Download Calculation Policy 2014 - St Mary`s Catholic Primary School

PROGRESSION THROUGH WRITTEN CALCULATION
+
-
x
÷
Children will use practical resources to work mathematically which also encourages them to
experiment with counting and with the number system.
Base 10
Place Value
Arrow Cards
Tens and
Units
Dice
Place Value
Counters
Numicon
Cuisenaire
Rods
Cubes/ Blocks
Dominoes
Magnets
Counters
100 Squares
Counting bears
Bead strings
1 | Page
PROGRESSION THROUGH WRITTEN CALCULATION
ADDITION +
(add, addition, more, plus, increase, sum, total, altogether, equals, inverse)
Big Maths Addition: Steps 1 – 8 (Level 1)
[Inverse Link: Page 13 Subtraction Steps 1 – 8]






1 I know when to add some more.
2 I know to find the total.
3 I add the right amount.
4 I add the right amount and can count how many altogether.
5 I can add numbers of objects to 10.
6 I can read a number sentence.
4
add
2
 7 I can arrange a number sentence.
 8 I can solve a number sentence.
2 | Page
equals
TOTAL
Big Maths Addition: Steps 9 – 20 (Level 2)
[Inverse Link: Page 14 Subtraction Steps 9 – 18]
 9 I can solve addition on a number line.
+1
+1
+1
3+4=7
+1
___________________________________________
0
1
2
3
4
5
6
7
8
9
10
+4
3+4=7
___________________________________________
3
7
 10 I can add 1 to a number up to 20.
Number Line
4+1=5
9 + 1 = 10
16 + 1 = 17
_________________________________________________________
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
100 Square
 11 I can add 2 or 3 to a number up to 20.
16 + 3 = 19
+1
+1
+1
_________________________________________________________
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
+3
_________________________________________________________
16
19
3 | Page
 12 I can add a 1 digit number to a number to 20.
16 + 7 = 23
+7
___________________________________________
16
20
 13 I can add 1 to a 2 digit number.
28 + 1 = 29
43 + 1 = 44
86 + 1 = 87
 14 I can add 10 to a 2 digit tens number.
 15 I can add 10 to any 2 digit number.
40 + 10 = 50
70 + 10 = 80
23 + 10 = 33
82 + 10 = 92
4 | Page
23
 16 I can add a 1 digit number to a 2 digit tens number.
30 + 4 = 34
50 + 6 = 56
80 + 2 = 82
 17 I can solve a 2 digit + a 1 digit number.
UNITS 2 + 4 = 6
TENS + UNITS 30 + 6 = 36
 18 I can add a 2 digit tens number to another one.
20 + 60 =
?
Start with the larger number.
60 + 20 = 80
2 tens and 6 tens are 8 tens
So
5 | Page
20 + 60 = 80
 19 I can solve any 1 digit + 1 digit number in my head.
Links to
Big Maths
Addition
Learn Its.
8 + 9 = 17
+8
___________________________________________
9
10
17
 20 I can solve any 2 digit number + 1 digit number.
Full Written Method
Abridged Writing Stage
60
60
17
17
68 + 9
60 + 17 = 77
Additional Stage if required
77
60
17
68 + 9
60 + 10 = 70
70 + 7 = 77
6 | Page
Big Maths Addition: Steps 21 – 30 (Level 3)
[Inverse Link: Page 17 Subtraction Steps 19 – 33]
