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Up, Up and Away
January 25, 2006
– Some problems on vectors
– Introduction to some 2D issues
Friday, Monday
– 2D Kinematics
– Exam #1 – Through 2D Stuff finished on Monday
– Going around in circles
Find the horizontal and vertical components of the d = 140 m
displacement of a superhero who flies from the top of a tall
building following the path shown in the Figure where = 30.0°.
The helicopter view in Figure
P3.35 shows two people
pulling on a stubborn mule.
Let the magnitude of F2 =
64.0 N and the angle at
which F1 pulls be =
(a) Find the single force that is
equivalent to the two
forces shown. The forces
are measured in units of
newtons (symbolized N).
(b) (b) Find the force that a
third person would have to
exert on the mule to make
the resultant force equal to
(c) Use I,j notation
2 Dimensional Motion
We will consider motion the the x-y plane.
Positions now have (x,y) coordinates so we
need to use vectors.
That’s why we did that pointy stuff on Monday
There are two types of problems we need to
Throw or drop an object at an angle to the
Make something go around in a circle
Positions are VECTOR quantities
ri  r  r f
ri  r f  r
Which way is the acceleration?
In 2D motion, lots of things happen at once!
An Example …
What is its velocity here?
It’s acceleration?
How long did it take to get here?
height (h)
Let’s Just Do it!
The Monkey Problem – Hit or Miss?