The Universe
... Oort cloud can be expressed used the next big unit of distance in astronomy: the light year. One light year is the distance light travels in one year. When expressed in metres this is an enormous number. We use this large measure because the distances in the universe are so large. Even so, the cross ...
... Oort cloud can be expressed used the next big unit of distance in astronomy: the light year. One light year is the distance light travels in one year. When expressed in metres this is an enormous number. We use this large measure because the distances in the universe are so large. Even so, the cross ...
The Moon does not fall to Earth because A: It generates a
... run away! A circular orbit means acceleration towards the center, that's what you mean by "falling"! The reason the moon doesn't HIT the earth is because it has a nice big SIDEWAYS velocity which never goes away (because it's always perpendicular to the force of gravity). That means that as the moon ...
... run away! A circular orbit means acceleration towards the center, that's what you mean by "falling"! The reason the moon doesn't HIT the earth is because it has a nice big SIDEWAYS velocity which never goes away (because it's always perpendicular to the force of gravity). That means that as the moon ...
Lecture 1
... • With respect to the stars, the Moon completes one orbit around the Earth in a sidereal month, averaging 27.32 days. • The Moon completes one cycle of phases (one orbit around the Earth with respect to the Sun) in a synodic month, averaging ...
... • With respect to the stars, the Moon completes one orbit around the Earth in a sidereal month, averaging 27.32 days. • The Moon completes one cycle of phases (one orbit around the Earth with respect to the Sun) in a synodic month, averaging ...
Lab 2
... 12. Draw the location of the Sun as accurately as possible on figure 3. 13. Two students are discussing their answers to the question “Figure 4 shows the same view of the sky one month later on January 1. Draw the location of the Sun as accurately as possible on figure 4.” Student 1 (Davey): The Sun ...
... 12. Draw the location of the Sun as accurately as possible on figure 3. 13. Two students are discussing their answers to the question “Figure 4 shows the same view of the sky one month later on January 1. Draw the location of the Sun as accurately as possible on figure 4.” Student 1 (Davey): The Sun ...
the Voyage Visitor Guide
... A Solar System in Miniature Did you know? Jupiter is the largest planet, but over 900 Jupiters could fit inside the Sun! What does the model tell you? If radio messages travel at the speed of light— on this scale, about 5 feet per minute— how long would a message from a spacecraft traveling near Jup ...
... A Solar System in Miniature Did you know? Jupiter is the largest planet, but over 900 Jupiters could fit inside the Sun! What does the model tell you? If radio messages travel at the speed of light— on this scale, about 5 feet per minute— how long would a message from a spacecraft traveling near Jup ...
Gravitatio
... suppose that there is a speed at which the cannonball could be fired such that the trajectory of the falling cannonball matched the curvature of the Earth. If such a speed could be obtained, then the cannonball would fall around the Earth instead of into it; the cannonball would fall towards the E ...
... suppose that there is a speed at which the cannonball could be fired such that the trajectory of the falling cannonball matched the curvature of the Earth. If such a speed could be obtained, then the cannonball would fall around the Earth instead of into it; the cannonball would fall towards the E ...
Colours of the rainbow
... 4. List all the pairs of alternate angles you can find in the diagram. 5. List all the pairs of corresponding angles you can find in the diagram. 6. List all the pairs of co-interior angles you can find in the diagram. 7. The angle that the rainbow appears to take in the sky is represented by ∠BGE. ...
... 4. List all the pairs of alternate angles you can find in the diagram. 5. List all the pairs of corresponding angles you can find in the diagram. 6. List all the pairs of co-interior angles you can find in the diagram. 7. The angle that the rainbow appears to take in the sky is represented by ∠BGE. ...
NEXT MEETING 7:30 p.m., Monday, November 3, 2014
... The orbit of Mimas is very slightly stretched out, forming an ellipse rather than a perfect circle. This slight deviation causes the point on Mimas' surface that faces Saturn tovary a bit over the course of an orbit -an observer on Saturn would see Mimas wobble slightly during its orbit, causing sm ...
... The orbit of Mimas is very slightly stretched out, forming an ellipse rather than a perfect circle. This slight deviation causes the point on Mimas' surface that faces Saturn tovary a bit over the course of an orbit -an observer on Saturn would see Mimas wobble slightly during its orbit, causing sm ...
