Slide 1
... Analyze: We are asked to judge whether each process will proceed spontaneously in the direction indicated, in the reverse direction, or in neither direction. Plan: We need to think about whether each process is consistent with our experience about the natural direction of events or whether we expect ...
... Analyze: We are asked to judge whether each process will proceed spontaneously in the direction indicated, in the reverse direction, or in neither direction. Plan: We need to think about whether each process is consistent with our experience about the natural direction of events or whether we expect ...
19 BROWN Chemical Thermodynamics PPTSExercise
... Analyze: We are asked to judge whether each process will proceed spontaneously in the direction indicated, in the reverse direction, or in neither direction. Plan: We need to think about whether each process is consistent with our experience about the natural direction of events or whether we expect ...
... Analyze: We are asked to judge whether each process will proceed spontaneously in the direction indicated, in the reverse direction, or in neither direction. Plan: We need to think about whether each process is consistent with our experience about the natural direction of events or whether we expect ...
Sample Chem 111 Final
... 40. A given mass of gas in a rigid container is heated from 100 ºC to 500 ºC. Which of the following responses best describes what will happen to the pressure of the gas? a) The pressure will decrease by a factor of five. b) The pressure will increase by a factor of five. c) The pressure will incre ...
... 40. A given mass of gas in a rigid container is heated from 100 ºC to 500 ºC. Which of the following responses best describes what will happen to the pressure of the gas? a) The pressure will decrease by a factor of five. b) The pressure will increase by a factor of five. c) The pressure will incre ...
2011 Exam 2 Key
... the answer must be clear. The final answer must be reported to the correct number of significant figures and have the correct units. Questions are written on both sides of each page. The last page contains useful information and a periodic table; the last page should be removed and used for scratch ...
... the answer must be clear. The final answer must be reported to the correct number of significant figures and have the correct units. Questions are written on both sides of each page. The last page contains useful information and a periodic table; the last page should be removed and used for scratch ...
50 Frequently Forgotten Facts Answer Key
... 4) Natural Decay: Parent Nuclide Decay particle + daughter nuclide [Tables N and O] a) Write the decay for U-238: _______ 23892U 42He + 23490Th_________ when the atomic # changes, the ID of the element changes as well. b) Write the decay for K-37:________ 3719K 0+1e + 3718Ar ____________ c) Wr ...
... 4) Natural Decay: Parent Nuclide Decay particle + daughter nuclide [Tables N and O] a) Write the decay for U-238: _______ 23892U 42He + 23490Th_________ when the atomic # changes, the ID of the element changes as well. b) Write the decay for K-37:________ 3719K 0+1e + 3718Ar ____________ c) Wr ...
Chemistry 20 Lesson 36 – The Whole Enchilada
... Suppose you are given four, unlabelled beakers, each containing a colorless aqueous solution of one solute. The possible solutions are NaCl(aq), HCl(aq), Ba(OH)2 (aq), and CH3Cl(aq). Write a series of diagnostic tests to distinguish each solution from the others. ...
... Suppose you are given four, unlabelled beakers, each containing a colorless aqueous solution of one solute. The possible solutions are NaCl(aq), HCl(aq), Ba(OH)2 (aq), and CH3Cl(aq). Write a series of diagnostic tests to distinguish each solution from the others. ...
AP_chemistry_Summer_Assignment_2014
... 80. Identify each of the following as being most like an observation, a law, or a theory. a. All coastal areas experience two high tides and two low tides each day. b. The tides in Earth’s oceans are caused mainly by the gravitational attraction of the moon. c. Yesterday, high tide in San Francisco ...
... 80. Identify each of the following as being most like an observation, a law, or a theory. a. All coastal areas experience two high tides and two low tides each day. b. The tides in Earth’s oceans are caused mainly by the gravitational attraction of the moon. c. Yesterday, high tide in San Francisco ...
AP Chemistry - Jackson County School System
... Identify each of the following as being most like an observation, a law, or a theory. a. All coastal areas experience two high tides and two low tides each day. b. The tides in Earth’s oceans are caused mainly by the gravitational attraction of the moon. c. Yesterday, high tide in San Francisco Bay ...
... Identify each of the following as being most like an observation, a law, or a theory. a. All coastal areas experience two high tides and two low tides each day. b. The tides in Earth’s oceans are caused mainly by the gravitational attraction of the moon. c. Yesterday, high tide in San Francisco Bay ...
Figure 6.15 When a reaction
... The caloric value of food is the energy produced by combustion of its proteins, carbohydrates and fats. The amount of energy liberated by the catabolism of food in the body is almost the same as the amount liberated when food is burnt outside the body. The energy liberated by catabolic processes is ...
