CST Review Part 2
... products and reactants. As a basis for understanding this concept: a. Students know how to describe chemical reactions by writing balanced equations. b. Students know the quantity on mole is set by defining one mole of carbon 12 atoms to have a mass of exactly 12 grams. c. Students know one mole equ ...
... products and reactants. As a basis for understanding this concept: a. Students know how to describe chemical reactions by writing balanced equations. b. Students know the quantity on mole is set by defining one mole of carbon 12 atoms to have a mass of exactly 12 grams. c. Students know one mole equ ...
Answers - Shelton State
... Above the critical temperature a gas can not be liquefied. Melting point and freezing point are the same temperature. What is vapor pressure? The pressure of vapor in equilibrium with its liquid state. The pressure of a vapor evaporating from the liquid state. What is boiling? The especially rapid e ...
... Above the critical temperature a gas can not be liquefied. Melting point and freezing point are the same temperature. What is vapor pressure? The pressure of vapor in equilibrium with its liquid state. The pressure of a vapor evaporating from the liquid state. What is boiling? The especially rapid e ...
R= 8.31 J/mol K = 0.0821 L atm/mol K = 62.4 L torr/mol K PV = nRT
... _______24. The total number of electron orbitals available in the fourth principal energy level is A) 4 B) 16 C) 9 D) 18 E) 32 _______25. In the Stern-Gerlach experiment, silver atoms were shot through a powerful magnetic field. The stream of atoms divided into two separate paths. This division wou ...
... _______24. The total number of electron orbitals available in the fourth principal energy level is A) 4 B) 16 C) 9 D) 18 E) 32 _______25. In the Stern-Gerlach experiment, silver atoms were shot through a powerful magnetic field. The stream of atoms divided into two separate paths. This division wou ...
Chemistry EOC Review Name
... be raised to occupy a volume of 6.5 liters? 110. A gas initially has a pressure of 1.5 atm and is at 20C. It has a volume of 3.0 L. If the pressure is increased to 2.5 atm and temperature is increased to 30C, what new volume will the gas occupy? 111. What is Dalton’s Law of Partial Pressure? 112. ...
... be raised to occupy a volume of 6.5 liters? 110. A gas initially has a pressure of 1.5 atm and is at 20C. It has a volume of 3.0 L. If the pressure is increased to 2.5 atm and temperature is increased to 30C, what new volume will the gas occupy? 111. What is Dalton’s Law of Partial Pressure? 112. ...
File
... _______24. The total number of electron orbitals available in the fourth principal energy level is A) 4 B) 16 C) 9 D) 18 E) 32 _______25. In the Stern-Gerlach experiment, silver atoms were shot through a powerful magnetic field. The stream of atoms divided into two separate paths. This division wou ...
... _______24. The total number of electron orbitals available in the fourth principal energy level is A) 4 B) 16 C) 9 D) 18 E) 32 _______25. In the Stern-Gerlach experiment, silver atoms were shot through a powerful magnetic field. The stream of atoms divided into two separate paths. This division wou ...
CHEMISTRY 1710 - Practice Exam #2
... gaseous CCl4 at 76.8°C (the normal boiling point for CCl4). The specific heat of CCl4(l) is 0.857 J/(g · °C), its heat of fusion is 3.27 kJ/mol, and its heat of vaporization is 29.82 kJ/mol. ...
... gaseous CCl4 at 76.8°C (the normal boiling point for CCl4). The specific heat of CCl4(l) is 0.857 J/(g · °C), its heat of fusion is 3.27 kJ/mol, and its heat of vaporization is 29.82 kJ/mol. ...
Chem Reactions (and Balancing Equations)
... • Can predict the products if it is a binary compound • Made up of only two elements • Falls apart into its elements • H2O electricity H2 (g) + O2 • HgO ...
... • Can predict the products if it is a binary compound • Made up of only two elements • Falls apart into its elements • H2O electricity H2 (g) + O2 • HgO ...
Paper 3 - TheAllPapers
... (ii) Newer catalysts have been discovered for this process. Using these catalysts, the operating temperature is lowered from 450°C to 400°C. What is the advantage of using a lower temperature? Explain your answer. advantage explanation ...
... (ii) Newer catalysts have been discovered for this process. Using these catalysts, the operating temperature is lowered from 450°C to 400°C. What is the advantage of using a lower temperature? Explain your answer. advantage explanation ...
