![Notes -- Unit 5 -- Reactions and Stoichiometry](http://s1.studyres.com/store/data/008694413_1-57db88952f8ccc10dee1133ca68e5db3-300x300.png)
Notes -- Unit 5 -- Reactions and Stoichiometry
... Shows what state of matter the compounds are in: Solid (s), Liquid (l), Gas (g), or dissolved in water (aqueous ...
... Shows what state of matter the compounds are in: Solid (s), Liquid (l), Gas (g), or dissolved in water (aqueous ...
ANSWERS Problem Set 5a – Chemical Reactions
... Subscripts are underlined, Coefficients are boxed 3 H2SO4+ 2 Al Al2(SO4)3 + 3 H2 11) Write the word equation for the following balanced reactions: a. 2 Mg (s) + O2 (g) 2 MgO (s) solid magnesium reacts with oxygen gas to produce solid magnesium oxide in a synthesis reaction. b. HCl (aq) + NaOH (a ...
... Subscripts are underlined, Coefficients are boxed 3 H2SO4+ 2 Al Al2(SO4)3 + 3 H2 11) Write the word equation for the following balanced reactions: a. 2 Mg (s) + O2 (g) 2 MgO (s) solid magnesium reacts with oxygen gas to produce solid magnesium oxide in a synthesis reaction. b. HCl (aq) + NaOH (a ...
ION-SELECTIVE ELECTRODES - Clayton State University
... - The study of the interconversion of chemical energy and electrical energy - The study of redox reactions - Electrochemical processes involve the transfer of electrons from one substance to another ...
... - The study of the interconversion of chemical energy and electrical energy - The study of redox reactions - Electrochemical processes involve the transfer of electrons from one substance to another ...
Equilibrium 5
... 5. At a certain temperature, a 1.00-L flask initially contained 0.298 moles of PCl3 (g) and 8.7 x 10-3 moles of PCl5 (g). After the system had reached equilibrium, 2.00 x 10-3 moles of Cl2 (g) was found in the flask. Gaseous PCl5 decomposes according to the reaction: PCl5 (g) ...
... 5. At a certain temperature, a 1.00-L flask initially contained 0.298 moles of PCl3 (g) and 8.7 x 10-3 moles of PCl5 (g). After the system had reached equilibrium, 2.00 x 10-3 moles of Cl2 (g) was found in the flask. Gaseous PCl5 decomposes according to the reaction: PCl5 (g) ...
Describe properties of particles and thermochemical - Mr
... a group, the shielding from the inner shells of electrons more than compensates for the increased nuclear charge, so it requires less energy to remove electrons. a) Across the table there is an increase in ionisation energy. This is because going across a row there is an increase in nuclear charge, ...
... a group, the shielding from the inner shells of electrons more than compensates for the increased nuclear charge, so it requires less energy to remove electrons. a) Across the table there is an increase in ionisation energy. This is because going across a row there is an increase in nuclear charge, ...
Chemical Equilibrium
... insignificant. If you need 2 sig figs, then it must be about 100 times smaller. If you need 3 sig figs it must be about 1000 times smaller. A good general rule for our purposes is that if a number is <5% of another number, it is significantly smaller. This maintains 2 sig figs in all the concentrati ...
... insignificant. If you need 2 sig figs, then it must be about 100 times smaller. If you need 3 sig figs it must be about 1000 times smaller. A good general rule for our purposes is that if a number is <5% of another number, it is significantly smaller. This maintains 2 sig figs in all the concentrati ...
chapter 8 - Denton ISD
... carbon or hydrogen atoms. Usually, the elements hydrogen and oxygen are balanced only after balancing all other elements in an equation. (You will read more about the rules of balancing equations later in the chapter.) Thus, we begin by counting carbon atoms. Inspecting the formula equation reveals ...
