Exercise 4 Solution
... Exercise 7 (Work, energy and power) Suggested Solutions 1. (a) (i) Work done by the force = F s = 50 N x 0.1 m = 5 J (ii) Work done by the force = increase in KE 0.5 = ½ mv2 => 0.5 = ½ (0.1) v2 => v = 5 m s-1 (b) F = ( mv – mu ) / t => [(0.1)(10) – (0.1)(-10)] / 0.2 = 10 N (c) The first statement is ...
... Exercise 7 (Work, energy and power) Suggested Solutions 1. (a) (i) Work done by the force = F s = 50 N x 0.1 m = 5 J (ii) Work done by the force = increase in KE 0.5 = ½ mv2 => 0.5 = ½ (0.1) v2 => v = 5 m s-1 (b) F = ( mv – mu ) / t => [(0.1)(10) – (0.1)(-10)] / 0.2 = 10 N (c) The first statement is ...
File
... A body is in equilibrium when the sum of the external forces is zero and when the sum of the external torques is zero. In other words…∑τ = 0 Hint: When acceleration is zero the net force and in the case of rotational motion, net torque is zero. Remember the lever arm must be determined relative to t ...
... A body is in equilibrium when the sum of the external forces is zero and when the sum of the external torques is zero. In other words…∑τ = 0 Hint: When acceleration is zero the net force and in the case of rotational motion, net torque is zero. Remember the lever arm must be determined relative to t ...
More on energy plus gravitation
... Newton’s 2nd law still works. The net force ! on !an object determines the object’s acceleration: Fnet = ma Remarkably, the mass in Newton’s 2nd law (called the inertial mass) is the same as the mass in the law of gravitation (called the gravitational mass). Einstein figured out (230 years later) th ...
... Newton’s 2nd law still works. The net force ! on !an object determines the object’s acceleration: Fnet = ma Remarkably, the mass in Newton’s 2nd law (called the inertial mass) is the same as the mass in the law of gravitation (called the gravitational mass). Einstein figured out (230 years later) th ...
Work, Energy & Power
... Energy is neither created or destroyed Energy is transferred from one object to another or changes from one form to another The change in an objects kinetic energy is the result of the net work done on it. Energy Gained is positive work Energy lost is negative work ...
... Energy is neither created or destroyed Energy is transferred from one object to another or changes from one form to another The change in an objects kinetic energy is the result of the net work done on it. Energy Gained is positive work Energy lost is negative work ...
Tutorial #8 Solutions
... Note that the total mechanical energy (U + K) of both masses is no longer conserved after the 7.0-kg block hits the floor because a nonconservative contact force acts to stop it. (c) When the 7.0 kg mass comes to rest on the floor, its kinetic energy is lost. K = 21 m 2 v B2 = 21 (7.0 kg)(5.172 m/s ...
... Note that the total mechanical energy (U + K) of both masses is no longer conserved after the 7.0-kg block hits the floor because a nonconservative contact force acts to stop it. (c) When the 7.0 kg mass comes to rest on the floor, its kinetic energy is lost. K = 21 m 2 v B2 = 21 (7.0 kg)(5.172 m/s ...
End of chapter exercises
... 1. The force with which the Earth attracts a body. 2. The unit for energy. 3. The movement of a body in the Earth's gravitational field when no other forces act on it. 4. The sum of the potential and kinetic energy of a body. 5. The amount of matter an object is made up of. Practise more questions l ...
... 1. The force with which the Earth attracts a body. 2. The unit for energy. 3. The movement of a body in the Earth's gravitational field when no other forces act on it. 4. The sum of the potential and kinetic energy of a body. 5. The amount of matter an object is made up of. Practise more questions l ...
Navier-Stokes - Northern Illinois University
... The equation of motion for an arbitrary density in a volume is a balance equation. Current J through the sides of the volume Source s inside the volume ...
... The equation of motion for an arbitrary density in a volume is a balance equation. Current J through the sides of the volume Source s inside the volume ...
Energy
... Level 1: Bowling Ball – Find the Kinetic Energy Hint: You will need a ruler, stopwatch, and calculator to complete this. Also, remember that: velocity(m/sec) = distance(m) / time(sec) d = 10 m ...
