Chapter 8, Part V
... Velocity v ω Acceleration a α Force (Torque) F τ Mass (moment of inertia) m I Newton’s 2nd Law ∑F = ma ∑τ = Iα Kinetic Energy (KE) (½)mv2 (½)Iω2 CONNECTIONS v = rω, atan= rα, aR = (v2/r) = ω2 r τ = rF, I = ∑(mr2) ...
... Velocity v ω Acceleration a α Force (Torque) F τ Mass (moment of inertia) m I Newton’s 2nd Law ∑F = ma ∑τ = Iα Kinetic Energy (KE) (½)mv2 (½)Iω2 CONNECTIONS v = rω, atan= rα, aR = (v2/r) = ω2 r τ = rF, I = ∑(mr2) ...
Kinematics, Momentum and Energy
... When a force is applied to an object, it will be accelerated. ...
... When a force is applied to an object, it will be accelerated. ...
Chapter 1 Quick Review
... 3. A 2.0-kg block starts from rest on the positive x axis 3.0 m from the origin and thereafter has an acceleration given by a = (4.0 m/s2)i-(3.0 m/s2)j. The torque, relative to the origin, acting on it at the end of 2.0 s is: (Torque as a Vector) a. 0 b. (-18N m)k c. (+24 N m)k d. (-144 N m)k e. (+1 ...
... 3. A 2.0-kg block starts from rest on the positive x axis 3.0 m from the origin and thereafter has an acceleration given by a = (4.0 m/s2)i-(3.0 m/s2)j. The torque, relative to the origin, acting on it at the end of 2.0 s is: (Torque as a Vector) a. 0 b. (-18N m)k c. (+24 N m)k d. (-144 N m)k e. (+1 ...
LOYOLA COLLEGE (AUTONOMOUS), CHENNAI – 600 034
... 11. Obtain the equations of motion of a simple pendulum by using Lagrangian method and hence deduce the formula for its time period for small amplitude oscillations. 12. Derive an expression for the rotational kinetic energy of a rigid body. 13. Show that the shortest distance between two points in ...
... 11. Obtain the equations of motion of a simple pendulum by using Lagrangian method and hence deduce the formula for its time period for small amplitude oscillations. 12. Derive an expression for the rotational kinetic energy of a rigid body. 13. Show that the shortest distance between two points in ...
Physics 103-02 Exam IV 4 Dec
... m/sec parallel to the x-axis. What is the angular momentum of the particle about the origin when its position is at r = 2.00 m from the origin along a line making a 30o angle with the x-axis? [Including direction!] ...
... m/sec parallel to the x-axis. What is the angular momentum of the particle about the origin when its position is at r = 2.00 m from the origin along a line making a 30o angle with the x-axis? [Including direction!] ...
MollyHungEmilyROTMOT
... used for two different concepts. Centrifugal force is one of the fictitious forces that appears to act on an object when its motion is viewed from a rotating frame of reference. Magnitude of centripetal force is F=mv2/r. ...
... used for two different concepts. Centrifugal force is one of the fictitious forces that appears to act on an object when its motion is viewed from a rotating frame of reference. Magnitude of centripetal force is F=mv2/r. ...
Newton`s Second and Third Laws of Motion
... Newton’s Second Law of Motion Force is proportional to mass and ...
... Newton’s Second Law of Motion Force is proportional to mass and ...
ppt
... The answer to the key question: To get the acceleration of each body, you first need to formulate the equations of motion ...
... The answer to the key question: To get the acceleration of each body, you first need to formulate the equations of motion ...
MODULE DESCRIPTOR Code: Alt Codes: Title:
... Mechanical Engineering Practical Skills I. Assessment: Written examination (100%) To pass this course, students must: Obtain an overall pass mark of 40% ...
... Mechanical Engineering Practical Skills I. Assessment: Written examination (100%) To pass this course, students must: Obtain an overall pass mark of 40% ...
