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GOVT. OF TAMILNADU DEPARTMENT OF SCHOOL EDUCATION BRIDGE COURSE 2011-2012 CLASS VIII- MATHS MATHEMATICIANS PYTHAGORAS 569 B.C. – 475 B.C. Greece First pure mathematician 5 beliefs Secret society Pythagorean theorem ARISTOTLE 384 B.C. – 322 B.C. Greece Philosopher Studied mathematics in relation to science EUCLID 325 B.C. – 265 B.C. Greece Wrote The Elements Geometry today AL-KHWARIZMI 780 A.D.-850 A.D. Baghdad (in Iraq) 1st book on Algebra Algebra Natural Number Equation Alileanardo-da-Vinci 1452 A.D. - 1519 A.D Italy Painter Architect Mechanic Galileo-Galili 1564 A.D.– 1642 A.D. Italy Teacher Mathematician ALGEBRA Types of polynomials: Polynomials are named according to the number of terms present in them. Monomial: Binomial: Trinomial They are special names given to a polynomial. Classify the following into monomials, binomials and trinomials: (A) x + 1 (B) 3m² (C) 2x²- x-4 ALGEBRA FIND THE VALUE OF THE VARIABLES 31.5 = a - 34.4 42 + y = 57 x + 76.31 = 164.89 x - 32 = 49 23+ y = 119 AREA Area measures the surface of something. 1 metre 1 metre 1m2 1 square metre 1 cm 1 cm 1 mm 1cm2 1 mm 1mm2 AREA OF A RECTANGULAR LAWN 5 metres long 3 metres wide The area is 15 square metres = 15 m2 Area of a rectangle = Length x Width Area of rectangle = Length x Width 65 m Field 32 m 210 mm 21 cm Page Area of field = 65 x 32 = 2080 m2 Area of the page = 30 x 21 = 630 cm2 30 cm 300 mm Area of the page = 300 x 210 = 63 000 mm2 UNITS OF AREA 1 square centimetre 1 cm 1 cm = 10 mm 1 cm2 = 100 mm2 1 cm 1 cm2 = 102 mm2 UNITS OF AREA 1 square metre 1000 mm 1m 100 cm 1 m = 100 cm 1 m2 = 100 x 100 cm2 1 m2 = 10 000 cm2 1000 mm 1m 100 cm 1 m = 1000 mm 1 m2 = 1000 x 1000 mm2 1 m2 = 1 000 000 mm2 1 m2 = 1002 cm2 = 10002 mm2 PERIMETER Perimeter of a shape is the total length of its sides. Perimeter of a rectangle = length + width + length + width length width width length P = l + w + l + w P = 2l + 2w P = 2(l + w) Example L-shaped room 3m Perimeter = 3 + 1.5 + 2.2 + 3 + 5.2 + 4.5 = 19.4 m 1.5 m 4.5 m A 2.2 m B 5.2 m 3m Area of A = 4.5 x 3 = 13.5 m2 Area of B = 3 x 2.2 Total area = 13.5 + 6.6 = 20.1 m2 = 6.6 m2 VOLUME is the amount of space occupied by any 3dimensional object. 1cm 1cm 1cm Volume = base area x height = 1cm2 x 1cm = 1cm2 Cuboid Side 2 Top Back Front Bottom Length (L) Side 1 Height (H) Breadth (B) THE NET L H B B H H L HH L B L H B B L B Total surface Area L L H L B B H B B H L H L H L H L Total surface Area = L x H + B x H + L x H + B x H +LxB+LxB = 2 LxB + 2BxH + 2LxH = 2 ( LB + BH + LH ) CUBE L L L Volume = Base area x height =LxLxL = L3 • Total surface area = 2LxL + 2LxL + 2LxL = 6L2 Name Cube Figure Volume L3 Total surface area 6L2 Cuboid LxBxH 2(LxB + BxH + LxH) Sample net VOLUME OF A CYLINDER WHAT IS THIS? It has 2 equal shapes at the base, but it is not a prism as it has rounded sides It is a Cylinder EXAMPLE V = Base area x Height 2 = r X h The Circle O CIRCLE Eg. ball,bangle,lemon.coin A CENTRE B CENTRE : O RADIUS : OA O RADIUS A . O In a plane,each point of the circle is at equal distance from a fixed point.The fixed point is called the centre of the circle. CENTRE = O O Radius A The distance from centre to any point on the circle is called radius of the circle. RADIUS = OA A D I A O M E T E R . B A Line segment passing through the centre of the circle and whose end