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Edexcel A2 Physics Unit 4 Bev Magnetic Fields Revision Booklet Rules, Rules, Rules! BIL Contents Review Questions.................................................................................................................................... 3 Wire Rule (Right Hand) ........................................................................................................................... 4 Coil Rule (Right Hand) ............................................................................................................................. 4 Motor Rule (Fleming’s Left Hand Rule) ................................................................................................... 5 Motor Rule for Charged Particles ....................................................................................................... 5 Motor Rule for Current-Carrying Wires .............................................................................................. 7 Generator Rule (Fleming’s Right Hand Rule) .......................................................................................... 9 Faraday’s Law & Lenz’s Law ................................................................................................................ 9 2|Page Review Questions 1. An iron bar is placed between two magnets as shown below, which makes the iron a temoprary magnet. Sketch the magnetic field (the lines of flux) between the permanent magnets and the nereast end of the iron bar. S N 2. Lines of flux by convetion point from the magnetic _____ pole to the magnetic _____ pole. 3. What pole of the bar magnet shown on the right is nearest the compass? a) North b) South Magnet ? 4. In the case below, the poles of the left magnets are _____ poles. 5. Attraction or repulsion of charges depends on their signs: positive or negative. Attraction of magnets depends on their magnetic _____: _____ or _____. Opposite poles _______; like poles _____. 6. You have an electromagnet that is not quite strong enough. What three changes could you make to increase the strength of the magnetic? 1. _________________________________________________________________________ 2. _________________________________________________________________________ 3. _________________________________________________________________________ 3|Page Wire Rule (Right Hand) A straight current-carrying wire creates a radial magnetic field around it. To determine its orientation, point your thumb in the direction of the conventional current (from + to – along the length of the wire). Your fingers will curl around the wire in the same direction as the magnetic field. - + Coil Rule (Right Hand) A current-carrying wire coiled around a core will create a magnetic field resembling that of a bar magnet, with distinct north and south poles at the ends of the coil. To determine which end of the coil is which, curl your right fingers around the coil so that they follow the direction of conventional current. Your thumb will point to the coil’s north pole. S N Use the Wire Rule and Coil Rule to answer the following questions. 7. A wire is shown with a radial magnetic field emanating from it. If the right end is positive, does the magnetic flux along the front side of the wire point upwards or downwards? _________________________________________________ 8. A wire is shown to the left in cross-section with its radial field around it. If the conventional current flows out of the page (as shown by the dot in the centre of the wire), is the field clockwise or anticlockwise? __________________________________________________________ + 9. A coil wrapped around a core is shown to the right, with the left end of the coil positive and the wire wrapped around it as indicated. Which end of the coil is the north pole? _________________________________________________ 10. A coil is wrapped around a core as shown on the diagram on the left, with its lines of flux. Which end is positive? __________________________________________________________________ 4|Page Motor Rule (Fleming’s Left Hand Rule) A charged particle moving perpendicularly through a magnetic field will experience a force that is perpendicular to both its velocity and the field. The same effect can also push a current-carrying wire. This is called a deflecting force. What does the thumb stand for? ____________________________________________ What does the first finger stand for? ____________________________________________ What does the second finger stand for? ____________________________________________ Motor Rule for Charged Particles For a charged particle moving through a magnetic field: I’m Bev! 𝐹 = 𝐵𝑒𝑣. 𝑠𝑖𝑛𝜃 Where θ is the angle between the velocity vector and the magnetic field vector. Since sin90° = 1, the force, F, is greatest when the particle moves perpendicular to the magnetic field lines. But since sin0° = 0, the force disappears if the particle moves parallel to the magnetic field. 11. A positively charged particle is moving uniform magnetic field with a velocity, v, directed out of the experiences a force as shown on the diagram on the right. direction of the magnetic field, B? through page What is a and the ____________________________________________________________ 12. A wire is immeresed in a magnetic field that points into the page. Which direction must the convetional current flow through the wire to cause the wire to be deflected to the left as shown in the diagram? _____________________________________________________ 5|Page 13. What is the direction of the force on the current-carrying wire in the magnetic field shown in the diagram? Conventional current flow is into the page. __________________________________________________________________________________ 14. The current flowing in the wire shown to the left creates a downward force on the wire. Show the direction of the conventional current flow. (Use a dot for out of the page and an X for into the page). 