Survey
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
By Mai Fukata Number of Sea Turtle hatchlings that survived 140 120 Number of sea turtles 100 80 All 60 Sites 40 20 0 Blue Yellow Green Red The color of the turtle Orange Atlantic Sharp-nose Sharks(Mean/Average) 1010 1000 990 980 970 The Mean of the Atlantic Sharp-nose sharks 960 Series1 950 940 930 920 Male Female Type of Gender The meaning of probability is… A way to measure the chances that something will occur in relation to the possible alternatives Distribution of 25 Sea Cigars 20 Number of the Sea Cigars 10 Number 0 "1-5" "6-10" "11-15" "16-20" Length of the Sea Cigars "21-25" "26-30" Number Below left: Mangrove sea cigar seedlings. Below right: Sea cigar, leaves, and the branch of a red mangrove tree. Percent Composition by Mass of the Flotsam Sea Grape Turtle Grass Manatee Grass Shoal Grass Red Manatee Leaf Black Manatee Leaf Detritivores Meaning: Two values that are used in statistics to describe how far away your date from the mean 6.7, 7.3, 7.5, 7.5, 9.4, 9.8, 11.2, 12.5, 13.1, 17.0(Measured in centimeters) Theoretical Distribution 4 3 Number of 2 Sea Cigars Theoretical Distribution Actual Data 1 0 1 3 5 7 9 11 13 15 17 19 21 23 25 Length The Chi-square test can be used to see if there are any significant differences between date sites or sources T-test: an equation you use designed to test whether there is a significant difference between the means of two independent samples. Question: Should the Fearless Fishers have rejected the null hypothesis? (Explain, using the T-statistic you generated and the table of critical values provided) Answer: Yes, the Fishers should have rejected the null hypothesis because their T-statistic value was calculated to be 3.75, which is greater than the critical value of 2.145 from the T-statistic table at 14 degrees of freedom and at the P-value of 0.05.