Unit 1
... • The number of protons (atomic number) in a nucleus determines what element a substance is. • Each element has a number of electrons equal to the number of protons • The electron orbitals are different for each element, and the energy differences between the orbitals are unique as well. • This mean ...
... • The number of protons (atomic number) in a nucleus determines what element a substance is. • Each element has a number of electrons equal to the number of protons • The electron orbitals are different for each element, and the energy differences between the orbitals are unique as well. • This mean ...
Triple Conjunction of Jupiter and Saturn
... The above discrepancies may have to do with the difference in Julian and Gregorian calendars or some glitches in the computer program Parpola used. If it is the latter, some smart readers could calibrate and write an article to pinpoint the correct time and dates of the triple conjunction, correctin ...
... The above discrepancies may have to do with the difference in Julian and Gregorian calendars or some glitches in the computer program Parpola used. If it is the latter, some smart readers could calibrate and write an article to pinpoint the correct time and dates of the triple conjunction, correctin ...
Physics@Brock - Brock University
... (a) the distance between the Earth and the Moon (b) the distance between the Earth and the Sun (c) the time needed for the Moon to orbit the Earth (d) the length of the tropical year 24. The most influential ancient Greek natural philosopher was (a) Aristotle. (b) Ari Gold. (c) Jeremias of Piven. (d ...
... (a) the distance between the Earth and the Moon (b) the distance between the Earth and the Sun (c) the time needed for the Moon to orbit the Earth (d) the length of the tropical year 24. The most influential ancient Greek natural philosopher was (a) Aristotle. (b) Ari Gold. (c) Jeremias of Piven. (d ...
4-6 Script
... astronomers look for or things you might see in the planetarium (stars, planets, etc). After discussing, ask if they can find 1 star in the sky in the current view. The sun is a star! Have all the students point to the sun and discuss how to explain it's location using the compass directions, and th ...
... astronomers look for or things you might see in the planetarium (stars, planets, etc). After discussing, ask if they can find 1 star in the sky in the current view. The sun is a star! Have all the students point to the sun and discuss how to explain it's location using the compass directions, and th ...
PSI AP Physics 1 Gravitation
... 2. Two objects, with masses m1 and m2, are originally a distance r apart. The magnitude of the gravitational force between them is F. The masses are changed to 2m1 and 2m2, and the distance is changed to 4r. What is the magnitude of the new gravitational force? A) F/16 B) F/4 C) 16F D) 4F 3. As a ro ...
... 2. Two objects, with masses m1 and m2, are originally a distance r apart. The magnitude of the gravitational force between them is F. The masses are changed to 2m1 and 2m2, and the distance is changed to 4r. What is the magnitude of the new gravitational force? A) F/16 B) F/4 C) 16F D) 4F 3. As a ro ...
Advances in Environmental Biology Approach Mahin Shahrivar and
... by a gigantic revolutionary phase and the resurrection of the human being starts [18]. The distribution of the stars in the resurrection day: And when the sky halves into some sections (Al Enfetar: 1). And when the stars separated to everywhere (Al Enfetar: 2). And that day the stars fall down (Takv ...
... by a gigantic revolutionary phase and the resurrection of the human being starts [18]. The distribution of the stars in the resurrection day: And when the sky halves into some sections (Al Enfetar: 1). And when the stars separated to everywhere (Al Enfetar: 2). And that day the stars fall down (Takv ...
HW: PSI Gravity Problems Worksheet With Answers
... 2. Two objects, with masses m1 and m2, are originally a distance r apart. The magnitude of the gravitational force between them is F. The masses are changed to 2m1 and 2m2, and the distance is changed to 4r. What is the magnitude of the new gravitational force? A) F/16 B) F/4 C) 16F D) 4F 3. As a ro ...
... 2. Two objects, with masses m1 and m2, are originally a distance r apart. The magnitude of the gravitational force between them is F. The masses are changed to 2m1 and 2m2, and the distance is changed to 4r. What is the magnitude of the new gravitational force? A) F/16 B) F/4 C) 16F D) 4F 3. As a ro ...
Jupiter
... Jupiter is the biggest planet in the solar system. Jupiter is 240 lbs in size. The volume of Jupiter is 1.43128×1015 km³ . ...
... Jupiter is the biggest planet in the solar system. Jupiter is 240 lbs in size. The volume of Jupiter is 1.43128×1015 km³ . ...
