12 V RB1 22 kW RL= 2.2 kW C Zin = ? B RB2 2.7 kW E RE = 220 W Zin is a combination of RB1, RB2, and rin of the transistor. VCC = 12 V RB1 22 kW Determine rin first: RL= 2.2 kW rin = b (RE + rE) C B RB2 2.7 kW E rin = 150 (220 W + 9.03 W) rin = 34.4 kW RE = 220 W Note: rin = b rE when RE is bypassed. RB1, RB2, and rin act in parallel to load the input signal. VCC = 12 V 1 Zin = 1 1 1 + + r RB2 in RB1 22 kW RL= 2.2 kW RB1 C B RB2 2.7 kW Zin = E RE = 220 W 1 1 1 + + 22 kW 2.7 kW 34.4 kW 1 Zin = 2.25 kW What happens when an amplifier is loaded? VCC = 12 V RL and the Load act in parallel. RP = 1.1 kW RB1 22 kW RL= 2.2 kW Load = 2.2 kW RB2 2.7 kW RE = 220 W There are two saturation currents for a loaded amplifier. VCC = 4.96 mA ISAT(DC) = RL + RE V = 12 V CC RB1 22 kW VCC ISAT(AC) = = 9.09 mA RP + RE RL= 2.2 kW RP = 1.1 kW Load = 2.2 kW RB2 2.7 kW RE = 220 W There are three load lines for a loaded amplifier. The DC load line connects VCC and ISAT(DC). 14 12 10 IC in mA 8 TEMPORARY AC 6 4 DC 2 0 2 4 6 8 10 12 14 16 18 VCE in Volts 100 mA 80 mA 60 mA 40 mA 20 mA 0 mA The temporary AC load line connects VCC and ISAT(AC). The quiescent VCE is projected to the DC load line to establish the Q-point. The AC load line is drawn through the Q-point, parallel to the temporary AC load line. 100 mA 14 12 10 IC in mA 8 AC 6 4 DC 2 80 mA 60 mA 40 mA TEMP. AC 0 2 4 6 5.3 V 8 10 12 14 16 18 VCE in Volts 20 mA 0 mA The AC load line shows the limits for VCE and if the Q-point is properly located. 14 12 10 IC in mA 8 6 4 2 100 mA 80 mA 60 mA 40 mA 20 mA AC 0 2 4 6 8 10 12 14 16 18 VCE in Volts 0 mA 5.3 V With loaded amplifiers, the Q-point is often closer to saturation. What about voltage gain for a loaded amplifier? RP AV = R + r E E VCC = 12 V 1.1 kW = 4.8 AV = 220 W + 9.03 W RL= 2.2 kW RB1 22 kW RP = 1.1 kW Load = 2.2 kW RB2 2.7 kW RE = 220 W When analyzing cascade amplifiers, remember: VCC 1st 2nd Zin of the 2nd stage loads the 1st stage. Amplifier ac conditions quiz Emitter bypassing _________ an amplifier’s input impedance. decreases Loading at the output of an amplifier ________ its voltage gain. decreases A loaded amplifier has two load lines: dc and ___________. ac The clipping points of a loaded amplifier are set by its _______ load line. ac In a cascade amplifier, the Zin of a stage _______ the prior stage. loads Common-source JFET amplifier. VDD = 20 V 20 V = 4 mA ISAT = 5 kW RL = 5 kW Drain Gate Input signal CC VGS = 1.5 V RG Source Phase-inverted output Fixed bias ID in mA 2 -1.5 1 -2.0 0 8 VP-P 5 10 20 15 VDS in Volts -2.5 25 AV = 8 VGS in Volts N-channel JFET characteristic curves The q-point is set by the fixed bias. 0 Load line 4 1 VP-P -0.5 3 -1.0 1.6 mA 2 -1.5 1 -2.0 0 Yfs = DID DVGS 5 10 VDS = 1.6 mS 15 -2.5 20 25 VDS in Volts VGS in Volts Determining forward transfer admittance: 0 4 ID in mA -0.5 3 -1.0 When the forward transfer admittance is known, the voltage gain can be determined using: VDD = 20 V RL = 5 kW D = 1.6 mS x 5 kW G CC VGS = 1.5 V RG AV = Yfs x RL S =8 This agrees with the graphic solution. Source bias eliminates the need for a separate VGS supply. VDD IS = I D RL D G CC RG VGS = ID x RS S RS This resistor also provides ac negative feedback which decreases the voltage gain. Summing junction A negative feedback model A(Vin - BVout) Vin Vin - BVout A Vout A = open loop gain BVout B Feedback B = feedback ratio Vin V Vin AV A AV in out in) VVout = A(V BV AB +1 ==AV ABV in - = out AB out1AB in out +1 =A Vout VV Vout A +1 out AB in AB +1 A simplified model Vout The feedback ratio (B) for this circuit is easy to determine since the source and drain currents are the same. VDD RL = 5 kW D G CC RG B= S RS = 800 W 800 W 5 kW = 0.16 Vin A AB +1 Use the simplified model: 8 A(WITH NEG. FEEDBACK) = = 3.51 (8)(0.16) + 1 Vout The source bypass capacitor will eliminate the ac negative feedback and restore the voltage gain. VDD RL D G CC RG RS CS JFET amplifier quiz In a common-source amplifier, the input signal goes to the _______. gate In a common-source amplifier, the input to output phase relationship is ____. 180o The voltage gain of a C-S amplifier is equal to Yfs x _________. load resistance Source bias is produced by current flow through the _______ resistor. source An unbypassed source resistor _______ the voltage gain of a C-S amp. decreases Amplifier Negative Feedback • DC reduces sensitivity to device parameters • DC stabilizes operating point • DC reduces sensitivity to temperature change • AC reduces gain • AC increases bandwidth • AC reduces signal distortion and noise • AC may change input and output impedances The frequency response curve of an ac amplifier A Midband Amax 0.707 Amax -3dB f Bandwidth The gain is maximum in the midband. The bandwidth spans the -3 dB points which are called the break frequencies. Amplifier frequency response • The lower break frequency is partly determined by coupling capacitors. • It is also influenced by emitter bypass capacitors. • The upper break frequency is partly determined by transistor internal capacitance. • Both break frequencies can be influenced by negative feedback. REVIEW • Amplifier Coupling • Voltage Gain • FET Amplifier • Negative Feedback • Frequency Response