... carbon or hydrogen atoms. Usually, the elements hydrogen and oxygen are balanced only after balancing all other elements in an equation. (You will read more about the rules of balancing equations later in the chapter.) Thus, we begin by counting carbon atoms. Inspecting the formula equation reveals ...
APEF – Equilibrium and Reaction Rate Multiple Choice Answers
... 13. Which phrase could be a definition of the activation energy of a reaction? A. the energy gained by reactant molecules to undergo a reaction B. the energy supplied by the attractive forces between molecules C. the energy supplied by a catalyst D. the heat content of the products minus that of the ...
... 13. Which phrase could be a definition of the activation energy of a reaction? A. the energy gained by reactant molecules to undergo a reaction B. the energy supplied by the attractive forces between molecules C. the energy supplied by a catalyst D. the heat content of the products minus that of the ...
chapter 8
... carbon or hydrogen atoms. Usually, the elements hydrogen and oxygen are balanced only after balancing all other elements in an equation. (You will read more about the rules of balancing equations later in the chapter.) Thus, we begin by counting carbon atoms. Inspecting the formula equation reveals ...
... carbon or hydrogen atoms. Usually, the elements hydrogen and oxygen are balanced only after balancing all other elements in an equation. (You will read more about the rules of balancing equations later in the chapter.) Thus, we begin by counting carbon atoms. Inspecting the formula equation reveals ...
Kinetics and Equilibrium ___ 1. In a chemical reaction the use of a
... ___ 41. A catalyst can increase the rate of a chemical reaction by (1) increasing the value of the equilibrium constant; (2) increasing the energy of the products; (3) decreasing the energy of the products; (4) decreasing the required activation energy. ___ 42. For a chemical system at equilibrium ...
... ___ 41. A catalyst can increase the rate of a chemical reaction by (1) increasing the value of the equilibrium constant; (2) increasing the energy of the products; (3) decreasing the energy of the products; (4) decreasing the required activation energy. ___ 42. For a chemical system at equilibrium ...
IWC-14-01 Comparison of Continuous Electrodeionization
... (H+) or hydroxide (OH-) form allow the and into the concentrate chamber due to exchange of contaminant cations and their attraction to the anode. Concentrate anions with hydrogen or hydroxide ions. and electrode flush water exits the EDI The released hydrogen and hydroxide ions module and is most of ...
... (H+) or hydroxide (OH-) form allow the and into the concentrate chamber due to exchange of contaminant cations and their attraction to the anode. Concentrate anions with hydrogen or hydroxide ions. and electrode flush water exits the EDI The released hydrogen and hydroxide ions module and is most of ...
1.6 Energy changes in chemical reactions
... Many of the devices that we use every day—including mobile phones—depend on batteries. Electric cars offer a low pollution future, but a big limitation is the size and cost of their batteries. Chemistry is at the heart of research to find new, lighter, low-cost batteries that are quickly charged. In ...
... Many of the devices that we use every day—including mobile phones—depend on batteries. Electric cars offer a low pollution future, but a big limitation is the size and cost of their batteries. Chemistry is at the heart of research to find new, lighter, low-cost batteries that are quickly charged. In ...
A flask contains 0
... Look for the word approximate in the question, if there, you can use estimation to help arrive at the answer. Strategies on the multiple choice questions: All multiple choice questions count the same amount…whether it took you 5 minutes or 15 seconds. Go through the test completely once, answe ...
... Look for the word approximate in the question, if there, you can use estimation to help arrive at the answer. Strategies on the multiple choice questions: All multiple choice questions count the same amount…whether it took you 5 minutes or 15 seconds. Go through the test completely once, answe ...
a ΔG - KFUPM Resources v3
... + 3[ΔGf (O2(g)] – 2[ΔGf (KClO3(s)] = 2[– 408.3 kJ/mol] + 3 [0] – 2[ – 289.9 kJ/mol] = – 816.6 – (– 579.8) = – 236.8 kJ/mol o The reaction is spontaneous. o A negative ΔG corresponds to a larger equilibrium constant (K), while a positive ΔG corresponds to a smaller equilibrium constant (K). Dr. A ...