Chap 2 Lecture(1)
... It differs due to it’s angle and the amount of interception that occurs as it passes through the earth’s atmosphere. Subsolar point: the point on the earth receiving the most insolation which is the point at which the sun’s rays are perpendicular (90°) to the earth. This point shifts between the tro ...
... It differs due to it’s angle and the amount of interception that occurs as it passes through the earth’s atmosphere. Subsolar point: the point on the earth receiving the most insolation which is the point at which the sun’s rays are perpendicular (90°) to the earth. This point shifts between the tro ...
kristen.gattshall.file7.1454335203.2016
... • 12. In blue dotted lines with arrows, draw the orbit of the earth around the sun. It should be a counterclockwise orbit! • In blue, along your line, write “365 ¼ days” since that’s how long it takes to orbit! ...
... • 12. In blue dotted lines with arrows, draw the orbit of the earth around the sun. It should be a counterclockwise orbit! • In blue, along your line, write “365 ¼ days” since that’s how long it takes to orbit! ...
Stellar Parallax
... Mapping of the Sky • It is important to be able to determine the position of an object in the Sky.This can be done in various ways. • Here we see the Celestial sphere.The stars are set on the surface of a huge sphere centred on the Earth.The point in the sky directly overhead is called the Zenith a ...
... Mapping of the Sky • It is important to be able to determine the position of an object in the Sky.This can be done in various ways. • Here we see the Celestial sphere.The stars are set on the surface of a huge sphere centred on the Earth.The point in the sky directly overhead is called the Zenith a ...
The universe and our planet
... A galaxy is a large group of stars: between 100 000 and 500 million. Towards the centre of the galaxy, the stars are close together, but in the outer areas of the galaxy they are farther apart. Stars are made up mainly of hydrogen and helium, the two most abundant gases in the universe. Many stars h ...
... A galaxy is a large group of stars: between 100 000 and 500 million. Towards the centre of the galaxy, the stars are close together, but in the outer areas of the galaxy they are farther apart. Stars are made up mainly of hydrogen and helium, the two most abundant gases in the universe. Many stars h ...
year
... The sidereal year is essentially the period of the Earth’s orbital revolution around the Sun with reference to the stars. Because of precession (see tropical year), the sidereal year is about 21 minutes longer than the tropical year. Tropical Year The time between successive passages of the Sun thro ...
... The sidereal year is essentially the period of the Earth’s orbital revolution around the Sun with reference to the stars. Because of precession (see tropical year), the sidereal year is about 21 minutes longer than the tropical year. Tropical Year The time between successive passages of the Sun thro ...
The Celestial Sphere
... The reason for this is illustrated below. On the first day, point A points directly toward the sun at exactly twelve noon. After a full rotation of the Earth, point A is pointing in the same direction in space, but since the Earth has also proceeded along its orbit, point A is no longer facing the ...
... The reason for this is illustrated below. On the first day, point A points directly toward the sun at exactly twelve noon. After a full rotation of the Earth, point A is pointing in the same direction in space, but since the Earth has also proceeded along its orbit, point A is no longer facing the ...
Gravitational Force Problem Set
... (b) If the satellite increases its orbital radius, how it would change the orbital velocity? Explain. (c) If the radius of the orbit is R, use Newton’s laws to derive an expression for the orbital period. (d) The satellite rotation is synchronized with Jupiter’s rotation. This requires an equatorial ...
... (b) If the satellite increases its orbital radius, how it would change the orbital velocity? Explain. (c) If the radius of the orbit is R, use Newton’s laws to derive an expression for the orbital period. (d) The satellite rotation is synchronized with Jupiter’s rotation. This requires an equatorial ...
Extraterrestrial skies
In astronomy, the term extraterrestrial sky refers to a view of outer space from the surface of a world other than Earth.The sky of the Moon has been directly observed or photographed by astronauts, while those of Titan, Mars, and Venus have been observed indirectly by space probes designed to land on the surface and transmit images back to Earth.Characteristics of extraterrestrial skies appear to vary substantially due to a number of factors. An extraterrestrial atmosphere, if present, has a large bearing on visible characteristics. The atmosphere's density and chemical composition can contribute to differences in colour, opacity (including haze) and the presence of clouds. Astronomical objects may also be visible and can include natural satellites, rings, star systems and nebulas and other planetary system bodies.For skies that have not been directly or indirectly observed, their appearance can be simulated based on known parameters such as the position of astronomical objects relative to the surface and atmospheric composition.