ch. 16 Molecular Basis of Inheritance
... • Within the replication bubbles, one daughter strand is made continuously (leading strand) while the other daughter strand must be made in short pieces (lagging strand) which are then joined together by DNA ligase These short pieces of DNA are called Okazaki fragments ...
... • Within the replication bubbles, one daughter strand is made continuously (leading strand) while the other daughter strand must be made in short pieces (lagging strand) which are then joined together by DNA ligase These short pieces of DNA are called Okazaki fragments ...
BIOLOGY Wednesday Sub Work
... this strand with no problem, super fast! c. The “Lagging Strand”: i. This is the strand on the original molecule which goes 5’ 3’. ii. This is called the lagging strand because remember DNA polymerase can only lay down nucleotides starting at the 5’ end. That means the Lagging Strand is going in ...
... this strand with no problem, super fast! c. The “Lagging Strand”: i. This is the strand on the original molecule which goes 5’ 3’. ii. This is called the lagging strand because remember DNA polymerase can only lay down nucleotides starting at the 5’ end. That means the Lagging Strand is going in ...
DNA
... • 1944- Avery identified DNA as the transforming factor • 1952- Hershey and Chase confirmed Avery’s results by radioactive tagging ...
... • 1944- Avery identified DNA as the transforming factor • 1952- Hershey and Chase confirmed Avery’s results by radioactive tagging ...
g.ML-6 DNA Replication1
... An origin recognition complex (ORC) is initially formed; and after binding of Cdc6, there is the assembly of Mcm (individual subunits of the AAA ATPase, helicase) to form the pre-replicative complex. S-Cdks trigger S phase by phosphorylating Cdc6, which then releases and is degraded. In the mean tim ...
... An origin recognition complex (ORC) is initially formed; and after binding of Cdc6, there is the assembly of Mcm (individual subunits of the AAA ATPase, helicase) to form the pre-replicative complex. S-Cdks trigger S phase by phosphorylating Cdc6, which then releases and is degraded. In the mean tim ...
Topic 3 The Chemistry of Life - wfs
... 2. Helicase is the enzyme that breaks the hydrogen bonds to allow the unwinding. 3. The exposed bases of each strand are then paired with an available nucleotide by complementary base pairing. The result is two strands where only one was first present. 4. DNA polymerase is an enzyme that allows the ...
... 2. Helicase is the enzyme that breaks the hydrogen bonds to allow the unwinding. 3. The exposed bases of each strand are then paired with an available nucleotide by complementary base pairing. The result is two strands where only one was first present. 4. DNA polymerase is an enzyme that allows the ...
INS Biology Name: Winter Quarter Midterm
... 3. Cytosine makes up 38% of the nucleotides in a sample of DNA from an organism. Approximately, what percentage of the nucleotides in this sample will be thymine? a. 12 b. 24 c. 31 d. 38 e. It cannot be determined from the information provided. 4. Which of the following statements is false when comp ...
... 3. Cytosine makes up 38% of the nucleotides in a sample of DNA from an organism. Approximately, what percentage of the nucleotides in this sample will be thymine? a. 12 b. 24 c. 31 d. 38 e. It cannot be determined from the information provided. 4. Which of the following statements is false when comp ...
Sample Exam #2 ( file)
... B. used to translate an mRNA into the amino acid sequence of a protein. C. the code geneticists use to let A stand for adenine, G for guanine, C for cytosine, and T for thymidine. D. sequences of one, two or three bases depending on how many amino acids are found in a protein. ...
... B. used to translate an mRNA into the amino acid sequence of a protein. C. the code geneticists use to let A stand for adenine, G for guanine, C for cytosine, and T for thymidine. D. sequences of one, two or three bases depending on how many amino acids are found in a protein. ...
Prentice hall Biology Worksheets
... 1. concluded that the genetic material of a bacteriophage is DNA 2. concluded that DNA was the factor that transmits genetic information from one generation to the next. 3. concluded that bacteria could be transformed from harmless to disease-causing by an unknown factor Completion On the lines prov ...
... 1. concluded that the genetic material of a bacteriophage is DNA 2. concluded that DNA was the factor that transmits genetic information from one generation to the next. 3. concluded that bacteria could be transformed from harmless to disease-causing by an unknown factor Completion On the lines prov ...
Chapter 9 Notes Guide – Mendel and Heredity
... Section 10.15 22) Now you have learned about transcription and translation. We are going to draw a large, comprehensive picture of the entire process. Please make sure you are taking notes on any part that you are confused about. Your drawing needs to be neat and done in pencil. ...
... Section 10.15 22) Now you have learned about transcription and translation. We are going to draw a large, comprehensive picture of the entire process. Please make sure you are taking notes on any part that you are confused about. Your drawing needs to be neat and done in pencil. ...
Targeted Fluorescent Reporters: Additional slides
... therefore the template strand controls which of the four deoxyribonucleotides (A, C, G or T) will be added. 2. The addition of the new bases is due to a large favorable free energy change caused by the release of pyrophosphate and its hydrolysis to two free inorganic phosphate groups. ...
... therefore the template strand controls which of the four deoxyribonucleotides (A, C, G or T) will be added. 2. The addition of the new bases is due to a large favorable free energy change caused by the release of pyrophosphate and its hydrolysis to two free inorganic phosphate groups. ...