... + 3[ΔGf (O2(g)] – 2[ΔGf (KClO3(s)] = 2[– 408.3 kJ/mol] + 3 [0] – 2[ – 289.9 kJ/mol] = – 816.6 – (– 579.8) = – 236.8 kJ/mol o The reaction is spontaneous. o A negative ΔG corresponds to a larger equilibrium constant (K), while a positive ΔG corresponds to a smaller equilibrium constant (K). Dr. A ...
chemistry writing team
... (c) Calculate the volume of 0.1 M NaOH solution is required to neutralise 100 mL of concentrated aqueous sulphuric acid which contains 98% H2SO4 by mass. The density of conc. H2SO4 is 1.84 g/mL. NaOH reacts with H2SO4 according to the following equation : 2NaOH + H2SO4 → Na2SO4 + 2H2O (At. mass/g mo ...
... (c) Calculate the volume of 0.1 M NaOH solution is required to neutralise 100 mL of concentrated aqueous sulphuric acid which contains 98% H2SO4 by mass. The density of conc. H2SO4 is 1.84 g/mL. NaOH reacts with H2SO4 according to the following equation : 2NaOH + H2SO4 → Na2SO4 + 2H2O (At. mass/g mo ...
Section 1 The Nature of Chemical Reactions
... single compound breaks down to form two or more simpler substances. • Decomposition reactions have the following general form: AB → A + B • Example: The following shows the decomposition of water. • 2H2O → 2H2 + O2 • Electrolysis is the process in which an electric current is used to produce a chemi ...
... single compound breaks down to form two or more simpler substances. • Decomposition reactions have the following general form: AB → A + B • Example: The following shows the decomposition of water. • 2H2O → 2H2 + O2 • Electrolysis is the process in which an electric current is used to produce a chemi ...
Mole/Stoich PowerPoint Notes
... Limiting reactant is the chemical in a reaction that restricts how much you can make, it’s the reactant that runs out first. STEP 1: Write the balanced equation! STEP 2: Find desired product in grams. You Will need to do 2 stoich problems. STEP 3:The reactant that gives you the smaller amount of pro ...
... Limiting reactant is the chemical in a reaction that restricts how much you can make, it’s the reactant that runs out first. STEP 1: Write the balanced equation! STEP 2: Find desired product in grams. You Will need to do 2 stoich problems. STEP 3:The reactant that gives you the smaller amount of pro ...
A STUDY OF THE RATE OF THE REACTION OF CHLORINE
... • The blue dye (FD & C #1) has an absorbance maximum at 630 nm. • We will supply you with a solution of the food dye. (We use 18 drops of “Club House” Brand blue food colouring per litre of solution. The blue colouring comes in a set of four different food colours, available at the supermarket.) • T ...
... • The blue dye (FD & C #1) has an absorbance maximum at 630 nm. • We will supply you with a solution of the food dye. (We use 18 drops of “Club House” Brand blue food colouring per litre of solution. The blue colouring comes in a set of four different food colours, available at the supermarket.) • T ...
An Introduction to Redox
... reaction by making sure that the number of electrons lost by the reducing agent equals the number of electrons gained by the oxidizing agent. The oxidation number method is the method we will use to balance redox equations. It consists of five steps that use the change in oxidation numbers to ...
... reaction by making sure that the number of electrons lost by the reducing agent equals the number of electrons gained by the oxidizing agent. The oxidation number method is the method we will use to balance redox equations. It consists of five steps that use the change in oxidation numbers to ...
Electrolysis of water
Electrolysis of water is the decomposition of water (H2O) into oxygen (O2) and hydrogen gas (H2) due to an electric current being passed through the water.This technique can be used to make hydrogen fuel (hydrogen gas) and breathable oxygen; though currently most industrial methods make hydrogen fuel from natural gas instead.