 21 I can add any 2 digit tens number to another one.
80 + 90
8 tens add 9 tens are 17 tens
17 tens are 170
80 + 90 = 170
 22 I can add a 2 digit tens number to a 2 digit number.
 23 I can add any 2 digit tens number to a 2 digit number.
60
20 + 40
60
3
23 + 40
60 + 3 = 63
3
Or 20 + 40 = 60
60 + 3 = 63
63
40 + 23 = 63
+40
23
63
 24 I can add a 2 digit number to a 2 digit number.
 25 I can solve any 2 digit number + 2 digit number.
90
40 + 50
90 95
7 | Page
5
3+2
43 + 52
90 + 5 = 95
5
Or 40 + 50 = 90
3+2=5
90 + 5 = 95
Continuation of Steps 24 and 25
+10
34 + 23 = 57
+10
+3
34
44
54
57
34 + 23 = 57
+20
+3
34
54
57
34
23+
57
67
24+
91
1
 26 I can solve a 3 digit number + a 2 digit number.
400
400
50
6
56
456
432
24+
456
8 | Page
50
6
432 + 24
Hundreds
400
Tens
30 + 20 = 50
Units
2+4=6
400 + 50 + 6 = 456
267
85+
352
1 1
 27 I can solve any 3 digit number + 2 digit number.
367 + 85
Hundreds
300
Tens
60 + 80
Units
7+5
300 + 140 + 12 = 452
 28 I can solve a 3 digit number + a 3 digit number.
 29 I can solve any 3 digit number + 3 digit number.
241 + 328
Hundreds
200 + 300
Tens
40 + 20
Units
1+8
500 + 60 + 9 = 569
241
328+
569
207
453+
660
1
587
375+
962
1 1
789
642+
1431
1 1 1
 30 I can solve a 3 digit number + a 3 digit number as money.
£2.41 + £3.53 = £5.94
If…
200 + 300 = 500
40 + 50 = 90
1+3=4
9 | Page
£2.41
£3.53+
£5.94
Then…
£2.00 + £3.00 = £5.00
£0.40 + £0.50 = £0.90
£0.01 + £0.03 = £0.04
£5.00 + £0.90 + £0.04 = £5.94
Big Maths Addition: Steps 31 – 39 (Level 4)
[Inverse Link: Page 22 Subtraction Steps 34 – 36]
 31 I can solve any 3 digit number + 3 digit number as money.
£3.85 + £8.67 = £12.52
If…
300 + 800 = 1100
80 + 60 = 140
5 + 7 = 12
£ 3.85
£ 8.67+
£
£12.52 £
1 1
Then…
£3.00 + £8.00 = £11.00
0.80 + £0.60 = £1.40
0.05 + £0.07 = £0.12
£11.00 + £1.40 + £0.12 = £12.52
1
 32 I can solve a 1 decimal place number + a 1 decimal place number.
 33 I can solve any 1 decimal place number + 1 decimal place number.
4 tenths and 3 tenths are 7 tenths
8 tenths and 9 tenths are 17 tenths
So
So
0.4 + 0.3 = 0.7
0.8 + 0.9 = 1.7
not 0.17
 34 I can solve a 1 digit number to 1 decimal place + a 1 digit number to 1
decimal place.
 35 I can solve any 1 digit number to 1 decimal place + 1 digit number to 1
decimal place.
5
3+2
0.4 + 0.5
5 5.9 0.9
10 | P a g e
3.4 + 2.5
3+2=5
0.4 + 0.5 = 0.9
5 + 0.9 = 5.9
0.9
3.4
2.5+
5.9
 36 I can solve additions with numbers to 2 decimal places.
 37 I can solve any additions with numbers to 2 decimal places.
3.85 + 8.67
3 + 8 = 11
0.8 + 0.6 = 1.4
0.05 + 0.07 = 0.12
3.85
8.67+
12.52
1 1
11 + 1.4 + 0.12 = 12.52
1
 38 I can solve additions with larger numbers.
3819 + 9632
3000 + 9000 = 12000
800 + 600 = 1400
10 + 30 = 40
9 + 2 = 11
3819
9632+
13451
1 1
12000 + 1400 + 40 + 11 = 13 451
1
 39 I can solve additions with several numbers.
834
92
5+
931
1
11 | P a g e
1
6244
8
36
935+
7223
1 1 2
42
6432
786
3
4681
11944
1 1 1
Big Maths Addition: Steps 40 – 41 (Level 5)
[Inverse Link: Page 22 Subtraction Step 37]
 40 I can solve a number to 2 decimal places + a number to 1 decimal
place.
 41 I can solve any number to 2 decimal places + a number to 1 decimal
place.
3.33
2.5 +
5.83
12 | P a g e
6.71
2.9 +
9.61
1
8.67
9.8 +
18.47
1 1
PROGRESSION THROUGH WRITTEN CALCULATION FOR
SUBTRACTION (subtract, subtraction, take away, minus, decrease, leave, difference, fewer, equals, inverse)
Big Maths Subtraction: Steps 1 – 5 (Level 1)





1
2
3
4
5
[Inverse Link: Page 2 Addition Steps 1 – 5]
I know when to take some away.
I know to take some away, then count how many are left.
I take away the right amount.
I take away the right amount and count how many are left.
I can take away numbers of objects to 10.





5 take away 3
Count how many objects you have.
See how many need taking away.
