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22.7 Source of magnetic field due to current The Oersted’s discovery in 1819 indicates an electric current can act as a source of magnetic field. Biot and Savart investigated the force exerted by an electric current on a nearby magnet in the 19th century. They arrived at a mathematical expression for the magnetic field at some point in space due to an electric current. 1 Biot-Savart Law The magnetic field is dB at some point P An infinitesimal length element is ds The wire is carrying a steady current of I The vector dB is perpendicular to both ds and the unit vector r̂ directed from the element toward P The magnitude of dB is inversely proportional to r2, where r is the distance from the element to P 2 Observations The magnitude of dB is proportional to the current and to the magnitude ds of the length element ds The magnitude of dB is proportional to sin q, where q is the angle between the vectors ds and r̂ 3 Biot-Savart Law, Equation The observations are summarized in the mathematical equation called BiotSavart Law: I ds rˆ dB km 2 r The Biot-Savart law gives the magnetic field only for a small length of the conductor 4 Permeability of Free Space mo 7 T m km 10 4p A The constant mo is called the permeability of free space mo = 4 p x 10-7 T. m / A The Biot-Savart Law can be written as mo I ds rˆ dB 2 4p r 5 Total Magnetic Field due a wire of current To find the total field, you need to sum up the contributions from all the current elements You need to evaluate the field by integrating over the entire current distribution 6 Exercise 52 The magnetic field at the point P is m0 I B (cosq1 cosq2 ) 4p a 7 B for an Infinite-Long, Straight Conductor, Direction The magnetic field lines are circles concentric with the wire The field lines lie in planes perpendicular to to wire The magnitude of the field is constant on any circle of radius a The right hand rule for determining the direction of the field is shown moI B 2p r 8 9 10 11 B for a Circular Current Loop The loop has a radius of R and carries a steady current of I Find B at point P Bx moIR 2 2 x R 2 2 3 2 The field at the center of the loop m0 I Bx 2R 12 22.8 Magnetic Force Between Two Parallel Conductors Two parallel wires each carry a steady current The field B2 due to the current in wire 2 exerts a force on wire 1 of F1 = I1l B2 Substituting the equation for B2 gives m II F1 o 1 2 2p a Parallel conductors carrying currents in the same direction attract each other Parallel conductors carrying current in opposite directions repel each other 13 Magnetic Force Between Two Parallel Conductors The result is often expressed as the magnetic force between the two wires, FB This can also be given as the force per unit length, FB m oI1I2 2pa 14 22.9 Definition of the Ampere The force between two parallel wires can be used to define the ampere When the magnitude of the force per unit length between two long parallel wires that carry identical currents and are separated by 1 m is 2 x 10-7 N/m, the current in each wire is defined to be 1 A 15 Magnetic Field of a Wire Without Current A compass can be used to detect the magnetic field When there is no current in the wire, there is no field due to the current The compass needles all point toward the earth’s north pole Due to the earth’s magnetic field 16 Magnetic Field of a Wire With a Current The wire carries a strong current The compass needles deflect in a direction tangent to the circle This shows the direction of the magnetic field produced by the wire 17 André-Marie Ampère 1775 –1836 Credited with the discovery of electromagnetism The relationship between electric currents and magnetic fields Died of pneumonia 18 Ampere’s Law The product of B ds can be evaluated for small length elements ds on the circular path defined by the compass needles for the long straight wire Ampere’s Law states that the line integral of B ds around any closed path equals moI where I is the total steady current passing through any surface bounded by the closed path B ds m o I 19 Field Due to a Long Straight Wire with a finite radius Want to calculate the magnetic field at a distance r from the center of a wire carrying a steady current I The current is uniformly distributed through the cross section of the wire 20 Field Due to a Long Straight Wire - From Ampere’s law Outside of the wire, r > R B ds B(2p r ) m I o mo I B 2p r Inside the wire, we need I’, the current inside the amperian circle B ds B(2p r ) m I ' o mI B o 2 r 2p R r2 I' 2 I R 21 Field Due to a Long Straight Wire – Summary The field is proportional to r inside the wire The field varies as 1/r outside the wire Both equations are equal at r = R 22 Magnetic Field of a Toroid Find the field at a point at distance r from the center of the toroid The toroid has N turns of wire B ds B(2p r ) m NI o mo NI B 2p r 23 22.10 Magnetic Field