Download Chapter 3 Control Methods

Chapter 3 Selections
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1
Motivations
If you assigned a negative value for radius in
Listing 2.1, ComputeArea.java, the program would
print an invalid result. If the radius is negative, you
don't want the program to compute the area. How
can you deal with this situation?
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2
The boolean Type and Operators
Often in a program you need to compare two
values, such as whether i is greater than j. Java
provides six comparison operators (also known
as relational operators) that can be used to
compare two values. The result of the
comparison is a Boolean value: true or false.
boolean b = (1 > 2);
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Comparison Operators
Operator Name
<
less than
<=
less than or equal to
>
greater than
>=
greater than or equal to
==
equal to
!=
not equal to
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Boolean Operators
Operator Name
!
not
&&
and
||
or
^
exclusive or
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Truth Table for Operator !
p
!p
true
false
!(1 > 2) is true, because (1 > 2) is false.
false
true
!(1 > 0) is false, because (1 > 0) is true.
Example
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Truth Table for Operator &&
p1
p2
p1 && p2
false
false
false
false
true
false
true
false
false
true
true
true
Example
(3 > 2) && (5 >= 5) is true, because (3 >
2) and (5 >= 5) are both true.
(3 > 2) && (5 > 5) is false, because (5 >
5) is false.
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Truth Table for Operator ||
p1
p2
p1 || p2
false
false
false
false
true
true
true
false
true
true
true
true
Example
(2 > 3) || (5 > 5) is false, because (2 > 3)
and (5 > 5) are both false.
(3 > 2) || (5 > 5) is true, because (3 > 2)
is true.
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Truth Table for Operator ^
p1
p2
p1 ^ p2
false
false
false
false
true
true
true
false
true
true
true
false
Example
(2 > 3) ^ (5 > 1) is true, because (2 > 3)
is false and (5 > 1) is true.
(3 > 2) ^ (5 > 1) is false, because both (3
> 2) and (5 > 1) are true.
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Examples
System.out.println("Is " + number + " divisible by 2 and 3? " +
((number % 2 == 0) && (number % 3 == 0)));
System.out.println("Is " + number + " divisible by 2 or 3? " +
((number % 2 == 0) || (number % 3 == 0)));
System.out.println("Is " + number +
" divisible by 2 or 3, but not both? " +
((number % 2 == 0) ^ (number % 3 == 0)));
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10
Problem: Determining Leap Year?
This program first prompts the user to enter a year as
an int value and checks if it is a leap year.
A year is a leap year if it is divisible by 4 but not by
100, or it is divisible by 400.
(year % 4 == 0 && year % 100 != 0) || (year % 400
== 0)
LeapYear
Run
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11
Selection Statements

if Statements

switch Statements

Conditional Operators
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Simple if Statements
if (booleanExpression) {
statement(s);
}
Boolean
Expression
if (radius >= 0) {
area = radius * radius * PI;
System.out.println("The area"
+ " for the circle of radius "
+ radius + " is " + area);
}
false
false
(radius >= 0)
true
true
Statement(s)
(A)
area = radius * radius * PI;
System.out.println("The area for the circle of " +
"radius " + radius + " is " + area);
(B)
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Note
Outer parentheses required
if ((i > 0) && (i < 10)) {
System.out.println("i is an " +
+ "integer between 0 and 10");
}
(a)
Braces can be omitted if the block contains a single
statement
Equivalent
if ((i > 0) && (i < 10))
System.out.println("i is an " +
+ "integer between 0 and 10");
(b)
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Caution
Adding a semicolon at the end of an if clause is a common
mistake.
if (radius >= 0);
Wrong
{
area = radius*radius*PI;
System.out.println(
"The area for the circle of radius " +
radius + " is " + area);
}
This mistake is hard to find, because it is not a compilation error or
a runtime error, it is a logic error.
This error often occurs when you use the next-line block style.