Count how many you are taking away.
Check you have taken away the right
amount.
Count how many are left.
Big Maths Subtraction: Steps 6 – 19 (Level 2)
[Inverse Link: Page 2 Addition Steps 6 – 20]
 6 I can read a subtraction number sentence.
6
take
away
4
equals
 7 I can arrange a subtraction number sentence.
13 | P a g e
 8 I can solve a subtraction number sentence.
2
 9 I can solve subtraction on a number line.
-1
-1
-1
6–4=2
-1
__________________________________________
0
1
2
3
4
5
6
7
8
9
10
6–4=2
-4
__________________________________________
2
6
 10 I can take 1 from a number to 20.
Number Line
4-1=3
9-1=8
16 - 1 = 15
_________________________________________________________
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
100 Square
14 | P a g e
 11 I can take 2 or 3 from a number to 20.
-1
16 - 3 = 13
-1
-1
_________________________________________________________
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
-3
_________________________________________________________
13
16
 12 I can take a 1 digit number from a number to 20.
-6
18 - 6 = 12
___________________________________________
12
18
16 - 7 = 9
-7
___________________________________________
9
10
16
 13 I can take 10 from a multiple of 10.
 14 I can take 10 from a 2 digit number.
-10
80 – 10 = 70
___________________________________________
70
80
40 - 10 = 30
70 - 10 = 60
23 - 10 = 13
82 - 10 = 72
15 | P a g e
 15 I can take a multiple of 10 from a multiple of 10.
80 – 30 = 50
8 tens – 3 tens = 5 tens
5 tens = 50
 16 I can take a 1 digit number from a multiple of 10.
30 – 4 = 26
50 - 6 = 44
80 – 2 = 78
 17 I can solve a 2 digit number – a 1 digit number.
 18 I can solve any 2 digit number – 1 digit number.
48 - 5 = 43
-5
___________________________________________
43
48
-4
43 - 7 = 36
-3
___________________________________________
36
16 | P a g e
40
43
 19 I can solve a 3 digit number – a 1 digit number.
343 – 7 = 336
-7
___________________________________________
336
340
Big Maths Subtraction: Steps 20 – 33 (Level 3)
343
[Inverse Link: Page 7 Addition Steps 21 – 30]
 20 I can spot the next multiple of 10.
 21 I can count to the next multiple of 10.
 22 I know the gap to the next multiple of 10.
What is the next multiple of 10 after 73?
___________________________________________
73
80
80 -
= 73
- 7 = 73
Link with Jigsaw Numbers
80 – 73 = 7
7
___________________________________________
73
17 | P a g e
80
 23 I know the 1 digit gap from a multiple of 10.
 24 I know the total gap across a multiple of 10.
84 – 73 = 11
7
4
________________________________________________
73
7
80
7
4
84
4
11
11
 25 I can take a multiple of 10 from any 2 digit number.
46 – 20 = 26
26
________________________________________________
20
46
 26 I can find the 2 gaps in a 2 digit – 2 digit question.
46 – 17 = 29
26
3
________________________________________________
17
3
18 | P a g e
20
26
46
3 + 26 = 29
 27 I can solve any 2 digit number – 2 digit number.
63 – 26 = 37
33
4
________________________________________________
26
30
4
89
- 57
63
4 + 33 = 37
33
=
80
50
30
+
+
+
9
7
2 = 32
Step 3
71
- 46
=
Step 2
20
+
5 =
Step 1
-
60
40
+
+
70
40
11
6
+
+
1
6
The calculation
should be read as
e.g. take 6 from 1.
25
 28 I can take any 2 digit number from 100.
100 – 35 = 65
60
5
________________________________________________
35
40
100
65
________________________________________________
35
Link with Jigsaw
Numbers
Total = 9
(90)