of a Solenoid A solenoid is a long wire wound in the form of a helix A reasonably uniform magnetic field can be produced in the space surrounded by the turns of the wire Each of the turns can be modeled as a circular loop The net magnetic field is the vector sum of all the fields due to all the turns 24 Ideal Solenoid – Characteristics An ideal solenoid is approached when The turns are closely spaced The length is much greater than the radius of the turns For an ideal solenoid, the field outside of solenoid is negligible The field inside is uniform 25 Ampere’s Law Applied to a Solenoid, cont Applying Ampere’s Law gives B ds B ds B path1 ds B path1 The total current through the rectangular path equals the current through each turn multiplied by the number of turns B ds B mo NI 26 Magnetic Field of a Solenoid, final Solving Ampere’s Law for the magnetic field is N B mo I mo nI n = N / l is the number of turns per unit length This is valid only at points near the center of a very long solenoid 27 Magnetic Field of a Solenoid with a finite length The field distribution is similar to that of a bar magnet As the length of the solenoid increases The field lines in the interior are The interior field becomes more uniform The exterior field becomes weaker Approximately parallel to each other Uniformly distributed Close together This indicates the field is strong and almost uniform 28 Magnetic field lines of a solenoid 29 22.11 Magnetic Moment – Bohr Atom The electrons move in circular orbits The orbiting electron constitutes a tiny current loop The magnetic moment of the electron is associated with this orbital motion The angular momentum and magnetic moment are in opposite directions due to the electron’s negative charge 30 Magnetic Moments of Multiple Electrons In most substances, the magnetic moment of one electron is canceled by that of another electron orbiting in the opposite direction The net result is that the magnetic effect produced by the orbital motion of the electrons is either zero or very small 31 Electron Spin Electrons (and other particles) have an intrinsic property called spin that also contributes to its magnetic moment The electron is not physically spinning It has an intrinsic angular momentum as if it were spinning Spin angular momentum is actually a relativistic effect 32 Electron Magnetic Moment In atoms with multiple electrons, many electrons are paired up with their spins in opposite directions The spin magnetic moments cancel Those with an “odd” electron will have a net moment Some moments are given in the table 33 Ferromagnetic Materials Some examples of ferromagnetic materials are Iron Cobalt Nickel Gadolinium Dysprosium They contain permanent atomic magnetic moments that tend to align parallel to each other even in a weak external magnetic field 34 Domains All ferromagnetic materials are made up of microscopic regions called domains The domain is an area within which all magnetic moments are aligned The boundaries between various domains having different orientations are called domain walls 35 Domains, Unmagnetized Material The magnetic moments in the domains are randomly aligned The net magnetic moment is zero 36 Domains, External Field Applied A sample is placed in an external magnetic field The size of the domains with magnetic moments aligned with the field grows The sample is magnetized 37 Domains, External Field Applied, cont The material is placed in a stronger field The domains not aligned with the field become very small When the external field is removed, the material may retain most of its magnetism 38 22.12 Magnetic Levitation The Electromagnetic System (EMS) is one design model for magnetic levitation The magnets supporting the vehicle are located below the track because the attractive force between these magnets and those in the track lift the vehicle 39 EMS 40 German Transrapid – EMS Example 41 Close surface and line integrals of Electric and Magnetic fields Electric field, E Close Surface Integral Magnetic field, qin S E dA 0 B ? (Gauss Law) Close Line Integral ? B dl μ0 I tot C (Ampere’s Law) 42 Line integral of electric field along a close path Potential difference between a and b points, Vb Va b a E dl For a close path, a=b and Va=Vb. E dl 0 c The electric force is conservative. 43 Magnetic Flux The magnetic flux is expressed as The flux depends on the magnetic field and the area: B B dA 44 Surface integral of magnetic field around any close surfaces B dA 0 S No magnetic monopole is found so far! 45 Close surface and line integrals of Electric and Magnetic fields Steady state only Electric field, E Close Surface Integral qin S E dA 0 (Gauss Law) Close Line Integral E dl 0 c The electric force is conservative. Magnetic field, B B dA 0 S No magnetic monopole! B dl μ0 I tot C (Ampere’s Law) 46 Exercises of Chapter 22 5, 8, 14, 18, 20, 22, 23, 29, 35, 38, 44, 49, 55, 68, 69 47