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Transcript
AP® Physics C: Electricity and Magnetism
2012 Free-Response Questions
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TABLE OF INFORMATION DEVELOPED FOR 2012
CONSTANTS AND CONVERSION FACTORS
Proton mass, m p = 1.67 ¥ 10 -27 kg
Neutron mass, mn = 1.67 ¥ 10 -27 kg
1 electron volt, 1 eV = 1.60 ¥ 10 -19 J
Electron mass, me = 9.11 ¥ 10 -31 kg
c = 3.00 ¥ 108 m s
Speed of light,
Universal gravitational
constant,
Acceleration due to gravity
at Earth’s surface,
Avogadro’s number, N 0 = 6.02 ¥ 1023 mol-1
R = 8.31 J (mol iK)
Universal gas constant,
e = 1.60 ¥ 10 -19 C
Electron charge magnitude,
G = 6.67 ¥ 10 -11 m 3 kgis2
g = 9.8 m s2
Boltzmann’s constant, k B = 1.38 ¥ 10 -23 J K
1 u = 1.66 ¥ 10 -27 kg = 931 MeV c 2
1 unified atomic mass unit,
h = 6.63 ¥ 10 -34 J is = 4.14 ¥ 10 -15 eV is
Planck’s constant,
hc = 1.99 ¥ 10 -25 J im = 1.24 ¥ 103 eV i nm
⑀0 = 8.85 ¥ 10 -12 C2 N im 2
Vacuum permittivity,
Coulomb’s law constant, k = 1 4 p⑀ 0 = 9.0 ¥ 109 N im 2 C2
m0 = 4 p ¥ 10 -7 (T im) A
Vacuum permeability,
Magnetic constant, k ¢ = m0 4 p = 1 ¥ 10 -7 (T i m) A
1 atm = 1.0 ¥ 105 N m 2 = 1.0 ¥ 105 Pa
1 atmosphere pressure,
UNIT
SYMBOLS
meter,
kilogram,
second,
ampere,
kelvin,
PREFIXES
Factor
Prefix
Symbol
m
kg
s
A
K
mole,
hertz,
newton,
pascal,
joule,
mol
Hz
N
Pa
J
watt,
coulomb,
volt,
ohm,
henry,
W
C
V
W
H
farad,
tesla,
degree Celsius,
electron-volt,
F
T
∞C
eV
VALUES OF TRIGONOMETRIC FUNCTIONS FOR COMMON ANGLES
q
30
0
37
45
53
60
90
10 9
giga
G
sin q
0
12
35
2 2
45
3 2
1
106
mega
M
cos q
1
3 2
45
2 2
35
12
0
103
kilo
k
tan q
0
3 3
34
1
43
3
•
10 -2
centi
c
10 -3
milli
m
10 -6
micro
m
-9
nano
n
10 -12
pico
p
10
The following conventions are used in this exam.
I. Unless otherwise stated, the frame of reference of any problem is
assumed to be inertial.
II. The direction of any electric current is the direction of flow of positive
charge (conventional current).
III. For any isolated electric charge, the electric potential is defined as zero at
an infinite distance from the charge.
