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Linear Functions and Models Lesson 2.1 Problems with Data Real data recorded Problems Experiment results Periodic transactions Data not always recorded accurately Actual data may not exactly fit theoretical relationships In any case … Possible to use linear (and other) functions to analyze and model the data Fitting Functions to Data Temperature Viscosity (lbs*sec/in2) 160 28 170 26 180 24 190 21 200 16 210 13 220 11 230 9 Consider the data given by this example Viscosity (lbs*sec/in2) Note the plot of the data points Close to being in a straight line 30 25 20 15 10 5 0 160 170 180 190 200 210 220 230 240 Finding a Line to Approximate the Data Draw a line “by eye” Note slope, y-intercept Statistical process (least squares method) Use a computer program such as Excel Use your TI calculator Chart Title 35 30 25 20 15 10 5 0 160 170 180 190 200 210 220 230 240 Graphs of Linear Functions For the moment, consider the first option Given the graph with tic marks = 1 Determine Slope Y-intercept A formula for the function X-intercept (zero of the function) Graphs of Linear Functions Slope – use difference quotient Y-intercept – observe Write in form change in y y m change in x x y m x b Zero (x-intercept) – what value of x gives a value of 0 for y? Modeling with Linear Functions Linear functions will model data when The constant rate is the slope of the function Physical phenomena and data changes at a constant rate Or the m in y = mx + b The initial value for the data/phenomena is the y-intercept Or the b in y = mx + b Modeling with Linear Functions Ms Snarfblat's SS class is very popular. It started with 7 students and now, 18 months later has grown to 80 students. Assuming constant monthly growth rate, what is a modeling function? Determine the slope of the function Determine the y-intercept Write in the form of y = mx + b Creating a Function from a Table Determine slope by using change in y y m change in x x Answer: y 10 7 3 x 5 3 2 y 3 1.5 m y 2 x x y 3 7 4 8.5 5 10 6 11.5 y Creating a Function from a Table Now we know slope m = 3/2 Use this and one of x the points to determine 3 y-intercept, b 4 Substitute an 3 10 5 b 5 ordered 2 pair into 6 20 3 5 2b y = (3/2)x + b 5 2b 5 b solution : y 2 y 7 8.5 10 11.5 3 5 x 2 2 Creating a Function from a Table Double check results Substitute a different ordered pair into the formula Should give a true statement 3 5 solution : y x 2 2 x y 3 7 4 8.5 5 10 6 11.5 Piecewise Function Function has different behavior for different portions of the domain Greatest Integer Function f ( x) x = the greatest integer less than or equal to x 6.7 6 3 3 2.5 3 Examples Calculator – use the floor( ) function Assignment Lesson 2.1A Page 88 Exercises 1 – 65 EOO Finding a Line to Approximate the Data Draw a line “by eye” Note slope, y-intercept Statistical process (least squares method) Use a computer program such as Excel Use your TI calculator Chart Title 35 30 25 20 15 10 5 0 160 170 180 190 200 210 220 230 15240 You Try It Consider table of ordered pairs showing calories per minute as a function of body weight Enter data into data matrix of calculator Weight Calories 100 2.7 120 3.2 150 4.0 170 4.6 200 5.4 220 5.9 APPS, Date/Matrix Editor, New, 16 Using Regression On Calculator Choose F5 for Calculations Choose calculation type (LinReg for this) Specify columns where x and y values will come from 17 Using Regression On Calculator It is possible to store the Regression EQuation to one of the Y= functions 18 Using Regression On Calculator When all options are set, press ENTER and the calculator comes up with an equation approximates your data Note both the original x-y values and the function which approximates the data 19 Using the Function Resulting function: C ( x) 0.027 x 0.0169 Use function to find Calories Weight Calories 100 2.7 for 195 lbs. 120 3.2 150 4.0 C(195) = 5.24 This is called extrapolation 170 4.6 200 5.4 220 5.9 Note: It is dangerous to extrapolate beyond the existing data Consider C(1500) or C(-100) in the context of the problem The function gives a value but it is not valid 20 Interpolation Use given data Determine proportional “distances” 30 25 25 x 30 0.8 x 0.4167 C 4.6 0.4167 5.167 Weight Calories 100 2.7 120 3.2 150 4.0 170 4.6 195 ?? 200 5.4 220 5.9 x Note : This answer is different from the extrapolation results 0.8 21 Interpolation vs. Extrapolation Which is right? Interpolation Between values with ratios Extrapolation Uses modeling functions C ( x) 0.027 x 0.0169 Remember do NOT go beyond limits of known data 22 Correlation Coefficient A statistical measure of how well a modeling function fits the data -1 ≤ corr ≤ +1 |corr| close to 1 high correlation |corr| close to 0 low correlation Note: high correlation does NOT imply cause and effect relationship 23 Assignment Lesson 2.1B Page 94 Exercises 85 – 93 odd