Rotational Motion - SFA Physics and Astronomy
... literally means “center seeking” and can be provided by many different forces or force combinations. Using Newton’s Second Law, we can write Fc = mac = mv2/r = mr2. “Centrifugal (center fleeing) force” is a fictitious force experienced by an object located in an accelerated reference frame. As view ...
... literally means “center seeking” and can be provided by many different forces or force combinations. Using Newton’s Second Law, we can write Fc = mac = mv2/r = mr2. “Centrifugal (center fleeing) force” is a fictitious force experienced by an object located in an accelerated reference frame. As view ...
ICNS 132 : Rotational Motion and Equilibrium
... •Equilibrium implies that the object moves with both constant velocity and constant angular velocity relative to an observer in an inertial reference ...
... •Equilibrium implies that the object moves with both constant velocity and constant angular velocity relative to an observer in an inertial reference ...
Chapter 11 - SFA Physics
... Kinetics of Particles: Newton’s Second Law 12.1 Introduction 12.2 Newton’s Second Law of Motion If the resultant force acting on a particle is not zero, the particle will have an acceleration proportional to the magnitude of the resultant and in the direction of this resultant force. ...
... Kinetics of Particles: Newton’s Second Law 12.1 Introduction 12.2 Newton’s Second Law of Motion If the resultant force acting on a particle is not zero, the particle will have an acceleration proportional to the magnitude of the resultant and in the direction of this resultant force. ...
Angular Motion Vocabulary
... 9. Centripetal Force- A force that acts on a body moving in a circular path and is directed toward the center around which the body is moving. 10. Centripetal Acceleration- The acceleration toward the center of rotation that holds an object in its circular motion 11. Gravitational Force- the force o ...
... 9. Centripetal Force- A force that acts on a body moving in a circular path and is directed toward the center around which the body is moving. 10. Centripetal Acceleration- The acceleration toward the center of rotation that holds an object in its circular motion 11. Gravitational Force- the force o ...
a previous Learning Experience
... A compact disk starts from rest and accelerates constantly to an angular speed of 300 rev/min (31.4 rad/s), taking t = 2.00 seconds to do so. Compute the angular displacement during this time interval. ...
... A compact disk starts from rest and accelerates constantly to an angular speed of 300 rev/min (31.4 rad/s), taking t = 2.00 seconds to do so. Compute the angular displacement during this time interval. ...
• Introduction
... If body A exerts a force F AB (action) on body B, then body B exerts a force FBA (reaction) on A of the same intensity but in the opposite direction. In other words, for every action there is an equal and opposite reaction: FAB = - F BA The forces of action and reaction act on different bodies. Newt ...
... If body A exerts a force F AB (action) on body B, then body B exerts a force FBA (reaction) on A of the same intensity but in the opposite direction. In other words, for every action there is an equal and opposite reaction: FAB = - F BA The forces of action and reaction act on different bodies. Newt ...
Examination Paper (Mechanics)
... (6) A rigid body is made of three identical thin rods, each with length L, fastened together in the form of a letter H, as shown in the diagram. The body is free to rotate about a horizontal axis that runs along the length of one of the legs of the H. The body is allowed to fall from rest from a pos ...
... (6) A rigid body is made of three identical thin rods, each with length L, fastened together in the form of a letter H, as shown in the diagram. The body is free to rotate about a horizontal axis that runs along the length of one of the legs of the H. The body is allowed to fall from rest from a pos ...
Document
... In problems dealing with several connected rigid bodies each body may be considered separately or, if no more than three unknowns are involved, the principles of impulse and momentum may be applied to the entire system, considering the impulses of the external forces only. When the lines of action o ...
... In problems dealing with several connected rigid bodies each body may be considered separately or, if no more than three unknowns are involved, the principles of impulse and momentum may be applied to the entire system, considering the impulses of the external forces only. When the lines of action o ...
Up, Up and Away
... P3.35 shows two people pulling on a stubborn mule. Let the magnitude of F2 = 64.0 N and the angle at which F1 pulls be = ...
... P3.35 shows two people pulling on a stubborn mule. Let the magnitude of F2 = 64.0 N and the angle at which F1 pulls be = ...
