FINAL REVIEW
... increased to 1065 cm3, what will the pressure of the gas be? 311 mm Hg 49. What will the volume of a gas sample be at 100. °C if its volume at 23.1 °C is 51.3 L? 64.6 L 50. If the pressure of a gas at 23 °C is 1.01 atm, what is its pressure at 35.0 °C? 1.05 atm 51. What is the partial pressure of ox ...
... increased to 1065 cm3, what will the pressure of the gas be? 311 mm Hg 49. What will the volume of a gas sample be at 100. °C if its volume at 23.1 °C is 51.3 L? 64.6 L 50. If the pressure of a gas at 23 °C is 1.01 atm, what is its pressure at 35.0 °C? 1.05 atm 51. What is the partial pressure of ox ...
CfE Higher Chemistry Homework 3.5
... In which of the following reactions would an increase in pressure cause the equilibrium position to move to the left? ...
... In which of the following reactions would an increase in pressure cause the equilibrium position to move to the left? ...
The Mole Ratio · the ratio between the molar amounts of any two
... · the method of predicting the quantity of a reactant or product in a chemical reaction based on the quantity of another reactant or product in the reaction ...
... · the method of predicting the quantity of a reactant or product in a chemical reaction based on the quantity of another reactant or product in the reaction ...
Exam practice answers
... (1/50) 100 = 2%. Given the inaccuracy of the experiment this is not a significant error. (c) There are many examples that could be used. The mark scheme shown below would be applied to all answers. The marking points are: ...
... (1/50) 100 = 2%. Given the inaccuracy of the experiment this is not a significant error. (c) There are many examples that could be used. The mark scheme shown below would be applied to all answers. The marking points are: ...
Chemistry 1- Final Exam Review
... ____ 67. Which of these elements does not exist as a diatomic molecule? a. C c. H b. F d. I ____ 68. At constant temperature and pressure, gas volume is directly proportional to the a. molar mass of the gas. c. density of the gas at STP. b. number of moles of gas. d. pressure of the gas ____ 69. Ca ...
... ____ 67. Which of these elements does not exist as a diatomic molecule? a. C c. H b. F d. I ____ 68. At constant temperature and pressure, gas volume is directly proportional to the a. molar mass of the gas. c. density of the gas at STP. b. number of moles of gas. d. pressure of the gas ____ 69. Ca ...
formula - eduBuzz.org
... • What is the rule for working out the number of hydrogen atoms in an alkane molecule? • What is a homologous series, and why are the alkanes an example of one? • What is the general formula for the alkanes? • Why are the products of combustion the same for every alkane? ...
... • What is the rule for working out the number of hydrogen atoms in an alkane molecule? • What is a homologous series, and why are the alkanes an example of one? • What is the general formula for the alkanes? • Why are the products of combustion the same for every alkane? ...
Semester 2 Review
... 7. Circle the empirical formulas, square the molecular formulas. Explain how they are different. ...
... 7. Circle the empirical formulas, square the molecular formulas. Explain how they are different. ...
UN1001: Section 11: Hydrogen Effects
... These hydrides are themselves brittle, and crack, and the crack can propagate through the material, with more hydride progressively precipitating at the crack tip. ...
... These hydrides are themselves brittle, and crack, and the crack can propagate through the material, with more hydride progressively precipitating at the crack tip. ...
PowerPoint - Types of Chemical Reactions
... Pb(NO3)2(aq) + BaCl2(aq) FeCl3(aq) + NaOH(aq) H2SO4(aq) + NaOH(aq) ...
... Pb(NO3)2(aq) + BaCl2(aq) FeCl3(aq) + NaOH(aq) H2SO4(aq) + NaOH(aq) ...
Chapter 11 Chemical Reactions
... arrow (→) separates the reactants from the products (arrow points to products) –Read as: “reacts to form” or yields The plus sign = “and” (s) after the formula = solid: Fe(s) (g) after the formula = gas: CO2(g) (l) after the formula = liquid: H2O(l) ...
... arrow (→) separates the reactants from the products (arrow points to products) –Read as: “reacts to form” or yields The plus sign = “and” (s) after the formula = solid: Fe(s) (g) after the formula = gas: CO2(g) (l) after the formula = liquid: H2O(l) ...
Chemical Reactions
... Symbols in equations? the arrow (→) separates the reactants from the products (arrow points to products) –Read as: “reacts to form” or yields The plus sign = “and” (s) after the formula = solid: Fe(s) (g) after the formula = gas: CO2(g) (l) after the formula = liquid: H2O(l) ...
