Survey
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Organic Chemistry Chemistry of Carbon Compounds (except oxides, carbides, & carbonates) Why so many C compounds? • Carbon atoms can bond with other carbon atoms in chains, rings, and networks. • Bonds are covalent. Lewis Diagram of C • •C• • Carbon has 4 unpaired electrons. It can form 4 covalent bonds. Note: C can form only 3 bonds to any other single C atom. Bonding Capacity of H, O, etc. • H can form only 1 bond. • O and S like to form 2 bonds. • The halogens (F, Cl, Br, I) form only 1 bond. • N and P form 3 bonds. Properties of Covalent Substances • • • • • • (also called molecular substances) Low melting & boiling points Poor conductors of heat & electricity May be soft or brittle Generally nonpolar – van der Waals forces Tend to dissolve in nonpolar solvents React more slowly than ionic compounds Chemical Formulas • show kind & number of atoms. CH3OH CH4 CH2Cl2 CH3Cl Structural Formulas • Show kind & number of atoms. • Also show bonding patterns and approximate shapes of molecules. • 2-D rep of 3-D object so structural formulas aren’t totally realistic. H H–C–H H Structural Formulas • – A single line represents one pair of electrons (a single bond). • = A double line represents two pairs of electrons (a double bond). • A triple line represents three pairs of electrons (a triple bond). Shape • The 4 unpaired electrons around the C atom are located at the corners of a tetrahedron. • 109.5 apart. Vocabulary Interlude • Saturated: organic compounds containing only Single bonds. • Unsaturated: organic compounds containing one or more double or triple bonds. Vocabulary • Hydrocarbons: organic compounds containing only C and H. • Homologous Series: a group of compounds with related structures and properties. Each member of the series differs from the one before it by the same additional unit. Homologous Series • The molecules have a fixed, numerical relationship among the numbers of atoms. Condensed Structural Formula • Shows kind & number of atoms • Shows some structural information, but not all the details. Fits on 1 line of type. H H H H–C–C–C–H H H H Becomes CH3CH2CH3 Alkanes • Homologous series of saturated hydrocarbons. • Release energy when burned. CH4 H H–C–H H C2H6 H H H–C–C–H H H • C2H6 is also written CH3CH3 Space-filling model Above: 3 representations of CH4. Below: Ball and stick model of ethane. Alkanes or CnH2n+2 • C3H8 Chemical Formula CH3CH2CH3 Condensed Structural Formula H H H H–C–C–C–H H H H Structural Formula Ball & stick model of propane. Bond angles = 109. th 4 straight-chain alkane C4H10 H H H H H–C–C–C–C–H H H H H Or CH3CH2CH2CH3 Ball and Stick model of butane. Alkanes: base unit CH4 CH3CH3 or C2H6 CH3CH2CH3 or C3H8 CH3CH2CH2CH3 or C4H10 CH3CH2CH2CH2CH3 or C5H12 Difference between each is CH2 Naming straight-chain Alkanes • Name describes molecule so you can draw it. • All alkanes have the suffix –ane. • The prefix depends on the number of C’s. Prefix Meth Eth Prop But Pent Hex Hept Oct Non Dec # of C atoms 1 2 3 4 5 6 7 8 9 10 Formula CH4 C2H6 C3H8 C4H10 C5H12 Name Meth + ane Ethane Propane Butane Pentane Properties of Alkanes • Change systematically with number of C’s • As the number of C’s increases, the boiling point increases. – The molecules get heavier & harder to change into the gas phase. Properties of Alkanes • • • • • • Low Reactivity Except readily undergo combustion – fuels Nonpolar – Don’t dissolve well in water. Low melting pts & boiling pts. (M.P. & B.P. increase with molecular mass) High vapor pressures Which property is generally characteristic of an organic compound? A. B. C. D. Low melting point High melting point Soluble in polar solvents Insoluble in nonpolar solvents Correct response = A Which of the following compounds has the highest boiling point? A. B. C. D. CH4 C2H6 C3H8 C4H10 Correct answer = D. In nonpolar covalent compounds, the boiling point depends on the strength of the van der Waals interactions. The van der Waals forces increase as the size of the molecule increases. (Bigger molecule, bigger electron cloud.) Branched-chain alkanes • Beginning with butane, C4H10, there is more than 1 way to arrange the atoms. H H–C–H H H H–C–C–C–H H H H Branched alkane. Can’t link all the C’s without lifting pencil off the paper. Methyl propane Isomers • Compounds with the same molecular formula but different structural arrangement. • The more