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The if...else Statement
if (booleanExpression) {
statement(s)-for-the-true-case;
}
else {
statement(s)-for-the-false-case;
}
true
Statement(s) for the true case
Boolean
Expression
false
Statement(s) for the false case
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if...else Example
if (radius >= 0) {
area = radius * radius * 3.14159;
System.out.println("The area for the “
+ “circle of radius " + radius +
" is " + area);
}
else {
System.out.println("Negative input");
}
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Multiple Alternative if Statements
if (score >= 90.0)
grade = 'A';
else
if (score >= 80.0)
grade = 'B';
else
if (score >= 70.0)
grade = 'C';
else
if (score >= 60.0)
grade = 'D';
else
grade = 'F';
Equivalent
if (score >= 90.0)
grade = 'A';
else if (score >= 80.0)
grade = 'B';
else if (score >= 70.0)
grade = 'C';
else if (score >= 60.0)
grade = 'D';
else
grade = 'F';
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animation
Trace if-else statement
Suppose score is 70.0
The condition is false
if (score >= 90.0)
grade = 'A';
else if (score >= 80.0)
grade = 'B';
else if (score >= 70.0)
grade = 'C';
else if (score >= 60.0)
grade = 'D';
else
grade = 'F';
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animation
Trace if-else statement
Suppose score is 70.0
The condition is true
if (score >= 90.0)
grade = 'A';
else if (score >= 80.0)
grade = 'B';
else if (score >= 70.0)
grade = 'C';
else if (score >= 60.0)
grade = 'D';
else
grade = 'F';
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animation
Trace if-else statement
Suppose score is 70.0
grade is C
if (score >= 90.0)
grade = 'A';
else if (score >= 80.0)
grade = 'B';
else if (score >= 70.0)
grade = 'C';
else if (score >= 60.0)
grade = 'D';
else
grade = 'F';
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21
Note
The else clause matches the most recent if clause in the
same block.
int i = 1;
int j = 2;
int k = 3;
int i = 1;
int j = 2;
int k = 3;
Equivalent
if (i > j)
if (i > k)
System.out.println("A");
else
System.out.println("B");
if (i > j)
if (i > k)
System.out.println("A");
else
System.out.println("B");
(a)
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(b)
22
Note, cont.
Nothing is printed from the preceding statement. To force
the else clause to match the first if clause, you must add a
pair of braces:
int i = 1;
int j = 2;
int k = 3;
if (i > j) {
if (i > k)
System.out.println("A");
}
else
System.out.println("B");
This statement prints B.
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TIP
if (number % 2 == 0)
even = true;
else
even = false;
(a)
Equivalent
boolean even
= number % 2 == 0;
(b)
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CAUTION
if (even == true)
System.out.println(
"It is even.");
Equivalent
if (even)
System.out.println(
"It is even.");
(a)
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(b)
25
Problem: Body Mass Index
Body Mass Index (BMI) is a measure of health on
weight. It can be calculated by taking your weight
in kilograms and dividing by the square of your
height in meters. The interpretation of BMI for
people 16 years or older is as follows:
BMI
Interpretation
below 16
16-18
18-24
24-29
29-35
above 35
serious underweight
underweight
normal weight
overweight
seriously overweight
gravely overweight
ComputeBMI
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Run
26
Problem: Computing Taxes
The US federal personal income tax is calculated based on
the filing status and taxable income. There are four filing
statuses: single filers, married filing jointly, married filing
separately, and head of household. The tax rates for 2002
are shown in Table 3.1.
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Problem: Computing Taxes, cont.
if (status == 0) {
// Compute tax for single filers
}
else if (status == 1) {
// Compute tax for married file jointly
}
else if (status == 2) {
// Compute tax for married file separately
}
else if (status == 3) {
// Compute tax for head of household
}
else {
// Display wrong status
}
ComputeTax
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Run
28
Problem: Guessing Birth Date
The program can guess your birth date. Run
to see how it works.
= 19
+
1 3 5 7
9 11 13 15
17 19 21 23
25 27 29 31
Set1
2
10
18
26
3
11
19
27
6
14
22
30
Set2
7
15
23
31
4 5 6 7
12 13 14 15
20 21 22 23
28 29 30 31
8 9 10 11
12 13 14 15
24 25 26 27
28 29 30 31
Set3
Set4
GuessBirthDate
16
20
24
28
17
21
25
29
18
22
26
30
Set5
Run
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19
23
27
31
switch Statements
switch (status) {
case 0: compute taxes for single filers;
break;
case 1: compute taxes for married file jointly;
break;
case 2: compute taxes for married file separately;
break;
case 3: compute taxes for head of household;
break;
default: System.out.println("Errors: invalid status");
System.exit(0);
}
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switch Statement Flow Chart
status is 0
Compute tax for single filers
break
Compute tax for married file jointly
break
Compute tax for married file separatly
break
Compute tax for head of household
break
status is 1
status is 2
status is 3
default
Default actions
Next Statement
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31
switch Statement Rules
The switch-expression
must yield a value of char,
byte, short, or int type and
must always be enclosed in
parentheses.
