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1. It is determined that the mean vehicle miles traveled by a U.S. household annually is greater than 22,000 miles. You conduct some research and determine that a random sample of 36 U.S. households has a mean annual vehicle miles of travel of 22,000 with a standard deviation of 775 miles. You conduct a statistical experiment where H0: µ≤ 22,000 and Ha: µ>22,000. At α = 0.05, explain why you cannot reject H0. Solution: (we use z distribution because n>30, we could use t statistic too) H0: µ≤ 22,000 Ha: µ>22,000 n = 36, x-bar =22,000, s=775 Statistic = z = (x-bar-22,000)/(775/√36) = 0 Critical value is: z(0.05) = 1.645 Critical region = {z/z>1.645} Answer: : We fail to reject Ho because the statistic value (0) is not greater than 1.645 (Statistic value is not in the critical region) 2. A local Jiffy Lube franchise questioned the frequency of oil changes. They believed that people traveled more than 3500 miles between oil changes. They took a random sample of 8 cars getting an oil change which has a mean distance of 3375 miles since having an oil change with a standard deviation of 225 miles. At α = 0.05, do you have enough evidence to support Jiffy Lube’s claim? Solution: We use t-statistic because n=8 (n<30) Ho: ≥ 3500 Ha: < 3500 n=8, x-bar=3375, s=225, α=0.05 Statistic = t = (x-bar-3500)/(s/√n) = (3375-3500)/(225/√8) = -1.571 Critical value = -t(α,n-1) = -t(0.05,7) = -1.895 Critical region = {t/t<-1.895} Decision: We fail to reject Ho since the ststistic value (-1.571) is not less than 1.895 Answer: We don`t have enough evidence to reject the claim ( ≥ 3500) 3. The table below shows the number of robberies reported (in millions) and the number of convictions reported (in millions) by the U.S. department of justice for 14 years. At α= 0.05, can you conclude that there is a significant linear correlation between the number of robberies and the number of convictions? Robberies, x 1.60 1.55 1.44 1.40 1.32 1.23 1.22 Convictions, y 0.78 0.80 0.73 0.72 0.68 0.64 0.63 Robberies, x 1.23 1.22 1.18 1.16 1.19 1.21 1.20 Convictions, y 0.63 0.62 0.60 0.59 0.60 0.61 0.58 Perform a hypothesis test to make a conclusion about the indicated correlation coefficient. Use the Table 5- t-distribution. 8 points Solution: Using excel coefficient of correlation = r = 0.981 Ho: = 0 Ha: ≠ 0 n = 14, r=0.981, α= 0.05 Statistic = t = r√(n-2)/√(1-r2) = 0.981√12/√(1-(0.981)2) = 17.516 Critical values are: -t(0.025,12) = -2.179 and t(0.025,12) =2.179 Critical region = {t/t<-2.179 or t>2.179} Decision: we reject Ho since the statistic value (17.156) is less than -2.179 Interpretation: There is a significant linear correlation between the number of robberies and the number of convictions 4. What does switching the explanatory and response variables have on the correlation coefficient? Calculate the correlation coefficient, letting row 1 represent x values and row 2 represent y values. Then calculate the correlation coefficient, r, letting row 2 represent the x values and row 1 represent the y values. Row 1 0 1 2 3 3 5 5 5 6 7 Row 2 96 85 82 74 95 68 76 84 58 65 Row 1 = x values Row 2 = y values r = -0.779 Row 1 = y values Row 2 = x values r = -0.779 Answer: correlation coefficient remains unchanged 5. For the given data, find the equation of the regression line letting row 1 represent the x-values and row 2 the y-values. Sketch a scatter plot of the data and draw the regression line. Then find the equation of the regression line letting row 1 represent the y-values and row 2 the x-values. Sketch a scatter plot of the data and draw the regression line. What effect does switching the explanatory and response variables have on the regression line? Row 1 16 25 39 45 49 64 70 Row 2 109 122 143 132 199 185 199 Row 1: x-values Row 2: y values Regression line: y = 1.7236x+79.733 (see graph) 250 y = 1.7236x + 79.733 200 150 Series1 Linear (Series1) 100 50 0 0 20 40 60 80 Row 1: y-values Row 2: x values Regression line: y = 0.4528x-26.448 (see graph) 80 y = 0.4528x - 26.448 70 60 50 Series1 40 Linear (Series1) 30 20 10 0 0 50 100 150 200 250 Answer: Switching the variables make a change of the regression line