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Chapter 5: Thermochemistry 1. Thermodynamics 2. Energy 3. Specific Heat 4. Enthalpy 5. Enthalpies of Reactions 6. Hess’s Law 7. State Functions 8. Standard Enthalpies of Formation 9. Determining Enthalpies of Reactions 5.1 ENERGY Energy - Capacity to Do Work (w) or Transfer Heat (q) Kinetic Energy - Energy of Motion Potential Energy - Stored Energy Thermodynamics “The science of heat and work” of energy transfer therme – heat dynamis – power (Greek) Molecular Kinetic Energy -Translational energy Ek, translational = 1/2mv2 -Rotational energy Ek, rotaional = 1/2Iw2 moment of inertia frequency I= w = rotational -Vibrational energy Ek, vibrational = 1/2Kx2 K = Hooke’s constant x = displacement from equilbrium Molecular Potential Energy Eatom –coulombic attraction of e- to nucleus Ebond – coulombic forces of covalent and ionic bonds Law of Conservation of Energy The total energy of the universe is constant Energy can not be created or destroyed, only transformed Enucleus – strong and weak nuclear forces holding nucleus together 1 Units of Energy Calorie (cal) - Amount of Energy (Heat) Required to Raise 1 Gram of Water 1 Degree Celsius (14.5 to 15.5o C) Modern Definition is Based on The Joule 1 Calorie = 4.184 Joule Note Dietary Calorie (Cal) = 1 Kcal Thermal Energy Units of Energy Two Common Units of Energy Joule –work based definition Calorie –heat based definition Joule – SI derived unit, the amount of JP Joule (1818-1889) work required to accelerate a 1 kg object 1 m/s2 a distance of 1 meter 1J 1kg m2 / sec2 Spontaneous Thermal Energy Transfer Heat (q) Flows From Hot to Cold Depends on the Temperature, # and Type of Atoms Present The Hotter an Object Is, the More Kinetic Energy It’s Constituent Atoms Posses 5.2 Heat Capacity (C) q = CDT -The heat required to induce a temperature change in a substance Is Heat an Intensive or Extensive Property? C = q/DT -The capacity of a substance to absorb heat as its temperature changes *Note: Heat capacity describes an object and has units in terms of energy per degree temperature 2 Specific Heat Capacity Specific Heat Capacity c=q mDT -the heat capacity per gram of substance q = mcDT q = Heat or Energy (cal or joule) m = Mass (in grams) c = Specific heat, the heat required to raise one gram of a substance by one degree Celsius DT = Change in Temperature (Tfinal - Tinitial) Is Specific Heat Capacity an Intensive or Extensive Property? •Specific heat capacity describes a type of substance and not a specific object. •Has Units of J/goC or cal/ goC • To know how much heat capacity an object has you need to know how much of it you have (it’s mass times it’s specific heat capacity). What Is the Specific Heat of Water? c(H2O) = 1cal/(goC) (original definition of the calorie) Specific Heat of Common Materials Substance Aluminum Graphite glass gold water(l) water(s) water(g) wood c(J/g. K) 0.902 0.72 0.888 0.128 4.184 2.06 2.01 1.76 Metals have small specific heat capacities, so it does not take much heat to raise the temperature of a metal Specific Heat of Common Materials Substance Aluminum Graphite glass gold water(l) water(s) water(g) wood c(J/g. K) 0.902 0.72 0.888 0.128 4.184 2.06 2.01 1.76 The Heat Capacity of a Substance Depends on it’s Phase 3 Calculating Energy Requirements Difference between C and c: C: Heat Capacity describes an object, like a 10 g piece of aluminum has a heat capacity of 9.02 J/K. How much