12.1 Avogadro`s Law and Molar Volume
... When gases react, volumes of gaseous reactants and products of chemical reaction (at equal temperatures and pressures) are in simple whole number ratios. Example: When hydrogen and oxygen come together to produce water, 2 unit volumes of hydrogen and 1 unit volume of oxygen results in 2 unit volumes ...
... When gases react, volumes of gaseous reactants and products of chemical reaction (at equal temperatures and pressures) are in simple whole number ratios. Example: When hydrogen and oxygen come together to produce water, 2 unit volumes of hydrogen and 1 unit volume of oxygen results in 2 unit volumes ...
Academic Chemistry Final Exam Review
... 2. What happens during an endothermic reaction? What is the sign of the H value? ...
... 2. What happens during an endothermic reaction? What is the sign of the H value? ...
File
... a carboxylic acid and an alcohol. Consequently, the name of an ester has two parts. The first part is the name of the alkyl group from the alcohol used in the esterification reaction. The second part comes from the acid. The ending of the acid name is changed from oic acid to -oate. For example, in ...
... a carboxylic acid and an alcohol. Consequently, the name of an ester has two parts. The first part is the name of the alkyl group from the alcohol used in the esterification reaction. The second part comes from the acid. The ending of the acid name is changed from oic acid to -oate. For example, in ...
South Pasadena · AP Chemistry
... 115 grams/mol. Determine the empirical formula and the molecular formula of the compound. 13. Sodium metal reacts vigorously with water to produce a solution of sodium hydroxide and hydrogen gas: 2Na(s) + 2H2O(l) 2NaOH(aq) + H2(g) What mass of hydrogen gas can be produced when 10 grams of sodium i ...
... 115 grams/mol. Determine the empirical formula and the molecular formula of the compound. 13. Sodium metal reacts vigorously with water to produce a solution of sodium hydroxide and hydrogen gas: 2Na(s) + 2H2O(l) 2NaOH(aq) + H2(g) What mass of hydrogen gas can be produced when 10 grams of sodium i ...
Homogeneous and Heterogeneous Catalysis
... but are also harnessed for industrial processes. A well-studied example is carbonic anhydrase, which catalyzes the release of CO2 into the lungs from the blood stream. D.Contrast with Heterogeneous Catalysis Homogeneous catalysis differs from heterogeneous catalysis in that the catalyst is in a diff ...
... but are also harnessed for industrial processes. A well-studied example is carbonic anhydrase, which catalyzes the release of CO2 into the lungs from the blood stream. D.Contrast with Heterogeneous Catalysis Homogeneous catalysis differs from heterogeneous catalysis in that the catalyst is in a diff ...
Chemistry Final Exam Review 2006-2007
... what would be the partial pressure of nitrogen? c) If a sample of gas occupies 15.9 L at 34 C, what will its volume be at 27 C if the pressure does not change? d) The volume of a sample of oxygen gas is 300.0 ml when the pressure is 1.00 atm and the temperature is 27.0 C. At what temperature would t ...
... what would be the partial pressure of nitrogen? c) If a sample of gas occupies 15.9 L at 34 C, what will its volume be at 27 C if the pressure does not change? d) The volume of a sample of oxygen gas is 300.0 ml when the pressure is 1.00 atm and the temperature is 27.0 C. At what temperature would t ...
sample paper chemistry clas xi set 3
... in about 30 words each. 5. Question nos. 19-27 are short answer questions and carry 3 marks each. Answer these questions in about 40 words each. 6. Question nos. 28-30 are long answer questions and carry 5 marks each. Answer these questions in about 70 words each. 7. Use log table if necessary, use ...
... in about 30 words each. 5. Question nos. 19-27 are short answer questions and carry 3 marks each. Answer these questions in about 40 words each. 6. Question nos. 28-30 are long answer questions and carry 5 marks each. Answer these questions in about 70 words each. 7. Use log table if necessary, use ...
15anespp
... • leaded petrol must not pass through the catalyst as the lead deposits on the catalyst’s surface and “poisons” it, thus blocking sites for reactions to take place. ...
... • leaded petrol must not pass through the catalyst as the lead deposits on the catalyst’s surface and “poisons” it, thus blocking sites for reactions to take place. ...
Chemistry Definitions
... Functional group: The part of a molecule characterized by a special arrangement of atoms that is largely responsible for the chemical behaviour of the parent molecule. Optical isomer: Compounds that are non superimposable mirror images, and can be detected by their different effects on plane polariz ...
... Functional group: The part of a molecule characterized by a special arrangement of atoms that is largely responsible for the chemical behaviour of the parent molecule. Optical isomer: Compounds that are non superimposable mirror images, and can be detected by their different effects on plane polariz ...