The value1, ..., and valueN must
have the same data type as the
value of the switch-expression.
The resulting statements in the
case statement are executed when
the value in the case statement
matches the value of the switchexpression. Note that value1, ...,
and valueN are constant
expressions, meaning that they
cannot contain variables in the
expression, such as 1 + x.
switch (switch-expression) {
case value1: statement(s)1;
break;
case value2: statement(s)2;
break;
…
case valueN: statement(s)N;
break;
default: statement(s)-for-default;
}
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switch Statement Rules
The keyword break is optional,
but it should be used at the end of
each case in order to terminate the
remainder of the switch
statement. If the break statement
is not present, the next case
statement will be executed.
The default case, which is
optional, can be used to perform
actions when none of the
specified cases matches the
switch-expression.
switch (switch-expression) {
case value1: statement(s)1;
break;
case value2: statement(s)2;
break;
…
case valueN: statement(s)N;
break;
default: statement(s)-for-default;
}
The case statements are executed in sequential
order, but the order of the cases (including the
default case) does not matter. However, it is good
programming style to follow the logical sequence
of the cases and place the default case at the end.
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Conditional Operator
if (x > 0)
y=1
else
y = -1;
is equivalent to
y = (x > 0) ? 1 : -1;
(booleanExpression) ? expression1 : expression2
Ternary operator
Binary operator
Unary operator
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Conditional Operator
if (num % 2 == 0)
System.out.println(num + “is even”);
else
System.out.println(num + “is odd”);
System.out.println(
(num % 2 == 0)? num + “is even” :
num + “is odd”);
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Conditional Operator, cont.
(booleanExp) ? exp1 : exp2
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Formatting Output
Use the new JDK 1.5 printf statement.
System.out.printf(format, items);
Where format is a string that may consist of substrings and
format specifiers. A format specifier specifies how an item
should be displayed. An item may be a numeric value,
character, boolean value, or a string. Each specifier begins
with a percent sign.
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Frequently-Used Specifiers
Specifier Output
Example
%b
a boolean value
true or false
%c
a character
'a'
%d
a decimal integer
200
%f
a floating-point number
45.460000
%e
a number in standard scientific notation
4.556000e+01
%s
a string
"Java is cool"
int count = 5;
items
double amount = 45.56;
System.out.printf("count is %d and amount is %f", count, amount);
display
count is 5 and amount is 45.560000
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Operator Precedence












var++, var-+, - (Unary plus and minus), ++var,--var
(type) Casting
! (Not)
*, /, % (Multiplication, division, and remainder)
+, - (Binary addition and subtraction)
<, <=, >, >= (Comparison)
==, !=; (Equality)
^ (Exclusive OR)
&& (Conditional AND) Short-circuit AND
|| (Conditional OR) Short-circuit OR
=, +=, -=, *=, /=, %= (Assignment operator)
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Operator Associativity
When two operators with the same precedence
are evaluated, the associativity of the operators
determines the order of evaluation. All binary
operators except assignment operators are leftassociative.
a – b + c – d is equivalent to ((a – b) + c) – d
Assignment operators are right-associative.
Therefore, the expression
a = b += c = 5 is equivalent to a = (b += (c = 5))
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Example
Applying the operator precedence and associativity rule,
the expression 3 + 4 * 4 > 5 * (4 + 3) - 1 is evaluated as
follows:
3 + 4 * 4 > 5 * (4 + 3) - 1
3 + 4 * 4 > 5 * 7 – 1
3 + 16 > 5 * 7 – 1
(1) inside parentheses first
(2) multiplication
(3) multiplication
3 + 16 > 35 – 1
19 > 35 – 1
19 > 34
false
(4) addition
(5) subtraction
(6) greater than
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Chapter 4 Loops
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Motivations
Suppose that you need to print a string (e.g.,
"Welcome to Java!") a hundred times. It would be
tedious to have to write the following statement a
hundred times:
System.out.println("Welcome to Java!");
So, how do you solve this problem?
