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1 - Net Start Class
1 - Net Start Class

... 7. A football is kicked into the air at an angle of 45 degrees with the horizontal. At the very top of the ball's path, its acceleration is _______. (Neglect the effects of air resistance.) 8. A football is kicked into the air at an angle of 45 degrees with the horizontal. At the very top of the ba ...
Yr 8 Core Knowledge Booklet
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... Year 8 This booklet contains the core knowledge that we believe is the foundation of understanding for each of the topics taught in year 8. Pupils are require to learn a selection of these questions each week for homework. Their teacher will then carry out regular quizzes to check pupil progress. Th ...
rest energy - Purdue Physics
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... from the star can pass by either side of the black hole and still be bent by gravity and reach the Earth • The black hole acts as a gravitational lens • Light from a single star can produce multiple images • Analysis of the images can be used to deduce the mass Section 27.10 of the black hole ...
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Motion and Forces

... Newton’s Second Law Practice 1 1. What is the net force on a dragster with a mass of 900 kg if is acceleration is 32.0m/s2? 2. What is the force on a helicopter that has a mass of 4500 kg if it’s acceleration is 4m/s2? 3. If a car with a mass of 1500 kg has an acceleration of 2.0m/s2, what is the f ...
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SPW Chapter 4 PPT

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... So far, we have discussed only the application of Newton’s laws to particles, or to bodies in situations where they can be treated as particles — planets in orbit round the Sun, for example. In this chapter, we apply Newton’s laws to systems of interacting particles, which could be as simple as two ...
Forces Introduction Powerpoint
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... The shell is fired from a gun leaving the barrel with a velocity of +770 m/s. The gun barrel is 1.5m long. Assume that the force, and the acceleration, of the shell is constant while the shell is in the gun barrel. What is the force on the shell while it is in the gun ...
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... Distance-Time Graphs • Distance is plotted on the vertical axis and Time on the horizontal axis. • The distance-time graph for an object moving at a constant speed is always a straight line with a slope. ...
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Ch 9 - Momentum and Collisions (No 2D)

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Answer, Key – Homework 4 – David McIntyre – 45123 – Mar 25

Lecture - Mr Lundy`s Room
Lecture - Mr Lundy`s Room

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... If we consider just the pulley above the painter’s head, there is a nonzero horizontal force to the left due to the tension in the rope. So the painter must actually pull the rope slightly to the left to balance this force. b) Find the acceleration of the platform. Solution: Let a1 denote the magnit ...
Dynamics and Space - Eyemouth High School
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... I can interpret speed-time graphs to describe motion and can calculate distance travelled from them for objects which are speeding up, slowing down, stationary and moving with constant speed. I can use the relationship involving acceleration, change in speed and time. Relationship between forces, mo ...
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... velocities. Within the same time interval, greater force will always be required to stop the car that has the greater: a. b. c. ...
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CM Test Booklet Serial No.:

... Q.43. On a frictionless surface, a block of mass M moving at speed u collides elastically with another block of the same mass that is initially at rest. After the collision, the first block moves at an angle e to its initial direction and has a speed 112 . The second block's speed after the collisi ...
L7 - University of Iowa Physics
L7 - University of Iowa Physics

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Lecture Mechanics Projectile ppt

... In this case, we have done work at two instances: (1)At the beginning, when we do work on the object to start it moving with velocity v. Using his equations, Newton found that in this case, we have transferred our energy to the object in forms of so called kinetic energy, K = mv2/2. ...
04_Force and Motion
04_Force and Motion

... of Motion According to Aristotle, the natural state of objects was to be at rest, and if you got them moving, eventually they would come to rest again. Galileo did experiments rolling balls down and up inclined planes, and realized that, in the absence of some kind of force, an object would keep mov ...
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... Solution The pivot point is at the hinges of the door, opposite to where you were pushing the door. The force you used was 50N, at a distance 1.0m from the pivot point. You hit the door perpendicular to its plane, so the angle between the door and the direction of force was 90 degrees. Since = r x ...
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Equations of motion

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