Survey
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Transcription Chapter 26 Genes • Nucleotide seq’s w/in DNA – ~2000 genes for peptides in prokaryotes – ~50,000 genes for peptides in eukaryotes • DNA is not DIRECT template for peptides – DNA = template for RNA (specifically mRNA) – Synth mRNA from DNA = transcription – So DNA transcribed to mRNA • mRNA used to translate genetic code peptide (next lecture) RNA Is Similar to DNA • Both nucleic acids • Both composed of 4 nucleotides: A, G, C – BUT RNA has U, not T • Both have form of ribose sugar – BUT RNA has ribose, DNA deoxyribose • Both linked by phosphodiester bonds – Sugar-phosphate backbone – BUT RNA in single-strand (not dbl helix) • Strand can fold back on itself • Can form intrastrand helices, other 2o structures Transcription DNA RNA Similar to Repl’n DNADNA • Complementarity – Base seq daughter DNA complementary to DNA template (parent) strand – Base seq mRNA complementary to DNA template strand • Initiation, Elongation, Termination Processes • Polymerases catalyze syntheses of new nucleic acid – Free 3’ –OH attacks –PO4 of incoming triphosphate – Pyrophosphate (PPi) is released – (NMP)n + NTP (NMP)n+1 + PPi Transcription DNA RNA Similar to Repl’n DNADNA • Template strand is read 3’ 5’ – So copied strand is synth’d 5’ 3’ – Complementary strands are antiparallel • DNA double helix must be unwound in both – Topoisomerases impt to relieve tension on helix in both Transcription DNARNA Different than Repl’n DNADNA • Amt DNA copied – Repl’n: entire chromosome copied • Both strands of dbl helix copied – Transcr’n: only 1 gene (part of chromosome) from 1 strand of double helix is copied • Single strand mRNA – BUT gene is copied more than once – Yields many transcripts of same gene • Each strand of DNA being transcribed has different name – RNA transcribed from DNA template strand (26-2) – Complementary strand of dbl helix is called DNA nontemplate strand or coding strand » This strand has same seq as RNA transcript, except for one difference » How is it different from transcript?? Transcription Is Different – cont’d • Origin – Repl’n: one origin in E. coli • What’s that called? – Transcr’n: Enz’s/prot’s must know where along length of DNA to begin copying/stop copying • Polymerase – Repl’n: DNA polymerase • Several types w/ varied subunits • Has proofreading ability • Requires primer • Elongation up to 1,000 nucleotides/sec Transcr’n Is Different -- cont’d • Polymerase – cont’d – Transcr’n: RNA polymerase (26-4) • 1 complex w/ 6 subunits – Called “holoenzyme” – 1 subunit (s) directs rest of enz to site of initiation of transcr’n Transcription Is Different – cont’d – Transcr’n: RNA polymerase – cont’d • No proofreading • No primer needed – Begins mRNA w/ GTP or ATP • Elongation ~50-90 nucleotides/sec • Unwinding – Repl’n: helicases are used – Transcr’n: RNA polymerase keeps ~17 bps unwound E. coli Promoter Region • DNA seq @ which transcr’n apparatus comes together to begin copying the gene – So each gene has a promoter • Consensus DNA seq’s -- highly conserved in both seq and location (26-5) E. coli Promoter – cont’d • Consensus DNA seq’s – cont’d – +1 base = first nucleotide to be transcribed • Usually a purine • What are the purines?? – -10 region (toward 3’ end of template strand) = 6 nucleotide seq w/ consensus TATAAT – Spacer = ~16-18 nucleotides – -35 region = 6 nucleotide seq w/ consensus TTGACA – -40 -60 region = AT-rich region = Up-stream Promoter (UP element) Fig.26-5 E. coli Promoter – cont’d • When pattern met exactly – RNA polymerase recognizes most efficiently – Get rapid transcription • When pattern varies from consensus sequences – Takes longer for RNA polymerase to recognize promoter – Get longer time of transcription Initiation of Transcr’n in E. coli (26-6) s subunit of RNA polymerase searches for promoter region – Scans ~2000 nucleotides/~ 3 sec along template strand • Holoenzyme binds at promoter region “closed complex” – DNA bound to holoenzyme is intact • About 15 bps unwound @ -10 region “open complex” – Probably conform’l changes in polymerase enz assist in “opening” Initiation of Transcr’n – cont’d • Now transcription initiated w/ nucleotides matched to template strand, added to polymer – After ~8-9 nucleotides added, s subunit dissociates • Can scan another region to find another promoter Initiation of Transcr’n – cont’d • Regulation of transcr’n – Strength of consensus at promoter region, as mentioned – Some polymerases have >1 s subunit • Cell stress use of diff s subunit, specific for partic promoters needed to alleviate specific stresses Initiation of Transcr’n – cont’d • Regulation of transcr’n – cont’d – Proteins may bind DNA seq’s in/around promoter • Some attract RNA polymerase to promoter region – So activate transcr’n of these genes • Some block RNA