15. A proton in the solar wind travels perpendicularly at 3.00x105ms-1 across the Earth’s magnetic field lines. The field at that location is 0.0000100T. Proton Charge = +1.6x10-19C Proton Mass = 1.67x10-27kg Use the motor rule equation for a particle to determine the magnitude of the force on the particle. __________________________________________________________________________________ __________________________________________________________________________________ _______________________________________________________________________________ The motor rule predicts that this force will act as a centripetal force, causing the proton to have circular motion. Calculate the radius of the circle it begins to make. __________________________________________________________________________________ __________________________________________________________________________________ _______________________________________________________________________________ 16. A neutron and an electron are shot between the poles of a U magnet which generates a uniform magnetic field across their paths of magnitude 0.600T. One of the particles flies straight through the magnet’s field lines without any deflection. Is that particle the neutron or the electron? Briefly explain how you know this. __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ 6|Page The other particle is deflected by a force of 4.00x10-15N. Determine the speed at which the particle was moving through the magnetic field. __________________________________________________________________________________ __________________________________________________________________________________ _______________________________________________________________________________ Motor Rule for Current-Carrying Wires For a current-carrying wire in a magnetic field: 𝐹 = 𝐵𝐼𝐿. 𝑠𝑖𝑛𝜃 I’m BIL! Where θ is the angle between the velocity vector and the magnetic field vector. Since sin90° = 1, the force, F, is greatest when the current flows perpendicular to the magnetic field lines. But since sin0° = 0, the force disappears if the current flows parallel to the magnetic field. 17. A simple motor consists of a straight wire 0.500m long lying at 90° across a uniform magnetic field of 0.300T. The motor will be used to accelerate a 5.00 gram mass at 3.00ms -2. What is the smallest current that could be used? __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ 18. A conductor of mass 40.0 grams per metre is hung by two wires in a magnetic field of strength 3.60T directed out of the page as shown. Which source, A or B, should be switched on so that the magnetic field will deflect the wire upward, helping balance the conductor’s weight? Explain your answer. A B _________________________________________________________________________________ __________________________________________________________________________________ How much current from the source would be needed so that the conductor would levitate, reducing the tension in the wires to zero? _________________________________________________________________________________ __________________________________________________________________________________ 7|Page 8|Page Generator Rule (Fleming’s Right Hand Rule) We have seen that a charge moving across magnetic field lines will experience a deflecting force. We can use this property to create or “induce” electric current when wires and coils are mechanically moved through magnetic fields. The charges in the wires and coils are then deflected so that they flow down the wire – we say that an electric current has been induced. This is the principle behind the electric generator, as first discovered by Michael Faraday. If you mechanically spin a coil of wire in a magnetic field (such as the armature of a motor), current will then be produced and you have a generator. Since a generator is a motor in reverse, you reverse the motor rule to use it for generators. What does the thumb stand for? ____________________________________________ What does the first finger stand for? ____________________________________________ What does the second finger stand for? ____________________________________________ Faraday’s Law & Lenz’s Law The induced voltage that creates an induced current is directly proportional to the strength of the magnetic field, the length of wire moving through the field, and the speed at which the wire moves through the field. The induced voltage is sometimes called the electromotive force or emf and given the symbol, ε. 𝜀 = 𝐵𝐿𝑣 The induced voltage can also be defined by Faraday’s Law: The magnitude of an induced emf is proportional to the rate of change of flux linkage. 9|Page ∆(𝑁Ф) 𝜀= − 𝑡 The negative sign is a result of Lenz’s Law: The direction of an induced emf is such as to oppose the change creating it. 19. A wire is immersed in a magnetic field that points out of the page. Which way must the wire be pushed to induce a conventional current that flows down the page as shown in the diagram on the right? _____________________________________________ _____________________________________________ 20. In which diagram below would electricity be produced? The diagrams show magnetic fields as arrows and a wire in cross-section as a circle with an arrow indicating its movement. _____________ A. B. 21. In the diagram you selected above, which way does the induced conventional current flow? Add a dot to your chosen diagram to represent the induced current flowing out of the page and a cross to represent the induced current flowing into the page. 22. A simple generator consists of a 2.00m long copper wire that is suspended in a perpendicular magnetic field and moved at right angles to the lines of flux. The resistance of the wire is 3.00Ω and the current induced in the wire is 0.0600A. If the wire moves at 0.150ms-1, what is the magnitude of the magnetic field? __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ 10 | P a g e 23. A rod is perpendicular to a magnetic field of 0.450T and is moved at right angles to the flux at the rate of 30.0cms-1. If the emf induced across the rod is 0.0200V, what is the length of the rod? __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ THE END 11 | P a g e