Download Paley-Wiener theorems

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Laplace transform wikipedia , lookup

Mathematical optimization wikipedia , lookup

Renormalization group wikipedia , lookup

Fourier transform wikipedia , lookup

Path integral formulation wikipedia , lookup

Probability box wikipedia , lookup

Mathematics of radio engineering wikipedia , lookup

Generalized linear model wikipedia , lookup

Dirac delta function wikipedia , lookup

Transcript
(September 7, 2013)
Paley-Wiener theorems
Paul Garrett [email protected]
http://www.math.umn.edu/egarrett/
[This document is http://www.math.umn.edu/˜garrett/m/fun/notes 2013-14/paley-wiener.pdf]
Of course, the original version [Paley-Wiener 1934] referred to L2 functions, not distributions. The
distributional aspect is from [Schwartz 1952]. We emphasize Gelfand-Pettis vector-valued integral techniques.
Proofs are given just for R, where all ideas are already manifest.
[0.0.1] Theorem: A test function f supported on a closed ball Br of radius r at the origin in R has Fourier
transform fb extending to an entire function on C, with
|fb(z)| N (1 + |z|)−N er·|y|
(for z = x + iy ∈ C, for every N )
Conversely, an entire function satisfying such an estimate has (inverse) Fourier transform which is a test
function supported in the ball of radius r.
[0.0.2] Remark: Most of the proof is expected. The interesting point is that rate-of-growth in the imaginary
part determines the support of the inverse Fourier transforms.
Proof: First, the integral for fb(z) is the integral of the compactly-supported, continuous, entire-functionvalued [1] function,
ξ −→ z → f (ξ) · e−iξz
Thus, the Gelfand-Pettis integral exists, and is entire. Multiplication by z is converted to differentiation
inside the integral,
(−iz)N · fb(z) =
Z
Br
∂ N −iz·ξ
e
· f (ξ) dξ = (−1)N
∂ξ N
Z
Br
e−iz·ξ ·
∂N
f (ξ) dξ
∂ξ N
by integration by parts. Note that differentiation does not enlarge support. Thus,
Z
Z
e−ix·ξ f (N ) (ξ) dξ e−iz·ξ f (N ) (ξ) dξ ≤ (1 + |z|)−N · er·|y| · |fb(z)| N (1 + |z|)−N · Br
Br
≤ (1 + |z|)−N · er·|y| ·
Z
|f (N ) (ξ)| dξ f,N (1 + |z|)−N · er·|y|
Br
Conversely, let F be an entire function with the indicated growth and decay property, and show that
Z
ϕ(ξ) =
eixξ F (x) dx
is a test function with support inside Br . Note that the assumptions on F do not directly assert that F
is Schwartz, so we cannot directly conclude that ϕ is smooth. Nevertheless, a similar obvious computation
would give
Z
Z
Z
∂ N ixξ
∂N
(ix)N · eixξ F (x) dx =
e
F
(x)
dx
=
eixξ F (x) dx
∂ξ N
∂ξ N
Of course, moving the differentiation outside the integral is necessary. As expected, it is justified in terms of
Gelfand-Pettis integrals, as follows. Since F strongly vanishes at ∞, the integrand extends continuously to
[1] As usual, the space of entire functions is given the sups-on-compacts semi-norms sup
z∈K |f (z)|. Since C can be
covered by countably-many compacts, this topology is metrizable. Cauchy’s integral formula proves completeness, so
this space is Fréchet.
1
Paul Garrett: Paley-Wiener theorems (September 7, 2013)
the stereographic-projection one-point compactification of R, giving a compactly-supported smooth-functionvalued function on this compactification. The measure on the compactification can be adjusted to be finite,
taking advantage of the rapid decay of F :