C atoms there are in the formula, the more isomers there will be. More possible ways to arrange them. Isomers • Different structures, different properties. • Isomers have different chemical and physical properties. A note about isomers --• If you are comparing 2 structural formulas & you can superimpose them, they are not isomers – they are the same molecule! • If you can rotate or flip one of the structural formulas & then superimpose it on the other one, they are not isomers – they are the same molecule! These diagrams represent the same molecule. Represents bond to H These diagrams represent the same molecule. Represents bond to H These diagrams represent the same molecule. Represents bond to H Two different molecules! Represents bond to H Naming Branched-Chain Alkanes • The goal of the name is to describe the molecule so you can draw it. Naming branched-chain alkanes • Find the longest continuous chain or backbone of C atoms. (Bends don’t count!) • The base name is derived from the number of C’s in the longest chain. • Branches are named in the prefix. Branches are also named by the number of C atoms. The “branch” part of the name ends in “yl.” • The location of the branch is shown by assigning numbers to the C’s in the backbone. Number from the end that gives the lowest number for the branch. • There may be more than 1 of the same type of branch. Use di, tri, etc. H H–C–H H H H–C–C–C–H H H H Longest continuous chain has 3 carbon atoms – propane. Branch has 1 carbon – methyl. Branch has to be at C-2. (Only give the number if necessary.) Methyl propane C4H10 CH3CH(CH3)CH3 H H–C–H H–C–H HH H H–C–C–C–C–H H H H H–C–H H Longest continuous chain has 6 carbon atoms. It’s a hexane. Branch is 1 carbon long – methyl. Branch is located at C-2. 2-methyl hexane C7H16 CH3CH(CH3)CH2CH2CH2CH3 A note about branches • If you have several branches with the same # of C atoms, you can condense the name a little. • 2-methyl 3-methyl pentane becomes 2,3dimethyl pentane. • The # of numbers must match the # of branches. H H–C–H H H H H– C–C–C–C–H H H H–C–H H–C–H H H Longest continuous chain has 6 carbon atoms: hexane Branch is 1 carbon long: methyl Branch is located at C-3 3-methyl hexane C7H16 CH3CH2CH2CH(CH3)CH2CH3 CH3(CH2)2CH(CH3)CH2CH3 Alkenes • Another homologous series of hydrocarbons. • Each member contains one double covalent bond between C atoms. So alkenes are unsaturated. • General formula = CnH2n Naming Alkenes • Names: # of C’s in parent chain gives prefix. Suffix = -ene. 1st member is C2H4, ethene. H H C=C H H Alkenes with 4 or more C’s • Number C atoms. • Use lowest possible # to specify location of 1st C in double bond. Naming Alkenes • Number C atoms in backbone. Give double bond the lowest possible number. 1-butene H HH C=C–C–C–H H H H H 2-butene H H HH H–C–C=C–C–H H H C4H8 C4H8 CH2CHCH2CH3 CH3CHCHCH3 Naming Branched-Chain Alkenes • Parent chain = longest chain that contains the double bond. • Also, position of double bond, not branches, determines numbering of backbone. • Give 1st C in bond lowest possible #. Properties of Alkenes • Nonpolar – low solubility in H2O • Fairly low M.P. & B.P. • More reactive than alkanes – double bond = site of reactivity. Alkynes • Homologous series of unsaturated hydrocarbons that contain one triple bond. • Each member contains one triple carboncarbon bond. – • Alkynes are unsaturated. General formula = CnH2n-2 Naming Alkynes • Name: Prefix depends on # of C’s. Suffix = -yne. • If necessary, number the 1st carbon atom at which the triple bond occurs. H–CC–H C2H2 ethyne H H–CC–C–H H C3H4 propyne CHCCH3 1-butyne CHCCH2CH3 HH H–CC–C–C–H HH C4H6 H H H–C–CC–C–H H H C4H6 2-butyne CHCH CH3CCCH3 3 Homologous Series of HC’s Name of Series General Formula Ending Alkanes CnH2n+2 -ane Alkenes CnH2n -ene Alkynes CnH2n-2 -yne Which compound belongs to the alkene series? A. B. C. D. C2H2 C2H4 C6H6 C6H14 Correct answer = B. Alkenes follow the format CnH2n. A & C are CnHn. D is CnH2n+2. In which group could the hydrocarbons all belong to the same homologous series? A. B. C. D. C2H2, C2H4, C2H6 C2H4, C3H4, C4H8 C2H4, C2H6, C3H6 C2H4, C3H6, C4H8 Correct answer = D. Members of a homologous series all have the same relationship between the atoms. Every compound in set D fits the formula CnH2n. Which of the following is a saturated hydrocarbon? A. B. C. D. Ethene Ethyne Propene Propane Correct answer = D. The alkanes are saturated.