... Symbols in equations? the arrow (→) separates the reactants from the products (arrow points to products) –Read as: “reacts to form” or yields The plus sign = “and” (s) after the formula = solid: Fe(s) (g) after the formula = gas: CO2(g) (l) after the formula = liquid: H2O(l) ...
Name……………………………………............................. Index number
... 2. State and explain the observation that would be made when a gas jar of sulphur (IV) oxide is inverted over a gas jar of hydrogen sulphide. ...
... 2. State and explain the observation that would be made when a gas jar of sulphur (IV) oxide is inverted over a gas jar of hydrogen sulphide. ...
SAT Practice Test 3
... HCl is a proton donor Powdered zinc has a greater surface area NH3 is a polar substance Water boils when the vapor pressure of the water is equal to the atmospheric pressure In an exothermic reaction the products have less potential energy than the reactants Pressure and volume have a direct relatio ...
... HCl is a proton donor Powdered zinc has a greater surface area NH3 is a polar substance Water boils when the vapor pressure of the water is equal to the atmospheric pressure In an exothermic reaction the products have less potential energy than the reactants Pressure and volume have a direct relatio ...
Dalton`s Laws worksheet
... Dalton’s Atomic Theory of Matter 1. Which of the following statements is part of Dalton’s atomic theory of matter? a. All atoms are identical b. All atoms of a given element are identical c. All atoms differ from one another d. Atoms of the same element can have a different shape 2. Dalton suggested ...
... Dalton’s Atomic Theory of Matter 1. Which of the following statements is part of Dalton’s atomic theory of matter? a. All atoms are identical b. All atoms of a given element are identical c. All atoms differ from one another d. Atoms of the same element can have a different shape 2. Dalton suggested ...
8492_Chemichal Weapons Production Indicators
... Phosgene is used as an intermediate in the manufacture of many organic chemicals. The largest amount (approximately 80% of world production) is used to produce toluene diisocyanate and other isocyanates. ...
... Phosgene is used as an intermediate in the manufacture of many organic chemicals. The largest amount (approximately 80% of world production) is used to produce toluene diisocyanate and other isocyanates. ...
Chem 30A, Test Review #2
... pressure of 2.50 atm at 20oC. The partial pressure of helium is 460 torr, and that of nitrogen is 950 torr. (a) What is the partial pressure of oxygen in the mixture? (b) How many grams of each gas are present in the cylinder? (R = 0.08206 L.atm/mol.K) (Asnwer: (a) 490 torr; (b) 4.03 g of Helium; 58 ...
... pressure of 2.50 atm at 20oC. The partial pressure of helium is 460 torr, and that of nitrogen is 950 torr. (a) What is the partial pressure of oxygen in the mixture? (b) How many grams of each gas are present in the cylinder? (R = 0.08206 L.atm/mol.K) (Asnwer: (a) 490 torr; (b) 4.03 g of Helium; 58 ...
- Jersey College For Girls
... Q7. Crude oil is an important source of organic compounds. (a) The diagram shows how crude oil is separated into fractions in the oil industry. ...
... Q7. Crude oil is an important source of organic compounds. (a) The diagram shows how crude oil is separated into fractions in the oil industry. ...
Direct production of hydrogen peroxide from CO, O2, and H2O over
... remarkable that a much higher H2O2 formation rate could be achieved over the 1st row transition metal catalyst systems. Among these, the Cu/Al2O3 catalyst was the most active, giving a formation rate of ca. 0.236 mmol (g cat.)1 h1 for the H2O2 production at 273 K. Note that this result is drastica ...
... remarkable that a much higher H2O2 formation rate could be achieved over the 1st row transition metal catalyst systems. Among these, the Cu/Al2O3 catalyst was the most active, giving a formation rate of ca. 0.236 mmol (g cat.)1 h1 for the H2O2 production at 273 K. Note that this result is drastica ...
PowerPoint
... carbon, and that the equilibrium constants for all four reactions are known at the temperature of interest, develop the necessary equations and indicate how to use them in order to determine whether it is thermodynamically possible for carbon to form. In doing so, assume that the system initially co ...
... carbon, and that the equilibrium constants for all four reactions are known at the temperature of interest, develop the necessary equations and indicate how to use them in order to determine whether it is thermodynamically possible for carbon to form. In doing so, assume that the system initially co ...
