
Student practical Name Class Date Charging by friction
... 1 Create a hammock which can hold a rod horizontally and which can be hung from the clamp so that the rod swings freely. 2 Rub two insulating rods of the same type with the same type of cloth. 3 Rest one of the rods in the hammock so that it hangs horizontally and can swing freely. 4 Hold the other ...
... 1 Create a hammock which can hold a rod horizontally and which can be hung from the clamp so that the rod swings freely. 2 Rub two insulating rods of the same type with the same type of cloth. 3 Rest one of the rods in the hammock so that it hangs horizontally and can swing freely. 4 Hold the other ...
AQA M1 - The Further Mathematics Support Programme
... Live Interactive Lectures are available for individual Further Pure and Applied units and take place in the spring and autumn terms. LIL FM is ideal for schools/colleges teaching Further Mathematics with small groups and/or limited time allocation. It is also useful to support less experienced teach ...
... Live Interactive Lectures are available for individual Further Pure and Applied units and take place in the spring and autumn terms. LIL FM is ideal for schools/colleges teaching Further Mathematics with small groups and/or limited time allocation. It is also useful to support less experienced teach ...
CSS - CBSE Guess
... Q.2> A particle of mass 5kg is kept at the point 2i + 3j + 7k. Another particle of mass 3kg is kept at the point having position vector 5i – 7j –k. Find the position vector of the CoM. If no external force is acting on the system, how would the position of CoM change? Q.3> A particle “P” having mass ...
... Q.2> A particle of mass 5kg is kept at the point 2i + 3j + 7k. Another particle of mass 3kg is kept at the point having position vector 5i – 7j –k. Find the position vector of the CoM. If no external force is acting on the system, how would the position of CoM change? Q.3> A particle “P” having mass ...
Chapter 5
... • We need to re-examine problems we formerly did as "ideal." • We need to be able to find frictional forces given the mass of the object and the nature of the surfaces in contact with each other. • There are two regions of friction: 1) when an object is sliding with respect to a surface kinetic-fr ...
... • We need to re-examine problems we formerly did as "ideal." • We need to be able to find frictional forces given the mass of the object and the nature of the surfaces in contact with each other. • There are two regions of friction: 1) when an object is sliding with respect to a surface kinetic-fr ...
ectrostatics Review KEY 1/19
... 29. In your lab, when two pieces of tape were pulled from the surface, the pieces of tape repelled one another because A) They were oppositely charged B) they became electrically charged. C) they were conducting electricity 30. The reason a charged balloon will stick to a wall is that A) electrons t ...
... 29. In your lab, when two pieces of tape were pulled from the surface, the pieces of tape repelled one another because A) They were oppositely charged B) they became electrically charged. C) they were conducting electricity 30. The reason a charged balloon will stick to a wall is that A) electrons t ...
Doris williams - HCC Learning Web
... This exists when the object is at rest relative to the surface. This force must be overcome in order to make the object start moving. It is given by fs = µs n. b) Kinetic friction ( fk) This exists when the object is in motion and is given by fk = µk n. where µs and µk are the coefficient of static ...
... This exists when the object is at rest relative to the surface. This force must be overcome in order to make the object start moving. It is given by fs = µs n. b) Kinetic friction ( fk) This exists when the object is in motion and is given by fk = µk n. where µs and µk are the coefficient of static ...
1 - hrsbstaff.ednet.ns.ca
... are gravitationally attracted to each other. Determine the magnitude of this force of gravitational attraction. (3.31*10-7N) 29. Determine the force of gravitational attraction between the Earth and the moon. Their masses are 5.98 x 1024 kg and 7.26 x 1022 kg, respectively. The average distance sepa ...
... are gravitationally attracted to each other. Determine the magnitude of this force of gravitational attraction. (3.31*10-7N) 29. Determine the force of gravitational attraction between the Earth and the moon. Their masses are 5.98 x 1024 kg and 7.26 x 1022 kg, respectively. The average distance sepa ...
algebra - Nuffield Foundation
... (a) Draw force diagrams showing the forces acting on (i) the suitcase (ii) the hotel guest as the lift sets off from the ground floor. (b) Use Newton's Second Law at the time the lift sets off from the ground floor to find (i) the force exerted by the hotel guest on her suitcase. (ii) the normal rea ...
... (a) Draw force diagrams showing the forces acting on (i) the suitcase (ii) the hotel guest as the lift sets off from the ground floor. (b) Use Newton's Second Law at the time the lift sets off from the ground floor to find (i) the force exerted by the hotel guest on her suitcase. (ii) the normal rea ...
Solutions to semester2 practice problems - Head
... a. what is the weight of the object? mg = 20N b. what is the mass of the object? m = 2 kg c. what is the force of gravity acting on the object? mg = 20N d. what is the acceleration when it falls (ignoring air resistance)? a = 10 m/s/s e. what is the value of “g” for this object? g = 10 m/s/s 5. A 1 ...
... a. what is the weight of the object? mg = 20N b. what is the mass of the object? m = 2 kg c. what is the force of gravity acting on the object? mg = 20N d. what is the acceleration when it falls (ignoring air resistance)? a = 10 m/s/s e. what is the value of “g” for this object? g = 10 m/s/s 5. A 1 ...
Student Class ______ Date ______ MULTIPLE
... 5. A soccer ball kicked on a level field has an initial vertical velocity component of 15.0 meters per second. Assuming the ball lands at the same height from which it was kicked, what is the total time the ball is in the air? [Neglect friction.] (1) 0.654 s (3) 3.06 s (2) 1.53 s (4) 6.12 s ...
... 5. A soccer ball kicked on a level field has an initial vertical velocity component of 15.0 meters per second. Assuming the ball lands at the same height from which it was kicked, what is the total time the ball is in the air? [Neglect friction.] (1) 0.654 s (3) 3.06 s (2) 1.53 s (4) 6.12 s ...
Free fall

In Newtonian physics, free fall is any motion of a body where its weight is the only force acting upon it. In the context of general relativity, where gravitation is reduced to a space-time curvature, a body in free fall has no force acting on it and it moves along a geodesic. The present article only concerns itself with free fall in the Newtonian domain.An object in the technical sense of free fall may not necessarily be falling down in the usual sense of the term. An object moving upwards would not normally be considered to be falling, but if it is subject to the force of gravity only, it is said to be in free fall. The moon is thus in free fall.In a uniform gravitational field, in the absence of any other forces, gravitation acts on each part of the body equally and this is weightlessness, a condition that also occurs when the gravitational field is zero (such as when far away from any gravitating body). A body in free fall experiences ""0 g"".The term ""free fall"" is often used more loosely than in the strict sense defined above. Thus, falling through an atmosphere without a deployed parachute, or lifting device, is also often referred to as free fall. The aerodynamic drag forces in such situations prevent them from producing full weightlessness, and thus a skydiver's ""free fall"" after reaching terminal velocity produces the sensation of the body's weight being supported on a cushion of air.