polymerase from binding @ promoter – Called “repressors” – So repress transcr’n of these genes • Proteins respond to metab, repro, stress conditions w/in the cell – Conditions may require much peptide or depletion of peptide – REMEMBER: Mech’s by cell to regulate glycolysis/metab?? Elongation of Transcr’n in E. coli • Holoenzyme free to move along template chain – Freer w/ dissoc’n of s subunit – Forms “transcription bubble” • Contains holoenzyme, template strand, new RNA strand Elongation of Transcr’n – cont’d • New RNA strand “transiently” base-paired to template DNA strand (26-1) – DNA-RNA hybrid Elongation of Transcr’n – cont’d • DNA helix rewinds behind transcription bubble (26-1) Elongation of Transcr’n – cont’d • Error rate in transcr’n ~1/105 bases added – Much higher than in repl’n – Acceptable • Cell will make many transcripts of same gene • Most proper (active) peptides • Some improper peptides that can be accommodated by cell – What if template strand were mutated? Termination of Transcr’n in E. coli • Need RNA polymerase to be processive – If falls off, must re-start @ promoter • What might happen in cell if problem w/ RNA polymerase processivity? • BUT may pause @ certain template strand seq’s • Some template strand seq’s cause RNA polymerase to stop Termination of Transcr’n – cont’d • Two types of termination in E. coli – Rho (r) independent (26-7) • Template seq RNA transcript w/ selfcomplementary nucleotides – ~ 15-20 nucleotides – G-C rich, followed by A-T rich regions – Transcript forms stable hairpin loop • Template has string of A nucleotides string of U nucleotides in transcript @ 3’ end – Causes RNA polymerase to pause Termination of Transcr’n – cont’d – Rho (r) independent – cont’d • Stable hairpin of transcript, followed by relatively unstable A-U pairings of DNARNA hybrid RNA transcript dissociates Termination of Transcr’n – cont’d – Rho (r) independent -- cont’d • Polymerase dissociates • DNA helix reanneals, rewinds r dependent r = protein = termination factor • Binds RNA transcript @ partic binding sites • Moves along new transcript 5’ 3’ to transcr’n bubble • Finds elongation paused • Disrupts DNA-RNA hybrid – Mechanism unknown – Has ATP hydrolysis ability Prokaryote Transcription • Prokaryote chromosome in cytoplasm – No organized nucleus • Prokaryote chromosome simple – mRNA transcr’d directly from DNA seq – No introns/exons; “junk” DNA; etc. • As mRNA synth’d, almost immediately translated peptide EukaryoteTranscription • More complex, less understood • 3 RNA polymerases – I, II, III – Each w/ specific function – Each binds diff promoter seq • RNA Polymerase I – Transcribes some rRNA’s • RNA Polymerase III – Transcribes tRNA’s and rRNA’s EukaryoteTranscription – cont’d • RNA Polymerase II – Transcribes mRNA (so most impt to transcr’n process) – Many subunits – Recognizes many promoters – Requires transcription factors EukaryoteTranscription – cont’d • Transcription factors (Table 26-1) – Proteins – Modulate binding of RNA polymerase II to promoter region – Complex w/ RNA polymerase proper binding to template, proper elongation (26-9) Fig.26-9 EukaryoteTranscription – cont’d Takes place in nucleus – mRNA transcript cytoplasm for translation • For peptides to be used outside the nucleus • REMEMBER: nuclear membr has pores • Euk genes complicated – REMEMBER: introns/exons, “junk?” DNA – Polymerase doesn’t seem to distinguish • Euk DNA transcr’d directly mRNA • Yields a primary transcript directly reflecting entire gene and any introns/junk EukaryoteTranscription – cont’d – For functioning peptide, intron seq’s excised before translation • So primary mRNA transcripts are spliced, rejoined • Through transesterification reaction (26-13) • Similar to topoisomerase mechanism EukaryoteTranscription – cont’d Euk genes complicated – cont’d – Intron seq’s excised – cont’d • Most nuclear mRNA’s spliced by specialized RNA-protein complexes – snRNP’s = small nuclear RiboNucleoProteins – About 5 RNA’s + 50 prot’s complex spliceosome (26-16) – Get “lariat” structure of intron seq nucleotides – Get attack by exon –OH end phosphate @ other exon end Fig.26-16 EukaryoteTranscription – cont’d – Euk mRNA’s also further modified at ends • 5’ cap – 7Methylguanosine added @ 5’ end – Get 5’, 5’triphosphate linkage (26-18) – May be impt in initiation of translation EukaryoteTranscription – cont’d – Euk mRNA’s also further modified at ends – cont’d • 3’ polyA tail – 80-250 adenylate residues (26-19) – May stabilize mRNA against enz destruction EukaryoteTranscription – cont’d – Final transcript = mature mRNA (26-20) Fig.26-11 Inhibition of Transcription by Antibiotics • Actinomycin D (26-10) – Planar, non-polar – Intercalates between nucleotide bases of DNA • Esp. between G-C’s in G-C rich seq’s – Now polymerase can’t move along DNA template Fig.26-10