Energy is Required to raise 1.000 gallon of water from 0.000 deg C to 100.0 deg C? dwater = 1 g/ml, 1 gal = 3.7854 L c: Specific Heat Capacity describes a material, aluminum has a specific heat capacity of 0.902 J/(g-K). Heat Problem What would be the final temperature if a 250 g piece of aluminum at 20.oC absorbed 1.5 kJ of energy? First Law of Thermodynamics -Total amount of energy of the universe is constant DE = q + w The change in the internal energy of a system is equal to the heat transfer and work done on/by the system with the surroundings. Interactive Quizzes 1-3 http://www.ualr.edu/rebelford/chem1402/q1402/chem1402QP.htm Internal Energy Heat of Reaction surroundings system Q (reaction) W DE = Ef - Ei = Q + W DE > 0, the system gains energy DE < 0, the system loses energy Endothermic Reaction - heat is added to the system (q is positive and the surroundings lose the heat) Exothermic Reaction - heat is lost from the system (q is negative and surroundings gain the heat) 4 5.3 Energy & Changes of State 6 Phase Changes What Are the Three Effects That Adding or Subtracting Heat Can Have on a Substance. 1. Decomposition the destruction of intramolecular bonds (chemical change) 2. Temperature Change within a phase (physical change) 3. Phase Change - Changes in the intermolecular forces (physical change) V EXO ENDO L S How Do We Quantitatively Determine the Heat Associated With Vaporization or Fusion Change? With the Molar Heat of Fusion or Vaporization Define the Molar Heat of Fusion: DHf (kJ/mol) For a Given Substance, Which Is Greater, the Molar Heat of Vaporization or the Molar Heat of Fusion? Define the Molar Heat of Vaporization: DHv(kJ/mol) Heating Diagram Calculating Energy Changes How much energy is required raise 100. g of ice from - 100C to 110oC? Given: DHf=6.02 kJ/mol DHv=40.6 kJ/mol cl=4.184 J/g.oC cv=2.01 J/g.oC cs=2.06 J/g.oC T e m p e r a t u r e (oC) Heat Added 5 Work -Work occurs when something moves against an opposing force Enthalpy DH = Enthalpy change, the heat transfer in/out of a system at constant P - Lets investigate the work of expansion at constant pressure W = FDX F = Force, X = distance W= P = F/A, F = P.A V = X.A, X = V/A (P.A)(DV/A) W = -PDV DH = qp DE = q + w w = -PDV DE = q -PDV DH = qP = DE + PDV Why is this negative? State Functions Enthalpy & Internal Energy are State Functions - their values are “path independent” and only depend on their current states, not how they were attained Is Work a State Function? 5.5 DH and Chemical Reactions Reactants + Heat --> Products -endothermic, heat was added to the reaction Sign Conventions of Energy Transfer Endothermic Reactions - absorb heat from the surroundings (DH > 0) Exothermic Reactions - release heat to the surroundings (DH < 0) DHrxn is associated with a chemical equation C(s) + 2H2(g) --> CH4(g) DH = -74.8kJ What do the units of the DH in the above reaction mean? Reactants --> Products + Heat -exothermic, heat was released by the reaction 74.8 kJ are released for every mole of carbon or for every 2 moles of hydrogen consumed 6 Is the Following Reaction Endothermic or Exothermic? CaO(s) + CO2(g) --> CaCO3(s) DH = -178 kJ DHForward = - DHreverse CaO(s) + CO2(g) --> CaCO3(s) DH = -178 kJ What is DH For the reaction: CaCO3(s) --> CaO(s) + CO2(g) Would this reaction heat the surroundings? 