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43
while Loop Flow Chart
while (loop-continuation-condition) {
// loop-body;
int count = 0;
while (count < 100) {
System.out.println("Welcome to Java!");
Statement(s);
count++;
}
}
count = 0;
Loop
Continuation
Condition?
true
Statement(s)
(loop body)
(A)
false
(count < 100)?
false
true
System.out.println("Welcome to Java!");
count++;
(B)
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animation
Trace while Loop, cont.
int count = 0;
(count < 2) is true
while (count < 2) {
System.out.println("Welcome to Java!");
count++;
}
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animation
Trace while Loop, cont.
int count = 0;
Print Welcome to Java
while (count < 2) {
System.out.println("Welcome to Java!");
count++;
}
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46
animation
Trace while Loop, cont.
int count = 0;
Increase count by 1
count is 1 now
while (count < 2) {
System.out.println("Welcome to Java!");
count++;
}
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animation
Trace while Loop, cont.
int count = 0;
(count < 2) is still true since count
is 1
while (count < 2) {
System.out.println("Welcome to Java!");
count++;
}
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animation
Trace while Loop, cont.
int count = 0;
Increase count by 1
count is 2 now
while (count < 2) {
System.out.println("Welcome to Java!");
count++;
}
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animation
Trace while Loop, cont.
int count = 0;
(count < 2) is false since count is 2
now
while (count < 2) {
System.out.println("Welcome to Java!");
count++;
}
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animation
Trace while Loop
int count = 0;
The loop exits. Execute the next
statement after the loop.
while (count < 2) {
System.out.println("Welcome to Java!");
count++;
}
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Ending a Loop with a Sentinel Value
Often the number of times a loop is executed is not
predetermined. You may use an input value to
signify the end of the loop. Such a value is known
as a sentinel value.
Write a program that reads and calculates the sum
of an unspecified number of integers. The input 0
signifies the end of the input.
SentinelValue
Run
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Caution
Don’t use floating-point values for equality checking in
a loop control. Since floating-point values are
approximations, using them could result in imprecise
counter values and inaccurate results. This example uses
int value for data. If a floating-point type value is used
for data, (data != 0) may be true even though data is 0.
// data should be zero
double data = Math.pow(Math.sqrt(2), 2) - 2;
if (data == 0)
System.out.println("data is zero");
else
System.out.println("data is not zero");
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do-while Loop
Statement(s)
(loop body)
true
do {
// Loop body;
Loop
Continuation
Condition?
false
Statement(s);
} while (loop-continuation-condition);
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for Loops
for (initial-action; loopcontinuation-condition;
action-after-each-iteration) {
// loop body;
Statement(s);
}
Initial-Action
Loop
Continuation
Condition?
int i;
for (i = 0; i < 100; i++) {
System.out.println(
"Welcome to Java!");
}
i=0
false
(i < 100)?
true
Statement(s)
(loop body)
true
System.out.println(
"Welcome to Java");
Action-After-Each-Iteration
i++
(A)
(B)
false
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animation
Trace for Loop, cont.
int i;
for (i = 0; i < 2; i++) {
System.out.println( "Welcome to Java!");
}
(i < 2) is true
since i is 0
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56
animation
Trace for Loop, cont.
Print Welcome to Java
int i;
for (i = 0; i < 2; i++) {
System.out.println("Welcome to Java!");
}
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57
animation
Trace for Loop, cont.
int i;
for (i = 0; i < 2; i++) {
System.out.println("Welcome to Java!");
}
Execute adjustment statement
i now is 1
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animation
Trace for Loop, cont.
int i;
for (i = 0; i < 2; i++) {
System.out.println("Welcome to Java!");
}
(i < 2) is still true
since i is 1
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animation
Trace for Loop, cont.
int i;
for (i = 0; i < 2; i++) {
System.out.println("Welcome to Java!");
}
Execute adjustment statement
i now is 2
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animation
Trace for Loop, cont.
int i;
for (i = 0; i < 2; i++) {
System.out.println("Welcome to Java!");
}
(i < 2) is false
since i is 2
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animation
Trace for Loop, cont.
int i;
for (i = 0; i < 2; i++) {
System.out.println("Welcome to Java!");
}
Exit the loop. Execute the next
statement after the loop
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Note
The initial-action in a for loop can be a list of zero or more
comma-separated expressions. The action-after-eachiteration in a for loop can be a list of zero or more commaseparated statements. Therefore, the following two for
loops are correct. They are rarely used in practice,
however.
