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CfE Higher Chemistry Unit 3: Chemistry in Society
CfE Higher Chemistry Unit 3: Chemistry in Society

... Atom Economy = (mass of desired product(s) / total mass of reactants) × 100. ...
F:\Users\Steven\Documents\Chemistry\CHEM120\Problem Set
F:\Users\Steven\Documents\Chemistry\CHEM120\Problem Set

... When I went to write this problem I looked at the periodic table and saw that Rubidium had a mass of 85.467. Since the mass of all isotopes are even (or nearly so) and this average was uneven I knew immediately that rubidium had to have two major isotopes. When I looked up the isotopes sure enough t ...
THESE DOCTORAT DE L`UNIVERSITE DE TOULOUSE ET
THESE DOCTORAT DE L`UNIVERSITE DE TOULOUSE ET

... presented. This comprises the investigation of the interaction between [Cp*2W2O5] and mercaptocarboxylic acids, especially 3-mercaptopropionic acid, which resulted in the isolation and structural characterization of compound [Cp*WO2(SCH2CH2COOH)]. This is the first reported structure of WVI surround ...
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evaluation copy

Chapter 14 Review
Chapter 14 Review

... A. Increasing the system volume shifts the equilibrium to the right. B. Increasing the temperature shifts the equilibrium to the right. C. A catalyst speeds up the approach to equilibrium and shifts the position of equilibrium to the right. D. Decreasing the total pressure of the system shifts the e ...
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June 2000 Practice Diploma
June 2000 Practice Diploma

Appendices and Glossary
Appendices and Glossary

12_chemistry_impq_CH13_amines_02
12_chemistry_impq_CH13_amines_02

... The hydrogen attached to nitrogen in sulphonamide is strongly acidic due to the presence of strong electron withdrawing sulphonyl group. Hence, it is soluble in alkali. (b) In the reaction with secondary amine, N,N-diethylbenzenesulphonamide is formed. ...
Question Bank for Pre Board Exam(XII Chemistry)
Question Bank for Pre Board Exam(XII Chemistry)

... 8. In a crystalline solid, the atoms A and B are arranged as follows:a. Atoms A are arranged in ccp array. b. Atoms B occupy all the octahedral voids and half of the tetrahedral voids. What is the 9. In compound atoms of element Y forms ccp lattice and those of element X occupy 2/3rd of tetrahedral ...
Unit 3: 1 Equilibrium and the Constant, K
Unit 3: 1 Equilibrium and the Constant, K

tro2_ppt_lecture_04 - Louisiana Tech University
tro2_ppt_lecture_04 - Louisiana Tech University

... The concentration [M] for the diluted solution is 0.50 M, which contains 0.15 moles of NaOH in 0.30 liters. (0.50 mol/L)(0.300 L) = 0.15 moles NaOH The original solution concentration was 3.0 M, which contains 0.15 moles of NaOH in 0.050 L, and the dilute solution also contains 0.15 moles of NaOH, b ...
Revised (12 Sept 2009)  Topic: Chemical Equilibrium
Revised (12 Sept 2009) Topic: Chemical Equilibrium

... This indicates that the concentration of Fe(NCS)2+(aq) is bigger than its concentration at equilibrium and the reversible reaction is not at equilibrium. In order to reach equilibrium, the value must be restored to 138. This can be achieved if some Fe(NCS)2+(aq) ions react (making the numerator smal ...
PART 3-ICHO 11-15
PART 3-ICHO 11-15

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... species have 10 electrons, the number of electrons in a neutral Ne atom (10 protons).  (a)  equal amounts of Na+ and F− in NaF; twice as much NO3− as Cu2+ in Cu(NO3)2;  equal amounts of Na+ and CH3CO2− in NaCO2CH3  (b)  FeCl2 and FeCl3 are the compounds formed by Fe2+ and Fe3+, respectively  (c)  Na ...
Class notes - Bullis Haiku
Class notes - Bullis Haiku

... This is the process of precipitating out the ions from each of the 5 groups sequentially and identifying them. This is a common type experiment in an advanced inorganic chemistry lab in college. We will come back to this at the end of today’s talk. But first some equilibrium… ...
Post Lab Questions
Post Lab Questions

... If you are going to miss class please inform me with an email. Your opportunity to make up work is dependent on written approval. In general most missed work is due on the next Friday. For any planned absence work that is due during the absence must be turned in before your departure. Laboratories, ...
Chemistry Club Demos - 10-8-15
Chemistry Club Demos - 10-8-15

... 1.) Add 300 mL water, 8 g KOH, and 10 g dextrose to the flask, swirling the solution until everything has dissolved. 2.) Add 5-6 drops of the M.B. indicator solution, swirling again to mix. The solution will initially turn blue, but after a few moments it will become colorless. 3.) To perform ...
Slide 1
Slide 1

... • At any given temperature, density does not change. • No matter how much or how little C2H5OH is present, its concentration remains constant. • Therefore, the term in the denominator is a constant and can be combined with K. ...
AS/A level
AS/A level

BASIC CONCEPTS OF CHEMISTRY
BASIC CONCEPTS OF CHEMISTRY

... the nature of the process, resulting in a system of this state . The functions of the state are: 1) the internal energy of the system (U); 2) the enthalpy ( heat content ) of ( H) ; 3 ) the entropy (a measure of disorder) of the system (S); 4) the Gibbs’ free energy (G); 5) the Helmholtz’s free ener ...
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Support Material

... Doping is the process of increasing the conductivity of intrinsic semiconductors by adding an appropriate amount of suitable impurity in Si or Ge. * n-type semiconductors : Silicon or Germinium (group-14) doped with electron rich impurity (group-15 element like P or As), Here conductivity is due to ...
Kinetic multi-layer model of aerosol surface and bulk chemistry (KM
Kinetic multi-layer model of aerosol surface and bulk chemistry (KM

... In order to overcome these limitations, Pöschl, Rudich and Ammann have developed a kinetic model framework (PRA framework) with a double-layer surface concept and universally applicable rate equations and parameters for mass transport and chemical reactions at the gas-particle interface of aerosols ...
Answer
Answer

... Chatelier’s principle, the reaction will shift to increase the pressure. It does this by favouring the side with a greater number of gaseous molecules: The reaction will shift to the left (3 moles of gas on the left, 2 moles of gas on the right). Calculate the value of the equilibrium constant, K, a ...
STUDY MATERIAL 2016-17 CHEMISTRY CLASS XII
STUDY MATERIAL 2016-17 CHEMISTRY CLASS XII

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Acid dissociation constant

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