19 | P a g e
2
4
7
6
100
Total = 10
= 100
 29 I can take 100 from any 3 digit number.
682 – 100 = 782
582
________________________________________________
100
682
 30 I can solve any 3 digit number – 2 digit number.
682 – 35 =
________________________________________________
35
582
65
682
________________________________________________
35
100
500 140
7
682
= 647
 31 I can solve a 4 digit number – a 2 digit number.
4628 – 35 = 4593
65
4528
________________________________________________
35
20 | P a g e
100
4628
 32 I can solve a 3 digit number – a 3 digit number.
628 – 235 = 393
328
65
________________________________________________
235
300
628
874
523 351
1
458
265 193
3
12
932
457 475
8
1
 33 I can solve a 3 digit number – a 3 digit number as money.
£6.28 - £2.35 = £3.93
£3.00 + £0.65 + £0.28 = £3.93
£3.00
£0.65
£0.28
________________________________________________
£2.35
£3.00
£6.00
£8.57 - £2.61 = £5.96
£6.28
£5.57 + £0.39 = £5.96
£5.57
£0.39
________________________________________________
£2.61
£3.00
£8.57
-
21 | P a g e
£9 . 4 6
£3 . 1 4
£6 . 3 2
7
-
£8 .15 7
£2 . 6 1
£5 . 9 6
2 1
-
1
£3 .5 6 5
£1 . 8 9
£1 . 7 6
Big Maths Subtraction: Steps 34 – 36 (Level 4)
[Inverse Link: Page 10 Addition Steps 31 – 39]
 34 I can subtract numbers with hundredths.
8.57 – 2.61 = 5.96
5.57 + 0.39 = 5.96
5.57
0.39
________________________________________________
2.61
3.00
8.57
-
7 8 .15
9.46
3.14
6.32
-
2
7
2.61
5.96
-
1
 35 I can subtract numbers with tenths.
4.5 – 1.7 = 2.8
2.5 + 0.3 = 2.8
2.5
0.3
________________________________________________
1.7
2.0
4.5
 36 I can solve any whole number subtraction question.
-
4698
167
4531
4 1
74358
2049
72309
5 1 4
-
Big Maths Subtraction: Step 37 (Level 5)
1
6452
2615
3837
4005
1998
2007
(Inverse Link: Page 12 Addition Steps 40 – 41)
 37 I can subtract numbers with different decimal places.
22 | P a g e
9
3 1 11 1
-
1
3 .5 6 5
1.89
1.76
PROGRESSION THROUGH WRITTEN CALCULATION FOR
MULTIPLICATION X
(steps, lots, groups of, times, multiply, multiplied by, repeated addition, array, product, inverse)
Big Maths Multiplication: Steps 1 – 4 (Level 1)




1
2
3
4
[Inverse Link: Page 28 Division Steps 1 – 4]
I can set out groups of toys when I play.
I can find the total amount of toys.
I can set out groups of blocks when I play.
I can find the total amount of blocks.
Set out 4 lots of 3 blocks






Set out one lot of 3
Set out another lot of 3
Set out two more lots of 3
Check you have 4 groups
Check there are 3 in each group
Count all of the objects
Big Maths Multiplication: Steps 5 – 8 (Level 2) [Inverse Link: Page 29 Division Steps 5 – 15]
 5 I can draw out groups of dots.
 6 I can find the total amount of dots.
 7 I can write out repeated addition.
3
+
3
+
=4x3
23 | P a g e
3
+
3
 8 I can solve repeated addition.
5 lots of 3 = 5 x 3 = 5 + 5 + 5
5
0
1
2
5
3
4
5
6
7
5
1
8
9
10 11 12 13 14 15
5
5
0
5
2
5
3
3
5
4
5
6
7
8
9
3
3
4 times 6
5
is
6
3
6
6
3
6 + 6 + 6 + 6 = 24
6
0
10 11 12 13 14 15
or 4 lots of 6 or 6 x 4
6
12
6
6
18
24
6
6
Big Maths Multiplication: Steps 9 – 11 (Level 3)
[Inverse Link: Page 30 Division Steps 16 – 19]
 9 I can solve a 1 digit number x a 1 digit number.
5 x 3 = 15
3 x 5 = 15
24 | P a g e
 10 I can do smile multiplication (x 2, 3, 4 and 5).
15
8
 11 I can solve a 2 digit number x a 1 digit number (x 2, 3, 4 and 5).
x
4
20
80
3 x 4 = 12
3
12
+
80
12
92
80 + 12 = 92
20 x 4 = 80
90 2
Big Maths Multiplication: Steps 12 – 17 (Level 4) [Inverse Link: Page 31 Division Steps 20 – 27]
 12 I can solve any 1 digit x 1 digit.
 x 5 = 20
3 x  = 18
 x  = 32
Links to Big
Maths
Multiplication
Learn Its.