CHEMISTRY I Final..#1..rev 4KEY
... 38. The boiling point of HBr is lower than that of HF because: a. HBr is heavier than HF and therefore it requires less energy to vaporize. b. HBr has dipole-dipole attractions which are weaker than the hydrogen bonding found in HF. c. The dispersion forces are weaker in HBr than in HF. d. All of th ...
... 38. The boiling point of HBr is lower than that of HF because: a. HBr is heavier than HF and therefore it requires less energy to vaporize. b. HBr has dipole-dipole attractions which are weaker than the hydrogen bonding found in HF. c. The dispersion forces are weaker in HBr than in HF. d. All of th ...
SAMPLE QUESTION PAPER-II Chemistry (Theory) Class-XII
... Neetu and Asha look organic compound synthesis as their chemistry project. They prepare benzene diazonium chloride and stored it at room temperature. Due to holiday, they start preparing azodye but it cannot be prepared. Then their friend Reena told them to prepare benzene diazonium chloride again a ...
... Neetu and Asha look organic compound synthesis as their chemistry project. They prepare benzene diazonium chloride and stored it at room temperature. Due to holiday, they start preparing azodye but it cannot be prepared. Then their friend Reena told them to prepare benzene diazonium chloride again a ...
Chapter 11 Chemical Reactions
... 1) Assemble the correct formulas for all the reactants and products, using “+” and “→” 2) Count the number of atoms of each type appearing on both sides 3) Balance the elements one at a time by adding coefficients (the numbers in front) where you need more - save balancing the H and O until LAST! ...
... 1) Assemble the correct formulas for all the reactants and products, using “+” and “→” 2) Count the number of atoms of each type appearing on both sides 3) Balance the elements one at a time by adding coefficients (the numbers in front) where you need more - save balancing the H and O until LAST! ...
CHEM 150
... ____ 28. Which regions of a heating curve correspond to regions where only a single phase of a material is present? a. horizontal regions b. regions with negative slope ...
... ____ 28. Which regions of a heating curve correspond to regions where only a single phase of a material is present? a. horizontal regions b. regions with negative slope ...
CH 301 Practice Test Questions
... mL flask. At 371 K, the pressure of the vapor in the flask is 754 torr. What is the molar mass in g/mol? 6. What is the density of nitrogen gas at STP? 7. Consider two equal-sized containers, one filled with H2 gas and one with O2 gas at the same temperature and pressure. The average velocity of the ...
... mL flask. At 371 K, the pressure of the vapor in the flask is 754 torr. What is the molar mass in g/mol? 6. What is the density of nitrogen gas at STP? 7. Consider two equal-sized containers, one filled with H2 gas and one with O2 gas at the same temperature and pressure. The average velocity of the ...
2 - DrChoChemistryWebSite
... the arrow (→) separates the reactants from the products (arrow points to products) –Read as: “reacts to form” or yields The plus sign = “and” (s) after the formula = solid: Fe(s) (g) after the formula = gas: CO2(g) (l) after the formula = liquid: H2O(l) ...
... the arrow (→) separates the reactants from the products (arrow points to products) –Read as: “reacts to form” or yields The plus sign = “and” (s) after the formula = solid: Fe(s) (g) after the formula = gas: CO2(g) (l) after the formula = liquid: H2O(l) ...
Catalytic reforming
Catalytic reforming is a chemical process used to convert petroleum refinery naphthas distilled from crude oil (typically having low octane ratings) into high-octane liquid products called reformates, which are premium blending stocks for high-octane gasoline. The process converts low-octane linear hydrocarbons (paraffins) into branched alkanes (isoparaffins) and cyclic naphthenes, which are then partially dehydrogenated to produce high-octane aromatic hydrocarbons. The dehydrogenation also produces significant amounts of byproduct hydrogen gas, which is fed into other refinery processes such as hydrocracking. A side reaction is hydrogenolysis, which produces light hydrocarbons of lower value, such as methane, ethane, propane and butanes.In addition to a gasoline blending stock, reformate is the main source of aromatic bulk chemicals such as benzene, toluene, xylene and ethylbenzene which have diverse uses, most importantly as raw materials for conversion into plastics. However, the benzene content of reformate makes it carcinogenic, which has led to governmental regulations effectively requiring further processing to reduce its benzene content.This process is quite different from and not to be confused with the catalytic steam reforming process used industrially to produce products such as hydrogen, ammonia, and methanol from natural gas, naphtha or other petroleum-derived feedstocks. Nor is this process to be confused with various other catalytic reforming processes that use methanol or biomass-derived feedstocks to produce hydrogen for fuel cells or other uses.