Exam notes for bio250 semester one
... computationally expensive to look for long sequences. The blast search gives you an e-value and a score. A higher score and a lower e-value is a better match. These give you relative measures (comparisons only). Next, you will want to do a sequence alignment to see if your sequence aligns to a famil ...
... computationally expensive to look for long sequences. The blast search gives you an e-value and a score. A higher score and a lower e-value is a better match. These give you relative measures (comparisons only). Next, you will want to do a sequence alignment to see if your sequence aligns to a famil ...
Somatic mosaicism and compound heterozygosity in female
... The different levels of F.IXC and F.IXAg in II3 are only compatible with the presence of each mutation on different alleles and II3 is therefore a compound heterozygote. Analysis of 2 intragenic polymorphic markers within the F.IX gene revealed that the 2 sisters, II2 and II3, inherited the same mat ...
... The different levels of F.IXC and F.IXAg in II3 are only compatible with the presence of each mutation on different alleles and II3 is therefore a compound heterozygote. Analysis of 2 intragenic polymorphic markers within the F.IX gene revealed that the 2 sisters, II2 and II3, inherited the same mat ...
Analyzing Text Structure
... system, is caused by a defective gene. In order for a person to have any symptoms of the disease, though, he or she must inherit the defective gene from both parents. Thus, many people who carry the defective gene will never pass cystic fibrosis on to their offspring. 6 Genetic links to other di ...
... system, is caused by a defective gene. In order for a person to have any symptoms of the disease, though, he or she must inherit the defective gene from both parents. Thus, many people who carry the defective gene will never pass cystic fibrosis on to their offspring. 6 Genetic links to other di ...
Molecular Cloning and Characterization of an
... lecular weights have been determined for many of these MAAs, the biological functions and relevance to tumor progression are little understood. Among the human MAAs, only two antigens, M, 97,000 protein (4) and NGF receptor (5, 6), have been characterized thus far by means of gene cloning. ME491 ant ...
... lecular weights have been determined for many of these MAAs, the biological functions and relevance to tumor progression are little understood. Among the human MAAs, only two antigens, M, 97,000 protein (4) and NGF receptor (5, 6), have been characterized thus far by means of gene cloning. ME491 ant ...
Perl Laboratory Study Guide – Section I
... Search Entrez for you favorite gene. (I have many favorites; if you can’t think of one, try prkr or cos1.) On the results page, follow the link for the protein database. If one doesn’t exist, pick another gene. Using the drop-down menu, display the file in FASTA format and save it to your [yourname] ...
... Search Entrez for you favorite gene. (I have many favorites; if you can’t think of one, try prkr or cos1.) On the results page, follow the link for the protein database. If one doesn’t exist, pick another gene. Using the drop-down menu, display the file in FASTA format and save it to your [yourname] ...
Oncomedicine Base Excision Repair Manipulation in Breast
... Based on the previous genetic and pathological study, BRCA1-associated breast cancers are more likely to be estrogen (ER) and progesterone receptor (PgR) negative (~90%) matched with sporadic breast cancers (~30%). In contrast, the occurrence of ER and PgR for BRCA2- and BRCAX-associated cancers is ...
... Based on the previous genetic and pathological study, BRCA1-associated breast cancers are more likely to be estrogen (ER) and progesterone receptor (PgR) negative (~90%) matched with sporadic breast cancers (~30%). In contrast, the occurrence of ER and PgR for BRCA2- and BRCAX-associated cancers is ...
Recombinant DNA
... cut into fragments. The fragments are created using enzymes, called restriction enzymes, which cleave the DNA double strand. Restriction enzymes leave special ends on the fragments they produce. The ends, called sticky ends, can be spliced to other DNA. The source DNA is cut in many locations, and t ...
... cut into fragments. The fragments are created using enzymes, called restriction enzymes, which cleave the DNA double strand. Restriction enzymes leave special ends on the fragments they produce. The ends, called sticky ends, can be spliced to other DNA. The source DNA is cut in many locations, and t ...
Genes without frontiers?
... Vries et al, 2001). Prudhomme et al also show that a single homologous region (942 bp) facilitates the integration of whole plasmids into bacterial chromosomes at a 100-fold greater rate than foreign DNA uptake from the same plasmid when linearised. Several studies estimate the degree of similarity ...
... Vries et al, 2001). Prudhomme et al also show that a single homologous region (942 bp) facilitates the integration of whole plasmids into bacterial chromosomes at a 100-fold greater rate than foreign DNA uptake from the same plasmid when linearised. Several studies estimate the degree of similarity ...
(Chapter 8) Lecture Materials for Amy Warenda Czura, Ph.D. Suffolk
... 4. The lagging strand is synthesized discontinuously: At the replication fork an RNA primer complementarily pairs with the single stranded parental DNA. Nucleotides are complementarily base paired to the single stranded DNA molecule and bonded to the 3’ end of the RNA primer and growing chain by DNA ...