 13 I can do any smile multiplication.
54
25 | P a g e
56
 14 I can solve any 2 digit number x 1 digit number.
x
10
6
60
10
60
14
x 6
84
24
(6 x 10) + (6 x 4)
x
6
4
60
+
24
84
4 x 6 = 24
4
24
60
24
84
+
60 + 24 = 84
10 x 6 = 60
80 4
 15 I can solve a 3 digit number x a 1 digit number.
342 x 7
x 300 40
7 2100 280
2
14
300 x 7
40 x 7
2x7
2100
+ 280
+
14
23 9 4
 16 I can solve a 2 digit number x a 2 digit number.
72 x 38
70
30
2
26 | P a g e
x
70
2
30 2100 60
8
560 16
8
70 x 30
70 x 8
20 x 30
20 x 8
2100
+ 560
+
60
+
16
2736
1
72
x 38
576
2160
2736
1
 17 I can multiply tenths.
6 x 8 = 48
7 x 3 = 21
48 ÷ 10 = 4.8
0.9 x 3 = 2.7
4.9 x 3
x 4
3 12
0.9
2.7
+
4x3
0.9 x 3
21 ÷ 10 = 2.1
12
2.7
14.7
12 + 2.7 = 14.7
4 x 3 = 12
10 4 0.7
Big Maths Multiplication: Steps 18 – 19 (Level 5) [Inverse Link: Page 33 Division Steps 28 – 33]
 18 I can multiply hundredths.
x 4
3 12
4.92 x 3
0.9
2.7
0.02
0.06
12
+ 2.7
+ 0.06
14.76
4x3
0.9 x 3
0.02 x 3
 19 I can solve a 3 digit number x a 2 digit number.
372 x 24
x
20
4
300 x 20
70 x 20
2 x 20
300
6000
1200
70
1400
280
300 x 4
70 x 4
2x4
2
40
8
6000
+ 1400
+ 1200
+ 280
+
40
+
8
8928
1
27 | P a g e
4.92
x
3
14.76
1 2
372
x
24
1488
7440
8928
1
PROGRESSION THROUGH WRITTEN CALCULATION FOR
DIVISION ÷
(halve, share, share equally, divide, divided by, left over, remainder, repeated subtraction, equals, inverse)
Big Maths Division: Steps 1 – 4 (Level 1)
[Inverse Link: Page 23 Multiplication Steps 1 – 4]
1 I can give out objects fairly.
 2 I can count how many each person was given.
 3 I can share an even number of objects between 2 people.

6 sweets shared
between 2 people,
how many do they
each get?

4 I can halve an even number of objects.
Half of 8 = 4
Big Maths Division: Steps 5 – 15 (Level 2)
[Inverse Link: Page 23 Multiplication Steps 5 – 8]
 5 I can share 6, 9, 12 or 15 objects between 3 people.
 6 I can share 6, 9, 12 or 15 objects into 3.
12 ÷ 3 = 4
28 | P a g e
15 ÷ 3 = 5




7 I can share 8, 12, 16 or 20 objects between 4 people.
8 I can share 8, 12, 16 or 20 objects into 4.
9 I can share equally to solve division problems. (÷ 2, 3 or 4)
10 I can make groups of 2, 5 or 10.
There are 6 sweets, how many people can have 2 sweets each?
 11 I can find how many altogether by counting through each group.
1, 2, 3, 4, 5, 6, 7, 8
 12 I can find how many altogether by counting in 2s, 5s or 10s.
5, 10, 15
 13 I can arrange a division number sentence.
15 blocks going into piles of 3
How many lots of 3 are there in 15?
 14 I can solve a division number sentence with objects.
3
12 ÷ 3 = 4
0
1
2
3
4
5
6
7
8
3
9
3
3
10 11 12
 15 I can solve division using objects (with remainders).
17 ÷ 3 = 5 r 2
-3
-3
-3
-3
-3
_________________________________________________
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
29 | P a g e
Big Maths Division: Steps 16 – 19 (Level 3)
[Inverse Link: Page 24 Multiplication Steps 9 – 11]
X 2, 3, 4 and 5
 16 I can use a tables fact to find a division fact.
If 6 x 4 = 24
24 ÷ 4 = 6
0
4
8
12
then
16
24 ÷ 4 = 6
20
24
* Children to use their knowledge of the Learn Its to support them with this *
 17 I can use a tables fact to find a division fact (with remainders).
13 ÷ 4 = 3 r 1
-4
0 1
-4
5
-4
9
13
 Write down the biggest multiple you can
see in the starting number. 12
 Write how many ‘lots of’ that is. 3
 Write how many are left in the starting
number to show your remainder. 1
 18 I can combine 2 or more tables facts to solve division.
 19 I can combine 2 or more tables facts to solve division (with
remainders).
