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43799 D&PS Jan11 The sample unbiased estimate � of standard deviation, s, is the �n 2 i=1 (xi − x̄) . The standard square root of the variance: s = n−1 deviation of the sample mean is called the standard error of the mean and is equal to √σn , and is often estimated by √sn . Population values, or parameters, are denoted by Greek letters. Population mean = µ. Population variance = σ 2 . Population standard deviation = σ. Sample values, or estimates, are denoted by roman letters. The mean of a sample of n observations x1 , x2 , . . . xn is �n x1 + x2 + · · · + xn i=1 xi = x̄ = n n The sample mean x̄ is an unbiased estimate of the population mean µ. The unbiased of the variance of these n sample �estimate n 2 i=1 (xi − x̄) which can be written as observations is s2 = n−1 n 1 � 2 nx̄2 s2 = xi − n − 1 i=1 n−1 c ln x + c or ln c� x ex + c ekx k +c − k1 cos kx + c 1 k sin kx + c � k, constant x kx + c x2 2 +c x2 x3 3 +c xn+1 n+1 + For more copies contact the Network at [email protected] This leaflet has been produced in conjunction with the Higher Education Academy Maths, Stats & OR Network, the UK Physical Sciences Centre, and sigma www.mathcentre.ac.uk f (x) dx Integration b2 − 4ac > 0 b2 − 4ac = 0 b2 − 4ac < 0 (1) x −b/2a nt adie e gr ativ neg (x2 ,y2 ) (x1 ,y1 ) d df (k × f (x)) = k × dx dx for k constant. 1 x y = f (x) dy dx k, constant x x2 xn , constant n sin(kx) cos(kx) ex ekx ln kx = loge kx 0 1 2x nxn−1 k cos(kx) −k sin(kx) ex kekx x minimum point mathcentre is a project offering students and staff free resources to support the transition from school mathematics to university mathematics in a range of disciplines. Mathematics for Chemistry Facts & Formulae For the help you need to support your course dy >0 dx dy <0 dx y = f � (x) Arithmetic Second priority Second priority Second priority as a percentage is 5 8 1 3 × 100% = 33 13 % Algebra Trigonometry Degrees and radians: 2π π 360◦ = 2π radians, 1◦ = = radians 360 180 180 degrees ≈ 57.3◦ 1 radian = π Trig ratios for an acute angle θ: e b side opposite to θ s u = ten po c hypotenuse c b hy sin θ = Removing brackets: a(b + c) = ab + ac, a(b − c) = ab − ac a ac (a + b)(c + d) = ac + ad + bc + bd c= b b Formula for solving a quadratic equation: √ −b ± b2 − 4ac if ax2 + bx + c = 0 then x = 2a Laws of Indices: am = am−n (am )n = amn (ab)n = an bn am an = am+n an √ √ m 1 a0 = 1 a−m = m a1/n = n a a n = ( n a)m a Logarithms: for any positive base b (with b = 1) logb A = c means A = bc . Logarithms to base e, denoted loge or alternatively ln are called natural logarithms. The letter e stands for the exponential constant which is approximately 2.718. loge A or ln A = c means A = ec . opposite When multiplying or dividing positive and negative numbers the sign of the result is given by: positive × positive = positive positive × negative = negative negative × positive = negative negative × negative = positive positive positive = positive = negative positive negative negative negative = negative = positive positive negative The BODMAS rule reminds us of the order in which operations are carried out. BODMAS stands for: Brackets () First priority Of Division ÷ Multiplication × Addition + Third priority Subtraction − Third priority numerator Fractions: fraction = denominator Adding and subtracting fractions: to add or subtract two fractions first rewrite each fraction so that they have the same denominator. Then, the numerators are added or subtracted as appropriate and the result is divided by the common denomina3 16 15 31 4 + = . tor: e.g. + = 5 4 20 20 20 Multiplying fractions: to multiply two fractions, multiply their numerators and then multiply their denominators: e.g. 3 5 3×5 15 × = = 7 11 7 × 11 77 Dividing fractions: to divide two fractions, invert the second 3 2 3 3 9 and then multiply: e.g. ÷ = × = . 5 3 5 2 10 Proportion and Percentage: To convert a fraction to a percentage multiply by 100 and label the result as a percentage. as a percentage is × 100% = 62.5% 5 8 1 3 a side adjacent to θ θ = cos θ = a hypotenuse c adjacent side opposite to θ b Pythagoras’ theorem: = side adjacent to θ a a2 + b2 = c2 tan θ = Standard triangles: √ 2 2 60◦ 1 1 45◦ 1 30◦ √ 1 sin 45◦ = √ , 2 cos 60◦ = c, the natural logarithm of a number A, is the power to which e would have to be raised to equal A. Note: eln A = A if A > 0; ln(eA ) = A Logarithms to base 10: log10 A = c means A = 10c . pH: of a solution measures its acidity or basicity. 