... Level 1: Bowling Ball – Find the Kinetic Energy Hint: You will need a ruler, stopwatch, and calculator to complete this. Also, remember that: velocity(m/sec) = distance(m) / time(sec) d = 10 m ...
Lecture 8: Forces & The Laws of Motion
... Another student pushes his physics book up a 30o inclined plane. Assuming the coefficient of kinetic friction is the same in both cases, in which case is the force of friction acting on the book greater? a) the book on the flat table b) the book on the inclined plane c) the force of friction is the ...
... Another student pushes his physics book up a 30o inclined plane. Assuming the coefficient of kinetic friction is the same in both cases, in which case is the force of friction acting on the book greater? a) the book on the flat table b) the book on the inclined plane c) the force of friction is the ...
Name Period
... 17. Work is a _________ quantity. A) vector B) scalar 18. A “weak” spring, like the spring in a mechanical pencil, has a ____________ spring constant. A) large B) small 19. T/F, A spring compressed twice its original distance has 2 times the elastic potential energy. 20. T/F, The energy we use on ea ...
... 17. Work is a _________ quantity. A) vector B) scalar 18. A “weak” spring, like the spring in a mechanical pencil, has a ____________ spring constant. A) large B) small 19. T/F, A spring compressed twice its original distance has 2 times the elastic potential energy. 20. T/F, The energy we use on ea ...
File
... 1. Work is being done on the textbook when a student a. sits in a chair holding a 0.15kg textbook. b. lifts a 0.15kg textbook from the floor to a desk. c. walks across the classroom holding a 0.15kg textbook. d. leans against a 0.15kg textbook that is sitting on a desk. 2. The engine of a car exerts ...
... 1. Work is being done on the textbook when a student a. sits in a chair holding a 0.15kg textbook. b. lifts a 0.15kg textbook from the floor to a desk. c. walks across the classroom holding a 0.15kg textbook. d. leans against a 0.15kg textbook that is sitting on a desk. 2. The engine of a car exerts ...
02 Effeciency and AMA
... force that must be applied initially to move an object. A ____________ is a doubleinclined plane (both sides are inclined) that moves to exert a force along the lengths of the sides. The force is perpendicular to the inclined surfaces, so it pushes two objects (or portions of a single object) a ...
... force that must be applied initially to move an object. A ____________ is a doubleinclined plane (both sides are inclined) that moves to exert a force along the lengths of the sides. The force is perpendicular to the inclined surfaces, so it pushes two objects (or portions of a single object) a ...
Document
... Approximately 5.73 104 kg of water fall each second through a height of 19.6 m. If 85 % of the gravitational potential energy of the water were converted to electrical energy, how much power would be generated? *A) 9.36 106 W B) 1.52 107 W ...
... Approximately 5.73 104 kg of water fall each second through a height of 19.6 m. If 85 % of the gravitational potential energy of the water were converted to electrical energy, how much power would be generated? *A) 9.36 106 W B) 1.52 107 W ...
Conservation of Energy
... You can think of potential energy as the energy “that is stored, waiting to be released”. Other examples of potential energy are chemical potential energy (batteries, explosives and donuts have lots of this), and nuclear potential energy (uranium and plutonium have lots of this). Another important e ...
... You can think of potential energy as the energy “that is stored, waiting to be released”. Other examples of potential energy are chemical potential energy (batteries, explosives and donuts have lots of this), and nuclear potential energy (uranium and plutonium have lots of this). Another important e ...
PEg KE and Spring Problems
... b) If the cart has that minimum speed at A, how fast will it be going when it reaches C? 2. A roller coaster cart starts at rest 80 m above the ground, and plunges down a hill to ground level. There is a circular loop, with its base on the ground, in the track. What is the maximum radius of this loo ...
... b) If the cart has that minimum speed at A, how fast will it be going when it reaches C? 2. A roller coaster cart starts at rest 80 m above the ground, and plunges down a hill to ground level. There is a circular loop, with its base on the ground, in the track. What is the maximum radius of this loo ...