-2-
ADVANCED PLACEMENT PHYSICS C EQUATIONS DEVELOPED FOR 2012
MECHANICS
u = u0 + at
x = x0 + u0 t +
1 2
at
2
u 2 = u0 2 + 2a ( x - x0 )
 F = Fnet = ma
dp
dt
F=
J = Ú F dt = Dp
p = mv
F fric £ m N
W =
Ú Fidr
K =
1 2
mu
2
P=
dW
dt
P = Fiv
DUg = mgh
ac =
u2
= w2 r
r
Ú r dm = Â mr
2
2
rcm =  mr  m
u = rw
x = xmax cos( wt + f)
2p
1
T =
=
w
f
m
k
1 2
Iw
2
Tp = 2p
FG = -
w = w0 + at
1 2
at
2
UG
F =
1 q1q2
4 p⑀0 r 2
E=
F
q
Q
Ú E i d A = ⑀0
UE
Gm1m2
r2
Gm1m2
=r
rˆ
q
 rii
1
4 p⑀0
V =
i
1 q1q2
= qV =
4 p⑀0 r
C =
Q
V
C =
k ⑀0 A
d
 Ci
Cp =
i
1
1
=Â
Cs
C
i i
dQ
I =
dt
1
1
QV = CV 2
2
2
A
B
C
d
E
=
=
=
=
=
e=
F =
I =
J =
L =
=
n =
N =
P
Q
q
R
r
t
U
=
=
=
=
=
=
=
V=
u =
r=
area
magnetic field
capacitance
distance
electric field
emf
force
current
current density
inductance
length
number of loops of wire
per unit length
number of charge carriers
per unit volume
power
charge
point charge
resistance
distance
time
potential or stored energy
electric potential
velocity or speed
resistivity
fm = magnetic flux
k = dielectric constant
Ú B i d ᐉ = m0 I
dB =
r
R=
A
F=
E = rJ
m0 I d ᐉ ¥ r
4p r3
Ú I dᐉ ¥ B
I = Neud A
Bs = m0 nI
V = IR
fm = Ú B i d A
Rs =
g
dV
dr
E =-
Uc =
1 2
kx
2
Ts = 2 p
L = r ¥ p = Iw
q = q0 + w0 t +
acceleration
force
frequency
height
rotational inertia
impulse
kinetic energy
spring constant
length
angular momentum
mass
normal force
power
momentum
radius or distance
position vector
period
time
potential energy
velocity or speed
work done on a system
position
coefficient of friction
angle
torque
angular speed
angular acceleration
phase angle
Us =
 t = t net = I a
K =
=
=
=
=
=
=
=
=
=
L =
m=
N =
P =
p =
r =
r =
T =
t =
U=
u =
W=
x =
m=
q =
t =
w=
a=
f =
Fs = - k x
t=r¥F
I =
a
F
f
h
I
J
K
k
ELECTRICITY AND MAGNETISM
 Ri
1
=
Rp
i
1
ÂR
i
i
P = IV
FM = qv ¥ B
-3-
Ú Eidᐉ = -
e
=
e
= -L
UL =
dI
dt
1 2
LI
2
d fm
dt
ADVANCED PLACEMENT PHYSICS C EQUATIONS DEVELOPED FOR 2012
GEOMETRY AND TRIGONOMETRY
Rectangle
A = bh
Triangle
A=
1
bh
2
Circle
A = pr2
C = 2p r
Rectangular Solid
V = wh
Cylinder
A=
C=
V=
S =
b =
h =
=
w=
r =
CALCULUS
df
d f du
=
dx
du dx
area
circumference
volume
surface area
base
height
length
width
radius
d n
( x ) = nxn -1
dx
d x
(e ) = e x
dx
d
( ln x ) = 1
dx
x
d
(sin x ) = cos x
dx
d
(cos x ) = - sin x
dx
V = pr2
Úx
S = 2p r + 2p r 2
Úe
Sphere
V =
4 3
pr
3
Ú
a 2 + b2 = c2
cos q =
b
c
tan q =
a
b
x
dx = e x
dx
= ln x
x
Ú sin x dx = - cos x
Right Triangle
a
c
dx =
Ú cos x dx = sin x
S = 4p r 2
sin q =
1
x n + 1 , n π -1
n +1
n
c
a
90°
q
b
-4-
2012 AP® PHYSICS C: ELECTRICITY AND MAGNETISM FREE-RESPONSE QUESTIONS
PHYSICS C: ELECTRICITY AND MAGNETISM
SECTION II
Time— 45 minutes
3 Questions
Directions: Answer all three questions. The suggested time is about 15 minutes for answering each of the questions, which
are worth 15 points each. The parts within a question may not have equal weight. Show all your work in this booklet in the
spaces provided after each part.
E&M.
1.
