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6.2 Linear Systems of Equations in Two Variables Solving systems by elimination Example: 1 x+y=4 2 x- y=1 Strategy -- add the two equations in order to "eliminate" one of the variables + 1 x+y=4 2 x- y=1 3 2x =5 You now have one equation with one unknown. Solve it and finish as for substitution. Example: 1 3x + 3y = 15 2 2x + 6y = 22 Mere adding won't eliminate. We multiply each equation by an appropriate constant so adding will eliminate (either x or y): 1 x 2: 6x + 6y = 30 2 x -3: -6x - 18y = -66 -12y = -36 y=3 etc. If all proceeds smoothly, and you get exactly one solution, implying that the lines cross in exactly one point. The system is termed consistent and independent. 6.2-1 Funny things that can happen, Ha! Ha! . . . . . . and how to cope Funny thing #1: How to cope: Example: you get an equation that is never true, e.g. 10 = 0 STOP! and write the answer "no solution" system consists of two parallel lines (they never cross) this is called an inconsistent system x - y = 10 -x + y = 5 _________________________ 0 + 0 = 15 no solution write this Funny thing #2: How to cope: Example: you get an equation that is always true, e.g. 10 = 10 STOP! and write answer as shown in the example below system consists of two identical lines (every point of the first is a point on the second) all (infinitely many) points on either line are solutions this is called a dependent (but consistent) system x - y = 10 -x + y = -10 _________________ 0+0= 0 {(x, y) | x - y = 10} write this 6.2-2