... 4. The lagging strand is synthesized discontinuously: At the replication fork an RNA primer complementarily pairs with the single stranded parental DNA. Nucleotides are complementarily base paired to the single stranded DNA molecule and bonded to the 3’ end of the RNA primer and growing chain by DNA ...
LP - Columbia University
... Sister/Sibling Chromatids: The DNA molecules in sister chromatids are identical because they are the two products of a single semi-conservative DNA replication. How many chromatids per chromosome? Can be 1 or 2; depends on where cell is in the cell cycle. Before S, each chromosome has one chromatid ...
... Sister/Sibling Chromatids: The DNA molecules in sister chromatids are identical because they are the two products of a single semi-conservative DNA replication. How many chromatids per chromosome? Can be 1 or 2; depends on where cell is in the cell cycle. Before S, each chromosome has one chromatid ...
Vocabulary deletion – inversion – translocation – nondisjunction
... 1. Which cell is the only one that is undergoing meiosis? ...
... 1. Which cell is the only one that is undergoing meiosis? ...
Molecular Genetics
... How could RNA interference be used to treat diseases such as cancer and diabetes? A. by activating genes to produce proteins that can overcome the disease B. by interfering with DNA replication in cells affected by the disease C. by preventing the translation of mRNA into 1. the A genes ...
... How could RNA interference be used to treat diseases such as cancer and diabetes? A. by activating genes to produce proteins that can overcome the disease B. by interfering with DNA replication in cells affected by the disease C. by preventing the translation of mRNA into 1. the A genes ...
tools and techniques
... We can run hundreds or thousands of samples at once in small spaces We can be INCREDIBLY accurate and precise We can use robotic assistance to run the full analysis ...
... We can run hundreds or thousands of samples at once in small spaces We can be INCREDIBLY accurate and precise We can use robotic assistance to run the full analysis ...
Chapter_10_HB_Molecular_Biology
... genes • Mutation: any change in the nucleotide sequence of DNA – Caused by errors in DNA replication or recombination, or by mutagens – Can involve large regions of a chromosome or a single base pair – Can cause many genetic diseases, such as sickle-cell disease Copyright © 2005 Pearson Education, I ...
... genes • Mutation: any change in the nucleotide sequence of DNA – Caused by errors in DNA replication or recombination, or by mutagens – Can involve large regions of a chromosome or a single base pair – Can cause many genetic diseases, such as sickle-cell disease Copyright © 2005 Pearson Education, I ...
Real Time PCR Testing for Biotech Crops: Issues
... Mon 810 has single copy of 35S NK603 has also single copy of 35S Mon 863 has 2 copy of 35S Total 4 copy of 35S in same hybrid. The expected results with 35 would be somewhere 4 times more than if used with the standard with single copy of 35S. ...
... Mon 810 has single copy of 35S NK603 has also single copy of 35S Mon 863 has 2 copy of 35S Total 4 copy of 35S in same hybrid. The expected results with 35 would be somewhere 4 times more than if used with the standard with single copy of 35S. ...
Genetics Project
... Collects and passes out group materials and work Communicates with the teacher Assigns a ‘Daily Participation Grade’ for each member of the group Collects and grades homework for the group when necessary ...
... Collects and passes out group materials and work Communicates with the teacher Assigns a ‘Daily Participation Grade’ for each member of the group Collects and grades homework for the group when necessary ...
DNA and Genetics
... increasing efficiency of RNA polymerase binding. Transcription factors binding DNA in promoter sequence to increase or decrease the likelihood of a gene expressing and transcription factors binding to enhancers. Transcription stops at a specific transcription termination sequence on the DNA at the 5 ...
... increasing efficiency of RNA polymerase binding. Transcription factors binding DNA in promoter sequence to increase or decrease the likelihood of a gene expressing and transcription factors binding to enhancers. Transcription stops at a specific transcription termination sequence on the DNA at the 5 ...
Paper 2
... Emma plans to have a baby. What must the father's genotype be so that there is a 50% chance that their child will not have Huntington's chorea? ...
... Emma plans to have a baby. What must the father's genotype be so that there is a 50% chance that their child will not have Huntington's chorea? ...
SECTION B
... Emma plans to have a baby. What must the father's genotype be so that there is a 50% chance that their child will not have Huntington's chorea? ...
... Emma plans to have a baby. What must the father's genotype be so that there is a 50% chance that their child will not have Huntington's chorea? ...
Biology, 8th Edition
... a bacteriophage injects its DNA into a bacterial cell. The bacterium can defend itself if it has restriction enzymes that can attack the bacteriophage DNA. The cell protects its own DNA from breakdown by modifying it after replication. An enzyme adds a methyl group to one or more bases in each restr ...
... a bacteriophage injects its DNA into a bacterial cell. The bacterium can defend itself if it has restriction enzymes that can attack the bacteriophage DNA. The cell protects its own DNA from breakdown by modifying it after replication. An enzyme adds a methyl group to one or more bases in each restr ...