
WHAT IS THE NEXT NUMBER IN THIS SEQUENCE?
... this the Strong Law Of Small Numbers [4]. Furthermore, it is well known that, given any n numbers, one can construct infinitely many polynomials f (x) of degree n that evaluate to these n numbers when x takes on the value of the integers from 0 to n − 1. As a result, Linderholm [5, p. 97] even sugge ...
... this the Strong Law Of Small Numbers [4]. Furthermore, it is well known that, given any n numbers, one can construct infinitely many polynomials f (x) of degree n that evaluate to these n numbers when x takes on the value of the integers from 0 to n − 1. As a result, Linderholm [5, p. 97] even sugge ...
OMAN COLLEGE OF MANAGEMENT AND TECHNOLOGY General
... 1. When 12 is added with a number the result is equal to 67. Find the number. 2. When a number is added with 19, the result is equal to 8 . Find the number. 3. When 93 is subtracted from three times of a number the result is equal to 122. Find the number. 4. When a number is subtracted from 98 the r ...
... 1. When 12 is added with a number the result is equal to 67. Find the number. 2. When a number is added with 19, the result is equal to 8 . Find the number. 3. When 93 is subtracted from three times of a number the result is equal to 122. Find the number. 4. When a number is subtracted from 98 the r ...
Congruent Number Problem 1 Congruent number problem
... Note. I will only speak about positive integers. We know from our earlier lemma that there exist integers n1 , m1 with (n1 , m1 ) = 1 such that a1 = n21 − m21 , b1 = 2n1 m1 , c1 = n21 + m21 , Area(∆1 ) = n1 m1 (n1 + m1 )(n1 − m1 ). Claim. All four factors on the right are relatively prime in pairs. ...
... Note. I will only speak about positive integers. We know from our earlier lemma that there exist integers n1 , m1 with (n1 , m1 ) = 1 such that a1 = n21 − m21 , b1 = 2n1 m1 , c1 = n21 + m21 , Area(∆1 ) = n1 m1 (n1 + m1 )(n1 − m1 ). Claim. All four factors on the right are relatively prime in pairs. ...