5.6 Calorimetry What happens when a hot object comes into thermal contact with a cold object? Calorimetry What is the final temperature if 2g of gold at 100oC is dropped into 25 ml of water at 30oC in an ideal calorimeter? cAu = 0.128J/g.oC. Heat lost by Au = Heat gained by water Insulated Jacket -Qhot = Qcold (First Law) Calorimetry 5.7 Hess’s Law Conservation of Energy What is the final temperature if 2g of gold at 100oC is dropped into 25 ml of water at 30oC in a real calorimeter? cAu = 0.128J/g.oC, Ccal = 36J/oC Heat lost by Au = Heat gained by water + calorimeter -Qhot = Qcold If the products of one reaction are consumed by another, the two equations can be coupled into a third equation. The energy of the third reaction will be the sum of the energies of the first 2 reactions (First Law) 7 Hess’s Law Hess’s Law Calculate DH for the reaction 2C(s) + O2(g) --> 2CO(g) From the reactions 2C(s) + O2(g) --> 2CO(g) DH= -231kJ E 2CO (g) + O2(g) DH= 556kJ DH= -787kJ 2C(s) + 2O2(g) --> 2CO2(g) 2CO2(g) --> 2CO (g) + O2(g) 2C(s) + 2O2(g) DH= 566kJ DH= -221kJ Calculate DH for the reaction 2S(s) + 3O2(g) --> 2SO3(g) From the reactions 1 2 2CO2(g) 2C(s) + 2O2(g) --> 2CO2(g) 2CO2(g) --> 2CO (g) + O2(g) 2C(s) + O2(g) --> 2CO(g) Hess’s Law DH= -787kJ DH= -787kJ DH= 566kJ 2 Step Path DH= -221kJ Why are Enthalpies Additive? -Enthalpy is a state function -Its value is only dependent on the state of the system, not the path -It’s a consequence of the conservation of energy S(s) + O2(g) --> SO2(g) DH=-296.8kJ 2SO2(g) + O2(g) --> 2SO3(g) DH= -197.0kJ For a Chemical Reaction Note, to cancel SO2, multiply first eq by 2 Is Not Dependent on the Steps the Reaction Involves Standard State Enthalpies DH = Hproducts-Hreactants Standard Molar Enthalpy of Formation DHo = Standard State Enthalpy Change of Reaction DHof = Standard Molar Enthalpy of Formation Standard State is the most stable form of a substance as it exists at 1 atm and 25oC. The Enthalpy Change Associated With the Formation of 1 Mol of a Substance From It’s Elements in Their Standard States For a Solution this is at a Concentration of 1M H2(g) +1/2O2(g) --> H2O(l) DHof = - 285.8kJ/mol DHof Listed in Appendix L of Text 8 Enthalpy of Formation Exercises Write the DHof equation for the following Calculate the Enthalpy of Formation of Acetylene (C2H2) from the following combustion data 1. NH4(g) 2. H2O(l) 3. O2(l) 1. 2C2H2(g) + 5O2(g) 4CO2(g) + 2H2O(l) -2600KJ 2. C(s) + O2(g) CO2(g) -394KJ 3. 2H2(g) + O2(g) 2H2O(l) -572KJ 4. O2(g) 5. O3(g) Standard Enthalpies of Reaction DHo rxn can be determined from DHof DH o rxn n [DH ( products )] m[DH (reactants ) o f o f Where n & m are the stoichiometric coefficients of the products & reactants Explain This in Terms of Enthalpy as a State Function and Hess’s Law for the following Reaction: 8Al(s) + 3Fe3O4 --> 4Al2O3(s) + 9Fe(s) Enthalpy of Vaporization for Water from Enthalpies of Formation Calculate DHVap(H2O) DHo rxn Exercises 8Al(s) + 3Fe3O4 --> 4Al2O3(s) + 9Fe(s) From Appendix 4: DHo f (Fe3O4 ) = -1118.4 kJ/mol DHo f (Al2O3 ) = -1675.7 kJ/mol 3Fe(s) + 2O2(g) Fe3O4(s) -1118.4kJ 2Al(s) + 3/2O2(g) Al3O3(s) -1675.5kJ Enthalpies of Reaction and Stoichiometric Problems 8Al(s) + 3Fe3O4 4Al2O3(s) + 9Fe(s) DHo rxn = -3363.6 kJ From Appendix 4: DHo f [H2O(l)] = -286 kJ/mol DHo f [H2O(g)] = -242 kJ/mol Determine the standard state enthalpy change when 15 g of Al react with 30.0 g of Fe3O4. 2 Steps What is the Equation that Describes Vaporization of Water? 1. Identify limiting reagent 2. Determine DH based on complete consumption of the limiting reagent 9