65 ÷ 5 = 13
13
5 ) 65
- 50
15
- 15
00
10x
3x
Answer :
x5
13
x5
65
69
10
50
15
10
50
19
3
15
0
3
15
4
13
30 | P a g e
13
r4
Big Maths Division: Steps 20 – 27 (Level 4)
[Inverse Link: Page 25 Multiplication Steps 12 – 17]
X 6, 7, 8 and 9
 20 I can use a tables fact to find a division fact.
÷2=4
20 ÷ a = 4
÷=4
If 4 x 8 = 32
32 ÷ 8 = 4
0
8
24 ÷  = 12
then
16
y ÷ 10 = 8
32 ÷ 8 = 4
24
32
* Children to use their knowledge of the Learn Its to support them with this *
 21 I can use a tables fact to find a division fact (with remainders).
25 ÷ 7 = 3 r 4
-7
0 4
-7
-7
11
18
25
 Write down the biggest multiple you can
see in the starting number. 21
 Write how many ‘lots of’ that is. 3
 Write how many are left in the starting
number to show your remainder. 4
 22 I can combine 2 or more tables facts to solve division.
 23 I can combine 2 or more tables facts to solve division (with
remainders).
117 ÷ 9 = 13
9)
-
13
0 11 1
7
90
27
- 27
00
Answer :
x9
10x
3x
13
x6
117
89
10
90
27
10
60
29
3
27
0
4
24
5
31 | 13
Page
14
r5
72 ÷ 5
-50
-5
-5
-5
-5
r2
_______________________________________________________
1
1
1
1
10
02
7
12
17
22
72
Smile Multiplication
 24 I can use a smile multiplication fact to find a division fact.
 25 I can use a smile multiplication fact to find a division fact (with
remainders).
152 ÷ 5 = 30 r 2
30r2
30 r 2
5 ) 152
- 150
30x
02
Answer :
1
5
152
30 r 2
 26 I can combine a smile multiplication fact with a tables fact to solve
division.
165 ÷ 5 = 33
133
5 ) 165
- 150
15
- 15
00
Answer :
30x
3x
 Write down the biggest multiple you can
see in the starting number. 150
 Write how many ‘lots of’ that is. 30
 Write how many are left in the starting
number to show your remainder. 15
 Repeat the first 3 steps. 3
 Find how many ‘lots of’ there are
altogether by adding. 30 + 3 = 33
33
33
5
32 | P a g e
1
1
165
 27 I can combine a smile multiplication fact with a tables fact to solve
division (with remainders).
32r4
196 ÷ 6 = 32 r 4
32 r 4
6 ) 196
- 180
30x
16
12
2x
4
Answer :
1
1
196
6
32
1
1
196
6
32 remainder 4 or
4
6
32 r 4
Big Maths Division: Steps 28 – 33 (Level 5)
[Inverse Link: Page 27 Multiplication Steps 18 – 19]
 28 I can use a coin card to find a division fact.
 29 I can use a coin card to find a division fact (with remainders).
280 ÷ 14 = 20
x 14
286 ÷ 14 = 20 r 6
1
2
14
28
x 14
280
x 14
286
5
10
70
140
20
280
20
280
20
280
50
100
700
1400
20
6
r6
 30 I can combine 2 or more coin facts to solve division.
 31 I can combine 2 or more coin facts to solve division (with
remainders).
336 ÷ 16 = 21
x 16
359 ÷ 16 = 22 r 7
1
2
16
32
x 16
5
10
80
160
20
320
16
20
320
39
20
320
1
16
0
2
32
7
50
100
800
1600
21
33 | P a g e
336
x 16
22
359
r7
 32 I can use a tables fact to find a decimal division fact.
 33 I can combine 2 or more tables facts to solve decimal division.
* Children to use their knowledge of the Learn Its to support them with this *
0. 3
87.5 ÷ 7
7)
-
12.5
87.5
70.0
17.5
14.0
3.5
3.5
0
Answer :
34 | P a g e
8
10x
If 0.3 x 8 = 2.4
then
2
2.4
2.4 ÷ 8 = 0.3
2x
0.5x
12.5
5.3
8
4
2
42.4