3 1 cos 45◦ = √ , 2 tan 45◦ = 1 √ 3 cos 30◦ = , 2 1 sin 30◦ = , 2 √ 3 , 2 sin 60◦ = 1 tan 30◦ = √ 3 1 , 2 y Some common conversions are: 1 1 3 1 = 10%, = 25%, = 50%, = 75% 10 4 2 4 Ratios are an alternative way of expressing fractions. Consider dividing £200 between two people in the ratio of 3:2. For every £3 the first person gets, the second person gets £2. So the first gets 35 of the total, and the second gets 52 of the total; that is £120 and £80. (1) (2) (3) (2) (1) Quadratic functions: y = ax2 + bx + c x x (x2, y2 ) y2 − y1 m= x2 − x1 c Differentiation Graphs of common functions Generally, to split a quantity in the ratio m : n, the quantity is m n of the total and m+n of the total. split into m+n b2 − 4ac < 0 b2 − 4ac = 0 b2 − 4ac > 0 (2) (3) x if a is negative www.mathcentre.ac.uk © mathcentre 2010 The linearity rule: � � � (af (x) + bg(x)) dx = a f (x) dx + b g(x) dx, (a, b constant) � b � b dv du u dx = [uv]ba − Integration by parts: v dx. dx dx a a xn , (n �= −1) x−1 = x1 ex ekx sin kx cos kx f (x) Statistics (1) (2) (3) −b/2a d2 f df , means differentiate dx2 � � dx df d2 f d . with respect to x. That is, = dx2 dx dx Partial derivatives: If f = f (x, y) is a function of two (or more) ∂f independent variables, ∂x means differentiate f with respect to means differentiate f x treating y as if it were a constant. ∂f ∂y with respect to y treating x as if it were a constant. Higher derivatives: f �� (x), or (3) if a is positive The product and quotient rules: v du − u dv dv du d �u� d (uv) = u +v = dx 2 dx . dx dx dx dx v v The chain rule: dy dy If y = y(u) where u = u(x) then dx = du × du . dx Graph of y = ex and y = e−x Graph of y = ln x and y = log x 10 showing exponential growth/ decay 1 -1 (x1 ,y1 ) pos a The linearity rules: d du dv (u(x)±v(x)) = ± dx dx dx x 1 1 y=ln x y = log1 0 x Exponential and log functions: e ≈ 2.718 is the exponential constant. y y = ex y= e-x x c gr itive t dien y dy Differentiating a function, y = f (x), we obtain its derivative dx . This new function tells us the gradient (slope) of the original dy = 0 the gradient is zero. function at any point. When dx The straight line: y = mx + c. m=gradient (slope), c = vertical intercept. tan 60◦ = √ ◦ pH = − log10 ([H+ ]/c− ) ◦ [H+ ] = 10−pH c− so where [H+ ] = hydrogen ion concentration in mol dm−3 and ◦ c− = 1 mol dm−3 . Equivalently, pH = − log10 aH3 O+ where aH O+ = hydronium ion activity. 3 Laws of Logarithms: for any positive base b, with b = 1, A logb A − logb B = logb , logb A + logb B = logb AB, B 3 Bragg’s Law: a fundamental law of x-ray crystallography. nλ = 2d sin θ λ = wavelength of the x-rays incident on a crystal lattice with planes a distance d apart, n is an integer (whole number), and θ, the Bragg angle, is the angle between the incident beam and the reflecting planes. n logb A= An , logb logb Formula for change of base: ln x log10 x = . ln 10 Inequalities: Matrices and Determinants � � a b The 2 × 2 matrix A = has determinant c� d � �a b� � = ad − bc |A| = �� c d� a11 a12 a13 The 3 × 3 matrix A = a21 a22 a23 has determinant a31 a32 a33 � � � � � �a �a a23 �� a23 �� a22 �� − a12 �� 21 + a13 �� 21 a33 � a31 a33 � a31 a32 � 1 = 0, loga x = logb logb x . logb a b = 1. Specifically, a > b means a is greater than b a < b means a is less than b a b means a is greater than or equal to b a b means a is less than or equal to b Sigma notation: The Greek letter sigma, Σ, is used to abbrevix , . . . xn , and add them, ate addition. If we have n values, 2 n xi . x1 , � �a |A| = a11 �� 22 a32 the sum x1 + x2 + . . . xn is written i=1 Note that i takes all whole number values from 1 to n. So, for 3 xi means x1 + x2 + x3 . The inverse of�a 2 × 2 matrix: � � � 1 a b d −b If A = then A−1 = c d ad − bc −c a provided that ad − bc �= 0. Matrix multiplication: for 2 × 2 matrices � �� � � � a b α γ aα + bβ aγ + bδ = c d β δ cα + dβ cγ + dδ instance i=1 Example: 5 2 2 2 2 2 2 i=1 i means 1 + 2 + 3 + 4 + 5 . n xi = x1 · x2 · . . . · xn . Product notation: i=1 Produced in conjunction with the Higher Education Academy Maths, Stats & OR Network, the UK Physical Sciences Centre, sigma, and the HE STEM Programme. Thanks to the many individuals who c 2010. - version draft 1, August 2010. offered detailed advice. Remember that AB �= BA except in special cases. www.mathcentre.ac.uk © mathcentre 2010 2∗ 2 1 0 www.mathcentre.ac.uk © mathcentre 2010 (* A + B → P reaction.) = kt d[A] dt = −k[A][B] d[A] dt d[A] dt 1 [B]0 −[A]0 ln [B][A]0 [A][B]0 Rate Law Integrated form Half-life Common unit of k = −k [A]0 − [A] = kt [A]0 2k mol dm−3 s−1 = −k[A] [A] = [A]0 e−kt ln 2 k s−1 1 k[A]0 mol−1 dm3 s−1 - mol−1 dm3 s−1 = −k[A]2 d[A] dt Rate Law Differential form a×b = 1 [A] − 1 [A]0 = kt (a2 b3 − a3 b2 )i + (a3 b1 − a1 b3 )j + (a1 b2 − a2 b1 )k � � � i j k �� � � a1 a2 a3 � � � � b1 b2 b3 � b a · b = a 1 b1 + a 2 b2 + a 3 b3 If a = a1 i + a2 j + a3 k and b = b1 i + b2 j + b3 k then a θ a · b = |a| |b| cos θ initial volumes. where Vfinal and Vinitial are the and final ∆H ∆G ∂ =− 2 . Gibbs-Helmholtz equation: ∂T T T p First Law: For a closed system, ∆U = q + w. Here ∆U is the change in internal energy of a system, w is the work done on the system, and q is the heat energy transferred to the system. Enthalpy: H = U +pV where U = internal energy, p=pressure and V = volume. � Heat capacity at constant volume: CV = ∂U �∂T V Heat capacity at constant pressure: Cp = ∂H ∂T p In general Cp depends upon T . Values of Cp at temperatures not much different from room temperature can be estimated c from Cp = a + bT + 2 T where a, b and c are experimentally determined constants. Second Law of thermodynamics: During a spontaneous change, the total entropy of an isolated system and its surroundings increases: ∆S > 0. For a reversible process, at constant temperature, T , change in entropy qrev ∆S = T where qrev = energy reversibly transferred as heat. Boltzmann formula: S = kB ln W where W = ‘weight’ of the most probable configuration of the system and kB is the Boltzmann constant. Helmholtz energy: A = U − T S. Gibbs energy: G = H − T S. Change in Gibbs energy: ∆G = ∆H − T ∆S (at constant temperature). Entropy change for isothermal expansion of an ideal gas: Vfinal ∆S = nR ln Vinitial General Thermodynamics A B Γ ∆ E Z H Θ b Scalar product: + y2 + z2 . α β γ δ ζ η θ alpha beta gamma delta epsilon zeta eta theta I K Λ M N Ξ O Π ι κ λ µ ν ξ o π NA = 6.022 × 1023 mol−1 kB = 1.381 × 10−23 J K−1 h = 6.626 × 10−34 J s e = 1.602 × 10−19 C R = 8.314 J K−1 mol−1 0 = 8.854 × 10−12 J−1 C2 m−1 c = 2.998 × 108 m s−1 F = e NA = 96.485 kC mol−1 iota kappa lambda mu nu xi omicron pi P Σ T Υ Φ X Ψ Ω ρ σ τ υ φ χ ψ ω rho sigma tau upsilon phi chi psi omega The Greek alphabet Units & Conversions If r = xi + yj + zk then |r| = x2 Avogadro constant Boltzmann constant Planck constant Elementary charge Ideal gas constant Vacuum permittivity Speed of light (vacuum) Faraday constant Physical constants � Dalton’s Law of partial pressures: states that the pressure exerted by a mix of ideal gases is the sum of the partial pressures each would exert if they were alone in the same volume: n pi Amount of substance etc. Scientific notation: is used to express large or small numbers concisely. Each number is written in the form a × 10n where a is usually a number between 1 and 10. We make use of . . . 0.01 = 10−2 , 0.1 = 10−1 , . . . , 100 = 102 , 1000 = 103 , . . . Then, for example, 6859 = 6.859 × 1000 = 6.859 × 103 and 0.0932 = 9.32 × 0.01 = 9.32 × 10−2 . SI base units: for most quantities it is necessary to specify the units in which they are measured. Quantity SI unit Symbol length metre m mass kilogram kg time second s temperature kelvin K amount of substance mole mol current ampere A luminous intensity candela cd Derived units are formed from the base units. For example, the unit of force is found by combining units of mass, length and time in the combination kg m s−2 . This combination is more usually known as the newton, N. Property unit name unit symbols frequency hertz Hz = s−1 force newton N = kg m s−2 pressure pascal Pa = N m−2 energy joule J = N m = kg m2 s−2 charge coulomb As potential difference volt V = J C−1 power watt W = J s−1 Celsius temperature degree Celsius ◦ C Capacitance farad F = C V−1 Resistance ohm Ω Common prefixes: a prefix is a method of multiplying the SI unit by an appropriate power of 10 to make it larger or smaller. J Order J where k = rate constant, Ea = the activation energy for the reaction, R = ideal gas constant, T = absolute temperature, and A is a constant. By taking logarithms this can be expressed as A Ea k = ln − − ln − k◦ k◦ RT ◦ where k− is a chosen standard rate constant. Together, A and Ea are called the Arrhenius parameters. Reaction Thermodynamics i Kinetics = i a θ a × b = |a| |b| sin θ ê eˆ Vector product: Vectors Multiple Prefix Symbol Multiple Prefix Symbol 1012 tera T 10−1 deci d 109 giga G 10−2 centi c 106 mega M 10−3 milli m 103 kilo k 10−6 micro µ 102 hecto h 10−9 nano n 101 deca da 10−12 pico p Interconversion of units: Sometimes alternative sets of units are used and conversion between these is needed. Pressure is often quoted in units corresponding to the Standard atmosphere (atm). Then 1 atm = 1.01325×105 Pa = 1.01325 bar = 760mm Hg = 760 Torr. (1 bar = 1 × 105 Pa). Length (of bonds) is sometimes quoted in Ångströms, Å where 1 Å = 10−10 m. 1 nm = 10−9 m. 0.1nm=100pm. Energy is often measured in calories (cal): 1 cal = 4.184 J. d ∆r H . ln K = dT RT 2 ◦ K2 1 ∆r H − 1 ln − =− K1 R T2 T1 van’t Hoff equation: − ◦ ◦ = RT ln K At equilibrium Q = K, ∆r G = 0 and −∆r G− where v K= (aJJ )equilibrium where aJ is the activity of species J and νJ is its stoichiometric number. Rate Laws In the table, [A] = molar concentration of reactant A at time t. [A]0 = concentration of reactant A at time t = 0. Standard state: The standard state of a substance is the pure substance at a pressure of 1 bar. The standard state value is ◦ denoted by the superscript symbol − ◦ , as in G− . ∆G Reaction Gibbs energy: ∆r G = is the slope of the ∆ξ graph of Gibbs energy against the progress of the reaction. Here, ∆ξ = ∆nJ /νJ for all species J in the reaction. Reaction Gibbs energy at any composition of the reaction mixture can be written v ◦ ∆r G = ∆r G− + RT ln Q where Q = aJ J Arrhenius equation: The rate at which most chemical reactions proceed depends upon the temperature. The amount of energy necessary for the reaction to take place at all is called the activation energy. These quantities are related by the Arrhenius equation: k = Ae−Ea /(RT ) Vm,i is the partial molar volume of the ith substance. Total Gibbs energy for the mixture is G = nA GA + nB GB where GA and GB are the partial molar Gibbs energies of substances A and B respectively. The partial molar Gibbs energies are also denoted µA and µB so that G = nA µA +nB µB . More n i µi . generally, with mixtures of several substances G = where Vm,A = partial molar