Z
Z
dx
ixξ
ϕ(ξ) =
e F (x) dx =
eixξ F (x) (1 + x2 )N
(1 + x2 )N
Thus, the Gelfand-Pettis integral exists, and ϕ is smooth. Thus, in fact, the justification proves that such
an integral of smooth functions is smooth without necessarily producing a formula for derivatives.
To see that ϕ is supported inside Br , observe that, taking y of the same sign as ξ,
F (x + iy) · eiξ(x+iy) N (1 + |z|)−N · e(r−|ξ|)·|y|
Thus,
Z
|ϕ(ξ)| N
(1 + |z|)−N · e(r−|ξ|)·|y| dx ≤ e(r−|ξ|)·|y| ·
R
Z
dx
−N
R (1 + |x|)
For |ξ| > r, letting |y| → +∞ shows that ϕ(ξ) = 0.
///
[0.0.3] Theorem: The Fourier transform ub of a distribution u supported in Br , of order N , is (integration
against) the function x → u(ξ → e−ixξ ), which is smooth, and extends to an entire function satisfying
|b
u(z)| (1 + |z|)N · er·|y|
Conversely, an entire function meeting such a bound is the Fourier transform of a distribution of order N
supported inside Br .
Proof: Recall that the Fourier transform ub is the tempered distribution defined for Schwartz functions ϕ by
Z
Z
−ixξ
u
b(ϕ) = u(ϕ)
b = u ξ→
e
ϕ(x) dx =
u(ξ → e−ixξ ) ϕ(x) dx
R
R
since x → (ξ → e−ixξ ϕ(ξ) extends to a continuous smooth-function-valued function on the stereographicprojection one-point compactification of R, and Gelfand-Pettis applies. Thus, as expected, u
b is integration
against x → u(ξ → e−ixξ ).
The smooth-function-valued function z → (ξ → e−izξ ) is holomorphic in z. Compactly-supported
distributions constitute the dual of C ∞ (R), so application of u gives a holomorphic scalar-valued function
z → u(ξ → e−izξ ).
Let νN be the N th -derivative seminorm on C ∞ (Br ), so
|u(ϕ)| ε νN (ϕ)
Then
|b
u(z)| = |u(ξ → e−izξ )| ε νN (ξ → e−izξ ) sup (1 + |z|)N e−izξ ≤ (1 + |z|)N er·|y|
Br
Conversely, let F be an entire function with |F (z)| (1+|z|)N er·|y| . Certainly F is a tempered distribution,
so F = u
b for a tempered distribution. We show that u is of order at most N and has support in Br .
R
With η supported on B1 with η ≥ 0 and η = 1, make an approximate identity ηε (x) = η(x/ε)/ε for ε → 0+ .
By the easy half of Paley-Wiener for test functions, ηbε is entire and satisfies
|b
ηε (z)| ε,N (1 + |z|)−N · eε·|y|
2
(for all N )
Paul Garrett: Paley-Wiener theorems (September 7, 2013)
Note that ηbε (x) = ηb(ε · x) goes to 1 as tempered distribution
By the more difficult half of Paley-Wiener for test functions, F · ηbε is ϕ
bε for some test function ϕε supported
in Br+ε . Note that F · ηbε → F .
For Schwartz function g with the support of gb not meeting Br , gb · ϕε for sufficiently small ε > 0. Since F · ηbε
is a Cauchy net as tempered distributions,
Z
Z
Z
Z
Z
u(b
g) = u
b(g) =
F ·g =
lim(F · ηbε ) g = lim (F · ηbε ) g = lim ϕ
bε g = lim ϕε gb = 0
ε
ε
This shows that the support of u is inside Br .
ε
ε
///
[Hörmander 1990] L. Hörmander, The analysis of linear partial differential operators, I, Springer-Verlag,
1990.
[Paley-Wiener 1934] R. Paley, N. Wiener, Fourier transforms in the complex domain, AMS Coll. Publ. XIX,
NY, 1934.
[Schwartz 1950/51] L. Schwartz, Théorie des Distributions, I,II Hermann, Paris, 1950/51, 3rd edition, 1965.
[Schwartz 1952] L. Schwartz, Transformation de Laplace des distributions, Comm. Sém. Math. Univ. Lund
(1952), 196-206.
[wikipedia 2013] Paley-Wiener theorem, retrieved 24 June 2013
http://en.wikipedia.org/wiki/Paley-Wiener theorem
3