Sect3DNAReplication - Ecology and Evolutionary Biology
... The chromosome replicates once to produce two chromosomes that are identical (except for rare mutations). The two identical daughter chromosomes move toward opposite end of the cell. When the cell divides the daughter chromosomes are partitioned one to each daughter cell. ...
... The chromosome replicates once to produce two chromosomes that are identical (except for rare mutations). The two identical daughter chromosomes move toward opposite end of the cell. When the cell divides the daughter chromosomes are partitioned one to each daughter cell. ...
DNA damage and repair
... of the DNA (e.g. G-C bp to methyl-G-C is DNA damage) •Mutation refers to a change in a base-pair (e.g. G-C bp to A-T bp is a mutation) •There are long term (inhertided) implications when DNA damage is converted to mutation ...
... of the DNA (e.g. G-C bp to methyl-G-C is DNA damage) •Mutation refers to a change in a base-pair (e.g. G-C bp to A-T bp is a mutation) •There are long term (inhertided) implications when DNA damage is converted to mutation ...
Who am I?
... What is cloning? Clones are identical copies of living things. Humans have cloned a lot of things already. ...
... What is cloning? Clones are identical copies of living things. Humans have cloned a lot of things already. ...
Document
... Unit 8 Protein Synthesis Test Review 1. Compare the structure of RNA with that of DNA? 2. What does a codon code for? 3. T/F: The genetic code works the same way in all organisms...DNAmRNAprotein 4. What are the differences between DNA and RNA? 5. In RNA, thymine is replaced by ___________________ ...
... Unit 8 Protein Synthesis Test Review 1. Compare the structure of RNA with that of DNA? 2. What does a codon code for? 3. T/F: The genetic code works the same way in all organisms...DNAmRNAprotein 4. What are the differences between DNA and RNA? 5. In RNA, thymine is replaced by ___________________ ...
7. NUCLEIC ACIDS 7.1 DNA structure and replication 7.2
... DNA polymerases can only add nucleotides to the 3’ end of a primer. ...
... DNA polymerases can only add nucleotides to the 3’ end of a primer. ...
What does DNA do?
... ___ 3) Follow the base pair rule to fill in the missing base pairs for each strand. ___ 4) Compare your strands. Are they similar? What have you done? Where did this process take place in the cell? Why is this process important? They are identical copies of each other (mirror images). This process t ...
... ___ 3) Follow the base pair rule to fill in the missing base pairs for each strand. ___ 4) Compare your strands. Are they similar? What have you done? Where did this process take place in the cell? Why is this process important? They are identical copies of each other (mirror images). This process t ...
Chapter 16: The Molecular Basis of Inheritance
... Watson and Crick used the X-ray diffraction photo of Franklin to deduce that DNA was a helix 2 nm wide, with nitrogenous bases stacked 0.34 nm apart, and making a full turn every 3.4 nm. Franklin had concluded that the sugar-phosphate backbones were on the outside for the helix with the bases extend ...
... Watson and Crick used the X-ray diffraction photo of Franklin to deduce that DNA was a helix 2 nm wide, with nitrogenous bases stacked 0.34 nm apart, and making a full turn every 3.4 nm. Franklin had concluded that the sugar-phosphate backbones were on the outside for the helix with the bases extend ...
1 - HCC Learning Web
... Characterize a prokaryotic mRNA transcript… Before a prokaryotic mRNA can be translated, must it be modified by the addition of a polyA tail? Does RNA polymerase have proofreading activity during transcription? Which type of RNA is found only in eukaryotes? Is a promoter a coding portion of a gene? ...
... Characterize a prokaryotic mRNA transcript… Before a prokaryotic mRNA can be translated, must it be modified by the addition of a polyA tail? Does RNA polymerase have proofreading activity during transcription? Which type of RNA is found only in eukaryotes? Is a promoter a coding portion of a gene? ...
DNA SCAVENGER HUNT
... DNA polymerase enzyme “checks” the new strand. If errors are found, other enzymes “cut “ out the error, and the correct nucleotides are inserted. How does the Nitrogen Base pairing make each species unique, if all species use the same 4 bases? The sequence and amounts of the nucleotides varies from ...
... DNA polymerase enzyme “checks” the new strand. If errors are found, other enzymes “cut “ out the error, and the correct nucleotides are inserted. How does the Nitrogen Base pairing make each species unique, if all species use the same 4 bases? The sequence and amounts of the nucleotides varies from ...
Bio 313 worksheet 2 - Iowa State University
... technique called electrophoresis. With this technique, DNA molecules are placed in a gel, an electrical current is applied to the gel, and the DNA molecules migrate toward the positive pole of the current. What aspect of its structure causes a DNA molecule to migrate toward the positive pole? ...
... technique called electrophoresis. With this technique, DNA molecules are placed in a gel, an electrical current is applied to the gel, and the DNA molecules migrate toward the positive pole of the current. What aspect of its structure causes a DNA molecule to migrate toward the positive pole? ...
Replisome
The replisome is a complex molecular machine that carries out replication of DNA. The replisome first unwinds double stranded DNA into two single strands. For each of the resulting single strands, a new complementary sequence of DNA is synthesized. The net result is formation of two new double stranded DNA sequences that are exact copies of the original double stranded DNA sequence.In terms of structure, the replisome is composed of two replicative polymerase complexes, one of which synthesizes the leading strand, while the other synthesizes the lagging strand. The replisome is composed of a number of proteins including helicase, RFC, PCNA, gyrase/topoisomerase, SSB/RPA, primase, DNA polymerase I, RNAse H, and ligase.