Multiple Choice:
... 1. No, the speed does not change. The force is perpendicular to the velocity and so only the direction of the velocity changes, not the magnitude. The force is centripetal. 2. While it is true that the acceleration due to gravity is dependent upon distance from the center of the earth, and so does t ...
... 1. No, the speed does not change. The force is perpendicular to the velocity and so only the direction of the velocity changes, not the magnitude. The force is centripetal. 2. While it is true that the acceleration due to gravity is dependent upon distance from the center of the earth, and so does t ...
Sects. 4.9 & 4.10
... particles relative to a rotating coordinate system. • Important application: Motion relative to coordinates of the rotating Earth. “The Coriolis Effect” comes in. An example of “fictitious” or non-inertial forces! Next, we will discuss noninertial forces in general. After the general discussion, the ...
... particles relative to a rotating coordinate system. • Important application: Motion relative to coordinates of the rotating Earth. “The Coriolis Effect” comes in. An example of “fictitious” or non-inertial forces! Next, we will discuss noninertial forces in general. After the general discussion, the ...
Forces Notes - watertown.k12.wi.us
... “An object rotating about an axis tends to remain rotating about that same axis unless it is interfered with by some external force.” This definition is similar to Newton’s ...
... “An object rotating about an axis tends to remain rotating about that same axis unless it is interfered with by some external force.” This definition is similar to Newton’s ...
Lever Arm
... Causing Rotational Motion • In order to make an object start rotating about an axis, a force is required • However, not only the amount of force applied but also the position from the axis to which it is applied is important in determining the amount of rotation (angular acceleration • Distance fro ...
... Causing Rotational Motion • In order to make an object start rotating about an axis, a force is required • However, not only the amount of force applied but also the position from the axis to which it is applied is important in determining the amount of rotation (angular acceleration • Distance fro ...
Newton`s 1st, 2nd and 3rd Law
... Snoopy has a mass of 15kg and kicks a 0.4kg ball with a force of 15N. a)Draw the free body diagram showing the forces acting on each object. b)With what force does the ball kick Snoopy and why? c)What was the acceleration of the ball? d)What was the acceleration of Snoopy? Ans: b) 15N, c) 37.5m/s2 d ...
... Snoopy has a mass of 15kg and kicks a 0.4kg ball with a force of 15N. a)Draw the free body diagram showing the forces acting on each object. b)With what force does the ball kick Snoopy and why? c)What was the acceleration of the ball? d)What was the acceleration of Snoopy? Ans: b) 15N, c) 37.5m/s2 d ...
Name: Date:______ Period:_____ Chapter 19 Honors Study Guide
... What are the proper units for: -acceleration? ___m/s2_______ -velocity? ___m/s + direction - speed? _________m/s________ Essays 1. A pitcher releases a fastball that moves toward home plate. Other than the force exerted by the pitcher, what are two forces that act on the ball as it travels between t ...
... What are the proper units for: -acceleration? ___m/s2_______ -velocity? ___m/s + direction - speed? _________m/s________ Essays 1. A pitcher releases a fastball that moves toward home plate. Other than the force exerted by the pitcher, what are two forces that act on the ball as it travels between t ...
Uniform Circular Motion
... NO. There is no longer a force pulling it towards the center. It will follow the path of the velocity vector, which is tangent to the circle. The ball with continue on a straight path. ...
... NO. There is no longer a force pulling it towards the center. It will follow the path of the velocity vector, which is tangent to the circle. The ball with continue on a straight path. ...
Newton`s Laws - AdvancedPlacementPhysicsC
... An object in motion remains in motion in a straight line and at a constant speed OR an object at rest remains at rest, UNLESS acted upon by an EXTERNAL (unbalanced) force. acc 0 F 0 The bottom line: There is NO ACCELERATION (no change in velocity) unless a force acts, but you can have MOTIO ...
... An object in motion remains in motion in a straight line and at a constant speed OR an object at rest remains at rest, UNLESS acted upon by an EXTERNAL (unbalanced) force. acc 0 F 0 The bottom line: There is NO ACCELERATION (no change in velocity) unless a force acts, but you can have MOTIO ...
Rotational Motion - SFA Physics and Astronomy
... directed “force.” They would feel pressed against the outer rim of the habitat and would experience the sensation of weight due to this force. The centripetal force is proportional to r2 and would be greater the farther from the center the occupant lives. This simulated gravity would, therefore, va ...
... directed “force.” They would feel pressed against the outer rim of the habitat and would experience the sensation of weight due to this force. The centripetal force is proportional to r2 and would be greater the farther from the center the occupant lives. This simulated gravity would, therefore, va ...
Force and the Laws of Motion
... 1. The upward force on an object falling through the air is ____. a. air resistance c. momentum b. inertia d. terminal velocity 2. The relationship among mass, force, and acceleration is explained by ____. a. conservation of momentum b. Newton's first law of motion c. Newton's second law of motion d ...
... 1. The upward force on an object falling through the air is ____. a. air resistance c. momentum b. inertia d. terminal velocity 2. The relationship among mass, force, and acceleration is explained by ____. a. conservation of momentum b. Newton's first law of motion c. Newton's second law of motion d ...
Chapter 7 Rotating Frames
... horizontally, N = −mω 2 x. Recall that |R| 6 µ|N| from §1.6.2, where µ is the coefficient of static friction; so mg 6 µmω 2 a, ...
... horizontally, N = −mω 2 x. Recall that |R| 6 µ|N| from §1.6.2, where µ is the coefficient of static friction; so mg 6 µmω 2 a, ...