... The caloric value of food is the energy produced by combustion of its proteins, carbohydrates and fats. The amount of energy liberated by the catabolism of food in the body is almost the same as the amount liberated when food is burnt outside the body. The energy liberated by catabolic processes is ...
2016-2017 Summer Assignment AP Chem 2017 Summer
... I hope you are looking forward to an exciting school year of chemistry. You will all do great with confidence, motivation, and study skills. Don’t let the year get ahead of you and remember you will have to study for this course daily. It is recommend that you spread out the summer assignment. Pleas ...
... I hope you are looking forward to an exciting school year of chemistry. You will all do great with confidence, motivation, and study skills. Don’t let the year get ahead of you and remember you will have to study for this course daily. It is recommend that you spread out the summer assignment. Pleas ...
1. Explain electrophile and nucleophile. 2. Explain
... 13. Why sodium metal is kept under Kerosene. 14.BeCl2 can be easily hydrolyzed explain. 15. What is ortho and para Hydrogen. ...
... 13. Why sodium metal is kept under Kerosene. 14.BeCl2 can be easily hydrolyzed explain. 15. What is ortho and para Hydrogen. ...
Chemistry I Exams and Keys Corrected 2016 Season
... 18. Joseph Proust(1754 to 1826) was the chemist to first formally state that: Rejected: because simple memorization. Also, student may not have read about Proust. All full credit. A) When two elements combine with each other to form more than one compound, the weights of one element that combine wi ...
... 18. Joseph Proust(1754 to 1826) was the chemist to first formally state that: Rejected: because simple memorization. Also, student may not have read about Proust. All full credit. A) When two elements combine with each other to form more than one compound, the weights of one element that combine wi ...
FINAL EXAM REVIEW PROBLEMS
... 56. When aqueous Na2SO4 and Pb(NO3)2 are mixed, PbSO4 precipitates. Calculate the PbSO4 formed when 1.25 L of 0.0500 M Pb(NO 3)2 and 2.00 L of 0.0250 M Na2SO4 are mixed. 57. Calculate the volume of 0.10 M HNO3 needed to neutralize 125 mL of 0.50 M KOH. 58. What volume of 0.50 N H2SO4 is required to ...
... 56. When aqueous Na2SO4 and Pb(NO3)2 are mixed, PbSO4 precipitates. Calculate the PbSO4 formed when 1.25 L of 0.0500 M Pb(NO 3)2 and 2.00 L of 0.0250 M Na2SO4 are mixed. 57. Calculate the volume of 0.10 M HNO3 needed to neutralize 125 mL of 0.50 M KOH. 58. What volume of 0.50 N H2SO4 is required to ...
Chemistry 2nd Semester Final Review
... An ideal gas is a gas whose molecules move randomly, colliding with other molecules. These collisions are perfectly elastic, meaning that all of the kinetic energy from the collision is transferred to the next molecule, not converted into heat or friction. This means that, over time, the gas will n ...
... An ideal gas is a gas whose molecules move randomly, colliding with other molecules. These collisions are perfectly elastic, meaning that all of the kinetic energy from the collision is transferred to the next molecule, not converted into heat or friction. This means that, over time, the gas will n ...
Advanced Placement Chemistry Test
... equilibrium at 1000 K. Determine whether the equilibrium concentration of HI(g) will be greater than, equal to, or less than the initial concentration of HI(g). Justify your answer. {3 marks} ...
... equilibrium at 1000 K. Determine whether the equilibrium concentration of HI(g) will be greater than, equal to, or less than the initial concentration of HI(g). Justify your answer. {3 marks} ...
Chapter 1 – Reaction Kinetics Answer Key
... is likely a bit smaller than 24.5 L/mol (or 26.5 L/mol for trial two). Dividing by a smaller number would lead to a LARGER MASS of zinc expected. 1.2 Review Questions (page 25) 1. Factors affecting heterogeneous and homogeneous reactions: • Nature of reactants • Temperature • Concentration • Presenc ...
... is likely a bit smaller than 24.5 L/mol (or 26.5 L/mol for trial two). Dividing by a smaller number would lead to a LARGER MASS of zinc expected. 1.2 Review Questions (page 25) 1. Factors affecting heterogeneous and homogeneous reactions: • Nature of reactants • Temperature • Concentration • Presenc ...
