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Transcript
How much heat is given off when an 869 g iron bar cools from 94.0°C to 5.0°C? Cs of Fe = 0.45 J/(g ⢠°C) DT = Tfinal â Tinitial = 5.0 °C â 94.0 °C = â 89.0 °C q = m·Cs·DT= (869 g) · (0.45 J/(g ⢠°C)) · (â 89.0 °C) = â 34,800 J â â 3.5 x 104 J = â 35 kJ