Review of Moles and Stoichiometry
... b.) 23.5 grams of iron will react with exactly how many liters of O2 gas at STP? ...
... b.) 23.5 grams of iron will react with exactly how many liters of O2 gas at STP? ...
Chapter 13…States of Matter
... 4. Calculate the amount of energy required to heat a 150 g chunk of aluminum from 20C to 40C. (Cp of aluminum = 0.220 cal/gC) H=mCpT (150g)(.22)(20) = 660 cal Chapters 17& 18…Reaction Rates & Equilibrium Define: 1. Equilibrium: the reaction occurs simultaneously in both directions. 2. Activate ...
... 4. Calculate the amount of energy required to heat a 150 g chunk of aluminum from 20C to 40C. (Cp of aluminum = 0.220 cal/gC) H=mCpT (150g)(.22)(20) = 660 cal Chapters 17& 18…Reaction Rates & Equilibrium Define: 1. Equilibrium: the reaction occurs simultaneously in both directions. 2. Activate ...
1 2016-17 Honors Chemistry Review for the Final Exam Each unit
... discussing the involved chemicals. What does this indicate about the type of intermolecular force available to this molecule? How could the molecule be soluble at all in water if it is so much more soluble in carbon tetrachloride? What could be added to the water to increase the solubility of the os ...
... discussing the involved chemicals. What does this indicate about the type of intermolecular force available to this molecule? How could the molecule be soluble at all in water if it is so much more soluble in carbon tetrachloride? What could be added to the water to increase the solubility of the os ...
educator exam series
... When 1.5litres of chlorine gas were completely reacted with element B 5.937g of the product were formed. Determine the relative atomic mass of element B. (Atomic mass of chlorine = 35.5 Molar gas volume = 24litres) ...
... When 1.5litres of chlorine gas were completely reacted with element B 5.937g of the product were formed. Determine the relative atomic mass of element B. (Atomic mass of chlorine = 35.5 Molar gas volume = 24litres) ...
Chemistry 111 Study Sheet - Answers
... Above the critical temperature a gas can not be liquefied. Melting point and freezing point are the same temperature. What is vapor pressure? The pressure of vapor in equilibrium with its liquid state. The pressure of a vapor evaporating from the liquid state. What is boiling? The especially rapid e ...
... Above the critical temperature a gas can not be liquefied. Melting point and freezing point are the same temperature. What is vapor pressure? The pressure of vapor in equilibrium with its liquid state. The pressure of a vapor evaporating from the liquid state. What is boiling? The especially rapid e ...
DME Rate Equations
... Applications of Model Variation of CO Conversion at the Reactor Outlet Figure 4 presents the experimental data for CO conversion at the reactor outlet and those predicted from the model. Apart from the initial period, the correlation between the two sets of data is satisfactory in all of the experim ...
... Applications of Model Variation of CO Conversion at the Reactor Outlet Figure 4 presents the experimental data for CO conversion at the reactor outlet and those predicted from the model. Apart from the initial period, the correlation between the two sets of data is satisfactory in all of the experim ...
Catalytic reforming
Catalytic reforming is a chemical process used to convert petroleum refinery naphthas distilled from crude oil (typically having low octane ratings) into high-octane liquid products called reformates, which are premium blending stocks for high-octane gasoline. The process converts low-octane linear hydrocarbons (paraffins) into branched alkanes (isoparaffins) and cyclic naphthenes, which are then partially dehydrogenated to produce high-octane aromatic hydrocarbons. The dehydrogenation also produces significant amounts of byproduct hydrogen gas, which is fed into other refinery processes such as hydrocracking. A side reaction is hydrogenolysis, which produces light hydrocarbons of lower value, such as methane, ethane, propane and butanes.In addition to a gasoline blending stock, reformate is the main source of aromatic bulk chemicals such as benzene, toluene, xylene and ethylbenzene which have diverse uses, most importantly as raw materials for conversion into plastics. However, the benzene content of reformate makes it carcinogenic, which has led to governmental regulations effectively requiring further processing to reduce its benzene content.This process is quite different from and not to be confused with the catalytic steam reforming process used industrially to produce products such as hydrogen, ammonia, and methanol from natural gas, naphtha or other petroleum-derived feedstocks. Nor is this process to be confused with various other catalytic reforming processes that use methanol or biomass-derived feedstocks to produce hydrogen for fuel cells or other uses.