IA Velikanova, AK Bolvako PHYSICAL CHEMISTRY
... (b) adding reactants shifts the equilibrium to the right; (c) exothermic reactions shift the equilibrium to the left with increasing temperature; (d) adding a catalyst shifts the equilibrium to the right. 10. Which one of the following is incorrect? (a) equilibrium is dynamic, as some molecules are ...
... (b) adding reactants shifts the equilibrium to the right; (c) exothermic reactions shift the equilibrium to the left with increasing temperature; (d) adding a catalyst shifts the equilibrium to the right. 10. Which one of the following is incorrect? (a) equilibrium is dynamic, as some molecules are ...
1411FINALSAMPLEs and Key
... second structure, which has an “expanded octet” around the sulfur atom. Hybridizations that allow more than an octet of electrons around an atom are sp3d (10 electrons) and sp3d2 (12 electrons), but not sp, sp2, or sp3. Furthermore, to form a -bond, we must have unhybridized p-orbitals on the sulfu ...
... second structure, which has an “expanded octet” around the sulfur atom. Hybridizations that allow more than an octet of electrons around an atom are sp3d (10 electrons) and sp3d2 (12 electrons), but not sp, sp2, or sp3. Furthermore, to form a -bond, we must have unhybridized p-orbitals on the sulfu ...
PHYSICAL SETTING CHEMISTRY
... structure of graphite is organized in layers. The bonds between carbon atoms within each layer of graphite are strong. The bonds between carbon atoms that connect different layers of graphite are weak because the shared electrons in these bonds are loosely held by the carbon atoms. The crystal struc ...
... structure of graphite is organized in layers. The bonds between carbon atoms within each layer of graphite are strong. The bonds between carbon atoms that connect different layers of graphite are weak because the shared electrons in these bonds are loosely held by the carbon atoms. The crystal struc ...
Notebook - Science
... principal quantum number n: describes energy of the electron; always a positive integer; large numbers seldom encountered; each atom has many orbitals associated with each value of n; these orbitals together are sometimes called electron shells azimuthal quantum number ℓ: describes orbital angular m ...
... principal quantum number n: describes energy of the electron; always a positive integer; large numbers seldom encountered; each atom has many orbitals associated with each value of n; these orbitals together are sometimes called electron shells azimuthal quantum number ℓ: describes orbital angular m ...
Unit 2: Practice
... ____ 10. Which of the following best describes one mole of potassium sulfate, K2SO4? a. It contains six atoms in total. c. It has a molar mass of 174.3 g. b. It contains one sulfur atom. ...
... ____ 10. Which of the following best describes one mole of potassium sulfate, K2SO4? a. It contains six atoms in total. c. It has a molar mass of 174.3 g. b. It contains one sulfur atom. ...
Ground state reactants Ground state products Ground state
... Energy levels for molecular oxygen. Excited triplet states have not been included because they are much higher in energy. The 1∆g state is the one normally refereed to as singlet oxygen. ...
... Energy levels for molecular oxygen. Excited triplet states have not been included because they are much higher in energy. The 1∆g state is the one normally refereed to as singlet oxygen. ...
AP Chemistry - Oak Park Unified School District
... bond. A double bond, such as that in C2H4, consists of one bond and (12) bond; a triple bond, such as ...
... bond. A double bond, such as that in C2H4, consists of one bond and (12) bond; a triple bond, such as ...
Bioorthogonal chemistry
The term bioorthogonal chemistry refers to any chemical reaction that can occur inside of living systems without interfering with native biochemical processes. The term was coined by Carolyn R. Bertozzi in 2003. Since its introduction, the concept of the bioorthogonal reaction has enabled the study of biomolecules such as glycans, proteins, and lipids in real time in living systems without cellular toxicity. A number of chemical ligation strategies have been developed that fulfill the requirements of bioorthogonality, including the 1,3-dipolar cycloaddition between azides and cyclooctynes (also termed copper-free click chemistry), between nitrones and cyclooctynes, oxime/hydrazone formation from aldehydes and ketones, the tetrazine ligation, the isocyanide-based click reaction, and most recently, the quadricyclane ligation.The use of bioorthogonal chemistry typically proceeds in two steps. First, a cellular substrate is modified with a bioorthogonal functional group (chemical reporter) and introduced to the cell; substrates include metabolites, enzyme inhibitors, etc. The chemical reporter must not alter the structure of the substrate dramatically to avoid affecting its bioactivity. Secondly, a probe containing the complementary functional group is introduced to react and label the substrate.Although effective bioorthogonal reactions such as copper-free click chemistry have been developed, development of new reactions continues to generate orthogonal methods for labeling to allow multiple methods of labeling to be used in the same biosystems.