volume of A and Vm,B = partial ni Vm,i , where molar volume of B. More generally, V = ê is a unit vector perpendicular to the plane containing a and b in a sense defined by the right hand screw rule. If a = a1 i + a2 j + a3 k and b = b1 i + b2 j + b3 k then where µ∗A = chemical potential of pure A and xA is the mole fraction. Properties of mixtures: suppose an amount nA of substance A is mixed with nB of substance B. The total volume of the mixture is V = nA Vm,A + nB Vm,B Mixtures Raoult’s law: states that the partial vapour pressure, pA , in a liquid mixture, A, is proportional to its mole fraction, xA , and its vapour pressure when pure, p∗A : pA = xA p∗A . Henry’s law: states that the vapour pressure, pB , of a volatile solute, B, is proportional to its mole fraction, xB , in a solution: pB = xB KB . Here KB is Henry’s law constant. Chemical potential of a solvent: µA = µ∗A + RT ln xA The mole is the amount of substance that contains 6.0221415× 1023 (Avogadro constant/ mol−1 ) atoms or molecules of the pure substance being measured. For example 1 mole (mol) of potassium will contain NA atoms. 1 mole of water contains NA water molecules. A mole of any substance contains as many atoms or molecules (as specified) as there are atoms in 12g of the carbon isotope 612 C. (To avoid confusion, always specify the type of particle.) The molar mass, M , of a substance is the mass divided by chemical amount. For pure materials, molar mass, M = molecular weight (or relative atomic or molecular mass) × g mol−1 . The concentration or molarity of a solute is c = Vn where n = amount of solute, V = volume of solution. Molarity is usually quoted in mol dm−3 . The unit 1 mol dm−3 is commonly denoted 1 M and read as ‘molar’. The molality, b, of a solute is the amount of solute divided by n the mass of solvent: b = m . So, molality represents 1 mole of a solute in 1 kg of solvent. The mole fraction, x, of a solute is the amount of solute divided by the total amount in the solution: n x= . ntotal The mass density (or just density), ρ, of a substance is its mass divided by its volume, that is ρ = m . V The mass percentage is the mass of a substance in a mixture as a percentage of the total mass of the mixture. The mass-volume percentage is the number of grams of solute in 100 millilitres of solution. The volume-volume percentage is the number of millilitres of liquid solute in 100 millilitres of solution. Parts per million (ppm): mg/kg. Parts per billion (ppb): µg/kg. Mass obtained Yield: % yield = × 100 Theoretical yield ptotal = p1 + p2 + . . . + pn or ptotal = i=1 The partial pressure, pi , of one of the gases can be calculated by multiplying the gas mole fraction, xi , by the total pressure of all the gases, ptotal . Perfect Gas Law: pV = nRT where R = ideal gas constant. p 2 V2 p 1 V1 = . Combined Gas Laws: T1 T2 Virial equation of state: This improves the perfect gas law because it takes into account intermolecular forces. B C pVm = RT (1 + + 2 + . . .) Vm Vm Vm = Vn = molar volume, B, C etc are the virial coefficients. Observe that when the molar volume is very large, the terms B and VC2 become increasingly less important, and in the limit Vm m we obtain the ideal gas law. Van der Waals equation takes into account the finite distance between molecules and interparticle attractions: an2 RT a p + 2 (V − nb) = nRT p= − 2 or Vm − b Vm V a is a measure of attraction between particles, b is the volume excluded by a mole of particles. Phases Gibbs’ phase rule: F = C − P + 2, where F is the number of degrees of freedom, C = number of independent components, P = the number of phases in equilibrium with each other. This is a relationship used to determine the number of state variables, F , chosen from amongst temperature, pressure and species compositions in each phase, which must be specified to fix the thermodynamic state of a system in equilibrium. Clapeyron equation relates change in pressure to change in temperature at a phase boundary. The slope of the phase dp boundary is dT . dp ∆H = dT T ∆V Here ∆H = molar enthalpy of transition, ∆V = change in molar volume during transition. Gases The general form of an equation of state is p = f (T, V, n) where p = pressure, T is temperature, V = volume, n = amount of substance. Boyle’s Law relates the pressure and volume of a gas when the temperature is fixed: p1 V1 = p2 V2 . 1 An equivalent form is: pV = nM c2 , where n = number of 3 molecules, m = mass of a molecule, M (= mNA ) is the molar mass of the molecules, c2 = mean square speed. Charles’s Law relates the volume and temperature of a gas at V1 T1 = . V2 T2 Clausius-Clapeyron equation is an approximation of the Clapeyron equation for a liquid-vapour phase boundary. Plotting vapour pressure for various temperatures produces a curve. For 1 pure liquids, plotting ln pp− ◦ against T produces a straight line ◦ with gradient − ∆H . (Here, p− = any standard pressure). R p1 ∆H 1 1 =− − p2 R T1 T2 constant pressure: ln Here ∆H = molar enthalpy of vaporisation. This equation relates the natural logarithm of the vapour pressure to the temperature at a phase boundary. www.mathcentre.ac.uk © mathcentre 2010 The sample unbiased estimate � of standard deviation, s, is the � n 2 i=1 (xi − x̄) . The standard square root of the variance: s = n−1 deviation of the sample mean is called the standard error of the mean and is equal to √σn , and is often estimated by √sn . Population values, or parameters, are denoted by Greek letters. Population mean = µ. Population variance = σ 2 . Population standard deviation = σ. Sample values, or estimates, are denoted by roman letters. The mean of a sample of n observations x1 , x2 , . . . xn is �n x1 + x2 + · · · + xn i=1 xi = x̄ = n n The sample mean x̄ is an unbiased estimate of the population mean µ. The unbiased estimate of the variance of these n sample � n 2 i=1 (xi − x̄) which can be written as observations is s2 = n−1 n 1 � 2 nx̄2 xi − n − 1 i=1 n−1 www.mathcentre.ac.uk © mathcentre 2010 43799 D&PS Jan11 a (af (x) + bg(x)) dx = a � Integration by parts: b The linearity rule: � s2 = 1 k x n+1 + c ln x + c or ln c� x ex + c ekx k +c − k1 cos kx + c sin kx + c xn , (n �= −1) x−1 = x1 ex ekx sin kx cos kx x2 2 x3 3 x2 kx + c +c � f (x) (2) (3) x if a is negative (1) (3) (2) x −b/2a Quadratic functions: y = ax2 + bx + c Graph of y = ex and y = e−x Graph of y = ln x and y = log x 10 showing exponential growth/ decay x x 1 y=ex Exponential and log functions: e ≈ 2.718 is the exponential constant. y x c t posi ive i grad ent x c (x , y ) 2 2 y2 − y1 m= x2 − x1 y y ive neg at grad ient (x2 ,y2 ) (x1 ,y1 ) 1 x 0 1 2x nxn−1 k cos(kx) −k sin(kx) ex kekx k, constant x x2 xn , constant n sin(kx) cos(kx) ex ekx ln kx = loge kx dy dx y = f (x) x minimum point dy >0 dx Mathematics for Chemistry Facts & Formulae For the help you need to support your course dy <0 dx y = f � (x) dy Differentiating a function, y = f (x), we obtain its derivative dx . This new function tells us the gradient (slope) of the original dy = 0 the gradient is zero. function at any point. When dx The straight line: y = mx + c. m=gradient (slope), c = vertical intercept. Differentiation Graphs of common functions 3 , sin 60 = 2 ◦ opposite 3 1 cos 45◦ = √ , 2 √ 3 cos 30◦ = , 2 1 , 2 √ (x1 ,y1 ) The linearity rules: d du dv d df (u(x)±v(x)) = ± (k × f (x)) = k × dx dx dx dx dx for k constant. The product and quotient rules: v du − u dv dv du d �u� d (uv) = u +v = dx 2 dx . dx dx dx dx v v The chain rule: dy dy If y = y(u) where u = u(x) then dx = du × du . dx mathcentre is a project offering students and staff free resources to support the transition from school mathematics to university mathematics in a range of disciplines. Generally, to split a quantity in the ratio m : n, the quantity is m n of the total and m+n of the total. split into m+n sin 30◦ = y=e-x y=ln x y = log1 0 x d2 f df Higher derivatives: f �� (x), or , means differentiate dx2 � � dx df d2 f d . with respect to x. That is, = dx2 dx dx Partial derivatives: If f = f (x, y) is a function of two (or more) ∂f independent variables, ∂x means differentiate f with respect to means differentiate f x treating y as if it were a constant. ∂f ∂y with respect to y treating x as if it were a constant. Some common conversions are: 1 1 3 1 = 10%, = 25%, = 50%, = 75% 10 4 2 4 Ratios are an alternative way of expressing fractions. Consider dividing £200 between two people in the ratio of 3:2. For every £3 the first person gets, the second person gets £2. So the first gets 35 of the total, and the second gets 52 of the total; that is £120 and £80. 1 sin 45◦ = √ , 2 1 f (x) dx Integration b2 − 4ac > 0 b2 − 4ac = 0 b2 − 4ac < 0 60◦ 1 ◦ 30 √ 1 www.mathcentre.ac.uk × 100% = 33 13 % 45 1 -1 This leaflet has been produced in conjunction with the Higher Education Academy Maths, Stats & OR Network, the UK Physical Sciences Centre, and sigma +c 2 (1) For more copies contact the Network at [email protected] n+1 k, constant x Statistics (a, b constant) a side adjacent to θ θ = a hypotenuse c adjacent side opposite to θ b Pythagoras’ theorem: tan θ = = side adjacent to θ a a2 + b2 = c2 Standard triangles: 2 if a is positive � as a percentage is 1 3 b cos θ = 1 Third priority Third priority numerator fraction = denominator Adding and subtracting fractions: to add or subtract two fractions first rewrite each fraction so that they have the same denominator. Then, the numerators are added or subtracted as appropriate and the result is divided by the common denomina3 16 15 31 4 + = . tor: e.g. + = 5 4 20 20 20 Multiplying fractions: to multiply two fractions, multiply their numerators and then multiply their denominators: e.g. 3 5 3×5 15 × = = 7 11 7 × 11 77 Dividing fractions: to divide two fractions, invert the second 3 2 3 3 9 and then multiply: e.g. ÷ = × = . 5 3 5 2 10 Proportion and Percentage: To convert a fraction to a percentage multiply by 100 and label the result as a percentage. 