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Transcript
Answer on Question 51719, Physics, Electromagnetism
2. What are the dimensions of electrical resistance?
a) 𝑀𝐿𝑇 βˆ’2 π΄βˆ’2
b) 𝑀2 𝐿2 π‘‡π΄πΏβˆ’2
c) 𝑀𝐿2 𝑇 βˆ’3 π΄βˆ’2
d) None of the above
Solution:
By the definition, electrical resistance of an object is defined as the ratio of voltage
across it to current through it:
𝑉
𝑅= .
𝐼
Voltage is measured in volts and is derived unit in SI system. Current is measured in
amperes and is based unit in SI system. So, let’s get the ratio:
𝑀𝐿2
𝑀𝐿2
3
𝐴𝑇
𝑅=
= 2 3 = 𝑀𝐿2 𝑇 βˆ’3 π΄βˆ’2 .
𝐴
𝐴 𝑇
Answer: c) 𝑀𝐿2 𝑇 βˆ’3 π΄βˆ’2 .
3. Select the correct option from the following?
a) Electric field is a scalar quantity.
b) Electromotive force is a vector quantity.
c) Electric current is a scalar quantity.
d) Electric potential is a vector quantity.
Answer:
A scalar is a quantity that is completely specified by its magnitude and has no
direction, while a vector is a quantity that specifies both the magnitude and a
direction. The examples of vectors are force and electric field. So, the correct answer
is b) Electromotive force is a vector quantity.
4. Calculate the currents in 3π‘œβ„Žπ‘šπ‘  resistor:
a) 1.94𝐴
b) 1.36𝐴
c) 3.23𝐴
d) 5.45𝐴
Solution:
Unfortunately, there is no scheme added to calculate the currents in 3π‘œβ„Žπ‘šπ‘  resistor.
5. A current flows in a wire of a circular cross-section with the free electrons
travelling with a mean drift velicity 𝑣. If an equal current flows in a wire of the same
material but of twice the radius, what is the new mean drift velocity?
a) 𝑣⁄2
b) 𝑣⁄4
c) 2𝑣
d) 4𝑣
Solution:
By the definition the formula for mean drift velocity looks like:
𝑣=
𝐼
π‘›π΄π‘ž
,
where, 𝑣 is the mean drift velocity, 𝐼 is the current flowing through the wire, 𝑛 is the
charge-carrier density, 𝐴 is the the area of cross-sectionof the wire, π‘ž is the charge on
the charge-carrier.
Because current, charge-carrier density and the charge on the charge-carrier in the
wire with radius 2π‘Ÿ are the same as in the wire with radius π‘Ÿ and are constant (from
the condition of question we know that current and material are the same) we can
write:
π‘£π‘Ÿ =
𝑣2π‘Ÿ =
1
1
1
=
=
(π‘“π‘œπ‘Ÿ π‘Ÿπ‘Žπ‘‘π‘–π‘’π‘  π‘Ÿ)
𝐴 πœ‹(π‘Ÿ)2 πœ‹π‘Ÿ 2
1
1
1
=
=
(π‘“π‘œπ‘Ÿ 𝑑𝑀𝑖𝑐𝑒 π‘Ÿπ‘Žπ‘‘π‘–π‘’π‘ )
𝐴 πœ‹(2π‘Ÿ)2 4πœ‹π‘Ÿ 2
So, we can see that the mean drift velocity will be 𝑣⁄4
Answer: b) 𝑣⁄4
6. Which of the following is not correct:
a) A changing electric field can produce a changing magnetic field.
b) A steady magnetic field produces a steady current.
c) A changing magnetic field can produce a changing current.
d) A changing magnetic field can produce a steady electric field.
Answer:
A static magnetic field relative to a wire induces a zero current.
The false statement is b) A steady magnetic field produces a steady current.
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