for (int i = 1; i < 100; System.out.println(i++));
for (int i = 0, j = 0; (i + j < 10); i++, j++) {
// Do something
}
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Note
If the loop-continuation-condition in a for loop is omitted,
it is implicitly true. Thus the statement given below in (a),
which is an infinite loop, is correct. Nevertheless, it is
better to use the equivalent loop in (b) to avoid confusion:
for ( ; ; ) {
// Do something
}
(a)
Equivalent
while (true) {
// Do something
}
(b)
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Caution
Adding a semicolon at the end of the for clause before
the loop body is a common mistake, as shown below:
Logic
Error
for (int i=0; i<10; i++);
{
System.out.println("i is " + i);
}
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Caution, cont.
Similarly, the following loop is also wrong:
int i=0;
Logic Error
while (i < 10);
{
System.out.println("i is " + i);
i++;
}
In the case of the do loop, the following semicolon is
needed to end the loop.
int i=0;
do {
System.out.println("i is " + i);
i++;
Correct
} while (i<10);
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Which Loop to Use?
The three forms of loop statements, while, do-while, and for, are
expressively equivalent; that is, you can write a loop in any of these
three forms. For example, a while loop in (a) in the following figure
can always be converted into the following for loop in (b):
while (loop-continuation-condition) {
// Loop body
}
Equivalent
for ( ; loop-continuation-condition; )
// Loop body
}
(a)
(b)
A for loop in (a) in the following figure can generally be converted into the
following while loop in (b) except in certain special cases (see Review Question
3.19 for one of them):
for (initial-action;
loop-continuation-condition;
action-after-each-iteration) {
// Loop body;
}
(a)
Equivalent
initial-action;
while (loop-continuation-condition) {
// Loop body;
action-after-each-iteration;
}
(b)
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Recommendations
Use the one that is most intuitive and comfortable for
you. In general, a for loop may be used if the number of
repetitions is known, as, for example, when you need to
print a message 100 times. A while loop may be used if
the number of repetitions is not known, as in the case of
reading the numbers until the input is 0. A do-while loop
can be used to replace a while loop if the loop body has to
be executed before testing the continuation condition.
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Nested Loops
Problem: Write a program that uses nested for
loops to print a multiplication table.
MultiplicationTable
Run
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Minimizing Numerical Errors
Numeric errors involving floating-point
numbers are inevitable. This section discusses
how to minimize such errors through an
example.
Listing 4.7 presents an example that sums a
series that starts with 0.01 and ends with 1.0.
The numbers in the series will increment by
0.01, as follows: 0.01 + 0.02 + 0.03 and so on.
TestSum
Run
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Problem: Finding the Sales Amount
Problem: You have just started a sales job in a department store. Your
pay consists of a base salary and a commission. The base salary is
$5,000. The scheme shown below is used to determine the
commission rate.
Sales Amount
Commission Rate
$0.01–$5,000
8 percent
$5,000.01–$10,000
10 percent
$10,000.01 and above
12 percent
Your goal is to earn $30,000 in a year. Write a program that will find
out the minimum amount of sales you have to generate in order to
make $30,000.
FindSalesAmount
Run
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Using break and continue
Examples for using the break and continue
keywords:

TestBreak.java
TestBreak

Run
TestContinue.java
TestContinue
Run
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Problem: Displaying Prime Numbers
Problem: Write a program that displays the first 50 prime numbers in
five lines, each of which contains 10 numbers. An integer greater than
1 is prime if its only positive divisor is 1 or itself. For example, 2, 3,
5, and 7 are prime numbers, but 4, 6, 8, and 9 are not.
Solution: The problem can be broken into the following tasks:
•For number = 2, 3, 4, 5, 6, ..., test whether the number is prime.
•Determine whether a given number is prime.
•Count the prime numbers.
•Print each prime number, and print 10 numbers per line.
PrimeNumber
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(GUI) Controlling a Loop with a
Confirmation Dialog
A sentinel-controlled loop can be implemented using a confirmation
dialog. The answers Yes or No to continue or terminate the loop. The
template of the loop may look as follows:
int option = 0;
while (option == JOptionPane.YES_OPTION) {
System.out.println("continue loop");
option = JOptionPane.showConfirmDialog(null, "Continue?");
}
SentinelValueUsingConfirmationDialog
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74