5 as a percentage is 58 × 100% = 62.5% 8 1 3 2π π = radians 360 180 180 degrees ≈ 57.3◦ π Trig ratios for an acute angle θ: e b side opposite to θ us = sin θ = ten po c hypotenuse c y h ◦ Addition + Subtraction − Fractions: Removing brackets: a(b + c) = ab + ac, 1 radian = √ −b/2a g(x) dx, � du v dx. dx Second priority Second priority Second priority 1◦ = (1) (2) (3) f (x) dx + b b Of Division ÷ Multiplication × Algebra Trigonometry 360◦ = 2π radians, b2 − 4ac < 0 b2 − 4ac = 0 b2 − 4ac > 0 � a dv dx = [uv]ab − dx The BODMAS rule reminds us of the order in which operations are carried out. BODMAS stands for: Brackets () First priority Degrees and radians: (1) (2) (3) u Arithmetic When multiplying or dividing positive and negative numbers the sign of the result is given by: positive × positive = positive positive × negative = negative negative × positive = negative negative × negative = positive positive positive = positive = negative positive negative negative negative = negative = positive positive negative 1 cos 60 = , 2 ◦ tan 45◦ = 1 1 tan 30◦ = √ 3 √ ◦ tan 60 = 3 Bragg’s Law: a fundamental law of x-ray crystallography. nλ = 2d sin θ λ = wavelength of the x-rays incident on a crystal lattice with planes a distance d apart, n is an integer (whole number), and θ, the Bragg angle, is the angle between the incident beam and the reflecting planes. Matrices� and�Determinants a b has determinant c� d � �a b� � = ad − bc |A| = �� c d� a11 a12 a13 The 3 × 3 matrix A = a21 a22 a23 has determinant a31 a32 a33 � � � � � � � a22 a23 � � � � � � − a12 � a21 a23 � + a13 � a21 a22 � |A| = a11 �� � a31 a33 � � a31 a32 � a32 a33 � The 2 × 2 matrix A = The inverse of�a 2 × 2 matrix: � � � 1 a b d −b If A = then A−1 = c d ad − bc −c a provided that ad − bc �= 0. Matrix multiplication: for 2 × 2 matrices � �� � � � a b α γ aα + bβ aγ + bδ = c d β δ cα + dβ cγ + dδ Remember that AB �= BA except in special cases. www.mathcentre.ac.uk © mathcentre 2010 a(b − c) = ab − ac a ac (a + b)(c + d) = ac + ad + bc + bd c= b b Formula for solving a quadratic equation: √ 2 −b ± b − 4ac if ax2 + bx + c = 0 then x = 2a Laws of Indices: m a = am−n (am )n = amn (ab)n = an bn am an = am+n an √ √ m 1 a0 = 1 a−m = m a1/n = n a a n = ( n a)m a Logarithms: for any positive base b (with b = 1) logb A = c means A = bc . Logarithms to base e, denoted loge or alternatively ln are called natural logarithms. The letter e stands for the exponential constant which is approximately 2.718. loge A or ln A = c means A = ec . c, the natural logarithm of a number A, is the power to which e would have to be raised to equal A. Note: eln A = A if A > 0; ln(eA ) = A Logarithms to base 10: log10 A = c means A = 10c . pH: of a solution measures its acidity or basicity. ◦ pH = − log10 ([H+ ]/c− ) so ◦ [H+ ] = 10−pH c− where [H+ ] = hydrogen ion concentration in mol dm−3 and ◦ c− = 1 mol dm−3 . Equivalently, pH = − log10 aH3 O+ where aH3 O+ = hydronium ion activity. Laws of Logarithms: for any positive base b, with b = 1, A logb A − logb B = logb , logb A + logb B = logb AB, B logb 1 = 0, logb b = 1. n logb A = logb An , bx . Specifically, Formula for change of base: loga x = log logb a ln x log10 x = . ln 10 Inequalities: a > b means a is greater than b a < b means a is less than b a b means a is greater than or equal to b a b means a is less than or equal to b Sigma notation: The Greek letter sigma, Σ, is used to abbreviate addition. If we have n values, x1 , x2 , . . . xn , and add them, n the sum x1 + x2 + . . . xn is written xi . i=1 Note that i takes all whole number values from 1 to n. So, for 3 instance xi means x1 + x2 + x3 . i=1 5 i2 means 12 + 22 + 32 + 42 + 52 . n xi = x1 · x2 · . . . · xn . Product notation: Example: i=1 i=1 Produced in conjunction with the Higher Education Academy Maths, Stats & OR Network, the UK Physical Sciences Centre, sigma, and the HE STEM Programme. Thanks to the many individuals who c 2010. - version draft 1, August 2010. offered detailed advice. www.mathcentre.ac.uk © mathcentre 2010 (* A + B → P reaction.) = kt ln K2 K1 van’t Hoff equation: ◦ d ∆r H − . ln K = dT RT 2 ◦ ∆r H − =− R 2∗ 1 1 − T2 T1 ◦ = RT ln K At equilibrium Q = K, ∆r G = 0 and −∆r G− where (aJvJ )equilibrium where aJ is the activity of species J and νJ is its stoichiometric number. Standard state: The standard state of a substance is the pure substance at a pressure of 1 bar. The standard state value is ◦ denoted by the superscript symbol − ◦ , as in G− . ∆G Reaction Gibbs energy: ∆r G = is the slope of the ∆ξ graph of Gibbs energy against the progress of the reaction. Here, ∆ξ = ∆nJ /νJ for all species J in the reaction. Reaction Gibbs energy at any composition of the reaction mixture can be written v ◦ ∆r G = ∆r G− + RT ln Q where Q = aJ J J Reaction Thermodynamics Vm,i is the partial molar volume of the ith substance. Total Gibbs energy for the mixture is G = nA GA + nB GB where GA and GB are the partial molar Gibbs energies of substances A and B respectively. The partial molar Gibbs energies are also denoted µ and µ so that G = n µ +n µ . More A B A A B B n i µi . generally, with mixtures of several substances G = i where Vm,A = partial molar volume of A and Vm,B = partial ni Vm,i , where molar volume of B. More generally, V = Order ∗ where µA = chemical potential of pure A and xA is the mole fraction. Properties of mixtures: suppose an amount nA of substance A is mixed with nB of substance B. The total volume of the mixture is mol dm−3 s−1 [A]0 2k Rate Law Integrated form Common unit of k Half-life Rate Laws In the table, [A] = molar concentration of reactant A at time t. [A]0 = concentration of reactant A at time t = 0. Arrhenius equation: k = Ae−Ea /(RT ) where k = rate constant, Ea = the activation energy for the reaction, R = ideal gas constant, T = absolute temperature, and A is a constant. By taking logarithms this can be expressed as A Ea k = ln − − ln − k◦ k◦ RT ◦ where k− is a chosen standard rate constant. Together, A and Ea are called the Arrhenius parameters. Arrhenius equation: The rate at which most chemical reactions proceed depends upon the temperature. The amount of energy necessary for the reaction to take place at all is called the activation energy. These quantities are related by the Kinetics = a×b = (a2 b3 − a3 b2 )i + (a3 b1 − a1 b3 )j + (a1 b2 − a2 b1 )k � � � j k �� � i � � � a1 a2 a3 � � b1 b2 b3 � ê is a unit vector perpendicular to the plane containing a and b in a sense defined by the right hand screw rule. If a = a1 i + a2 j + a3 k and b = b1 i + b2 j + b3 k then a θ a × b = |a| |b| sin θ ê eˆ Vector product: ln xA b a · b = a 1 b1 + a 2 b2 + a 3 b3 If a = a1 i + a2 j + a3 k and b = b1 i + b2 j + b3 k then a θ a · b = |a| |b| cos θ b Scalar product: If r = xi + yj + zk then |r| = � General Thermodynamics NA = 6.022 × 1023 mol−1 kB = 1.381 × 10−23 J K−1 h = 6.626 × 10−34 J s e = 1.602 × 10−19 C R = 8.314 J K−1 mol−1 0 = 8.854 × 10−12 J−1 C2 m−1 c = 2.998 × 108 m s−1 F = e NA = 96.485 kC mol−1 Avogadro constant Boltzmann constant Planck constant Elementary charge Ideal gas constant Vacuum permittivity Speed of light (vacuum) Faraday constant Physical constants x2 + y 2 + z 2 . Vectors The general form of an equation of state is p = f (T, V, n) where p = pressure, T is temperature, V = volume, n = amount of substance. Boyle’s Law relates the pressure and volume of a gas when the temperature is fixed: p1 V1 = p2 V2 . 1 An equivalent form is: pV = nM c2 , where n = number of 3 molecules, m = mass of a molecule, M (= mNA ) is the molar mass of the molecules, c2 = mean square speed. Charles’s Law relates the volume and temperature of a gas at V1 T1 constant pressure: = . V2 T2 Mixtures s−1 ln 2 k = kt First Law: For a closed system, ∆U = q + w. Here ∆U is the change in internal energy of a system, w is the work done on the system, and q is the heat energy transferred to the system. Enthalpy: H = U +pV where U = internal energy, p=pressure and V = volume. � Heat capacity at constant volume: C = ∂U V �∂T V Heat capacity at constant pressure: Cp = ∂H ∂T p In general Cp depends upon T . Values of Cp at temperatures not much different from room temperature can be estimated c from Cp = a + bT + 2 T where a, b and c are experimentally determined constants. Second Law of thermodynamics: During a spontaneous change, the total entropy of an isolated system and its surroundings increases: ∆S > 0. For a reversible process, at constant temperature, T , change in entropy qrev ∆S = T where qrev = energy reversibly transferred as heat. Boltzmann formula: S = kB ln W where W = ‘weight’ of the most probable configuration of the system and kB is the Boltzmann constant. Helmholtz energy: A = U − T S. Gibbs energy: G = H − T S. Change in Gibbs energy: ∆G = ∆H − T ∆S (at constant temperature). Entropy change for isothermal expansion of an ideal gas: Vfinal Vinitial ∆S = nR ln A B Γ ∆ E Z H Θ α β γ δ ζ η θ alpha beta gamma delta epsilon zeta eta theta I K Λ M N Ξ O Π ι κ λ µ ν ξ o π iota kappa lambda mu nu xi omicron pi P Σ T Υ Φ X Ψ Ω ρ σ τ υ φ χ ψ ω rho sigma tau upsilon phi chi psi omega The Greek alphabet Gases Raoult’s law: states that the partial vapour pressure, pA , in a liquid mixture, A, is proportional to its mole fraction, xA , and ∗ ∗ its vapour pressure when pure, pA : p A = xA p A . Henry’s law: states that the vapour pressure, pB , of a volatile solute, B, is proportional to its mole fraction, xB , in a solution: pB = xB KB . Here KB is Henry’s law constant. Chemical potential of a solvent: = + RT mol−1 dm3 s−1 1 k[A]0 Multiple Prefix Symbol Multiple Prefix Symbol 1012 tera T 10−1 deci d 109 giga G 10−2 centi c 106 mega M 10−3 milli m 103 kilo k 10−6 micro µ 2 10 hecto h 10−9 nano n 101 deca da 10−12 pico p Interconversion of units: Sometimes alternative sets of units are used and conversion between these is needed. Pressure is often quoted in units corresponding to the Standard atmosphere (atm). Then 1 atm = 1.01325×105 Pa = 1.01325 bar = 760mm Hg = 760 Torr. (1 bar = 1 × 105 Pa). Length (of bonds) is sometimes quoted in Ångströms, Å where 1 Å = 10−10 m. 1 nm = 10−9 m. 0.1nm=100pm. Energy is often measured in calories (cal): 1 cal = 4.184 J. ∗ µA mol−1 dm3 s−1 - Amount of substance etc. The mole is the amount of substance that contains 6.0221415× 1023 (Avogadro constant/ mol−1 ) atoms or molecules of the pure substance being measured. For example 1 mole (mol) of potassium will contain NA atoms. 