points lie on the circle is called the diameter of the circle. DIAMETER = AB . O The length of the circle or the distance around it is called circumference of the circle. Relation between radius and diameter RADIUS = DIAMETER 2 A OB = AB 2 . O B EG. IF DIAMETER OF THE CIRCLE IS 10 CM THEN FIND ITS RADIUS? Sol. Radius =diameter / 2 radius=10 cm/ 2 radius =5 cm A . O Diameter = 10cm B LINES AND ANGLES PARALLEL LINES Def: line that do not intersect. Illustration: B A l m Notation: l || m AB || CD D C PERPENDICULAR LINES Def: Lines that intersect to form a right angle. Illustration: m Notation: m n Key Fact: 4 right angles are formed. n TRANSVERSAL Def: a line that intersects two lines at different points Illustration: t VERTICAL ANGLES Two angles that are opposite angles. t 1 2 3 4 6 5 7 8 1 4 2 3 5 8 6 7 VERTICAL ANGLES Find the measures of the missing angles t 125 ? 125 ? 55 55 SUPPLEMENTARY ANGLES/ LINEAR PAIR Two angles that form a line (sum=180) 1+2=180 2+4=180 4+3=180 3+1=180 t 1 2 3 4 6 5 7 8 5+6=180 6+8=180 8+7=180 7+5=180 SUPPLEMENTARY ANGLES/ LINEAR PAIR Find the measures of the missing angles t 108? 72 ?108 180 - 72 ALTERNATE INTERIOR ANGLES Two angles that lie between parallel lines on opposite sides of the transversal t 1 2 3 4 5 6 7 8 3 6 4 5 ALTERNATE INTERIOR ANGLES Find the measures of the missing angles t 82 98 ?82 ALTERNATE EXTERIOR ANGLES Two angles that lie outside parallel lines on opposite sides of the transversal t 1 2 3 4 5 6 7 8 2 7 1 8 ALTERNATE EXTERIOR ANGLES Find the measures of the missing angles t 120 60 ?120 CONSECUTIVE INTERIOR ANGLES Two angles that lie between parallel lines on the same sides of the transversal t 1 2 3 4 5 6 7 8 3 +5 = 180 4 +6 = 180 CONSECUTIVE INTERIOR ANGLES Find the measures of the missing angles t 135 ?45 180 - 135 GRAPH GRAPH THE FOLLOWING LINES Y = -4 Y=2 X=5 X = -5 X=0 Y=0 ANSWERS x = -5 Y x=5 X ANSWERS Y y=2 X y = -4 MEAN DEFINITION Mean – the average of a group of numbers. 2, 5, 2, 1, 5 Mean = 3 MEAN IS FOUND BY EVENING OUT THE NUMBERS 2, 5, 2, 1, 5 MEAN IS FOUND BY EVENING OUT THE NUMBERS 2, 5, 2, 1, 5 Copy right © 2000 by Moni ca Yusk MEAN IS FOUND BY EVENING OUT THE NUMBERS 2, 5, 2, 1, 5 mean = 3 HOW TO FIND THE MEAN OF A GROUP OF NUMBERS • Step 1 – Add all the numbers. 8, 10, 12, 18, 22, 26 8+10+12+18+22+26 = 96 Step 2 – Divide the sum by the number of addends = 96/6 = 16 HOW TO FIND THE MEAN OF A GROUP OF NUMBERS The mean or average of these numbers is 16. 8, 10, 12, 18, 22, 26 WHAT IS THE MEAN OF THESE NUMBERS? 7, 10, 16 11 WHAT IS THE MEAN OF THESE NUMBERS? 2, 9, 14, 27 13 WHAT IS THE MEAN OF THESE NUMBERS? 1, 2, 7, 11, 19 8 WHAT IS THE MEAN OF THESE NUMBERS? 26, 33, 41, 52 38 DEFINITION Median – the middle number in a set of ordered numbers. 1, 3, 7, 10, 13 Median = 7 HOW TO FIND THE MEDIAN IN A GROUP OF NUMBERS Step 3 – If there are two middle numbers, find the mean of these two numbers. 21+ 25 = 46 median 23 2) 46 DEFINITION Mode – the number that appears most frequently in a set of numbers. 1, 1, 3, 7, 10, 13 Mode = 1 Find the mode for the following 7, 4, 5, 1, 7, 3, 4, 6, 7 Find the mode of the following frequency table: If the data are arranged in the form of a frequency table the class corresponding to the maximum frequency is called the model class. The value of the variate of the model class is the mode. x 10 20 30 40 50 60 F 8 15 12 10 9 6