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Transcript
Chapter 2 Integral Forms of the Conservation Equations for Inviscid Flow 2-1 Problem Solving • 1. Physics 2. Approach methods 3. Tools (mathematics) 4. Solve the problem Approach methods : • Classical mechanics , no relativity: 1.Mass is conserved 2.Force = ma 3.Energy is conserved 2-2 Approach A. Finite Control Volume Approach (macroscopic , Integral Form ) FIG. 2-1 Finite control volume approach B. Infinitesimal Fluid Element Approach (Macroscopic , Differential Form) Eulerian coordinate Lagrangian coordinate FIG.2-2 Infinitesimal fluid element approach C. Molecular Approach (Microscopic) Statistical averaging → Boltzmann equation from kinetic theory Ref. Hirschfelder , Curtiss and Bird “Molecular Theory of Gases and Liquids” 2-3 Continuity Equation Physical principle : Mass can be neither created nor destroyed. mdenotes the mass flow u through dS u are local velocity and density at B m (u cos )ds un ds u ds FIG.2-3 Fixed control volume The net mass flow into the control volume through the entire control surface S u dS Note : s u dS (- ) inflow (+) outflow The total mass inside the control volume dV V The time rate of change of this mass inside the C.V. dV t V Mass is conserved u dS dV t V s Continuity equation (Integral Form) Applies to all flows , compressible or incompressible , viscous or inviscid 2-4 Momentum Equation Physical principle : The time rate of change of momentum of a m const. d ( mu ) F dt body equals the net force exerted on it . F ma 1. Body forces on V , eg. Gravitational and E.M forces Forces on the control volume Total body force = fdV V f Body force / mass 2. Surface forces on S , eg. P and τ pdS Total surface force due to pressure = s The total force F F fdV pdS acting on the C.V. is v s We consider inviscid flows only The total time rate of change of momentum of the fluid as it flows through a fixed control volume = the net rate of flow of momentum across the surface S + the change in momentum in V due to unsteady fluctuations in the local flow ( u dS )u s udV t V s ( u )dV t V ( u dS )u (For fixed C.V.) d ( mu ) dt Therefore : Momentum Equation ( u dS )u s V ( u ) fdV pdS t V s Fviscous 2-5 Energy Equation Physical principle : Energy can be neither created nor destroyed ; It can only change in form. ------- the 1st law of thermodynamics (δQ+δW=dE) B1= rate of heat added to the fluid inside the C.V. from the surroundings B2= rate of work done on the fluid inside the C.V. B3= rate of change of the energy of the fluid as it flows through the C.V. B1 + B 2 = B3 B1 : volumetric heating of the fluid in V due to a. Radiation b. Thermal conduction & diffusion (viscous effect) q : the rate of heat added to C.V./mass B1 qdV v B2 = the rate of doing work on a moving body = = rate of work done on the fluid + inside V due to pressure forces on S = F u rate of work done on the fluid inside V due to body forces Pu dS ( f u )dV s V B3 = net rate of flow of energy across the C.V. + time rate of change of energy inside V due to transient variations of the flow field variables = u2 u2 (e )dV s ( u dS )(e 2 ) t 2 V Therefore , qdV pu d S ( f u )dV V s V Energy Equation u2 u 2 (Integral Form , Inviscid) (e ) dV (e )u dS t 2 2 V s More general form Q W shaft W viscous pu dS ( f u )dV s V 2 2 u u (e ) dV (e )u dS t 2 2 V s