1 mole of water contains NA water molecules. A mole of any substance contains as many atoms or molecules (as specified) as there are atoms in 12g of the carbon isotope 12 6 C. (To avoid confusion, always specify the type of particle.) The molar mass, M , of a substance is the mass divided by chemical amount. For pure materials, molar mass, M = molecular weight (or relative atomic or molecular mass) × g mol−1 . The concentration or molarity of a solute is c = Vn where n = amount of solute, V = volume of solution. Molarity is usually quoted in mol dm−3 . The unit 1 mol dm−3 is commonly denoted 1 M and read as ‘molar’. The molality, b, of a solute is the amount of solute divided by n the mass of solvent: b = m . So, molality represents 1 mole of a solute in 1 kg of solvent. The mole fraction, x, of a solute is the amount of solute divided by the total amount in the solution: n x= . ntotal The mass density (or just density), ρ, of a substance is its mass divided by its volume, that is ρ = m . V The mass percentage is the mass of a substance in a mixture as a percentage of the total mass of the mixture. The mass-volume percentage is the number of grams of solute in 100 millilitres of solution. The volume-volume percentage is the number of millilitres of liquid solute in 100 millilitres of solution. Parts per million (ppm): mg/kg. Parts per billion (ppb): µg/kg. Mass obtained Yield: % yield = × 100 Theoretical yield µA 1 [A]0 where Vfinal and Vinitial [B][A]0 [A][B]0 [A]0 − [A] = kt = −k Rate Law Differential form i V = nA Vm,A + nB Vm,B − ln [A] = [A]0 e−kt = −k[A] d[A] dt 0 1 [A] = −k[A]2 d[A] dt 1 1 [B]0 −[A]0 = −k[A][B] d[A] dt 2 J K= d[A] dt are the initial volumes. and final ∆H ∆G ∂ =− 2 . ∂T T T p Gibbs-Helmholtz equation: Units & Conversions Scientific notation: is used to express large or small numbers concisely. Each number is written in the form a × 10n where a is usually a number between 1 and 10. We make use of . . . 0.01 = 10−2 , 0.1 = 10−1 , . . . , 100 = 102 , 1000 = 103 , . . . Then, for example, 6859 = 6.859 × 1000 = 6.859 × 103 and 0.0932 = 9.32 × 0.01 = 9.32 × 10−2 . SI base units: for most quantities it is necessary to specify the units in which they are measured. Quantity SI unit Symbol length metre m mass kilogram kg time second s temperature kelvin K amount of substance mole mol current ampere A luminous intensity candela cd Derived units are formed from the base units. For example, the unit of force is found by combining units of mass, length and time in the combination kg m s−2 . This combination is more usually known as the newton, N. Property unit name unit symbols frequency hertz Hz = s−1 force newton N = kg m s−2 pressure pascal Pa = N m−2 energy joule J = N m = kg m2 s−2 charge coulomb As potential difference volt V = J C−1 power watt W = J s−1 Celsius temperature degree Celsius ◦ C Capacitance farad F = C V−1 Resistance ohm Ω Common prefixes: a prefix is a method of multiplying the SI unit by an appropriate power of 10 to make it larger or smaller. Dalton’s Law of partial pressures: states that the pressure exerted by a mix of ideal gases is the sum of the partial pressures each would exert if they were alone in the same volume: n or ptotal = pi ptotal = p1 + p2 + . . . + pn i=1 The partial pressure, pi , of one of the gases can be calculated by multiplying the gas mole fraction, xi , by the total pressure of all the gases, ptotal . Perfect Gas Law: pV = nRT where R = ideal gas constant. p 2 V2 p 1 V1 = . Combined Gas Laws: T1 T2 Virial equation of state: This improves the perfect gas law because it takes into account intermolecular forces. B C pVm = RT (1 + + 2 + . . .) Vm Vm Vm = Vn = molar volume, B, C etc are the virial coefficients. Observe that when the molar volume is very large, the terms B and VC2 become increasingly less important, and in the limit Vm m we obtain the ideal gas law. Van der Waals equation takes into account the finite distance between molecules and interparticle attractions: an2 RT a p + 2 (V − nb) = nRT p= − 2 or Vm − b Vm V a is a measure of attraction between particles, b is the volume excluded by a mole of particles. Phases Gibbs’ phase rule: F = C − P + 2, where F is the number of degrees of freedom, C = number of independent components, P = the number of phases in equilibrium with each other. This is a relationship used to determine the number of state variables, F , chosen from amongst temperature, pressure and species compositions in each phase, which must be specified to fix the thermodynamic state of a system in equilibrium. Clapeyron equation relates change in pressure to change in temperature at a phase boundary. The slope of the phase dp boundary is dT . dp ∆H = dT T ∆V Here ∆H = molar enthalpy of transition, ∆V = change in molar volume during transition. Clausius-Clapeyron equation is an approximation of the Clapeyron equation for a liquid-vapour phase boundary. Plotting vapour pressure for various temperatures produces a curve. For 1 pure liquids, plotting ln pp− ◦ against T produces a straight line − ◦ ∆H with gradient − R . (Here, p = any standard pressure). p1 ∆H 1 1 ln =− − p2 R T1 T2 Here ∆H = molar enthalpy of vaporisation. This equation relates the natural logarithm of the vapour pressure to the temperature at a phase boundary. www.mathcentre.ac.uk © mathcentre 2010