Two thin, concentric, conducting spherical shells, insulated from each other, have radii of 0.10 m and 0.20 m, as shown
above. The inner shell is set at an electric potential of -100 V , and the outer shell is set at an electric potential of +100
V, with each potential defined relative to the conventional reference point. Let Qi and Qo represent the net charge on
the inner and outer shells, respectively, and let r be the radial distance from the center of the shells. Express all algebraic
answers in terms of Qi , Qo , r, and fundamental constants, as appropriate.
(a) Using Gauss’s Law, derive an algebraic expression for the electric field E (r ) for 0.10 m < r < 0.20 m .
(b) Determine an algebraic expression for the electric field E (r ) for r > 0.20 m .
(c) Determine an algebraic expression for the electric potential V (r ) for r > 0.20 m .
(d) Using the numerical information given, calculate the value of the total charge QT on the two spherical shells
(QT
= Qi + Qo ) .
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-5-
2012 AP® PHYSICS C: ELECTRICITY AND MAGNETISM FREE-RESPONSE QUESTIONS
(e) On the axes below, sketch the electric field E as a function of r . Let the positive direction be radially outward.
(f) On the axes below, sketch the electric potential V as a function of r .
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-6-
2012 AP® PHYSICS C: ELECTRICITY AND MAGNETISM FREE-RESPONSE QUESTIONS
E&M.
2.
A physics student wishes to measure the resistivity of slightly conductive paper that has a thickness of 1.0 ¥ 10 -4 m .
The student cuts a sheet of the conductive paper into strips of width 0.02 m and varying lengths, making five resistors
labeled R1 to R5. Using an ohmmeter, the student measures the resistance of each strip, as shown above. The data are
recorded below.
Resistor
R1
R2
R3
R4
R5
Length (m)
0.020
0.040
0.060
0.080
0.100
Resistance ( W )
80,000
180,000
260,000
370,000
440,000
(a) Use the grid below to plot a linear graph of the data points from which the resistivity of the paper can be determined.
Include labels and scales for both axes. Draw the straight line that best represents the data.
(b) Using the graph, calculate the resistivity of the paper.
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-7-
2012 AP® PHYSICS C: ELECTRICITY AND MAGNETISM FREE-RESPONSE QUESTIONS
The student uses resistors R4 and R5 to build a circuit using wire, a 1.5 V battery, an uncharged 10 mF capacitor, and an
open switch, as shown above.
(c) Calculate the time constant of the circuit.
(d) At time t = 0, the student closes the switch. On the axes below, sketch the magnitude of the voltage Vc across the
capacitor and the magnitudes of the voltages VR4 and VR5 across each resistor as functions of time t. Clearly label
each curve according to the circuit element it represents. On the axes, explicitly label any intercepts, asymptotes,
maxima, or minima with values or expressions, as appropriate.
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-8-
2012 AP® PHYSICS C: ELECTRICITY AND MAGNETISM FREE-RESPONSE QUESTIONS
E&M.
3.
A closed loop is made of a U-shaped metal wire of negligible resistance and a movable metal crossbar of
resistance R. The crossbar has mass m and length L. It is initially located a distance h0 from the other end of the
loop. The loop is placed vertically in a uniform horizontal magnetic field of magnitude B0 in the direction
shown in the figure above. Express all algebraic answers to the questions below in terms of B0 , L, m, h0 , R, and
fundamental constants, as appropriate.
(a) Determine the magnitude of the magnetic flux through the loop when the crossbar is in the position shown.
The crossbar is released from rest and slides with negligible friction down the U-shaped wire without losing
electrical contact.
(b) On the figure below, indicate the direction of the current in the crossbar as it falls.
Justify your answer.
(c) Calculate the magnitude of the current in the crossbar as it falls as a function of the crossbar’s speed u .
(d) Derive, but do NOT solve, the differential equation that could be used to determine the speed u of the
crossbar as a function of time t.
(e) Determine the terminal speed uT of the crossbar.
(f) If the resistance R of the crossbar is increased, does the terminal speed increase, decrease, or remain the
same?
____ Increases
____ Decreases
____ Remains the same
Give a physical justification for your answer in terms of the forces on the crossbar.
STOP
END OF EXAM
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-9-